Bertwim,
I'm not sure that the volume renderer can handle VTK_HEXAHEDRON
elements. Try the Tetrahedralize filter on your source and see if
the Volume representation works.
Thanks,
Cory
On Mon, Oct 13, 2014 at 10:19 AM, B.W.H. van Beest b...@xs4all.nl wrote:
Hi,
I'm struggling to get a proper
No, it doesn't work. The filter creates tets, which are visible in the
wireframe representation,
but when I select Volume representation the image disappears.
I can't imagine it is so difficult to render a volume in Paraview. I
must be doing something wrong
Regards,
Bertwim
On 10/13/2014
do you have any scalars? those are not optional for volume rendering.
Additionally you may need to adjust the transfer function,
On 10/13/2014 10:22 AM, B.W.H. van Beest wrote:
No, it doesn't work. The filter creates tets, which are visible in the
wireframe representation,
but when I select
Yes, I do set a scalar for each cell. I left them out in the example, as
also with a scalar I couldn't get a volume display.
I'm not sure what you mean by adjusting the transfer function.
Regards,
Bertwim
On 10/13/2014 07:28 PM, Burlen Loring wrote:
do you have any scalars? those are not
Aashish,
I do see errors in the wavelet example, but not in the other cases. If
ok with you , I'll send the full code (it is not much, ~100K) as a
zipped tar file by email. There is no other data.
Regards,
Bertwim
On 10/13/2014 07:43 PM, Aashish Chaudhary wrote:
Bertwim,
If you are seeing
Cory, Bertwin, et al.;
The exact volume of an arbitrarily oriented, arbitrary 8-vertex
hexahedron can be computed with a very elementary construct.
First, place an average-coordinate point at the center of the
hexahedron; this point will be a common vertex point for a set of
tetrahedrons
Samuel,
Thanks for taking the efforts to dive into this.
In fact, it is a good reminder to me to try a single tetraeder first. My
primary problem seems to be that
I cannot get volume rendering to work.
Kind Regards,
Bertwim
On 10/13/2014 07:17 PM, Samuel Key wrote:
Cory, Bertwin, et al.;
The
