On 30 May 2011 22:31, Nazish naz...@jhu.edu wrote:
Hi all,
I've run into a little barrier, and I'm wondering whether you have any
insights. I'm entering values into a MySQL database. Before running the
mysql_query, I'm checking if the value already exists (using mysql_num_rows
== 0). If the
try this instead..
if(mysql_num_rows($check) 0) {
//true
} else {
//false
}
and yes, Peter's right... please dont make everything die().
Karl
On May 30, 2011, at 3:43 PM, Peter Lind wrote:
On 30 May 2011 22:31, Nazish naz...@jhu.edu wrote:
Hi all,
I've run into a little
That did the trick: I was over-enthusiastic in my usage of die(mysql_error).
I initially used mysql_error to troubleshoot another problem (which has now
re-emerged), but that's a different question which is puzzling me. The error
message ($alert = Username already exists!;) displays on the page
Code runs smoothly now, thanks. It's always great to pick up diverse coding
tips through the conversations here.
2011/5/30 Nazish naz...@jhu.edu
That did the trick: I was over-enthusiastic in my usage of
die(mysql_error).
I initially used mysql_error to troubleshoot another problem (which
Richard Dunne wrote:
In my code below, I am trying to verify that the query is selecting data from both rows of my answers table. I have run the query on my MySQL CLI and getting answers from both rows, but running this script I get $rows = 0. I can't figure out why its not returning 2 for the
This much is working:
?PHP
ini_set('error_reporting',E_All);
DEFINE (host,localhost);
DEFINE (user,root);
DEFINE (password,password);
DEFINE (database,questions);
$connection=mysql_connect(host,user,password) or die ('Could not connect' .
mysql_error() );
That means that you dont have any rows to work with. It could mean
that you are not connected to the database, or the query you performed
did not return any rows.
Calvin
On Tue, 8 Mar 2005 16:11:10 +0300, Tsegaye Woldegebriel
[EMAIL PROTECTED] wrote:
Dear Sir or Madame,
I found the following
Use the mysql_error() function which may give you more answers. In
addition you can use something like
$num = mysql_num_rows($test);
echo $num;
If it returns 0 you have no entries, if nothing happens then you have
problem with your query or connection. If you get a number then there is
Calvin Lough wrote:
That means that you dont have any rows to work with. It could mean
that you are not connected to the database, or the query you performed
did not return any rows.
Calvin
On Tue, 8 Mar 2005 16:11:10 +0300, Tsegaye Woldegebriel
[EMAIL PROTECTED] wrote:
Dear Sir or Madame,
I found
From a quick glance, I noticed that you have commented out the code that does the
actual query against the MySQL database. This is the line:
// $result = mysql_query($query, $db);
Without this statement, there is no query to the database. It should be:
$result = mysql_query($query);
because you're supplying it with a string not the result of the query..
uncomment your line that says:
$result = mysql_query($query, $db);
and change the num rows line to:
else if (mysql_num_rows($result)==1)
Your line that gets the column results will fail for the same reason, give it
the
$query =SELECT username FROM users WHERE username=('$username');
// $result = mysql_query($query, $db);
Above line should be uncommented.
if (!$query)
And the if checking the number of rows returned from the $result set.
--
PHP Database Mailing List (http://www.php.net/)
To
ok, I uncommented the line and changed a few things around. However I
am still getting errors. I really do appreciate everyone's help.
Thanks CH
Here is the 'new' code:
function notify_password($username, $password)
// notify the user that their password has been changed
{
$query
-Original Message-
From: Craig Hoffman [mailto:[EMAIL PROTECTED]
Sent: Wednesday, March 03, 2004 3:34 PM
To: [EMAIL PROTECTED]
Subject: Re: [PHP-DB] mysql_num_rows
ok, I uncommented the line and changed a few things around.
However I
am still getting errors. I really do
the $db variable isn't referencing a proper connection. As you did not create
the db connection in this function, I'm assuming it's a scope problem. Make
sure that $db is global, and then add a global statement to the first line in
the function for this variable.
the $db you're referencing
I got it working! Thanks everyone!
__
Craig Hoffman - eClimb Media
v: (847) 644 - 8914
f: (847) 866 - 1946
e: [EMAIL PROTECTED]
w: www.eclimb.net
_
On Mar 3, 2004, at 2:46 PM, Micah Stevens wrote:
the $db variable isn't referencing a
On Wednesday 20 November 2002 09:11, Tyler Whitesides wrote:
Hi,
I have been having some trouble with this, I mysql_num_rows() to find
out how many rows there are and do an insert statement in the for loop
for every row returned. So, if mysql_num_rows returns 17 then the for
loops does an
I'm getting a strange error message from calling this function
It spits out Unknown column 'Resource' in 'field List'
This is my query:
SELECT dept.name, count(maintenance.deptid)/$total AS percentage FROM
maintenance
JOIN dept WHERE maintenance.deptid=dept.deptid GROUP BY dept.name
-Original Message-
From: Gurhan Ozen [mailto:[EMAIL PROTECTED]]
Sent: 06 January 2002 20:10
I am pretty sure that the query is correct. here is the actual query:
$query=select distinct(nodeid), nodename
from books where
bookid=$bookid;
:07
To: 'Gurhan Ozen'; [EMAIL PROTECTED]
Subject: RE: [PHP-DB] mysql_num_rows
-Original Message-
From: Gurhan Ozen [mailto:[EMAIL PROTECTED]]
Sent: 06 January 2002 20:10
I am pretty sure that the query is correct. here is the actual query:
$query=select distinct(nodeid
-Original Message-
From: Gurhan Ozen [mailto:[EMAIL PROTECTED]]
Sent: 06 January 2002 20:10
I am pretty sure that the query is correct. here is the
actual query:
$query=select distinct(nodeid), nodename
from books where
bookid=$bookid;
-Original Message-
From: matt stewart [mailto:[EMAIL PROTECTED]]
Sent: 08 January 2002 14:10
don't know if this makes a difference, but i've always used
WHERE bookid =
'$bookid'; - single quote round the $bookid variable - not
sure if that's
the problem, or if it's just good
:07 AM
Subject: RE: [PHP-DB] mysql_num_rows
-Original Message-
From: Gurhan Ozen [mailto:[EMAIL PROTECTED]]
Sent: 06 January 2002 20:10
I am pretty sure that the query is correct. here is the actual query:
$query=select distinct(nodeid), nodename
from books where
bookid
Drop the $result from the mysql_num_rows() so it reads:
$num_results=mysql_num_rows();
Depending upon the PHP version, that might do the trick for you.
kind regards,
bill
Mike Ford wrote:
-Original Message-
From: Gurhan Ozen [mailto:[EMAIL PROTECTED]]
Sent: 06 January 2002
It would help if we could see the actual query. It sounds like the problem
is a syntax error in the query itself.
At 11:52 AM 1/6/2002, Gurhan Ozen wrote:
Hi everyone,
I have a problem with mysql connectivety which is making me nuts. If the
query is select blah, blah from table (i.e.
, 2002 3:01 PM
To: Gurhan Ozen; [EMAIL PROTECTED]
Subject: Re: [PHP-DB] mysql_num_rows
It would help if we could see the actual query. It sounds like the problem
is a syntax error in the query itself.
At 11:52 AM 1/6/2002, Gurhan Ozen wrote:
Hi everyone,
I have a problem with mysql
Hm, if the result you want is the number of distinct nodeid values, why not
use a query like this:
select count(distinct(nodeid)) as nodecount from books where bookid =
$bookid;
Then the number of nodeid's is stored in nodecount.
You might also want to look into the GROUP BY clause. That
Message-
From: Richard S. Crawford [mailto:[EMAIL PROTECTED]]
Sent: Sunday, January 06, 2002 3:34 PM
To: Gurhan Ozen; [EMAIL PROTECTED]
Subject: RE: [PHP-DB] mysql_num_rows
Hm, if the result you want is the number of distinct nodeid values, why not
use a query like this:
select count(distinct
Message -
From: Gurhan Ozen [EMAIL PROTECTED]
To: Richard S. Crawford [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Sent: 06 January 2002 20:42
Subject: RE: [PHP-DB] mysql_num_rows
hmm that's an idea... I stil don't get why mysql_num_rows wouldn't work with
WHERE clause but i will try to do a workaround
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