On Wed, 2007-05-23 at 16:24 -0700, Adz07 wrote:
i want to set up a php server that can communicate with a client (CLI PHP
Script). I can setup the server socket fine. What i need to know is whether
it is possible for the client to call a function in the servers php code and
the server return
Can anyone help with this. On a Linux/Apache server.
I want to simply copy a file with ftp_put() from one dir to another.
To make certain I'm pointing to the correct dirs, I'm using this:
print_r(ftp_nlist($conn_id, FTP_EP_DIR)); //It is the correct dir
print_r(ftp_nlist($conn_id, $rpdir));
I get a syntax error on strlen.
$newTypes = array();
$newTypes[0] = array();
$newTypes[0][0] = Starting with
$newTypes[0][1] = strlen( $newTypes[0][0] );
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Looks like you are missing a comma on line 3.
James Lockie wrote:
I get a syntax error on strlen.
$newTypes = array();
$newTypes[0] = array();
$newTypes[0][0] = Starting with
$newTypes[0][1] = strlen( $newTypes[0][0] );
--
Wishlists: http://snipurl.com/1gqpj
Switch:
Looks like you are missing a comma on line 3.
James Lockie wrote:
I get a syntax error on strlen.
$newTypes = array();
$newTypes[0] = array();
$newTypes[0][0] = Starting with
$newTypes[0][1] = strlen( $newTypes[0][0] );
Missing semicolon;
Paul
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PHP General Mailing List
Rahul Sitaram Johari wrote:
Didn't help. Tried X:\\Transfer\\test.dbf
Still can't access the file.
On 5/23/07 3:11 PM, Tijnema [EMAIL PROTECTED] wrote:
The \ is an escape token, and you should use \\ instead.
Try X:\\Transfer\\test.dbf instead.
Tijnema
ps. Please don't top post.
Try a
Paul Novitski wrote:
Looks like you are missing a comma on line 3.
James Lockie wrote:
I get a syntax error on strlen.
$newTypes = array();
$newTypes[0] = array();
$newTypes[0][0] = Starting with
$newTypes[0][1] = strlen( $newTypes[0][0] );
Missing semicolon;
Paul
Argh,
Rahul Sitaram Johari wrote:
Ave,
Apache 2.2, PHP5 mySQL 5 on Windows 2003.
I have some files sitting on a Network Drive accessible on the Windows 2003
Server. But my php script is not able to open the files.
Let¹s say there¹s a database on X:\Transfer\test.dbf
If I use:
$db =
On 5/23/07, James Lockie [EMAIL PROTECTED] wrote:
Argh, that is the worst error. :-(
The error messages in PHP suck.
When I run your code it says:
Parse error: syntax error, unexpected T_VARIABLE in
/opt/local/apache2/htdocs/missing.php on line 5
If you did not get a similar error you may
I have a problem please help me
when i loged in to egroup this show
Database error: Invalid SQL: SELECT DISTINCT
egw_cal_repeats.*,egw_cal.*,cal_start,cal_end,cal_recur_date FROM egw_cal
JOIN egw_cal_dates ON egw_cal.cal_id=egw_cal_dates.cal_id JOIN egw_cal_user
ON
Might I suggest using an IDE to develop your code in. It would be able
to spot simple oversights such as syntax errors. I personally use Zend
Studio, however if you aren't looking to invest in a license, there are
plenty of open source solutions out there.
Cheers,
- sf
James Lockie wrote:
Paul
wisuttorn wrote:
I have a problem please help me
when i loged in to egroup this show
Database error: Invalid SQL: SELECT DISTINCT
egw_cal_repeats.*,egw_cal.*,cal_start,cal_end,cal_recur_date FROM egw_cal
JOIN egw_cal_dates ON egw_cal.cal_id=egw_cal_dates.cal_id JOIN egw_cal_user
ON
Dear all.
I have a script that is called by an AJAX popup. Now I use an image
file to get the path of an image for an img tag
eg:
img border=0 id=middleImage name=middleImage src=? echo
$getImageURL; ?
the $getImageURL is composed as follows:
$getImageURL =
SOLVED. seems that something else was causing the script not to work.
Thanks anyway
Angelo Zanetti wrote:
Dear all.
I have a script that is called by an AJAX popup. Now I use an image
file to get the path of an image for an img tag
eg:
img border=0 id=middleImage name=middleImage
On 22/05/07, Robert Cummings [EMAIL PROTECTED] wrote:
On Tue, 2007-05-22 at 13:47 -0500, Greg Donald wrote:
On 5/22/07, Robert Cummings [EMAIL PROTECTED] wrote:
Nothing said it was important, but why implement a half-assed solution
when you can implement a superior solution in as much time?
itoctopus wrote:
I think what you need is simply something like this:
function get_day($int_day){
$arr_day_of_week = array('1'='Sunday', '2'='Monday', '3'='Tuesday',
'4'='Wednesday', '5'='Thurdsay', '6'='Friday', '7'='Saturday');
}
echo(get_day(1)); //will print Sunday
Hmm, not so
Hi,
I have a PHP script that reads and updates either a small file or a
mysql database. This script is called from several places every .5 seconds.
I would like to move this file to a variable for extra speed as the file
is causing a few problems being accessed so many times.
Is it possible
Darren Whitlen wrote:
I have a PHP script that reads and updates either a small file or a
mysql database. This script is called from several places every .5 seconds.
I would like to move this file to a variable for extra speed as the file
is causing a few problems being accessed so many
Stut wrote:
Darren Whitlen wrote:
I have a PHP script that reads and updates either a small file or a
mysql database. This script is called from several places every .5
seconds.
I would like to move this file to a variable for extra speed as the
file is causing a few problems being
How about a table using the mysql memory engine ?
Darren Whitlen wrote:
Hi,
I have a PHP script that reads and updates either a small file or a
mysql database. This script is called from several places every .5
seconds.
I would like to move this file to a variable for extra speed as the
Darren Whitlen wrote:
Stut wrote:
Darren Whitlen wrote:
I have a PHP script that reads and updates either a small file or a
mysql database. This script is called from several places every .5
seconds.
I would like to move this file to a variable for extra speed as the
file is causing a few
John Comerford wrote:
How about a table using the mysql memory engine ?
Darren Whitlen wrote:
Hi,
I have a PHP script that reads and updates either a small file or a
mysql database. This script is called from several places every .5
seconds.
I would like to move this file to a variable for
On Wednesday 23 May 2007 11:52:27 Darren Whitlen wrote:
Hi,
I have a PHP script that reads and updates either a small file or a
mysql database. This script is called from several places every .5 seconds.
I would like to move this file to a variable for extra speed as the file
is causing a
We are planning to eventually develop a web service and communicate in this
fashion but i want to get something up quiclly that is operational while we
spec the project in full.
Thanks
Shannon
itoctopus [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
In case you have no control on
THanks,
I will have far to much data to append to a GET request so a POST is the
best option I think.
Myron Turner [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
On Sat, May 19, 2007 10:22 pm, Shannon Whitty wrote:
I'm looking for a piece of software or coding that will let me
THanks,
I will have far to much data to append to a GET request so a POST is the
best option I think.
Myron Turner [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
On Sat, May 19, 2007 10:22 pm, Shannon Whitty wrote:
I'm looking for a piece of software or coding that will let me
Darren Whitlen wrote:
Hi,
I have a PHP script that reads and updates either a small file or a
mysql database. This script is called from several places every .5 seconds.
I would like to move this file to a variable for extra speed as the file
is causing a few problems being accessed so many
THanks,
I will have far to much data to append to a GET request so a POST is the
best option I think.
Myron Turner [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
On Sat, May 19, 2007 10:22 pm, Shannon Whitty wrote:
I'm looking for a piece of software or coding that will let me
THanks,
That's what I thought...
I really only need to check for one value = success - anything else should
redirect back to the form entry page and display whatever result has been
returned from the remote site.
cUrl should be able to differentiate between a connection and an application
Hi,
I have this script testing.php that I run on a Linux machine thru the
command line. In the end of the file you see two cases. One where it
is just having a while(true) loop doing nothing, and the other calling
an other script that is doing nothing but doesn't exit. When I send
Hi all a i am running a windows 2003 server with IIS. I have created a php
script that uploads a file to a server.
in the server i have users and a user1 has permission to folder1, user2 has
permissions to folder2. I want an administrator to run the script and upload a
file to these foldes.
Darren Whitlen wrote:
Hi,
I have a PHP script that reads and updates either a small file or a
mysql database. This script is called from several places every .5 seconds.
assuming your using a real OS
whilst your figuring out an even better way to do it you might consider sticking
the
As far as I remember, IIS used to have a reserved user that it ran all its
actions under.
All you have to do is to give this user the necessary permissions (I
remember the username started with I).
Here's a link that might help : http://support.microsoft.com/kb/812614
--
itoctopus -
Hi all,
I am writing a script and need to eject the cd-rom drive at some point.
Does anyone have an idea how to do this?
This is a simple command isn't it?
I greatly appreciate your help
Blessings,
Chetanji
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PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit:
Hi all,
I am writing a script and need to eject the cd-rom drive at
some point.
Does anyone have an idea how to do this?
This is a simple command isn't it?
I greatly appreciate your help
Blessings,
Chetanji
Found this little snippet on the php.net site. (
Hi all,
I am writing a script and need to eject the cd-rom drive at
some point.
Does anyone have an idea how to do this?
This is a simple command isn't it?
I greatly appreciate your help
Blessings,
Chetanji
Found this little snippet on the php.net site. (
If you are on linux just shell out the linux eject command (which should
eject the drive for you).
If you are on windows (or another OS), then I'm sure you can still find a
similar commnad line app that will do the same task.
There isn't a built in way in PHP.
Andrew
- Original Message
exec(eject);
on linux/unix
greets
Zoltán Németh
2007. 05. 23, szerda keltezéssel 14.23-kor Chetan Graham ezt írta:
Hi all,
I am writing a script and need to eject the cd-rom drive at some point.
Does anyone have an idea how to do this?
This is a simple command isn't it?
I greatly
-Original Message-
From: Chetan Graham [mailto:[EMAIL PROTECTED]
Sent: 23 May 2007 12:23
To: php-general@lists.php.net
Subject: [PHP] How to eject cd-rom with php code?
Hi all,
I am writing a script and need to eject the cd-rom drive at some point.
Does anyone have an idea
I am writing a script and need to eject the cd-rom drive at some point.
Does anyone have an idea how to do this?
This is a simple command isn't it?
I greatly appreciate your help
?php
system( 'eject [-dfnpq] [device | nickname]' );
?
http://us.php.net/manual/en/function.system.php
On Wed, 2007-05-23 at 10:31 +0300, Robin Vickery wrote:
On 22/05/07, Robert Cummings [EMAIL PROTECTED] wrote:
On Tue, 2007-05-22 at 13:47 -0500, Greg Donald wrote:
On 5/22/07, Robert Cummings [EMAIL PROTECTED] wrote:
Nothing said it was important, but why implement a half-assed solution
I was trying to put embedded image on HTML Mail using PHP Mailer, my problem is
my image does not located on filesystem but located within MySQL Server.
How I can put image from database into HTML Mail.
Thanks in advance, bgs
On 5/23/07, Robin Vickery [EMAIL PROTECTED] wrote:
they're all bloated:
print jddayofweek($day_number, 1);
Must go --enable-calendar now :)
--
Greg Donald
http://destiney.com/
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PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Okay, I think I'm doing everything right, but for whatever reason my include
isn't working.
?php
echo $_POST['status_code'];
if ($_POST['status_code'] = C) {
include ('complete_save.php');
}
?
The echo of my status_code retruns the correct value so the if should
trigger.
This is my include
Dan Shirah wrote:
Okay, I think I'm doing everything right, but for whatever reason my
include
isn't working.
?php
echo $_POST['status_code'];
if ($_POST['status_code'] = C) {
include ('complete_save.php');
}
?
The echo of my status_code retruns the correct value so the if should
trigger.
On Wed, 2007-05-23 at 09:23 -0500, Greg Donald wrote:
On 5/23/07, Robin Vickery [EMAIL PROTECTED] wrote:
they're all bloated:
print jddayofweek($day_number, 1);
Must go --enable-calendar now :)
Awww, I didn't notice it's a compile flag... hmmm, not so portable that
way. Something tells
On 5/23/07, Greg Donald [EMAIL PROTECTED] wrote:
On 5/23/07, Dan Shirah [EMAIL PROTECTED] wrote:
Okay, I think I'm doing everything right, but for whatever reason my
include
isn't working.
?php
echo $_POST['status_code'];
if ($_POST['status_code'] = C) {
== not =
--
Greg Donald
On Wed, 2007-05-23 at 07:41 -0500, kvigor wrote:
if($field == conState || $field == schState || $field == strState)
//if these 3 fields are entered
{
if($value != 'Alabama' || $value!= 'AL' || $value != 'Alaska' || $value!=
'AK' || $value != 'Arizona' || $value!= 'AZ' || $value
Has anyone looked at the Zend Framework lately?
http://framework.zend.com/manual
I've been playing with a few parts of it off and on the past couple of
days. It seems really heavy overall and there is no Javascript
integration anywhere. Nothing on the roadmap about Javascript either:
2007. 05. 23, szerda keltezéssel 07.41-kor kvigor ezt írta:
Hi,
I have an issue with a particular if statement when I check 3 form fields
for their value. The problem is no matter what input is entered in the
fields the output is the same. I only added the 3 fields in question of the
On 5/23/07, kvigor [EMAIL PROTECTED] wrote:
The code is:
?php
$label_array = array (conName = Consumer Name,
conAddress = Consumer Address,
conCity = Consumer City,
conState = Consumer State,
conZip = Consumer Zip Code,
conPhone = Consumer Phone,
schName = School
Thanks Dan,
Work like a dream. I solute you.
Daniel Brown [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
On 5/23/07, kvigor [EMAIL PROTECTED] wrote:
Hi,
I have an issue with a particular if statement when I check 3 form fields
for their value. The problem is no matter what
On Wed, 2007-05-23 at 10:17 -0500, kvigor wrote:
Thanks Dan,
Work like a dream. I solute you.
Don't look now Dan... but you're dissolving!!! *hehe*
Cheers,
Rob.
--
..
| InterJinn Application Framework - http://www.interjinn.com |
Dan Shirah wrote:
Okay, I think I'm doing everything right, but for whatever reason my
include
isn't working.
?php
echo $_POST['status_code'];
if ($_POST['status_code'] = C) {
include ('complete_save.php');
}
?
The echo of my status_code retruns the correct value so the if should
trigger.
On Wed, 2007-05-23 at 10:10 -0500, Greg Donald wrote:
On 5/23/07, kvigor [EMAIL PROTECTED] wrote:
[-- SNIPPITY SNIP SNIP --]
!= 'Texas' || $value!= 'TX' || $value != 'Utah' || $value!= 'UT' || $value
!= 'Vermont' || $value!= 'VT' || $value != 'Virginia' || $value!= 'VA' ||
$value !=
On 5/23/07, Jim Lucas [EMAIL PROTECTED] wrote:
Dan Shirah wrote:
Okay, I think I'm doing everything right, but for whatever reason my
include
isn't working.
?php
echo $_POST['status_code'];
if ($_POST['status_code'] = C) {
include ('complete_save.php');
}
?
The echo of my
On 5/23/07, Robert Cummings [EMAIL PROTECTED] wrote:
You should really look into learning in_array() for stuff like this.
Wouldn't that slow things down and increase the memory footprint? ;)
It'd be interesting to see a benchmark.
--
Greg Donald
http://destiney.com/
--
PHP General Mailing
kvigor wrote:
if($value != 'Alabama' || $value!= 'AL' || $value != 'Alaska' || $value!=
'AK' || $value != 'Arizona' || $value!= 'AZ' || $value != 'Arkansas' ||
$value!= 'AR' || $value != 'California' || $value!= 'CA' || $value !=
'Colorado' || $value!= 'CO' || $value != 'Conneticut' ||
On Wed, 2007-05-23 at 10:55 -0500, Greg Donald wrote:
On 5/23/07, Robert Cummings [EMAIL PROTECTED] wrote:
You should really look into learning in_array() for stuff like this.
Wouldn't that slow things down and increase the memory footprint? ;)
It'd be interesting to see a benchmark.
Having a giant conditional statement such as the one you have posted is a
real problem for many different reasons. Below is a simple states class that
allows you to test for a state using a couple of different checks (such as
making both comparables lower or upper case). One major issue with the
On 5/23/07, Jim Lucas [EMAIL PROTECTED] wrote:
$states['TN'] = 'Tennesee';
:%s/Tennesee/Tennessee/
--
Greg Donald
http://destiney.com/
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
On 5/23/07, Jim Lucas [EMAIL PROTECTED] wrote:
Ok, here is something that might help you.
$states['AL'] = 'Alabama';
$states['AK'] = 'Alaska';
And a little something for you as well:
:%s/=/=/g
--
Greg Donald
http://destiney.com/
--
PHP General Mailing List (http://www.php.net/)
To
On Wed, 2007-05-23 at 11:16 -0500, Jared Farrish wrote:
Abraham Maslow: If the only tool you have is a hammer, you tend to see
every problem as a nail. $$
Robert Cummings:
if every problem can be described as a nail, then all you
need is a hammer.
Cheers,
Rob.
--
Also, Indiana and Connecticut were misspelled.
--
Jared Farrish
Intermediate Web Developer
Denton, Tx
Abraham Maslow: If the only tool you have is a hammer, you tend to see
every problem as a nail. $$
Greg Donald wrote:
On 5/23/07, Jim Lucas [EMAIL PROTECTED] wrote:
Ok, here is something that might help you.
$states['AL'] = 'Alabama';
$states['AK'] = 'Alaska';
And a little something for you as well:
:%s/=/=/g
oops, did over look that one
--
Jim Lucas
Some men are born to
Greg Donald wrote:
On 5/23/07, Jim Lucas [EMAIL PROTECTED] wrote:
$states['TN'] = 'Tennesee';
:%s/Tennesee/Tennessee/
Not my typo, this was the ops list just reformatted.
--
Jim Lucas
Some men are born to greatness, some achieve greatness,
and some have greatness thrust upon
I have a script to process the post from a form.
The form is used to upload photos and has fields for the filename, alt text,
caption and a checkbox to indicate if this photo is the main page image
rotation.
I wanted to build a general routine to build the form to allow for a varying
Daniel Brown wrote:
On 5/23/07, Jim Lucas [EMAIL PROTECTED] wrote:
Dan Shirah wrote:
Okay, I think I'm doing everything right, but for whatever reason my
include
isn't working.
?php
echo $_POST['status_code'];
if ($_POST['status_code'] = C) {
include ('complete_save.php');
}
?
The
On 5/23/07, Daniel Brown [EMAIL PROTECTED] wrote:
On 5/23/07, Jim Lucas [EMAIL PROTECTED] wrote:
Dan Shirah wrote:
Okay, I think I'm doing everything right, but for whatever reason my
include
isn't working.
?php
echo $_POST['status_code'];
if ($_POST['status_code'] = C) {
On 5/23/07, Stephen [EMAIL PROTECTED] wrote:
I have a script to process the post from a form.
The form is used to upload photos and has fields for the filename, alt text,
caption and a checkbox to indicate if this photo is the main page image
rotation.
I wanted to build a general routine
On 5/23/07, Robert Cummings [EMAIL PROTECTED] wrote:
Robert Cummings:
if every problem can be described as a nail, then all you
need is a hammer.
Don't you ever get the urge to swing a different hammer? I sure do.
As I watch PHP de-evolve into Java, I find myself wanting something
On 5/23/07, Tijnema [EMAIL PROTECTED] wrote:
include is a control structure, I believe it isn't required, but
preferred to use the include without (), like this:
include complete_save.php;
What variable or escape sequence are you interpolating in that double
quoted string?
include
I am a newbie so please bear with me.
I get this error message when I try to run a query
Connected successfullyCould not successfully run query () from DB: Unknown
column '$today' in 'where clause'
this is the query command
$query = 'SELECT *
FROM `job listing`
WHERE open =$today
LIMIT 0 , 30
I am reading in a date field from a mysql database the field on the screen
shows up as 2007-05-01 on the screen I would like the field to show
05-01-2007 currently I am issueing the following command print
$row['open']; how can I format this field???
while I am at it how can I accept the date
Sorry I am a bit of a newbie with php and hope this has not been aswered a
million times, but here it goes
I have a date base with a couple of date fields when I pull up and display
the fields it show 2007-05-21. the question I have is how to convert the
field to 05-21-2007?
Currently the
On 5/21/07, Mike Ryan [EMAIL PROTECTED] wrote:
I am a newbie so please bear with me.
I get this error message when I try to run a query
Connected successfullyCould not successfully run query () from DB: Unknown
column '$today' in 'where clause'
this is the query command
$query = 'SELECT *
On 5/23/07, Mike Ryan [EMAIL PROTECTED] wrote:
I am reading in a date field from a mysql database the field on the screen
shows up as 2007-05-01 on the screen I would like the field to show
05-01-2007 currently I am issueing the following command print
$row['open']; how can I format this
On 5/23/07, Greg Donald [EMAIL PROTECTED] wrote:
On 5/23/07, Tijnema [EMAIL PROTECTED] wrote:
include is a control structure, I believe it isn't required, but
preferred to use the include without (), like this:
include complete_save.php;
What variable or escape sequence are you
I've been experimenting with it for a new site revision at the company I
work at. I have to agree, it's feels heavy, almost bloated. Mind you,
I've only used a small fraction of the framework -- namely the Zend_Db,
Zend_Config and Zend_Controller portions. The lack of Javascript seems
like
On 5/21/07, Mike Ryan [EMAIL PROTECTED] wrote:
Sorry I am a bit of a newbie with php and hope this has not been aswered a
million times, but here it goes
I have a date base with a couple of date fields when I pull up and display
the fields it show 2007-05-21. the question I have is how to
Em Segunda 21 Maio 2007 16:46, Mike Ryan escreveu:
I get this error message when I try to run a query
Connected successfullyCould not successfully run query () from DB: Unknown
column '$today' in 'where clause'
this is the query command
$query = 'SELECT *
FROM `job listing`
WHERE open
On Wed, 2007-05-23 at 11:51 -0500, Greg Donald wrote:
On 5/23/07, Robert Cummings [EMAIL PROTECTED] wrote:
Robert Cummings:
if every problem can be described as a nail, then all you
need is a hammer.
Don't you ever get the urge to swing a different hammer?
I sure do.
I
On 5/23/07, Tijnema [EMAIL PROTECTED] wrote:
Again, this is Off topic,
/me rolls eyes
Do you even know what P-H-P stands for? HTML questions are not off
topic, especially form related ones.
--
Greg Donald
http://destiney.com/
--
PHP General Mailing List (http://www.php.net/)
To
Leave the date as is, its a MySQL thing. To format it on your page,
use the date function:
$formattedDate = date(m-d-Y,strtotime($row[open]));
http://us2.php.net/manual/en/function.date.php
--
Kevin Murphy
Webmaster: Information and Marketing Services
Western Nevada Community College
On 5/21/07, Mike Ryan [EMAIL PROTECTED] wrote:
I am a newbie so please bear with me.
I get this error message when I try to run a query
Connected successfullyCould not successfully run query () from DB: Unknown
column '$today' in 'where clause'
this is the query command
$query = 'SELECT *
On 5/23/07, Greg Donald [EMAIL PROTECTED] wrote:
On 5/21/07, Mike Ryan [EMAIL PROTECTED] wrote:
I am a newbie so please bear with me.
I get this error message when I try to run a query
Connected successfullyCould not successfully run query () from DB:
Unknown
column '$today' in 'where
Change the single quote to a double quote:
code
$query = SELECT * FROM `job listing` WHERE open = '$today' LIMIT 0 , 30
;
/code
This tells the PHP string parser to replace all declared, in-scope variables
that are detected in a string with the value of the variable (as a
toString() method, so a
Thank you for all of the quick responses. I guess jumping between
ColdFusion, PHP and Informix all day long got the better of me.
Thanks again!
Dan
On 5/23/07, Daniel Brown [EMAIL PROTECTED] wrote:
On 5/23/07, Greg Donald [EMAIL PROTECTED] wrote:
On 5/23/07, Tijnema [EMAIL PROTECTED]
Mike Ryan wrote:
Sorry I am a bit of a newbie with php and hope this has not been aswered a
million times, but here it goes
I have a date base with a couple of date fields when I pull up and display
the fields it show 2007-05-21. the question I have is how to convert the
field to 05-21-2007?
Chetan Graham wrote:
Hi all,
I am writing a script and need to eject the cd-rom drive at some point.
Does anyone have an idea how to do this?
This is a simple command isn't it?
I greatly appreciate your help
Seeing as everyone is telling you to use exec('eject') to eject your
disk I'll
Ave,
Apache 2.2, PHP5 mySQL 5 on Windows 2003.
I have some files sitting on a Network Drive accessible on the Windows 2003
Server. But my php script is not able to open the files.
Let¹s say there¹s a database on X:\Transfer\test.dbf
If I use:
$db = dbase_open(³X:\Transfer\test.dbf², 0);
It
[snip]
Let¹s say there¹s a database on X:\Transfer\test.dbf
If I use:
$db = dbase_open(³X:\Transfer\test.dbf², 0);
It is not able to open the database. The X: Drive is a network drive.
Any clues on how to make this happen?
[/snip]
Have you checked the permissions?
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PHP General Mailing List
Well, Full Permissions (Full Control, including read write) have been
given to the Machine on which the Apache Web Server is setup. Not sure if
anything else needs to be done!
On 5/23/07 3:02 PM, Jay Blanchard [EMAIL PROTECTED] wrote:
[snip]
Let¹s say there¹s a database on
On 5/23/07, Rahul Sitaram Johari [EMAIL PROTECTED] wrote:
Well, Full Permissions (Full Control, including read write) have been
given to the Machine on which the Apache Web Server is setup. Not sure if
anything else needs to be done!
The \ is an escape token, and you should use \\ instead.
Other than permissions, you might be referencing the folder by the local
network mapping drive initial, instead of the actual path:
X:\\offsite\db\test.dbf == \\compname-x\offsite\db\test.dbf
Generally, I like using the computer name and not a mapping. I find this
name-based address through the
Oh yeah, and tijnema has a good point:
\\compname-x\\offsite\\db\\test.dbf
Btw, what does top post mean?
On 5/23/07, Jared Farrish [EMAIL PROTECTED] wrote:
Other than permissions, you might be referencing the folder by the local
network mapping drive initial, instead of the actual path:
Didn't help. Tried X:\\Transfer\\test.dbf
Still can't access the file.
On 5/23/07 3:11 PM, Tijnema [EMAIL PROTECTED] wrote:
The \ is an escape token, and you should use \\ instead.
Try X:\\Transfer\\test.dbf instead.
Tijnema
ps. Please don't top post.
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PHP General Mailing List
Tried that too. Used
\\Servername\sharename\test.dbf
Also used additional backslashes for the escape issue:
Servername\\sharename\\test.dbf
Still doesn't work!
I'm not getting a permissions related issue and I'm doubting it is a
permissions issue. I have Full Control given to the system
Try to simply include() and var_dump() or something. Start from just
checking you can access the file first (I'd even start with a
test.txtfile), before you inflate the db...
Let us know what the error is exactly, as well. What happens? Error?
Warning? Blank page? What tells you the script
On Thursday 24 May 2007 00:51, Greg Donald wrote:
As I watch PHP de-evolve into Java, I find myself wanting something
lighter weight and with a smaller syntax.
PHP has long since spawned into something uncontrollable. Compare the
number of functions (and its aliases) to eg Ruby. The string
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