.
Thanks to Kurt and Justin for the help offered on this simple (now that it
is working) problem.
I do not know where my stumbling block was but after a good nights rest and
some coffee this morning I have this and the GetImageSize function
incorporated.. I will list the code incase someone
.
Thank you for the heads up on using like. I was wondering since there will
be 2 similar variables from each page var1 var2 (identical except for the
number). I programmed in DataFlex for about 6 years back in the late 80's
early 90's but have not done anything db wise in over 8 years I
] wrote in message
E15yy3N-0005qE-00@z8">news:E15yy3N-0005qE-00@z8...
On Wednesday 31 October 2001 07:45 am, turtle wrote:
img src=? echo $imglocation ? ? echo $size[3]; ?
Glad we could help. Also, you can re-write the above so you don't have to
define two sets of ?php ? tags
I am trying to pass a variable to a popup window, to do a search in a
database, and display an image based on the results... Here is what I have
messed up so far (this is the 1st time I have used php/mysql no
userID/Pswd on local host)
The script that passes the variable (variable does
for someone who has only used PHP for 2
weeks.
Mike
Kurt Lieber [EMAIL PROTECTED] wrote in message
E15ydj6-0003KZ-00@z8">news:E15ydj6-0003KZ-00@z8...
On Tuesday 30 October 2001 10:13 am, turtle wrote:
?
$link = mysql_connect('localhost')or die (Could not connect);
mysql_select_db
r-0003fP-00@z8...
On Tuesday 30 October 2001 11:58 am, turtle wrote:
No reading that section of the manual did me no good. I do not
understand
other than I cannot store the results as a variable.
yes, you can.
Is there any of what I have done that is usable?
yes, there is. see belo
Kurt Lieber
You would use a while loop if/when you have multiple records to retrive.
From your original code example, it seemed as though you would only have
one
record. (though, for safety's sake, you should code a LIMIT into your sql
statement)
Yes I only need one image location with
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