I know that in a case like this
if((test1) (test2) (test3)) {
...
}
if test1 fails, dear PHP won't bother doing test2 and 3. Am I correct? Is there a
syntax that will make it carry on with test2 and 3 anyway, regardless of how test1
came out?
At 22:13 13.03.2003, Liam Gibbs said:
[snip]
I know that in a case like this
if((test1) (test2) (test3)) {
...
}
if test1 fails, dear PHP won't bother doing test2 and 3. Am I correct? Is
there a syntax that will make it carry on with test2 and 3
That's exactly what logical operators are for.
http://www.php.net/manual/en/language.operators.logical.php
use || instead of for allowing either to be true.
if ((test1) || (test2) || (test3))
{
\\ if any of these can return true, this will execute
}
HTH,
Jason k Larson
Liam Gibbs wrote:
I know
Liam Gibbs wrote:
I know that in a case like this
if((test1) (test2) (test3)) {
...
}
if test1 fails, dear PHP won't bother doing test2 and 3. Am I correct? Is there a syntax that will make it carry on with test2 and 3 anyway, regardless of how test1 came out?
The more efficient
The more efficient compilers/parsers stop when one test fails, some do
them all. I don't know which php does but surely it is irrelevant? If
test1 fails, because of the and the if statement will not be
executed. I wonder what the reason is for your wanting it to do test2
and test3, maybe I'm
Hi,
Friday, March 14, 2003, 7:13:15 AM, you wrote:
LG I know that in a case like this
LG if((test1) (test2) (test3)) {
LG ...
LG }
LG if test1 fails, dear PHP won't bother doing test2 and 3. Am I correct? Is there a
syntax that will make it carry on with test2 and 3 anyway, regardless of
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