Hi all,
I wrote a php script that creates options for select boxes. What this
script does is selects tomorrows date. However I have tested the code
when the day is the last day of the month and the script blows up.
Instead of displaying June it displays January and repeats the months
12 times I
Paul Goepfert wrote:
... What this script does is selects tomorrows date...
Here is a one-line way to find the month and day of tomorrow:
?php
list($tomorrow_month, $tomorrow_day) = split(':', date('m:d',
time()+86400));
?
Test that ... I just wrote it off the top of my head. Maybe that
Ok, thx, I've got it done. Dumb mistake, the user didn't have rights to
delete, it's as simple as that. My trials thru the command line where as
root
thx guys
janbro
Richard Lynch schrieb:
What you are doing wrong is ignoring the error messages MySQL is storing
for you...
On Mon, May
On 5/30/05, janbro [EMAIL PROTECTED] wrote:
Hi List, I don't know where else to look. I've got PHP 5.0.0 and MySQL
4.1.3. (on Windwows XP with Apache 2.0.50)
Here is my Code: the Query with the delete is not executed and I don't
know why. If I copy it into the MySQL Command line like it is
Hi List, I don't know where else to look. I've got PHP 5.0.0 and MySQL
4.1.3. (on Windwows XP with Apache 2.0.50)
Here is my Code: the Query with the delete is not executed and I don't
know why. If I copy it into the MySQL Command line like it is here,
everything works fine. I have another
janbro wrote:
Hi List, I don't know where else to look. I've got PHP 5.0.0 and MySQL
4.1.3. (on Windwows XP with Apache 2.0.50)
Here is my Code: the Query with the delete is not executed and I don't
know why. If I copy it into the MySQL Command line like it is here,
everything works fine. I
What you are doing wrong is ignoring the error messages MySQL is storing
for you...
On Mon, May 30, 2005 12:37 pm, janbro said:
Hi List, I don't know where else to look. I've got PHP 5.0.0 and MySQL
4.1.3. (on Windwows XP with Apache 2.0.50)
Here is my Code: the Query with the delete is not
Hi,
Can anyone see why this code isn't working
$SID = $_SESSION['svUserID'];
$AdID = $_GET['AdID'];
// get the campuses assigned
$qCampusID = SELECT inst_id FROM ads_campuses WHERE ad_id = $AdID;
$CampusIDList = mysql_query($qCampusID, $CCB) or die(mysql_error());
$row_CampusIDList =
Hmm, ok I took out the
$row_CampusIDList = mysql_fetch_assoc($CampusIDList);
and it works But how come?
J
-Original Message-
From: James Johnson [mailto:[EMAIL PROTECTED]
Sent: Wednesday, September 17, 2003 9:17 AM
To: [EMAIL PROTECTED]
Subject: [PHP] Code check please
From: James Johnson [EMAIL PROTECTED]
Can anyone see why this code isn't working
$SID = $_SESSION['svUserID'];
$AdID = $_GET['AdID'];
// get the campuses assigned
$qCampusID = SELECT inst_id FROM ads_campuses WHERE ad_id = $AdID;
You say down below that this query only selects one
Sorry to bother you all with this, but I have no way to test this, as I have
no access to a Mac. Could you tell me if this little piece of code looks as
if it would work (detect whether someone's using the Mac OS)?
if (preg_match(/mac/i, $HTTP_USER_AGENT) || preg_match(/macintosh/i,
on 8/23/01 11:51 AM, Tom Malone at [EMAIL PROTECTED] wrote:
Sorry to bother you all with this, but I have no way to test this, as I have
no access to a Mac. Could you tell me if this little piece of code looks as
if it would work (detect whether someone's using the Mac OS)?
ie 5.0 macos 9,
You want mysql_error(), call it somewhere after your query.
echo mysql_error();
Regarding the query, the following should work just fine :
$sql = INSERT INTO tablefoo (a,b,c) VALUES ('$a','$b','$c');
Be sure to add slashes sometime to your values beforehand. Anyway,
mysql_error() is what
and execute
the preceding text as a query and after executing that query, continue on
from the next character.
hope you got it working,
Warren Vail
-Original Message-
From: Andreas Skarin [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, June 20, 2001 9:00 AM
To: PHP General
Subject: [PHP] Code check
, 2001 3:46 PM
To: PHP General
Subject: Re: [PHP] Code check please
I'm sorry guys, neither of the snippets work. I must have screwed something
else up
too. Is there any way I can provoke an error message from your code examples
below?
If anyone manages to find out what's wrong, please tell me. I'm
Andreas Skarin wrote:
I've tried to get this working for over an hour
now, and it still won't. I don't even get an error
message to help me find the problem so I was
hoping that someone could check my code for me.
I'm fooling around with a basic form that is
supposed to send one's
I've tried to get this working for over an hour
now, and it still won't. I don't even get an error
message to help me find the problem so I was
hoping that someone could check my code for me.
I'm fooling around with a basic form that is
supposed to send one's name, surname and e-mail
address to
Your code is [mostly] fine, except for two things:
1. Although you connected to your database with mysql_connect() and
mysql_select_db(), you didn't do anything with connection.
Try using mysql_query() to send a query to the db, i.e.
mysql_query($sql).
2. Your SQL is a bit out of
General
Subject: [PHP] Code check please
I've tried to get this working for over an hour
now, and it still won't. I don't even get an error
message to help me find the problem so I was
hoping that someone could check my code for me.
I'm fooling around with a basic form that is
supposed to send
At 18:00 Uhr +0200 20.06.2001, Andreas Skarin wrote:
I've tried to get this working for over an hour
now, and it still won't. I don't even get an error
message to help me find the problem so I was
hoping that someone could check my code for me.
[snip]
$sql = INSERT INTO tabell SET .
ROTECTED]]
Sent: Wednesday, June 20, 2001 12:00 PM
To: PHP General
Subject: [PHP] Code check please
I've tried to get this working for over an hour
now, and it still won't. I don't even get an error
message to help me find the problem so I was
hoping that someone could check my code for m
I'm sorry guys, neither of the snippets work. I must have screwed something else up
too. Is there any way I can provoke an error message from your code examples below?
If anyone manages to find out what's wrong, please tell me. I'm not giving up until
I smash this bug :-)
// Andreas
Rich
2. Your SQL is a bit out of whack. The SET clause is used for
UPDATEs, not INSERTs.
Instead, try:
$sql = INSERT INTO tabell (fornamn, efternamn, email) VALUES ( .
'$fornamn', '$efternamn', '$email');;
MySQL actually lets you use SET for INSERTS, though.
Jason
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