On 15 February 2011 20:28, Ethan Rosenberg eth...@earthlink.net wrote:
Dear List -
I have a form. In one field, the customer types the name of a product.
The first seven(7) results of the MySQL query that the entry generates
should be displayed as a clickable drop down list.
How do I do
Ah, I see. In Brad's reply there was two $result = mssql_query($sql) or
die(mssql_error()); in the code. Removed the one from outside of the loop
and it works fine now.
Thanks to both of you for your help!
On 1/18/07, Chris [EMAIL PROTECTED] wrote:
Dan Shirah wrote:
The code above
Dan Shirah wrote:
Hello all,
I am trying to pull data and then loop through the multiple results
display
in seperate rows.
My database contains several tables which are all tied together by the
credit_card_id. After running the query, it ties the unique record
together
by matching the
The code above displays no information at all.
What I want to do is:
1. Retrieve my information
2. Assign it to a variable
3. Output the data into a table with each unique record in a seperate row
On 1/18/07, Brad Bonkoski [EMAIL PROTECTED] wrote:
Dan Shirah wrote:
Hello all,
I am trying
Dan Shirah wrote:
The code above displays no information at all.
What I want to do is:
1. Retrieve my information
2. Assign it to a variable
3. Output the data into a table with each unique record in a seperate row
As Brad posted:
echo table;
while ($row = mssql_fetch_array($result)) {
]]
Sent: Tuesday, April 16, 2002 9:58 PM
To: [EMAIL PROTECTED]
Subject: Re: [PHP] Displaying Results
On Wednesday 17 April 2002 08:21, Jason Soza wrote:
Sorry, I just noticed that the count() function will do at least the
first part of my question, i.e. SELECT year, COUNT(*) FROM cars GROUP
Sorry, I just noticed that the count() function will do at least the
first part of my question, i.e. SELECT year, COUNT(*) FROM cars GROUP
BY year
But the second part still has me a bit stumped. I know that you can
pass a variable using something like script.php?year=1991, but doesn't
that
You're part way there:
SELECT COUNT(matches) FROM table GROUP BY matches;
- Original Message -
From: Jason Soza [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Tuesday, April 16, 2002 5:49 PM
Subject: [PHP] Displaying Results
Suppose I want a script that goes into a table, looks up all
On Wednesday 17 April 2002 08:21, Jason Soza wrote:
Sorry, I just noticed that the count() function will do at least the
first part of my question, i.e. SELECT year, COUNT(*) FROM cars GROUP
BY year
But the second part still has me a bit stumped. I know that you can
pass a variable using
: Wednesday, April 17, 2002 10:21 AM
To: [EMAIL PROTECTED]
Subject: Re: [PHP] Displaying Results
Sorry, I just noticed that the count() function will do at least the
first part of my question, i.e. SELECT year, COUNT(*) FROM cars GROUP
BY year
But the second part still has me a bit stumped. I
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