Gary wrote:
This is what I have now and it works. I do know that on the second line I
have $_POST['mort']}\n : ; in the second half. I'm not sure I understand
the comment about use the !empty if you dont care about PHP.
if you don't care about PHP Notice...
eror_reporting:
error_reporting( E_ALL | E_STRICT );
if you want to be extremely sure about your app (only in develop)
On Thu, Jun 18, 2009 at 5:04 PM, LAMP l...@afan.net wrote:
Gary wrote:
This is what I have now and it works. I do know that on the second line I
have $_POST['mort']}\n : ; in the second
Martin Scotta wrote:
error_reporting( E_ALL | E_STRICT );
if you want to be extremely sure about your app (only in develop)
Actually, I use error_reporting(E_ALL) while developing
:-)
Afan
On Thu, Jun 18, 2009 at 5:04 PM, LAMP l...@afan.net
mailto:l...@afan.net wrote:
Gary wrote:
the solution has been found. array_key_exists() can actually be used
on objects, and yields the correct result.
http://no.php.net/array_key_exists
thanks to dordea cosmin for pointing this out.
On 17/08/07, Olav Mørkrid [EMAIL PROTECTED] wrote:
the test i need should give the following
Found something.
For class variables..
http://us.php.net/manual/en/function.property-exists.php
class a {
var $b;
}
if (property_exists('a','b')) {
print yes\n;
}
On 8/17/07, Olav Mørkrid [EMAIL PROTECTED] wrote:
the test i need should give the following results:
- FALSE when $a-b
yes, but that assumes you have a defined class. if $a comes from
mysql_fetch_object() for instance you have just a stdobject, and this
method will produce an error.
On 17/08/07, Michael Preslar [EMAIL PROTECTED] wrote:
Found something.
For class variables..
the test i need should give the following results:
- FALSE when $a-b does not exist at all
- TRUE when $a-b = null
- TRUE when $a-b = any value
empty() gives true for both $a-b = null and not setting any value, so
that's no good.
borokovs suggestion seems to miss the purpose.
anyone else?
On
Maybe if you tell us exactly what you wish to achieve.
Class variables that are not created at object creation is bad design.
Olav Mørkrid schreef:
yes, but that assumes you have a defined class. if $a comes from
mysql_fetch_object() for instance you have just a stdobject, and this
method will
On Sat, 2006-02-18 at 04:56, Rafael wrote:
After a little test, although the results are not conclusive, I would
say that isset(), and also that array_key_exists() may even use isset()
(or similiar) internally as a first step -let's remember that isset()
only does a fast search and it
- Original Message -
From: Robert Cummings [EMAIL PROTECTED]
To: Rafael [EMAIL PROTECTED]
Cc: PHP-General php-general@lists.php.net
Sent: Saturday, February 18, 2006 3:21 PM
Subject: Re: [PHP] Re: isset or array_key_exists?
On Sat, 2006-02-18 at 04:56, Rafael wrote:
After a little
Actually, it doesn't have much sense that it creates a variable (or
index), though it had sense why wouldn't be so easily detected, so I
printed the array after the loops and there's no new keys. I think that
if that was the case, it was definitely a bug that has been corrected
(PHP 4.4.0)
On Sat, 2006-02-18 at 12:39, Rafael wrote:
Actually, it doesn't have much sense that it creates a variable (or
index), though it had sense why wouldn't be so easily detected, so I
printed the array after the loops and there's no new keys. I think that
if that was the case, it was
Marek Kilimajer wrote:
M. Sokolewicz wrote:
Also note that empty($non_existent_var) will always throw an E_NOTICE
error when the variable in question is not set.
No, it does not.
hmm... seems to have changed since I last checked (PHP5 change?)
I appoligize :)
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PHP General Mailing List
* Bret Hughes [EMAIL PROTECTED]:
I just wish there was a use strict; sort of deal so I would not have to
hunt down logic errors due to mistyping a variable name.
There is, in PHP5: E_STRICT. From the manual
(http://php.net/manual/en/ref.errorfunc.php#errorfunc.constants):
Run-time notices.
On Wed, 2005-02-16 at 07:54, Matthew Weier O'Phinney wrote:
* Bret Hughes [EMAIL PROTECTED]:
I just wish there was a use strict; sort of deal so I would not have to
hunt down logic errors due to mistyping a variable name.
There is, in PHP5: E_STRICT. From the manual
Bret Hughes wrote:
On Wed, 2005-02-16 at 07:54, Matthew Weier O'Phinney wrote:
* Bret Hughes [EMAIL PROTECTED]:
I just wish there was a use strict; sort of deal so I would not have
to
hunt down logic errors due to mistyping a variable name.
There is, in PHP5: E_STRICT. From the manual
On Wed, 2005-02-16 at 10:34, Richard Lynch wrote:
Bret Hughes wrote:
On Wed, 2005-02-16 at 07:54, Matthew Weier O'Phinney wrote:
* Bret Hughes [EMAIL PROTECTED]:
I just wish there was a use strict; sort of deal so I would not have
to
hunt down logic errors due to mistyping a variable
It's common mistake what you are doing...
the first thing should be to test if there is such key in array:
if (array_key_exists('cmd',$_POST))
{
}
this means to test it the variable exists, then you can test if it was set
Brona
Chris W. Parker wrote:
M. Sokolewicz mailto:[EMAIL PROTECTED]
on
M. Sokolewicz mailto:[EMAIL PROTECTED]
on Tuesday, February 15, 2005 8:25 AM said:
seems lengthy. is there a way around this?
i tried using
$cmd = @ $_POST['cmd'];
to suppress errors but didnt seem to have ay effect.
still
if(isset($_POST['cmd'])) {
$cmd = $_POST['cmd'];
}
Chris W. Parker wrote:
M. Sokolewicz mailto:[EMAIL PROTECTED]
on Tuesday, February 15, 2005 8:25 AM said:
seems lengthy. is there a way around this?
i tried using
$cmd = @ $_POST['cmd'];
to suppress errors but didnt seem to have ay effect.
still
if(isset($_POST['cmd'])) {
$cmd =
M. Sokolewicz wrote:
Also note that empty($non_existent_var) will always throw an E_NOTICE
error when the variable in question is not set.
No, it does not.
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On Tue, 2005-02-15 at 16:22, M. Sokolewicz wrote:
Chris.
that's a different issue.
There are always at least 2 things you should do with your (expected) input:
1 - check if it *exists* (isset)
2 - check the validity (input-validation)
for step #2 empty is very commonly used, and also a
-Original Message-
From: John Manko [mailto:[EMAIL PROTECTED]
Sent: 30 June 2003 15:14
To: [EMAIL PROTECTED]
Subject: [PHP] Re: IsSet() and $_SESSION
None of these worked for me. ok, if you look at the code, the part
where echo $_SESSION['uid']; is actually works.
I get
5:35 PM
To: [EMAIL PROTECTED]
Subject: [PHP] Re: isset
i think what you're trying to do is
?php
if($REQUEST_METHOD == POST)
{
echo Form has been submitted.;
exit;
}
else
{
echo Display the form that has to be submitted.':
exit;
}
?
Preston Wade [EMAIL
ubmitted!;
}
?
form action=?=$PHP_SELF ? method=post
blah, blah
input type=submit name=submit value=Submit
/form
-Original Message-
From: vins [EMAIL PROTECTED]@INTERNET@HHC
Sent: Tuesday, July 09, 2002 5:35 PM
To: [EMAIL PROTECTED]
Subject: [PHP] Re: isset
i think what you'r
jtjohnston wrote:
I can't get this to work:
if(isset($submit))
with:
input type=\image\ name=\submit\ value=\submit\
src=\nextgif\ border=\0\ align=\ABSCENTER\
I'm not coding correctly?
If you are testing for $submit a work around is to have a hidden field
in your form that looks like
just use an input type=hidden and call it submit,thats what i do
- Original Message -
From: jtjohnston [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Thursday, February 28, 2002 5:32 AM
Subject: Re: [PHP] if(isset($submit))
So I can forget using type=image :(
Wah, it's not fair
I used this code
form action=/inetpub/wwwroot/top.html method=get
input type=image src=none.gif width=125 height=25 name=submit
value=submit
/form
when I clicked on the image, I got this url
file:///C:/inetpub/wwwroot/top.html?submit.x=118submit.y=20
so php would get this as $submit_x and
I s'pose, but where/why are you getting submit.x=118submit.y=20
Martin Towell wrote:
I used this code
form action=/inetpub/wwwroot/top.html method=get
input type=image src=none.gif width=125 height=25 name=submit
value=submit
/form
when I clicked on the image, I got this url
it's a browser thing, i guess, when you use an image as a submit button
Martin
-Original Message-
From: jtjohnston [mailto:[EMAIL PROTECTED]]
Sent: Thursday, February 28, 2002 4:28 PM
To: [EMAIL PROTECTED]
Subject: Re: [PHP] if(isset($submit))
I s'pose, but where/why are you getting
]
Organization: FLSH, Université de Sherbrooke
Reply-To: [EMAIL PROTECTED]
Date: Thu, 28 Feb 2002 00:28:09 -0500
To: [EMAIL PROTECTED]
Subject: Re: [PHP] if(isset($submit))
I s'pose, but where/why are you getting submit.x=118submit.y=20
Martin Towell wrote:
I used this code
form action
Nope, not following.
:)
More particularily why will isset accept type=submit and not type=image ?
Martin Towell wrote:
I used this code
form action=/inetpub/wwwroot/top.html method=get
input type=image src=none.gif width=125 height=25 name=submit
value=submit
/form
when I clicked on the
So I can forget using type=image :(
Wah, it's not fair!
:) J
Martin Towell wrote:
I used this code
form action=/inetpub/wwwroot/top.html method=get
input type=image src=none.gif width=125 height=25 name=submit
value=submit
/form
when I clicked on the image, I got this url
or have a hidden field, maybe, called submit
-Original Message-
From: jtjohnston [mailto:[EMAIL PROTECTED]]
Sent: Thursday, February 28, 2002 4:33 PM
To: [EMAIL PROTECTED]
Subject: Re: [PHP] if(isset($submit))
So I can forget using type=image :(
Wah, it's not fair!
:) J
PROTECTED]
Subject: Re: [PHP] if(isset($submit))
Nope, not following.
:)
More particularily why will isset accept type=submit and not type=image ?
Martin Towell wrote:
I used this code
form action=/inetpub/wwwroot/top.html method=get
input type=image src=none.gif width=125 height=25 name
Over kill?
Martin Towell wrote:
or have a hidden field, maybe, called submit
-Original Message-
From: jtjohnston [mailto:[EMAIL PROTECTED]]
Sent: Thursday, February 28, 2002 4:33 PM
To: [EMAIL PROTECTED]
Subject: Re: [PHP] if(isset($submit))
So I can forget using type
On Wednesday, February 6, 2002, at 03:28 PM, CC Zona wrote:
PHP's loose typing means that !$somevar evalutes as true if the
variable is
null, if it has an (integer, float, or string) value of zero, if it's an
empty string, or if it is set to boolean false. Or if the variable/index
does
In article [EMAIL PROTECTED],
[EMAIL PROTECTED] (Mark) wrote:
if(isset($) and !empty($a) and !$a)
this is the same as if(!empty($a))
or
if(isset($) and $a===FALSE)
this is the same as if(empty($a))
(Aside from accidentally omitted the a in the var name...oops...)
No, they're not
On Sun, 16 Sep 2001 09:18:23 -0700, CC Zona wrote:
In article [EMAIL PROTECTED],
[EMAIL PROTECTED] (Mark) wrote:
if(isset($) and !empty($a) and !$a)
this is the same as if(!empty($a))
or
if(isset($) and $a===FALSE)
this is the same as if(empty($a))
Aside from accidentally omitted the
In article [EMAIL PROTECTED],
[EMAIL PROTECTED] (Mark) wrote:
calling empty($a) does not give a warning.
Sheesh. It doesn't at that. WTF?
--
CC
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In article [EMAIL PROTECTED],
[EMAIL PROTECTED] (Andrew Perevodchik) wrote:
JD isset checks to see if the $a variable has
JD been set, ie, if it exists. if($a) checks for
JD the truthood of $a, meaning, if it has a
JD non-zero, non-null/empty-string value, then
JD its true, else, false.
On Sat, 15 Sep 2001 13:20:59 -0700, CC Zona wrote:
In article [EMAIL PROTECTED],
[EMAIL PROTECTED] (Andrew Perevodchik) wrote:
JD isset checks to see if the $a variable has
JD been set, ie, if it exists. if($a) checks for
JD the truthood of $a, meaning, if it has a
JD non-zero,
isset checks to see if the $a variable has been set, ie, if it exists.
if($a) checks for the truthood of $a, meaning, if it has a non-zero,
non-null/empty-string value, then its true, else, false.
jack
-Original Message-
From: David Yee [mailto:[EMAIL PROTECTED]]
Sent: Friday, September
I see one typo, is that the problem?
Kirk
Hi! I have this weird thing happening here and I just can't
see the problem.
Can someone look at this and tell me if you see what is wrong?
Code
print isset($config["harvester_list"]) ."\n1\n";
print
What are you wanting to print? Here's a set of examples that may help
understand what's happening with your code. In short, isset() is not
being used properly.
// if $var is set, this will return 1. if not set then it will return 0.
// essentially, you don't want to print this directly as
how do I write a Not isset as in:
if != isset($order)
{
$order=$Table."ID";
}
if( !( isset( $order ))) {
}
I'm big on parens. :p
OR
if( empty( $order )) {
}
Chris
try
if(!(isset($order)))
{
$order=$Table."ID";
}
hth
Thank you
Brian Paulson
Sr. Web Developer
[EMAIL PROTECTED]
http://www.chieftain.com
1-800-269-6397
-Original Message-
From: Mike [mailto:[EMAIL PROTECTED]]
Sent: Friday, March 09, 2001 1:34 PM
To: [EMAIL
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