why don't you do something like
$var = $foo $baa;
?
-Original Message-
From: Hasan Niyaz [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, June 20, 2001 12:07 PM
To: [EMAIL PROTECTED]
Subject: [PHP] inserting a variable into a variable
Hello all,
I have come to a
I have come to a situation where i am having a variable inside another
variable.
for example.
$rm_$cat_adt
This works for me:
?
$cat=def;
${abc_.$cat._ghi}=TEST;
echo 'abc_.$cat._ghi = '.${abc_.$cat._ghi}.br\n;
echo 'abc_def_ghi = '.$abc_def_ghi.br\n;
?
michi
--
GMX - Die
What on earth are you trying to do? :)
I'm not sure what your getting at, do you mean defining a variable based
on another variables name? Perhaps try using an array, and specifying
$rm($cat)
Sorry, im not too sure what you mean
Ray Hilton
-
[EMAIL PROTECTED]
http://rayh.co.uk
-Original
I have come to a situation where i am having a variable inside another
variable.
for example.
$rm_$cat_adt
PHP would read this as trying to prepend the variable $cat_adt to the
variable $rm_
You seem to be trying to insert the variable $cat into the middle of a
variable.. possible, but
Michi,
Yours did the trick...
thank you and everyone else who contributed.
Hasan
- Original Message -
From: [EMAIL PROTECTED]
To: Hasan Niyaz [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Sent: Wednesday, June 20, 2001 11:46 AM
Subject: Re: [PHP] inserting a variable into a variable
I
it's there for ;)
-Original Message-
From: Tom Carter [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, June 20, 2001 5:24 AM
To: Hasan Niyaz; [EMAIL PROTECTED]
Subject: Re: [PHP] inserting a variable into a variable
I have come to a situation where i am having a variable inside
just use a hash... that's what it's there for ;)
-Original Message-
From: Tom Carter [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, June 20, 2001 5:24 AM
To: Hasan Niyaz; [EMAIL PROTECTED]
Subject: Re: [PHP] inserting a variable into a variable
I have come to a situation
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