RE: [PHP] sorting results of opendir()

2001-07-09 Thread Jeff Lewis
Why don't you add the $file to an array, then do a sort on the array? sort($array) Jeff -Original Message- From: kmurrah [mailto:[EMAIL PROTECTED]] Sent: Monday, July 09, 2001 2:06 PM To: [EMAIL PROTECTED] Subject: [PHP] sorting results of opendir() Greetings. I need to read

Re: [PHP] sorting results of opendir()

2001-07-09 Thread Steve Edberg
Here's one way: $dir = opendir('.'); unset($FileList); while ($file=readdir($dir)) { if($file!= '.' $file != '..') { $FileList[] = $file; } } sort $FileList; reset($FileList); while(list(, $F) = each($FileList)) { echo $Fbr\n; } If you're using

Re: [PHP] sorting results of opendir()

2001-07-09 Thread bleythbe
Just store each $file into an array ($array[] = $file) and the sort($array). Works dandy = Ben Quoting kmurrah [EMAIL PROTECTED]: Greetings. I need to read the contents of a directory, sort it alphabetically, and display it i'm doing find on the reading and displaying, but can

Re: [PHP] sorting results of opendir()

2001-07-09 Thread Don Read
On 09-Jul-01 Steve Edberg wrote: Here's one way: $dir = opendir('.'); unset($FileList); while ($file=readdir($dir)) { if($file!= '.' $file != '..') { $FileList[] = $file; } } sort $FileList; reset($FileList); while(list(, $F) = each($FileList))