, the first character in a file name is lost
using the PHP basename function. Below is an excerpt from a Horde
webmail server's log that shows the error.
More reading can be found on the Horde list here:
http://marc.info/?l=hordem=124653708009981w=2
and here
http://marc.info/?l=hordem=124683029904466w=2
I'm running php on linux and wish to use basename() to get the file name
from a windows path.
basename() on our linux/php box can't seem to cope with the use of
backslash (\) in the Windows paths I'm feeding it.
In other words:
basename(/usr/blah/doh/yuck/wow/abigfile.html)
resolves to :
ROBERT MCPEAK wrote:
basename(/usr/blah/doh/yuck/wow/abigfile.html)
resolves to : abigfile.html
but
basename(adirectory\onawindowsbox\abigfile.html)
does not resovle to abigfile.html.
Does anybody have a workaround for this?
What about str_replace()?
--
PHP General Mailing
MCPEAK [mailto:[EMAIL PROTECTED]]
Sent: Thursday April 25, 2002 9:41 AM
To: [EMAIL PROTECTED]
Subject: [PHP] basename unix/windows
I'm running php on linux and wish to use basename() to get the file name
from a windows path.
basename() on our linux/php box can't seem to cope with the use
ROBERT MCPEAK [EMAIL PROTECTED] wrote:
In other words:
basename(/usr/blah/doh/yuck/wow/abigfile.html)
resolves to : abigfile.html
but
basename(adirectory\onawindowsbox\abigfile.html)
does not resovle to abigfile.html.
Does anybody have a workaround for this?
Convert all \ to /
On Thursday, April 25, 2002, at 09:54 AM, Matt Friedman wrote:
Replace the \ with / using str_replace or some such function before
using basename. Windows will handle either kind of path. Linux does not
know the \ as a file path separator. It only knows /
Just make sure that you never need
On Mon, Aug 20, 2001 at 03:42:34PM -0400, Gerard Samuel wrote:
$file = basename ($path);
$file = $file.php3;
You might want to consider using,
$file = basename ($path);
$file = $file.php3; // -- !
instead, if you don't like warnings.
$file = $file.php3
isn't the way to do it!
Oh yes, I dont like warnings. Thanks for pointing that out
Renze Munnik wrote:
On Mon, Aug 20, 2001 at 03:42:34PM -0400, Gerard Samuel wrote:
$file = basename ($path);
$file = $file.php3;
You might want to consider using,
$file = basename ($path);
$file = $file.php3; // -- !
Hello,
Can someone please show me how to use basename() correctly?
This is what I am doing:
$file = basename ($path);
$file = basename ($path,.php3);
This is the error I'm gettig:
Warning: Wrong parameter count for basename() in
/home/virtual/ppcu/home/httpd/html/jeremy/stats4.php on line 43
$file = basename ($path);
$file = $file.php3;
Jeremy Morano wrote:
Hello,
Can someone please show me how to use basename() correctly?
This is what I am doing:
$file = basename ($path);
$file = basename ($path,.php3);
This is the error I'm gettig:
Warning: Wrong parameter count for
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