The else clause can be removed, since it is not doing anything. What is the
error message?
Kirk
Hey everyone, I need some help with a variable issue. How can
I delcare a variable and then if a url variable of the same
name is present use that value instead?
this is what I have:
replace the if statement if(!$dte)
with
if (!isset($dte))
- Original Message -
From: Johnson, Kirk [EMAIL PROTECTED]
To: PHP General [EMAIL PROTECTED]
Sent: Friday, November 09, 2001 2:35 PM
Subject: RE: [PHP] variable issue
The else clause can be removed, since it is not doing
if(!isset($dte))
{
$dte=date(j, time()+$ctime);}
You don't need the else statement.
Matthew Luchak
Webmaster
Kaydara Inc.
[EMAIL PROTECTED]
-Original Message-
From: Clint Tredway [mailto:[EMAIL PROTECTED]]
Sent: Friday, November 09, 2001 2:37 PM
To: PHP
thanks for all the help. I realized that I did not need the else, and the isset()
works great! Now I have my calendar working the way I want it to!
Thanks!
Clint
-- Original Message --
From: Matthew Luchak [EMAIL PROTECTED]
Date: Fri, 9 Nov 2001 15:07:22
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