Re: [PHP] Sendemail appends domain to mail function

2001-12-26 Thread Alexander Skwar
So sprach »Peter« am 2001-12-21 um 18:48:13 +0800 : How can I avoid this? By using a valid $from adress. It might also help to put the adress in , so: $from = xyz company; Alexander Skwar -- How to quote: http://learn.to/quote (german) http://quote.6x.to (english) Homepage:

Re: [PHP] Sendemail appends domain to mail function

2001-12-21 Thread Alex Vargas
That's because XYZ company isn't a valid email address and sendmail fixes the address with the name of the server. If you'd put [EMAIL PROTECTED], you'd see that address unchanged. Alex. - Original Message - From: Peter [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Friday, December 21,

Re: [PHP] Sendemail appends domain to mail function

2001-12-21 Thread Bogdan Stancescu
Or, better yet, try From: XYZ company xyz@mydomain; Bogdan Alex Vargas wrote: That's because XYZ company isn't a valid email address and sendmail fixes the address with the name of the server. If you'd put [EMAIL PROTECTED], you'd see that address unchanged. Alex. - Original Message

Re: [PHP] Sendemail appends domain to mail function

2001-12-21 Thread TD - Sales International Holland B.V.
On Friday 21 December 2001 11:48, Peter stuffed this into my mailbox: You probably have masquerading on I think. I believe it's the DM tag in the sendmail.conf off record I think you want to use this for spam. since else it's pretty useless to send email from a non-existing domain which XYZ

RE: [PHP] Sendemail appends domain to mail function

2001-12-21 Thread Michael Geier
set From: like this - $mailheaders .= From: XYZ Company [EMAIL PROTECTED]\n; -Original Message- From: Peter [mailto:[EMAIL PROTECTED]] Sent: Friday, December 21, 2001 4:48 AM To: [EMAIL PROTECTED] Subject: [PHP] Sendemail appends domain to mail function Hi, I have problem.