N.P. Khelili added the comment:
@Brett: Honestly I don't think it is the best way. But fact is:
nono@ACER ~ % cd /
nono@ACER / % python
Python 3.7.3 (default, Mar 26 2019, 21:43:19)
[GCC 8.2.1 20181127] on linux
Type "help", "copyright", "credits" or
N.P. Khelili added the comment:
After digging the question,I'd rather go for a minimal change.
- setting .name to '' for '..'
- let it be known in the doc
- special-casing Path('..').stem (to keep the old behaviour)
- update tests
More could be done, but I don't feel like rewriting too much
Change by N.P. Khelili :
--
keywords: +patch
pull_requests: +13887
stage: test needed -> patch review
pull_request: https://github.com/python/cpython/pull/14022
___
Python tracker
<https://bugs.python.org/issu
N.P. Khelili added the comment:
First, there is no real special case about the '.' path. The parse_args()
method simlply removes then during __new__() (around line 80) as they are not
needed. Double dots having to be kept, are later considered valid by the name
@property
New submission from N.P. Khelili :
The test suite does not handle an OS that does not have IPv6.
When Linux kernel is started with argument:
ipv6.disable=1
The test suite fails. ( See attached file )
5 tests failed:
test_asyncio test_imaplib test_importlib test_socket test_zipapp
N.P. Khelili added the comment:
The idea in my last post was quite bad,
setting name to None breaks a lot of functions
that expect name to be a string.
Path('.').parent and Path('..').parent both return '.'.
Even if it is not stupid (regarding them as special dirs
pointing to somewhere else
N.P. Khelili added the comment:
in the definition of the name property
https://github.com/python/cpython/blob/9ab2fb1c68a75115da92d51b8c40b74f60f88561/Lib/pathlib.py#L792
:
if len(parts) == (1 if (self._drv or self._root) else 0):
return ''
could also become
if self.parent == self
New submission from N.P. Khelili :
Hi guys!
I'm new to python and working on my first real project with it
I'm sorry if it's not the right place for posting this.
I noticed that that pathlib.with_name() method does not accept to give a name
to a path that does not already have one
