[issue39110] UserList-subclass Tree slicing changes node attribute

Change by ctarn : -- resolution: not a bug -> ___ Python tracker ___ ___ Python-bugs-list mailing list Unsubscribe:

[issue39110] UserList-subclass Tree slicing changes node attribute

ctarn added the comment: Sorry but it is not. See the first time I print ls[4].owner. We get d as expected, not a slice of d, that is, d[0:2]. However the next time we print it after _ = list(d[0:1]), noticed that ls[4] == d[0:1], we get d[0:1], it’s extremely surprising!!! I have to

[issue39110] UserList-subclass Tree slicing changes node attribute

Terry J. Reedy added the comment: (ctarn), if you want to discuss what you are doing further, please try a discussion list, such as python-list. -- nosy: +terry.reedy ___ Python tracker

[issue39110] UserList-subclass Tree slicing changes node attribute

Change by Terry J. Reedy : -- stage: -> resolved status: pending -> closed ___ Python tracker ___ ___ Python-bugs-list mailing

[issue39110] UserList-subclass Tree slicing changes node attribute

Change by Terry J. Reedy : -- status: open -> pending ___ Python tracker ___ ___ Python-bugs-list mailing list Unsubscribe:

[issue39110] UserList-subclass Tree slicing changes node attribute

Change by Terry J. Reedy : -- status: pending -> open title: It seems that list() changes the value of the parameter -> UserList-subclass Tree slicing changes node attribute ___ Python tracker