Dear list,
I have a data frame of survey respondents, a little like this:
set.seed(20081215)
n - 100
dat - data.frame(id=1:100,
addr1=sample(LETTERS, n, replace=TRUE),
addr2=sample(LETTERS, n, replace=TRUE),
addr3=sample(LETTERS, n, replace
I think you mean duplicated *rows*, not columns, despite your subject
line.
See ?dublicated, which has a data.frame method.
On Mon, 15 Dec 2008, Andrew C. Ward wrote:
Dear list,
I have a data frame of survey respondents, a little like this:
set.seed(20081215)
n - 100
dat - data.frame(id=1
Hi all,
I my c: drive I have possibly 1,000 notepad files, with .txt extension. They
are named as the dates on which they were saved i.e. 1st file name is
Volume_4-18-2008, 2nd one is Volume_4-21-2008, 3rd one
Volume_4-22-2008 and so on
Also, content of each file are in same format
I'm trying to estimate a tobit model with survrec function. I use
the following code :
reg-survreg(Surv(crs_prod,crs_prod=1)~SOLVA+log(AF088)
+HHI+ACTIONNA,data=dat,dist=gaussian)
I get this error message with R 2.7.2
Error in survreg(Surv(crs_prod, crs_prod = 1) ~ SOLVA + log(AF088) +
Laura Harries wrote:
Hi,
I am trying to download the new version of R from Bristol University (the UK mirror). However when I have down loaded the files and am trying to 'run' them to install the software but Windows is telling me that the files are corrupted and to 'obtain a new version
First of many Rookie questions sorry: Finally broke free of Mathematica and
gone for real OO programing, and up 2 grand a year to boot !
Problem concerns the use of nls function mostly but I have used an example
from finance that is similar to my aim:
Using an fOptions PlainVanillaOptions
Dear all:
I have a list of dataframes like this, i try to merge this lists of dataframes
into one single dataframe, and keep ther column names as usual, how can i do
this?
i try lapply(aa,rbind), but it dose not work.
Best regard!
summary(aa)
Length Class Mode
[1,] 3
Hi,
I am trying to download the new version of R from Bristol University (the UK
mirror). However when I have down loaded the files and am trying to 'run' them
to install the software but Windows is telling me that the files are corrupted
and to 'obtain a new version of the programme'.
I
have you tried do.call(rbind, aa) , or perhaps do.call(merge, aa) ?
Hope this helps,
baptiste
On 15 Dec 2008, at 13:23, 江文恺 wrote:
Dear all:
I have a list of dataframes like this, i try to merge this lists of
dataframes into one single dataframe, and keep ther column names as
usual,
Try do.call(rbind, aa)
HTH,
Thierry
ir. Thierry Onkelinx
Instituut voor natuur- en bosonderzoek / Research Institute for Nature and
Forest
Cel biometrie, methodologie en kwaliteitszorg / Section biometrics, methodology
Dear All
suppose that a=7.5,if i need only integer part of a that is 7 then what
command i can use in R for this purpose.
Zahid Khan
Lecturer in Statistics
Department of Mathematics
Hazara University Mansehra.
[[alternative HTML version deleted]]
Prof Brian Ripley wrote:
On Sun, 14 Dec 2008, Dennis Fisher wrote:
Colleagues,
I am interesting in opening a PDF document via the command line from
both Windows, OS X, and Linux ( R version 2.8.0). I found a command
openPDF in Biobase. However, I would rather execute the command
myself.
Dieter wrote:
It would be good if you could tell us how you found out that the random
effects were significant. I must have missed something here.
One of the models that I have fit looks like this:
blueredminute - read.table(/Users/sachi/Desktop/blueredminute.txt,
header=TRUE)
Sorry,
but this gives me the shivers!
Are all your time series linear?
For each model you should check the residuals and their squares to see if
they are uncorrelated (Box-ljung Chi-sq).
Another useful check is to test for a trend in the coefficient of variation
of the residuals.
If the series
I hope someone can point out my stupid error, because I'm baffled.
I am calculating a bunch of variable values and then placing them in a
document using odfWeave tags.
This is working very nicely for every spot except one.
One of the values I calculate is traindev:
traindev - if
I'd take a good look at trainlength, trainscores and traindev using str()
and summary(), and print at least part of each to the screen. If the same
line of code works with one dataset and not another, the problem is more
likely your data than your code.
If that doesn't help you figure it out,
-Original Message-
From: Wacek Kusnierczyk [mailto:waclaw.marcin.kusnierc...@idi.ntnu.no]
Sent: Sunday, December 14, 2008 5:39 AM
To: Greg Snow
Cc: R help
Subject: Re: [Rd] gregexpr - match overlap mishandled (PR#13391)
Greg Snow wrote:
Controlling the pointer is going to be very
Hi Zahid,I think the following should work, though there's probably a
dozen different ways to do what you want i think:
a-7.5
as.integer(a)
[1] 7
trunc(a)
[1] 7
Hope that helps a little,
Tony Breyal
On 15 Dec, 07:11, zahid khan solo_...@yahoo.com wrote:
Dear All
suppose that a=7.5,if i need
I think it because you are trying to use the if-else control
construct, when you should be using the ifelse function:
?ifelse
Try (perhaps):
traindev - ifelse( (trainlength0), round(sd(trainscores, na.rm=T),
1) , )
You do seem to be mixing types, though, so perhaps you should use NA
Sarah Goslee says: I'd take a good look at trainlength, trainscores and
traindev using str()
and summary(), and print at least part of each to the screen. If the same
line of code works with one dataset and not another, the problem is more
likely your data than your code. If that doesn't help
Hello R-helpers,
I have a lot of series of data and I want to obtain the best probability
distributions (and the distribution to estimate parameters) of each serie.
Besides this paper
http://cran.r-project.org/doc/contrib/Ricci-distributions-en.pdf, do you
know if there are other papers that
Dear all,
I'm trying to estimate a tobit model with survrec function. I use the
following code :
reg-survreg(Surv(crs_prod,crs_prod=1)~SOLVA+log(AF088)+HHI+ACTIONNA,data=dat,dist=gaussian)
I get this error message with R 2.7.2
Error in survreg(Surv(crs_prod, crs_prod = 1) ~ SOLVA +
Try this:
Lines - ID;record
1;20
;30
;25
2;26
;15
3;21
x - read.table(textConnection(Lines), sep = ;, header = TRUE)
library(zoo)
x$ID - na.locf(x$ID)
On Sun, Dec 14, 2008 at 11:56 PM, Zhixin Liu z...@efs.mq.edu.au wrote:
Hi R helpers,
If I have a dataset looks like:
ID record
1
Hello everyone,
I am a very new user of R and I have a query about the cuminc function
in the package cmprsk. In particular I would like to verify that I am
interpreting the output correctly when we have a stratification
variable.
Hypothetical example:
group : fair hair, dark hair
fstatus:
Unfortunately - no luck. Changing to the ifelse construction didn't fix the
problem, and changing the to a zero or a NA also didn't help.
Meanwhile, I have 4 other sd calculations on the same dataset, using the
same construction, elsewhere in the document and code. None of them are
giving me
On Sun, 14 Dec 2008, Mark Wardle wrote:
Hi.
You don't need to download the whole of the output database table to
look for an already generated answer. You can write a SQL query to do
that instead. ie. give me any rows with these parameters... Get the
database to do the work - it is what they
Try:
trunc(a)
On Mon, Dec 15, 2008 at 5:11 AM, zahid khan solo_...@yahoo.com wrote:
Dear All
suppose that a=7.5,if i need only integer part of a that is 7 then
what command i can use in R for this purpose.
Zahid Khan
Lecturer in Statistics
Department of Mathematics
Hazara University
On 12/15/2008 8:15 AM, Laura Harries wrote:
Hi,
I am trying to download the new version of R from Bristol University (the UK mirror). However when I have down loaded the files and am trying to 'run' them to install the software but Windows is telling me that the files are corrupted and to
You can also try ?rep and something like
dat - read.table(textConnection(ID record
120
. 30
. 25
2 26
. 15
3 21
),header=TRUE,na.strings=.)
ind - !is.na(dat$ID)
id - dat$ID[ind]
reps - diff(c(seq_len(nrow(dat))[ind],nrow(dat)+1))
dat$new.id -
David Winsemius wrote:
I think it because you are trying to use the if-else control construct,
when you should be using the ifelse function:
?ifelse
Try (perhaps):
traindev - ifelse( (trainlength0), round(sd(trainscores, na.rm=T),1) ,
)
Does anything change if you rename to (say) trainsd??
On Mon, 15 Dec 2008, Nathan S. Watson-Haigh wrote:
-BEGIN PGP SIGNED MESSAGE-
Hash: SHA1
Nathan S. Watson-Haigh wrote:
I'm trying to calculate Pearson correlation coefficients for a large
matrix of size 18563 x 18563. The following function takes about XX
minutes to complete, and I'd
Dear List,
Apologies for this off-topic post but it is R-related in the sense that
I am trying to understand what R is telling me with the data to hand.
ROC curves have recently been used to determine a dissimilarity
threshold for identifying whether two samples are from the same type
or not.
Dear R Users,
I was running some data analysis scripts and ran into this error:
Error: cannot allocate vector of size 27.6 Mb
Doing a memory.size(max=TRUE) will give me:
[1] 1506.812
The current situation is:
I'm working on a Windows Vista 32bit laptop with 4GB RAM (effectively
3GB I
renaming the variable does not help. I actually started with trainsd as the
variable name.
I believe that Sarah Goslee must be correct, and it's the data set I'm
working from. Which moves my inquiry to the statement that establishes the
dataset - I am combing through that now and will report
I have a network of four machines set up. I'm having trouble spawning
my slaves on these machines.
All the examples I have found so far use makeCluster with type=MPI,
and I guess I'm missing some kind of cluster configuration in my
environment variables because all my clusters are formed on the
wrote:
Dear list,
I have a data frame of survey respondents, a little like this:
set.seed(20081215)
n - 100
dat - data.frame(id=1:100,
addr1=sample(LETTERS, n, replace=TRUE),
addr2=sample(LETTERS, n, replace=TRUE),
addr3=sample(LETTERS, n, replace
Greg Snow wrote:
mystr - paste(rep(1122, 10), collapse=)
n - nchar(mystr)
mystr2 - substr(rep(mystr,n), 1:n, n)
tmp - regexpr(^11221122, mystr2)
(tmp + 1:n - 1)[tmp0]
[1] 1 5 9 13 17 21 25 29 33
attr(tmp,match.length)[tmp0]
[1] 8 8 8 8 8 8 8 8 8
I'm new to bugs, so please bear with me. Can someone tell me if the
following two models are doing the same thing? The reason I ask is
that with the same data, the first (based on 4 separate coeffs
a1--a4) takes about 50 secs, while the second (based on a vectorized
form, a[]) takes about
On Mon, 15 Dec 2008, megh wrote:
Hi all,
I my c: drive I have possibly 1,000 notepad files, with .txt extension. They
are named as the dates on which they were saved i.e. 1st file name is
Volume_4-18-2008, 2nd one is Volume_4-21-2008, 3rd one
Volume_4-22-2008 and so on
Also,
Also,each data.frame of the 1500 working as data sources floating in
the global environment is of a size ranging from 2000x36 to 9000x36
Please help...! THANKS!!!
- John
On Mon, Dec 15, 2008 at 1:12 PM, tsunhin wong thjw...@gmail.com wrote:
Dear R Users,
I was running some data analysis
On Mon, 15 Dec 2008, tsunhin wong wrote:
Dear R Users,
I was running some data analysis scripts and ran into this error:
Error: cannot allocate vector of size 27.6 Mb
Doing a memory.size(max=TRUE) will give me:
[1] 1506.812
The current situation is:
I'm working on a Windows Vista 32bit
Nothing leaps out as obviously wrong to me. It may even be something earlier
in the ODFWeave file that is causing the error. You said the code works at
the command line, right?
The next thing I'd do is try to make the smallest possible ODFWeave file
that has the problem - make a copy, then start
Thanks Charles for this reply. I have started according to your suggestion
and hopefully I can do it. In the mean time what I was thinking, instead of
calling my text files by their names, is there any mechanism to call them by
the order they are stored in that directory? Means, suppose, I have
RichardLang wrote:
I've just started using R last week and am still scratching my head.
I have a data set and want to run a separate regression across each level
of a factor (treating each one separately). The data right now is arranged
such that the value of the factor along which I
Philip A. Viton wrote:
I'm new to bugs, so please bear with me. Can someone tell me if the
following two models are doing the same thing? The reason I ask is
that with the same data, the first (based on 4 separate coeffs
a1--a4) takes about 50 secs, while the second (based on a
After writing some code (stupidly without checking to see if there was
code to do this already) to generate PostGIS SQL insert statements for
simple geometry (wkt), I didn't check see if there is already something
available to convert WKT strings into some R package geometry (sp?).
Does anyone
All interesting suggestions. Let's see...
Running the code on a randomly-generated dataframe or a different real
dataset still has the problem.
A whole new document with only a single line \Sexpr{trainsd} seems to work
just fine.
If, in the actual project document, I use:
test,
All interesting suggestions. Let's see...
Running the code on a randomly-generated dataframe or a different real
dataset still has the problem.
A whole new document with only a single line \Sexpr{trainsd} seems to work
just fine.
If, in the actual project document, I use:
test,
Dear all,
I have a huge problem after downloading and exporting data from Reuters3000
XTra:
I downloaded many many monthly, quarterly and yearly data. I do not know
why, but after saving, I have mixed-data sets, i.e. files which can be
imported as read.csv and others that are in the
Philip,
If you are using WinBUGS 1.4, then the poor performance of the
inprod function is a known problem. An inprod2 function
was introduced in 1.4.3 to improve performance. See
http://www.mrc-bsu.cam.ac.uk/bugs/winbugs/contents.shtml#problems
You might try using that.
For WinBUGS problems,
On Mon, 15 Dec 2008, megh wrote:
Thanks Charles for this reply. I have started according to your suggestion
and hopefully I can do it. In the mean time what I was thinking, instead of
calling my text files by their names, is there any mechanism to call them by
the order they are stored in that
I saw a thread from September 24 in which Duncan Temple Lang told us:
- The package currently has no Rd files, but there is a brief user's
guide. The package is available from
http://www.omegahat.org/RGoogleDocs
I could not find it by using Tinn-R or RGui's package install tool.
Then
Hello,
You can probably extract a .tar.gz using 7zip on Windows.
Regards,
Gustavo.
On Mon, Dec 15, 2008 at 8:07 PM, Farrel Buchinsky fjb...@gmail.com wrote:
I saw a thread from September 24 in which Duncan Temple Lang told us:
- The package currently has no Rd files, but there is a brief
Dear list,
I am trying to program semi-random movement within a circle, with no particles
leaving the circle. I would like them to bounce back when they come to close to
the wall, but I don't seem to be able to get this right. Would somebody be
able to give me a hint ? This is my code so
On Mon, 15 Dec 2008, Farrel Buchinsky wrote:
I saw a thread from September 24 in which Duncan Temple Lang told us:
- The package currently has no Rd files, but there is a brief user's
guide. The package is available from
http://www.omegahat.org/RGoogleDocs
I could not find it by using
Tubin wrote:
All interesting suggestions. Let's see...
Running the code on a randomly-generated dataframe or a different real
dataset still has the problem.
A whole new document with only a single line \Sexpr{trainsd} seems to work
just fine.
If, in the actual project document, I use:
Great. I have previously installed 7zip.
It worked well. I installed the files. See below (way below).
When I entered library(RGoogleDocs)
it did not run.
So I just ran auth.R
Then I was able to run
auth -getGoogleAuth(fjb...@gmail.com,mypassword)
con = getConnection(auth)
con$getDocs()
all
No one seems to have mentioned that the size of the protection stack can
be set when starting R. It worked for me starting R with
--max-ppsize=10. I'm not sure that will do more that postpone the
problem, but it may help.
On Tue, 9 Dec 2008, Bert Gunter wrote:
Apparently the former, as
On Mon, Dec 15, 2008 at 01:16:46PM -0500, Whit Armstrong wrote:
I have a network of four machines set up. I'm having trouble spawning
my slaves on these machines.
All the examples I have found so far use makeCluster with type=MPI,
and I guess I'm missing some kind of cluster configuration
On Dec 15, 2008, at 5:20 PM, Juliane Struve wrote:
Dear list,
I am trying to program semi-random movement within a circle, with no
particles leaving the circle. I would like them to bounce back when
they come to close to the wall, but I don't seem to be able to get
this right. Would
Megh,
You can capture all your external files into R using:
All_files - dir(pattern=txt)
Then read files one by one and insert the contents from section 2,
say, in line 10, to section 3, say in line 40, into file cont:
no_files - length(All_files)
cont - vector(list,no_files)
for(i in
Farrel Buchinsky wrote:
Great. I have previously installed 7zip.
It worked well. I installed the files. See below (way below).
When I entered library(RGoogleDocs)
it did not run.
So I just ran auth.R
Then I was able to run
auth -getGoogleAuth(fjb...@gmail.com,mypassword)
con =
When I rungetDocs(con)
I get this error:
Error in getDocs(con) : could not find function xmlParse
Where should xmlParse be coming from?
You had asked where I got the idea to enter con$getDocs(). I got it
from run.html. But now that you bring the words In the future, we
might to my attention I
Farrel Buchinsky wrote:
When I rungetDocs(con)
I get this error:
Error in getDocs(con) : could not find function xmlParse
Where should xmlParse be coming from?
From the XML package.
You had asked where I got the idea to enter con$getDocs(). I got it
from run.html. But now that you
I have loaded the XML package. Should the function not be xmlTreeParse?
Look at this
library(XML)
help(xmlParse)
No documentation for 'xmlParse' in specified packages and libraries:
you could try 'help.search(xmlParse)'
help.search(xmlParse)
Help files with alias or concept or title matching
I took the liberty of replacing all the xmlParse in auth.R with
xmlTreeParse. Alas still no joy.
getDocs(con)
Error in UseMethod(xpathApply) : no applicable method for xpathApply
Farrel Buchinsky
GrandCentral Tel: (412) 567-7870
On Mon, Dec 15, 2008 at 20:00, Farrel Buchinsky fjb...@gmail.com
Dear list,
I am trying to program semi-random movement within a circle, with no particles
leaving the circle. I would like them to bounce back when they come to close to
the wall, but I don't seem to be able to get this right. Would somebody kindly
give me a hint ? This is my code so far,
I'm having trouble getting the relaimpo package to use a covariance matrix as
input. I'm getting an error message that reads as follows:
Error in eval(m$weights, data, parent.frame()) :
numeric 'envir' arg not of length one
I'm guessing there is something wrong with the structure of my
barplot(5000*((1-.26)^(0:49)))
jimdare wrote:
Hi,
I am new to R. I am trying to plot the decay of a population over time
(0-50yrs). I have the initial population value (5000) and the mortality
rate (0.26/yr) and I can't figure out how to apply this so I get a
remaining population
Hai everbody, Is there anyone have simple application b-spline in r language?
I need it for make me understanding about b-spline for polynomial spline.
thank u
ArifÂ
New Email addresses available on Yahoo!
Get the Email name you#39;ve always wanted on the new @ymail and
I´m a PhD student at the University of Warsaw, and have started using R.
In many books they specify to use - instead of = when assigning
values, and this is also mentioned in older posts on the R website.
However, it seams to me that some update has occured, becuase I
continously get the same
Dear Prof Ripley
I am writing to you regarding a query on reporting the results of the repeated
measures ANOVA.
I am a dphil student from the dept. of Education at Oxford. I have used the
repeated measures design to analyse the effects of my intervention.I have a main
effect of time(pre and post
Hi,
I am new to R. I am trying to plot the decay of a population over time
(0-50yrs). I have the initial population value (5000) and the mortality
rate (0.26/yr) and I can't figure out how to apply this so I get a remaining
population value each year. In excel (ignoring headings) I would put
Dear Petter,
Take a look at this post:
http://www.nabble.com/What-to-use-for-assignment,--%3D--or--to16521827.html#a16521827http://www.nabble.com/What-to-use-for-assignment,-%22-%3D-%22-or-%22-%3C--%22--to16521827.html#a16521827
HTH,
Jorge
On Mon, Dec 15, 2008 at 4:26 PM, Petter Hedberg
Hi,
I have a data frame with several columns.
Now I want to transfer the data into a new variable (also a data
frame), but I only want a part of the data, defined by a rule ...
for example; I have following data frame:
row1row2row3
x 2 3
x
This question might seem silly, because I felt that it MUST be in the
mailing list archives or help files somewhere, but I simply couldn't find
it.
I want to make some simple CDF (cumulative distribution function) plots
to check whether distributions are Gaussian / normal. But in order
Dear Jörg,
Try this:
# Data
DF=read.table(textConnection(
row1row2row3
x 2 3
x 1 4
y 5 3
y 2 3),header=TRUE)
closeAllConnections()
# Splitting
res=with(DF,split(DF,row1))
res
In most cases - and = are the same yet its not always
true so its safest to use - for assignment.
Check this out:
http://tolstoy.newcastle.edu.au/R/e4/help/08/06/12940.html
On Mon, Dec 15, 2008 at 4:26 PM, Petter Hedberg ekologkons...@gmail.com wrote:
I´m a PhD student at the University of
Another method :
DF[DF$row1 == x, ]
row1 row2 row3
1x23
2x14
On Dec 15, 2008, at 8:51 PM, Jorge Ivan Velez wrote:
Dear Jörg,
Try this:
# Data
DF=read.table(textConnection(
row1row2row3
x 2 3
x 1 4
y
If you look at the distribution of those with analogs==TRUE versus the
whole groups it is not surprising that the upper range of Dij's result
in a very low probability estimate:
plot(density(dat$Dij))
lines(density(dat[dat$analogs == TRUE, 2]))
Appears as though more than 25% of the
Colleagues,
Several days ago, I queried about using the system command to open a
PDF file. A number of people responded, each providing useful ideas.
I integrated these ideas into a function that others can tailor to
their needs:
OPENPDF - function(PDFFILENAME)
{
-BEGIN PGP SIGNED MESSAGE-
Hash: SHA1
Charles C. Berry wrote:
On Mon, 15 Dec 2008, Nathan S. Watson-Haigh wrote:
-BEGIN PGP SIGNED MESSAGE-
Hash: SHA1
Nathan S. Watson-Haigh wrote:
I'm trying to calculate Pearson correlation coefficients for a large
matrix of size 18563 x
Hi,
how can I change a defined factor-variable?
Like adding levels, renaming existing levels or merge several levels
of a factor to one level?
For example; following factor-variable is given:
x - factor(c(xyz1, abc1, xyz2, abc2))
How can I add the level fgh?
And how can I merge xyz1
Dear R Core Team,
I am using package {urca} to do cointegration and estimate ECM model,
but I have the following two problems:
(1)I use ca.jo() to do cointegration first and can get the
cointegration rank, alpha and beta. The next step is to test some
restrictions on beta with
Jörg
To add a level you could:
x - factor(c(xyz1, abc1, xyz2, abc2))
x1 - factor(x, levels=c(levels(x), 'fgh'))
summary(x)
abc1 abc2 xyz1 xyz2
1111
summary(x1)
abc1 abc2 xyz1 xyz2 fgh
11110
For the others, I tend to convert to a character, make the changes
On Dec 15, 2008, at 10:15 PM, Peter Alspach wrote:
Jörg
To add a level you could:
x - factor(c(xyz1, abc1, xyz2, abc2))
x1 - factor(x, levels=c(levels(x), 'fgh'))
Could also use:
levels(ff) - c(levels(ff), fgh)
summary(x)
abc1 abc2 xyz1 xyz2
1111
summary(x1)
abc1 abc2 xyz1
Hi,
I have a problem sorting and selecting entries within a data-frame and
I don't know if it is possible to solve it with R ... (probably yes,
but I have no idea how).
Following Data;
row1row2
a 12
pos NA
a 3
neg NA
a
grep for pos or neg reducing the data frame to
the rows prior to those matched. With this reduced
data frame pick out those row2 for which a is in row1:
# input
DF - data.frame(row1 = c(a, pos, a, neg, a, neg, a, pos),
row2 = c(12, NA, 3, NA, 5, NA, 11, NA), stringsAsFactors = FALSE)
# soln 1.
Petter Hedberg wrote:
I´m a PhD student at the University of Warsaw, and have started using R.
In many books they specify to use - instead of = when assigning
values, and this is also mentioned in older posts on the R website.
However, it seams to me that some update has occured, becuase I
Wacek Kusnierczyk wrote:
Petter Hedberg wrote:
I´m a PhD student at the University of Warsaw, and have started using R.
In many books they specify to use - instead of = when assigning
values, and this is also mentioned in older posts on the R website.
However, it seams to me that some
The following has a bug in it, but it does a reasonable job. The bug
occurs in the lines that says
if(inner(xnew,xnew) R^2)
xnew - x[n,] - eps ##error - sometimes x[n,] - eps is outside
circle
If it is changed to something like xnew - proj(x[n,] + eps) where
proj is a projection function
Hi all,
I have a very large binary vector, I wish to calculate the number of
1's over sliding windows.
this is my very slow function
slide-function(seq,window){
n-length(seq)-window
tot-c()
tot[1]-sum(seq[1:window])
for (i in 2:n) {
tot[i]- tot[i-1]-seq[i-1]+seq[i]
}
92 matches
Mail list logo
