OIS
Thank you both for pointing me to it. I did not notice this as the
unscaled position of points was quite clear and strightforward according
to my knowledge of data. The scaled plot is slightly more distorted and
the relationships are not so obvious.
Thank you both
Petr Pikal
Dear All,
I am not being able to load RHtestV2 or rhtest_gui.r for homogeneity test of
climatic data. I have 2 user manual RHTest (0.95) and RHtestV2. Though, I load
source code for RHtestV2 no any other window pops up. However, I am unable to
find source code rhtest_gui.r.
Regards,
Binaya
Hi
Michael Kogan michael.ko...@gmx.net napsal dne 19.08.2009 17:22:04:
Thanks, that was the solution! But in fact I didn't want to have this
list of lists layer at all. And now I'm having trouble writing
matrices into the database. It's really really strange... If I write a
matrix into
Vincent Chouraki wrote:
When I'm using Hmisc's latex() function with ctable=TRUE on a
summary.formula with method=reverse object and saving in a .tex file,
the latter contains an unwanted empty line which makes compilation fail.
... Example removed
Vincent,
I checked it and
Chris Friedl wrote:
Text is really small and legend boxes are huge in this plot when saved to
.png with ggsave. Plot is correct (i.e. looks the same as the screen) when
saved with dev.print. Saving to .pdf with ggsave give the correct output.
You are not alone. Things like this always
Dear R users
I would like to do some spreadsheet style expansion of dates. For
example, I would need to obtain a vector of months. I approached in an
obviously wrong way:
paste(01:12)
[1] 1 2 3 4 5 6 7 8 9 10 11 12
as.Date(paste(01:12), %m)
[1] NA NA NA NA NA NA NA NA NA NA NA NA
to
Hi Jimmy,
please be reassured that I did not intend to offend you nor any other in
the list.
Rnewbie ha scritto:
I read the boxplot() help file and googled before making the post, and with
my little knowledge on R I was not able to plot in the way I wanted.
If I'm allowed, this was not
Hi Rolf,
On Thu, 2009-08-20 at 12:31 +1200, Rolf Turner wrote:
I despair. Why do you keep insisting that black is white?
The OP wanted to be able to specify an argument to boxplot()
that would cause it to plot mild and extreme outliers with
different symbols.
Then you and I were reading
I'm very sorry for all this, but still serene.
I'm (trying) to use R since may be 5 or 6 years now.
What I learned from this list is that you have to show some code to let
others to help you out, a thing that Rnewbye did not in this particular
case.
I had a look myself at the help pages and
Dear Jim Michael
the file contains 1000 lines and 1.200.000 columns, txt format and i
wish to read all the file with R if possible, or read a few columns?
I tried without success to turn bigmemory and colbycol packages, also
scan and readLines function but It takes a long time without
Hi every one,
I read one excel external file into R, in that R dataset i have 20
variables. now my querry is i want to print only selected variables (eg:10
variables) with complete data. pls send me the code it will be very helpful
for us.
Thanks in Advance.
--
View this message in context:
assume dependent variable y( continuous),independent variable x (
continuous),I try to categorize x with some interval,such that,those
intervals would has most significant different effect on y.
any one knows which method I should apply,I really need some hints,thanks
so much~
On Thu, 2009-08-20 at 08:14 +0100, Liviu Andronic wrote:
Dear R users
I would like to do some spreadsheet style expansion of dates. For
example, I would need to obtain a vector of months. I approached in an
obviously wrong way:
paste(01:12)
[1] 1 2 3 4 5 6 7 8 9 10 11 12
Rakknar wrote:
Hello everybody. I've been learning R for about a month to do a
econometric study and now i'm stuck with some problems to make R do the
things I want. Here I give the list of things I wanna do from the most
simple to the more complex (for me of course):
1. Make a log. I've
rajclinasia wrote:
Hi every one,
I read one excel external file into R, in that R dataset i have 20
variables. now my querry is i want to print only selected variables (eg:10
variables) with complete data. pls send me the code it will be very helpful
for us.
Thanks in Advance.
Hi,
Please
One possible (but not very elegant) solution is:
aa - paste(1:12,:10:2009,sep=)
dd-as.Date(aa,format=%m:%d:%Y)
mon - format(dd,%b)
mon
[1] Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov Dec
--- On Thu, 20/8/09, Liviu Andronic landronim...@gmail.com wrote:
From: Liviu Andronic
Hi Jun,
I have three levels for a factor names StdLot and want to make three
comparisons, 1 vs 2, 1 vs 3 and 2 vs 3.
With only three levels to your factor, the contrast matrix you are
specifying is over-parametrized (i.e. over-specified): it has 3 rows and 3
columns.
## Look at the default
Readers,
How do I configure R so that all units of measurement are in
millimetres? For example if I want to set the width of a graph, I want
to write:
width=100
and R interprets this value as millimetres.
Yours,
rh...@conference.jabber.org
r 251
mandriva 2008
Hi,
in my project I want the user to be able to write hook functions that
are in turn called in my main code. I'd like the user's hooks to be able
to call some function that set a variable outside their running
environment. The trick is that this variable is not global, but defined
on
Thank you very much, Jun. This is what I was looking for.
Best!
Dani
On Wed, 2009-08-19 at 09:52 -0500, Jun Shen wrote:
I would suggest a model with a baseline level, something like
nls(AMP~E0+(Emax-E0)*Time**gamma/(EC50**gamma+Time**gamma),data=your
data,
dimple thyagarajan wrote:
Hello!
I am trying to merge two xy-plot with different ylimits.
It seems that you are using lattice graphics (which you do not mention),
if so, look at the documentation of xyplot, specifically to the panel
argument.
cheers,
Paul
Can someone please give me
On 18/08/2009, Stefan Grosse singularit...@gmx.net wrote:
On Tue, 18 Aug 2009 16:08:36 +0100 e-letter inp...@gmail.com wrote:
EL
postscript(/pathto/filename.eps,horizontal=FALSE,onefile=FALSE,paper=special)
EL
EL This command created a small blank eps file.
Its hard to say why without
Dear Chris,
That problem is due to the fact that ggsave() and png() use different
default for the resolution. ggsave() uses 300 dpi and png() 72 dpi. If
you set the resolution in ggsave() to 72 then you get exactly the same
output as on the screen. But the resolution is way to low for
On Thu, 20-Aug-2009 at 12:21AM +0100, Ted Harding wrote:
[]
| Again, what I routinely do (in Linux) when developing R code is to
| have two terminal windows open. In one I am running R. In the
| other, beside it, I am editing a file of R code. To run code in R
| that has been entered in the
Dear Terry,
The following is an additional set of two simple examples. In these,
no issue with factor levels, etc, arises. It looks like the problem
consistently shows up when the number of rows of newdata differs
from the number of rows in the original data set AND time and status
are not part
Rakknar ha scritto:
Hello everybody. I've been learning R for about a month to do a
econometric study and now i'm stuck with some problems to make R do the
things I want. Here I give the list of things I wanna do from the most
simple to the more complex (for me of course):
1. Make a log.
Is there a function to fit heckman probit model in R ?
Sincerly..
Justin BEM
BP 1917 Yaoundé
Tél (237) 76043774
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
Dear all,
Suppose I have a nested, repeated measure lme model. Which of the following
formulae is correct?
(assuming data are sampled from several plots in an agricultural experiment)
(1) y~explanatory.variables,random=~time|block/plot/subplot/individual
(2)
Dear Christoph,
Why should (1) not work? As long as you have enough levels, it should
not be a problem. You need at least 6 levels for each random effect.
When you have less than six levels, then you better move those variables
to the fixed effects.
An example: 2 blocks with each 2 plots. Each
Dear all
I would like to globally set
options(digits = 4)
in an Sweave document. I've read this thread [1] where it was
suggested to set the above option and pass every printed number
through format(). Aanother way to do so would be to round(expr, 4).
However I would like to set the digits option
Lazarus Mramba wrote:
Dear Sir,
I am almost giving up on getting the R-2.9.1 on the ubuntu 9.04 using the
instructions found on the R site.
I decided to use the R-2.9.1.tar.gz and untarred it.
I then typed ./configure and the results are shown below.
However, on typing make, I got an
Dear list,
I would like to calculate Sobol indices (first-order and total indices) with
the sobol2002 function in the 'sensitivity' package for a hydrologic model. The
input of my model consists of a parameter vector, the output of a single value
(agreement between observed and simulated
Hi Shankar
On a slightly different note - below produces a strip to the left without
the stacked strips
require(latticeExtra) # NB install if not found
useOuterStrips(strip=strip.custom(bg=skyblue),
strip.left=strip.custom(bg=yellow),
xyplot(V4~V3|frac.f*stdev.f,
Dear Sir,
I am almost giving up on getting the R-2.9.1 on the ubuntu 9.04 using the
instructions found on the R site.
I decided to use the R-2.9.1.tar.gz and untarred it.
I then typed ./configure and the results are shown below.
However, on typing make, I got an error, No targets specified and
ONKELINX, Thierry wrote:
My workaround is to always save my plots to pdf.
..
In that case I convert the pdf to png outside R.
The best tools I found for that are Ghostfriend
(http://www.noliturbare.com/index.php) and www.zamzar.com.
Which is also my approach, but not using ggsave or
Hi Ottorino,
Nevermind. I'm not in a position to require answers. As I said, I appreciate
any help and that people would spend time reading my post.
I didn't intend to elicit debates over my post, but again I thank all for
offering help. I need some time to digest the information before making
Thanks, I was already told this solution by somebody (he just forgot to
add the mailing list as CC). Well, the purpose of the whole thing is to
get something like this:
http://home.att.net/~numericana/data/polycount.htm where the numbers in
the table cells give the number of matrices saved in
On Thu, Aug 20, 2009 at 3:23 AM, Gavin Simpsongavin.simp...@ucl.ac.uk wrote:
Hi Rolf,
On Thu, 2009-08-20 at 12:31 +1200, Rolf Turner wrote:
I despair. Why do you keep insisting that black is white?
The OP wanted to be able to specify an argument to boxplot()
that would cause it to plot
Hi all,
Can anyone suggest me how to insert rows in between data frames and also
keep the ordering of row numbers correct?
Estimate Std. Errort
value Pr(|t|)
recmeanC2 9.275880e-176.322780e-17 1.467057e+00
Dear all,
Because my last email was in html format, so it was a disaster to read. I
have second thought of my question asked in my last email, and came up some
solution to myself, but I found the result was a bit weird, can someone
please help look at my coding and advise where I have done wrong?
Dear All,
Here are the codes of a histogram a kernel density estimates that I used.
For the hist estimate
par(mex=1.3)
dens-density(q)
options(scipen=4)
ylim-range(dens$y)
h-hist(q,breaks=scott,freq=FALSE,probability=TRUE,
+ right=FALSE,xlim=c(9000,16000),ylim=ylim,main=Histogram of q(scott))
month.abb
[1] Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov Dec
# or random
month.abb[sample(1:12)]
[1] Jan Apr Sep Mar Nov May Aug Oct Dec Jul Jun Feb
On Thu, Aug 20, 2009 at 3:14 AM, Liviu Androniclandronim...@gmail.com wrote:
Dear R users
I would like to do some spreadsheet style
I am not sure what the purpose of workspace is so I
have eliminated it in the following. We just use the
environment within main and when main exits all its
variables go too so that seems sufficient.
fun.global - function() { message('fun.global'); setVar(5) }
main - function() {
l.var
month.abb
month.name
On Thu, Aug 20, 2009 at 3:14 AM, Liviu Androniclandronim...@gmail.com wrote:
Dear R users
I would like to do some spreadsheet style expansion of dates. For
example, I would need to obtain a vector of months. I approached in an
obviously wrong way:
paste(01:12)
[1] 1 2
Dear R Users,
I have 120 objects stored in R's memory and I want to pass the names of these
many objects to be held as just one single object. The naming convention is
month, year in sequence for all months between January 1986 to December 1995
(e.g. Jan86, Feb86, Mar86... through to Dec95).
Rakknar wrote:
Hello everybody. I've been learning R for about a month to do a
econometric study and now i'm stuck with some problems to make R do the
things I want. Here I give the list of things I wanna do from the most
simple to the more complex (for me of course):
1. Make a log. I've
the short answer is to add [[i]] in your loop,
file_list[[i]] - paste(index$month[i], index$year[i], sep='')
yet a shorter answer would be,
file_list = apply(index, 1, paste, collapse=)
HTH,
baptiste
2009/8/20 Steve Murray smurray...@hotmail.com:
Dear R Users,
I have 120 objects stored
e-letter wrote:
Readers,
How do I configure R so that all units of measurement are in
millimetres? For example if I want to set the width of a graph, I want
to write:
width=100
and R interprets this value as millimetres.
Hi e-letter,
If you just want a quick hack:
mm2in-function(mm)
Also - is there a better way for the future? I know some people use IDE's
but is that for serious programming or for building a small function and
tweaking it?
What about a version control system to (locally) save the different
stages of your script files?
(I use git but Subversion (SVN) may
Thanks Richard,
I tried running the analysis the way you suggested but here is the error
that I get
track.aov - aov(mice ~ coon+block*veget*fruit*time -
block:veget:fruit:time
+ + Error(block/plot), data = track)
Warning message:
In aov(kotz.mice ~ kotz.coon + block * veget *
Hi there,
what you means by complete data.
Read the posting guide, where it is suggested a minimum reproducible code,
as well as good clarification about what you have/get and what you realy
want to get.
bests
milton
On Thu, Aug 20, 2009 at 3:38 AM, rajclinasia r...@clinasia.com wrote:
Hi
Hi Gabor,
thanks.
Indeed I reckon implementing it using an object would be better, but I
wanted to keep it as simple as possible for the end user, by hiding the
object mechanism. The user would not have to define its function with an
extra parameter, maybe obscure to him.
My problem now is
Manli Yan wrote:
assume dependent variable y( continuous),independent variable x (
continuous),I try to categorize x with some interval,such that,those
intervals would has most significant different effect on y.
any one knows which method I should apply,I really need some hints,thanks
so
Error in Math.factor(c(2L, 1L, 1L, 1L, 1L, 3L, 1L, 1L, 1L, 1L, 1L, 1L, :
log not meaningful for factors
In addition:Warning messages:
1: In Ops.factor(LRUpBound, LRLowBound) : * not meaningful for factors
2: In Ops.factor(TransitCoefStdDev, TransitCoefMean) :
/ not meaningful for factors
I got the answer:
weights=varComb(varFixed(~1/n),varPower(~Age))
Bond, Stephen-2 wrote:
Hello everybody,
I have a dataset where each row has number of subjects and that gives me
natural weights for the variance function. Additionally I see that
variance increases with Age, which is a
Hello,
I write this message because I have a problem with cointegration and causality
tests on R.
I'm working with time series data. I use ucra and vars packages.To perform
cointegration and Granger causality tests, I respectively write :
sjv - vardata[, c(upd, nc, r, up,
A function finds its free variables in its environment. Changing
the environment of one function does not change the environment of
other functions; however, if instead of messing with environments you
use the proto solution already posted then that would handle this situation
by passing the
On Thu, 2009-08-20 at 12:54 +, Inchallah Yarab wrote:
Error in Math.factor(c(2L, 1L, 1L, 1L, 1L, 3L, 1L, 1L, 1L, 1L, 1L, 1L, :
log not meaningful for factors
In addition:Warning messages:
1: In Ops.factor(LRUpBound, LRLowBound) : * not meaningful for factors
2: In
Hello everybody,
Please help with connecting the AIC and BIC numbers printed by summary.gls to
the logLik number.
1. is the logLik number the true ML or density scaling constants have been
omitted?
2. what is the formula for calculating the AIC and BIC from logLik (and how
can I see it)?
On Thu, 20 Aug 2009 12:54:33 + (GMT) Inchallah Yarab
inchallahya...@yahoo.fr wrote:
IY Error in Math.factor(c(2L, 1L, 1L, 1L, 1L, 3L, 1L, 1L, 1L, 1L, 1L,
IY 1L, : log not meaningful for factors
IY In addition:Warning messages:
IY
IY 1: In Ops.factor(LRUpBound, LRLowBound) : * not meaningful
Hi,
I'm working with a data.frame containing values between 0 and 22000.
Most of the values are actually between 0 and 50 and the high ones are
outliers.
I want to generate a boxplot and since the outliers are extremely
high, I need to scale the y scale logarithmically. Otherwise one
Indeed.
So is there no way to do that without passing an object as parameter,
which acts as a 'global local' workspace?
Isn't there a way to do say: run this function and subsequent calls
within this environment?
Gabor Grothendieck wrote:
A function finds its free variables in its
What about starting the data by adding some small amount to the 0's?
Perhaps something like
mysample - data.frame(aa = sample(c(A,B,C), 20, replace=TRUE),
bb = sample(0:9, 20, replace=TRUE))
ifelse(mysample$bb==0,.1, mysample$bb)
though you may wish to make .1
On 20/08/09 14:15, Anne Skoeries wrote:
Hi,
I'm working with a data.frame containing values between 0 and 22000.
Most of the values are actually between 0 and 50 and the high ones are
outliers.
I want to generate a boxplot and since the outliers are extremely
high, I need to scale the y scale
If your data is in a data frame named mydata and you want to print
the 3rd, 5th and 10th variables:
mydata[ , c(3,5,10) ]
-Don
At 12:38 AM -0700 8/20/09, rajclinasia wrote:
Hi every one,
I read one excel external file into R, in that R dataset i have 20
variables. now my querry is i want
It is a big file which is going to take some time to read. How long
probably depends as much on your disks as on R. On my system:
system.time( y - scan(file = /tmp/dat.txt, what = integer(0)) )
Read 12 items
user system elapsed
197.085 15.164 216.149
This is with a test file
I'm trying to create a histogram from the following code, but my data keeps
adding the Num vector and plotting that. My data in the CSV file is just
one vector. Does anyone know why?
Thanks
Conrad
SPXdf = data.frame(read.csv(file = SPX.csv, header = TRUE, sep = ,, dec
= ., fill = TRUE))
Max
Dear All!
I'm trying to extract one specific row from a data frame without columnnames
being included. I only want a 1-dimensional vector that consists of the
specific data on this row. Here's an example:
existing data:
column names: v1v2v3
Row 1 ab cd ef
Row 2 gh ij kl
Hi group,
I have the following error code after submitting library(wordnet) in a
standalone pc. rJava is already in place.
Error in .jpackage(pkgname,lib.loc=libname)
unused argument(s) (lib.loc=libname)
Error: .onLoad failed in 'loadNamespace' for 'wordnet'
Error: package/namespace load
I found that the syntax
ahnven wrote:
model=geeglm(y~covariates,offset(log(xxx)),data=data,family=poisson,id=idx)
indeed fits offset(log(xxx)) as weights.
--
View this message in context:
I saved an array of dim=c(28,28,28,28) using write.table. When I try to read
it in with read.table I get a data frame of dim=c(28,28^3).
Of course it is very important to preserve the structure of the saved array
when I read it in. Does anyone know how to read it in so that it is an array
of the
Dr Shen
Even though you pose 3 contrasts, there are only 2 degrees of freedom as
the 3rd contrast is the sum of the first two. Your aov output states this
as StdLot has only 2 df. Having used up your df, the aov has nothing to
report.
Joe
Joseph F. Lucke
Senior Statistician
Research
Assuming your data.frame has the name data, you would extract arbitrary
row n by
data[n, ]
Daniel
-
cuncta stricte discussurus
-
-Ursprüngliche Nachricht-
Von: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] Im
What you have is a one-dimensional vector.
I think that you are up against an R default. You are going to get some names
no matter what you do. You can always change them using the names() command,
e.g. names(xx) - c(a,b, c) to replace the v1 v2 v3
--- On Thu, 8/20/09, Henrik Kallberg
Hm
I still suppose that you do not need matrix as a top level object. If you
are sure there is only one level of nesting, e.g. in each node of the list
there is only one level of saved matrices, you can get summary
information from str, length and/or summary.
lll-list(a=1, b=2,
This is not a purely stats question as it depends on the implementation of
mixed models in R.
The help says that ordered factors are treated differently than unordered,
which is not very informative.
More explicitly: does ordering simply imply that February follows January or
that February has
It gave me a the following error
Error in cylinder3d(pts, radius = 0.1, e2 = rbind(c(1, 0, 0), c(1, 0, :
subscript out of bounds
The code I used is below for completeness.
library(rgl)
pts-structure(list(x = c(-0.975688, -0.975688), y = c(9.258795, -9.258795), z
= c(-1.8, 1.8)), .Names =
There may be a much cleaner and better way but just split the data.frame into
two parts, create the NA rows as another data.frame and use rbind to put them
back together again.
Example
#===
(mydata - data.frame(aa=letters[1:5],
Hi
r-help-boun...@r-project.org napsal dne 20.08.2009 15:33:38:
I'm trying to create a histogram from the following code, but my data
keeps
adding the Num vector and plotting that. My data in the CSV file is
just
one vector. Does anyone know why?
Well, I think that only you know why CSV
On Thu, Aug 20, 2009 at 10:57:52AM +0300, Lazarus Mramba wrote:
Dear Sir,
I am almost giving up on getting the R-2.9.1 on the ubuntu 9.04 using the
instructions found on the R site.
I decided to use the R-2.9.1.tar.gz and untarred it.
I then typed ./configure and the results are shown
Try this also:
as.data.frame(t(sapply(append(split(mydata, row.names(mydata)), list(c('f',
6)), after = 2), as.matrix)))
The after argument of append can be the line number where you want the new
line.
On Thu, Aug 20, 2009 at 8:18 AM, Moumita Das
das.moumita.onl...@gmail.comwrote:
Hi all,
Hi,
Here's one toy example that shows what I believe to be a problem with
plot.lm. This was brought up by another user (Marcos Tadeu Andrade
Cordeiro). I took a look at the source and the problem appears to be
related to the fact that you need to reorder the data by the group
means and
Rakknar ha scritto:
1. Make a log. I've been using Stata and there i have a great tool to
register what the program do: the log file, wich it's a simple .txt file
where Stata writes every output it makes (not graphics of course). When I
wanted to make the same thing with R I started to use the
For history of both commands and output, consider running R inside emacs
using the ESS package and simply saving the buffer to a file. If you save
the session as an S transcript file (extension .St) it is also easy to
reload and re-execute any part of it. Emacs or xemacs is available on most
Hello dear R-help group.
My task looks simple, but I can't seem to find a smart (e.g: non loop)
solution to it.
Task: I wish to randomize a data.frame by one column, while keeping the
inner-order in the second column as is.
So for example, let's say I have the following data.frame:
xx
On 8/20/2009 6:19 AM, Liviu Andronic wrote:
Dear all
I would like to globally set
options(digits = 4)
in an Sweave document. I've read this thread [1] where it was
suggested to set the above option and pass every printed number
through format(). Aanother way to do so would be to round(expr, 4).
On 8/20/2009 4:27 AM, Renaud Gaujoux wrote:
Hi,
in my project I want the user to be able to write hook functions that
are in turn called in my main code. I'd like the user's hooks to be able
to call some function that set a variable outside their running
environment.
The trick is that this
I'm having trouble achieving the results I want using a regular expression.
I want to eliminate all characters that fall within square brackets as well
as the brackets themselves, returning an . I'm not sure if it's R's use of
double slash escapes or something else that is tripping me up. If I
Bert:
Thanks for your help. I'll try to clarify some of your doubts
1. logs. help.search(history) and ?savehistory shows you that R does
exactly what you want very easily (depending on the platform, which contrary
to the posting guide's request, you did not tell us).
I've already find out
If I look in the stats package for the 'R' source code for predict.HoltWinters
I see the following lines:
vars - function(h) {
psi - function(j) object$alpha * (1 + j * object$beta) +
(j%%f == 0) * object$gamma * (1 - object$alpha)
var(residuals(object)) * if
Yes, I meant summary(). anova() isn't defined for aovlist objects and
summary() is.
Warning message:
In aov(kotz.mice ~ kotz.coon + block * veget * fruit * time -
block:veget:fruit:time + :
Error() model is singular
You will need to investigate the singular Error() model. You might
To echo what others have said, it is often easier to write a script (in
STATA terms, a do file) of commands and then source the script. When
it runs to your satisfaction, usually not the first time for me, there
are several ways to store the output. Both the R2HTML and prettyR
packages
How about this:
myCharVec - c([the rain in spain], (the rain in spain))
gsub('\\[.*\\]', '', myCharVec)
[1] (the rain in spain)
you had *. when you should have .*
On Thu, Aug 20, 2009 at 11:30 AM, Mark Kimpelmwkim...@gmail.com wrote:
I'm having trouble achieving the
Possibly just a typo:
gsub('\\[.*\\]', '', myCharVec)
^^
[1] (the rain in spain)
HTH,
-- David
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
On Behalf Of Mark Kimpel
Sent: Thursday, August 20, 2009 10:31 AM
Mark,
Try this:
myCharVec
[1] [the rain in spain] (the rain in spain)
gsub(\\[.*\\], , myCharVec)
[1] (the rain in spain)
You need two backslashes to escape the square brackets. The regular
expression \\[.\\] translates to a [ followed by 0 or more instances
of any
Put the objects that you want to save in a 'list' and then 'save' the
list. You can build up the contents of the list dynamically in your
program and then save it at the appropriate point.
On Thu, Aug 20, 2009 at 10:59 AM, Rakknaraliengene...@yahoo.com wrote:
To echo what others have said, it
Why not
if ( 0 ) {
commented with zero
} else {
commented with one
}
Greg Snow-2 wrote:
I believe that #if lines for C++ programs is handled by the preprocessor,
not the compiler. So if you want the same functionality for R programs,
it would make sense to just preprocess the R file.
Hi, Adrian-
If you use overwrite=T parameter, you will overwrite the entire table, not
each record. this is the essence of my problem and i still haven't found out
right solution. i am thinking of writing my own MySQLwriteTable function...
Thank you for your answer anyway!
Adrian Dusa
Dear all,
I am pleased to announce the CRAN release of a new package called 'KFAS' -
Kalman filter and smoother.
The package KFAS contains functions of multivariate Kalman filter,
smoother, simulation smoother and forecasting. It uses univariate approach
algorithm (aka sequential processing),
On 8/20/09, Duncan Murdoch murd...@stats.uwo.ca wrote:
Why not put
echo=FALSE=
options(digits=4)
@
somewhere near the top of your document?
I did so, but it has no practical effect on \Sexpr{} (which I'm
interested in, and failed to mention in the original e-mail).
With
echo=FALSE=
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