Dear All,
I want to connnect R with oracle. I am using RODBC package for this
connection. Following is my code to connect
library(RODBC)
channel - odbcConnect(Vikrant)
I am getting following error.
1: In odbcDriverConnect(DSN=Vikrant) :
[RODBC] ERROR: state NA000, code 12288, message
example:
y=(rbind(c(TRUE,TRUE,TRUE),c(FALSE,FALSE,FALSE)))
y
[,1] [,2] [,3]
[1,] TRUE TRUE TRUE
[2,] FALSE FALSE FALSE
as.numeric(y)
[1] 1 0 1 0 1 0
I am trying to make some important matrixes become nuemric (1 or 0) but they
change their dimensions.. anyone know how to easily fix
Hi All,
The last line if the following code returns the error right below this
paragraph. Essentially, I use the operator %:% to retrieve a variable
in a nested frame. Then I want to use the same operator (with '-') to
change its value. I'm not sure if this is possible in R with %:%
operator.
Hello All,
?environmentName shows how to get the environment name. But I don't
see how to set the name in the first place. Could you tell me where to
look for the function that set the environment name?
--
Tom
__
R-help@r-project.org mailing list
example:
y=(rbind(c(TRUE,TRUE,TRUE),c(
FALSE,FALSE,FALSE)))
y
[,1] [,2] [,3]
[1,] TRUE TRUE TRUE
[2,] FALSE FALSE FALSE
as.numeric(y)
[1] 1 0 1 0 1 0
I am trying to make some important matrixes become nuemric (1 or 0) but they
change their dimensions.. anyone know how to easily fix
Better moral: read the basic documentation. You missed matrix
indexing (indexing an array with a matrix subscript), and that is
described in 'An Introduction to R', section 5.3
E.g.
s$p - match(s$prefix, colnames(y))
y[cbind(s$idx, s$p)] - s$val
(You are trying to use different types of
In virtually every case where people think they need gobs of similarly-named
variables, what they really need are vectors or data frames. I strongly
recommend reading the Introduction to R document again to learn how to create
them and access individual elements and subsets of elements.Data
OK, I thought I was being explicit enough, but here goes. The out of the first
five rows of mu dataframe is:
Time hour lev.morgan lev.lock2 lev.lock1 flow direction
velocity bearingvelcat
1 2009-07-06 15:00:00 15 3.266 3.274 3.240 1710.6180.28
4.352
Hi Megan,
Answer for you third question. This function will return the maximum CCF
value along with corresponding lag value. Input to this function are a and b
which are nothing but two time series.
Find_Max_CCF- function(a,b)
{
d - ccf(a, b, plot = FALSE)
cor = d$acf[,,1]
lag =
Please help if anybody has got this error earlier. Or please explain how
should I use package RODBC to connect to oracle
--
View this message in context:
http://r.789695.n4.nabble.com/Error-while-connecting-to-Oracle-using-RODBC-package-tp2288304p2288389.html
Sent from the R help mailing list
Hi
r-help-boun...@r-project.org napsal dne 14.07.2010 00:44:02:
Hi, there:
Suppose I want create variables with indexes in their names, e.g.,
X_1_1,
X_1_2, X_1_3, ..., X_1_10, X_2_1, X_2_2, X_2_3, .. X_2_10,..., X_10_1,
X_10_2, ... X_10_10. It looks like I need to use 2 indexes I and J
Hi,
Thanks for the reproducible example.
as.POSIXlt(1982-01-01)
works fine for me. You did not specify which OS, R version etc you are
using, which is requested by the posting guide. If you haven't done so
already, please upgrade R to the latest version, this might help.
My info:
R version
OK, I thought I was being explicit enough, but here goes. The out of the first
five rows of mu dataframe is:
Time hour lev.morgan lev.lock2 lev.lock1 flow direction
velocity bearingvelcat
1 2009-07-06 15:00:00 15 3.266 3.274 3.240 1710.6180.28
4.352
Hi
r-help-boun...@r-project.org napsal dne 14.07.2010 07:54:51:
example:
y=(rbind(c(TRUE,TRUE,TRUE),c(FALSE,FALSE,FALSE)))
y
[,1] [,2] [,3]
[1,] TRUE TRUE TRUE
[2,] FALSE FALSE FALSE
as.numeric(y)
[1] 1 0 1 0 1 0
I am trying to make some important matrixes become nuemric
You want:
storage.mode(y) - numeric
as said, for instance, on page 49
of 'The R Inferno'.
On 14/07/2010 07:04, Felipe Bhering wrote:
example:
y=(rbind(c(TRUE,TRUE,TRUE),c(
FALSE,FALSE,FALSE)))
y
[,1] [,2] [,3]
[1,] TRUE TRUE TRUE
[2,] FALSE FALSE FALSE
as.numeric(y)
[1] 1 0
RR == Raubertas, Richard richard_rauber...@merck.com
on Tue, 13 Jul 2010 13:46:41 -0400 writes:
RR I agree that 'list' is a terrible package name, but only
RR secondarily because it is a data type. The primary
RR problem is that it is so generic
RR as to be almost totally
NC == Nai-Wei Chen s90225...@yahoo.com.tw
on Wed, 14 Jul 2010 05:20:09 +0800 (CST) writes:
(to both R-help and R-SIG-mixed-models; this is called
cross posting and not liked, even considered impolite.
I'm only replying to R-help ..)
NC Dear all R-users, When I install the package
Worik R wrote:
I have been examining the Mann-Whitney test closely. And there are two
features of the R implementation that puzzles me. The test statistic is
reported as W and depends on the order of the arguments to the function.
Why calculate U, or W, at all?
Did you read the note on
thmsfuller...@gmail.com wrote:
Hi All,
The last line if the following code returns the error right below this
paragraph. Essentially, I use the operator %:% to retrieve a variable
in a nested frame. Then I want to use the same operator (with '-') to
change its value. I'm not sure if this
On Wed, Jul 14, 2010 at 7:39 AM, thmsfuller...@gmail.com
thmsfuller...@gmail.com wrote:
Hi All,
The last line if the following code returns the error right below this
paragraph. Essentially, I use the operator %:% to retrieve a variable
in a nested frame. Then I want to use the same operator
Does anyone have any R code for computing the entropy of a simple
first or second order Markov chain, given a transition matrix something
like the following (or the symbol vector from which it is computed)?
AGRe ARIe CSRe DIRe DSCe eos
HRMe SPTe TOBe
Dear R community,
I have been perusing your mailing list (via Nabble) but have not been
able to find a suitable solution yet.
First of all, my aim would be to run R (or Rterm or Rscript)
interactively, while still being able to start the session with an
R-script and command line parameters.
I am trying to use Levene's test (of package car), but I do
not understand quite well how to use it. '?levene.test' does
not unfortunately provide any example. My data are in a data
frame and correspond to 1 factor plus response. Could
someone please give me an example about how to use the
On Wed, 2010-07-14 at 01:37 -0700, martanair wrote:
I am trying to use Levene's test (of package car), but I do
not understand quite well how to use it. '?levene.test' does
not unfortunately provide any example.
Err, yes it does, several examples in fact.
My data are in a data
frame and
On Wed, 2010-07-14 at 01:37 -0700, martanair wrote:
I am trying to use Levene's test (of package car), but I do
not understand quite well how to use it. '?levene.test' does
not unfortunately provide any example. My data are in a data
frame and correspond to 1 factor plus response. Could
Hi,
I find that the p-value printed out by wilcox.test() and the p-value
stored in the p.value attribute in the object returned by
wilcox.test() are not the same. There seems to be a lower limit of
2.2e-16 for the printed value although it does say that it is less
than that. What I want to know
Dear list,
I would like to know if there is a package in R which is able to set the
structure of the element of a list or dataframe in order to use xtable's
options without problems. I will do an example to be more clear:
if I have a list like this with the following element:
$ind1
Dear all,
Are there any functions in R to reverse the order of the string.
smth like reverse(abc) to get cba?
Thanks a lot.
[[alternative HTML version deleted]]
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On Wed, 2010-07-14 at 06:50 -0300, Bernardo Rangel Tura wrote:
On Wed, 2010-07-14 at 01:37 -0700, martanair wrote:
I am trying to use Levene's test (of package car), but I do
not understand quite well how to use it. '?levene.test' does
not unfortunately provide any example. My data are in
Hi,
I have searched a methode to rotate a dendrogramm with the leafs to the left
The dendrogram with the leafs to the bottom.
plot(hclust(dist(USArrests), ave))
plot from the dendrogram{stats} packages can rotate the dendrogram, but
only with the leafs to the right.
Hi,
I've no idea if there is a function for doing it, but if not, the
following seems to work
a = this is a string
paste(rev(substring(a,1:nchar(a),1:nchar(a))),collapse=)
Martyn
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
On Behalf Of
On Wed, 2010-07-14 at 12:13 +0200, Trafim Vanishek wrote:
Dear all,
Are there any functions in R to reverse the order of the string.
smth like reverse(abc) to get cba?
paste(rev(strsplit(abc, split = )[[1]]), collapse = )
[1] cba
If your real data is a vector of strings to reverse then
Dear R-users,
I have a problem with randomForest{outlier}.
After running the following code ( that produces a silly data set and builds
a model with randomForest ):
###
library(randomForest)
set.seed(0)
## build data set
X - rbind( matrix( runif(n=400,min=-1,max=1), ncol =
Hi
Quick glance to strsplit help page
strReverse - function(x) sapply(lapply(strsplit(x, NULL), rev), paste,
collapse=)
Regards
Petr
r-help-boun...@r-project.org napsal dne 14.07.2010 12:36:12:
On Wed, 2010-07-14 at 12:13 +0200, Trafim Vanishek wrote:
Dear all,
Are there any
On Wed, Jul 14, 2010 at 6:13 AM, Trafim Vanishek rdapam...@gmail.com wrote:
Dear all,
Are there any functions in R to reverse the order of the string.
smth like reverse(abc) to get cba?
Suppose data.frame DF has a column for which we wish to reverse each
component. Then using the builtin
What are some reliable R functions that can compute the value of a
convergent series?
David
--
David R. Bickel, PhD
Associate Professor
Ottawa Institute of Systems Biology
Biochem., Micro. and I. Department
Mathematics and Statistics Department
University of Ottawa
451 Smyth Road
Ottawa,
Hi
I am using igraph package in R.
My goal is to read a network (in pajek format) and decompose the network
into components.
In addition, I am also interested in sending this output to to a file.
I am having problem in while writing to a file!
my code looks like this
g - read.graph
Hi,
I have a data frame with several factors and I want to count the occurrences
of an event resulting from an interaction of some factors.
I tried to do several tables (and then converting to d.f and then merge them
by one factor and the freq
Tab1 - merge
Hallo!
Does anyone know a possibility to perform a sample size estimation for an
ANCOVA? Would be great!
Thanks
Karl
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R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
On 14-Jul-10 10:57:02, David Bickel wrote:
What are some reliable R functions that can compute the value of a
convergent series?
David
Please give an example of a definition (as you would specify it
to an R function) of a convergent series that you want to compute!
Your query is about as
Hi,
I have a data frame with several factors and I want to count the occurrences
of an event resulting from an interaction of some factors.
I tried to do several tables (and then converting to d.f and then merge them
by one factor and the freq
Tab1 - merge
Dear All,
does anybody know of a package (working under Linux) for multilevel IRT
modelling?
I'd love to do this without having to go on WINSTEPS or the like..
thanks for the attention!
Federico Andreis
-
Dr. Federico Andreis
Università degli Studi di Milano-Bicocca, PhD Student
MEB
Hi
You does not say much about what you really did. You probably want to
consult table or xtabs functions
xtabs(~Petal.Width+Species, data=iris)
Species
Petal.Width setosa versicolor virginica
0.1 5 0 0
0.2 29 0 0
On Tue, 13 Jul 2010, thmsfuller...@gmail.com wrote:
Hello All,
?environmentName shows how to get the environment name. But I don't
see how to set the name in the first place. Could you tell me where to
look for the function that set the environment name?
It is not AFAIK possible from R code.
What are some effective ways to leverage the strengths of R and
Mathematica for the analysis of a single data set?
More specifically, are there any functions that can assist with any of
the following?
1. Calling an R function from Mathematica.
2. Calling a Mathematica function from R.
3.
I am trying to use Levene's test (of package car), but I do
not understand quite well how to use it. '?levene.test' does
not unfortunately provide any example. My data are in a data
frame and correspond to 1 factor plus response. Could
someone please give me an example about how to use the
On 2010-07-14 6:07, martanair wrote:
I am trying to use Levene's test (of package car), but I do
not understand quite well how to use it. '?levene.test' does
not unfortunately provide any example. My data are in a data
frame and correspond to 1 factor plus response. Could
someone please give me
On Wed, 2010-07-14 at 05:07 -0700, martanair wrote:
I am trying to use Levene's test (of package car), but I do
not understand quite well how to use it. '?levene.test' does
not unfortunately provide any example. My data are in a data
frame and correspond to 1 factor plus response. Could
On Wed, Jul 14, 2010 at 7:53 AM, Prof Brian Ripley
rip...@stats.ox.ac.uk wrote:
On Tue, 13 Jul 2010, thmsfuller...@gmail.com wrote:
Hello All,
?environmentName shows how to get the environment name. But I don't
see how to set the name in the first place. Could you tell me where to
look for
the value of the F-test is uncorrect.
If I calculate the Levene's Test for Homogeneity of Variance with SPSS I get
F = 5.128 Pr ( F) = 0.033
Why?
what is the exact formula which R calculate Levene's test for two groups?
Thanks
marta
--
View this message in context:
On 2010-07-14 4:04, chakri_amateur wrote:
Hi
I am using igraph package in R.
My goal is to read a network (in pajek format) and decompose the network
into components.
In addition, I am also interested in sending this output to to a file.
I am having problem in while writing to a file!
my
On Wed, 2010-07-14 at 05:47 -0700, martanair wrote:
the value of the F-test is uncorrect.
If I calculate the Levene's Test for Homogeneity of Variance with SPSS I get
F = 5.128 Pr ( F) = 0.033
Why?
what is the exact formula which R calculate Levene's test for two groups?
Thanks
marta
Who
Dear Marta,
As it says in ?levene.test, The version of Levene's test implemented here
is based on absolute deviations from the group medians. Other, less robust,
versions, not implemented, are based on absolute deviations from group means
or trimmed means. What does SPSS do? (Possibly it uses
R Code begins
unem=read.csv(book5.csv,header=T,row.names=1)
attach(unem)
unem1=ts(unem$Allen, start=1)
ts.plot(unem1,main=Allen)
points(unem1,type=o)
R Code ends
because the time starts at JAN_08 and ends on DEC_09, how to make the
y axis in the plot show month starting from JAN_08 instead of
On 2010-07-14 3:53, Govind Chandra wrote:
Hi,
I find that the p-value printed out by wilcox.test() and the p-value
stored in the p.value attribute in the object returned by
wilcox.test() are not the same. There seems to be a lower limit of
2.2e-16 for the printed value although it does say that
R Code begins
unem=read.csv(book5.csv,header=T,row.names=1)
attach(unem)
unem1=ts(unem$a, start=1)
ts.plot(unem1,main=a)
points(unem1,type=o)
R Code ends
because the time starts at JAN_08 and ends on DEC_09, how to make the
y axis in the plot show month starting from JAN_08 instead of having
the
On 2010-07-14 6:47, martanair wrote:
the value of the F-test is uncorrect.
If I calculate the Levene's Test for Homogeneity of Variance with SPSS I get
F = 5.128 Pr ( F) = 0.033
Why?
Why do you assume that SPSS provides the correct value?
what is the exact formula which R calculate
barbara horta e costa wrote:
I have a data frame with several factors and I want to count the
occurrences
of an event resulting from an interaction of some factors.
I'd only need a table as excel does with pivot table and summarize data as
count
Only what pivot tables does: Pivot
On Jul 14, 2010, at 6:13 AM, Karl Knoblick wrote:
Hallo!
Does anyone know a possibility to perform a sample size estimation for an
ANCOVA? Would be great!
Thanks
Karl
I don't know of a function in R that performs this directly. However, if you
Google:
You do not provide a reproducible example, as the posting guide asks you
to. But I guess that your time series setup using ts() is insufficient,
see ?ts. If the data starts in January 2008, why do you tell R that it
starts in 1? Presumably you have monthly data and
unem1 - ts(unem$a, start
On Jul 13, 2010, at 11:57 PM, vikrant wrote:
Dear All,
I want to connnect R with oracle. I am using RODBC package for this
connection. Following is my code to connect
library(RODBC)
channel - odbcConnect(Vikrant)
I am getting following error.
1: In odbcDriverConnect(DSN=Vikrant) :
Hi Dennis,
Thanks for the quick reply.
Once I removed solid = TRUE, which was giving errors, the code is accepted
fine.
It's strange though, no legend appears. Even when I try something simple
like:
p + scale_shape_manual(values=1:3)
No legend appears. I can't find any similar problems on
Fahim,
Please see the Writing R Extensions manual
http://cran.r-project.org/doc/manuals/R-exts.pdf
There are simple instructions in this document under the heading System
and foreign language interfaces.
-Matt
On Wed, 2010-07-14 at 01:21 -0400, Fahim Md wrote:
Hi,
I am trying to call a C
how do I calculate the differences from the mean?
levene.test(filedati$y , filedati$fertilizzante, location=mean)
Is it right?
regards
marta
--
View this message in context:
http://r.789695.n4.nabble.com/levene-test-tp2288632p2288832.html
Sent from the R help mailing list archive at
On Jul 14, 2010, at 6:59 AM, David Bickel wrote:
What are some effective ways to leverage the strengths of R and Mathematica
for the analysis of a single data set?
More specifically, are there any functions that can assist with any of the
following?
1. Calling an R function from
Take a look at Sage, which is an open source alternative. It already
integrates R (http://www.sagemath.org)
albyn
Quoting David Bickel davidbickel.com+rh...@gmail.com:
What are some effective ways to leverage the strengths of R and
Mathematica for the analysis of a single data set?
Thanks, Ted. I meant to post this previous reply to the list:
On 10-07-14 07:43, David Bickel wrote:
Hi Ted,
Here are my translations to integrate-like syntax of a conflation of
examples from the following Mathematica pages:
x - 2.232; sum(f = function(n) {x^n/factorial(n)}, lower = 0, upper
Hi,
Can you show the results of str() on your original dataframe? Also it
would help if you could make an example that demonstrates your
problem. I used this little example, and did not notice any problems:
samp.frame - data.frame(a = 1:10, b = c(3,2,5,3,1,5,NA,4,5,NA))
str(samp.frame)
I am trying to use the mi package to impute data, but am running into
problems with the functions it calls.
For instance, I am trying to impute a categorical variable called
min.func. The mi() function calls the mi.categorical() function to
deal with this variable, which in turn calls the
Hi all, can somebody help me to split a time series (zoo) object on monthwise.
For example, suppose I have following time series object:
library(zoo)
dat1 - zooreg(rnorm(300), start=as.Date(2009-01-01), frequency=1)
From dat1, I want to create a list-object dat2 like:
dat2[[1]] - all
The transition matrix is a collection of conditional distributions.
it would seem natural to compute the entropy of the stationary
distribution.
albyn
Quoting Wilson, Andrew a.wil...@lancaster.ac.uk:
Does anyone have any R code for computing the entropy of a simple
first or second order
Hello Jack,
1 ) why do you thought that larger C is prone to overfitting than smaller
C ?
2 ) if you look at the formulation of the quadratic program problem you will
see that C rules the error of the cutting plane ( and overfitting ).
Therfore for hight C you allow that the cutting plane
On Wed, 14 Jul 2010, Megh Dal wrote:
Hi all, can somebody help me to split a time series (zoo) object on monthwise.
For example, suppose I have following time series object:
library(zoo)
dat1 - zooreg(rnorm(300), start=as.Date(2009-01-01), frequency=1)
From dat1, I want to create a
Ggplot will only produce legends based on factors. Integers are not factors.
Ian Bentley ian.bent...@gmail.com wrote:
Hi Dennis,
Thanks for the quick reply.
Once I removed solid = TRUE, which was giving errors, the code is accepted
fine.
It's strange though, no legend appears. Even when I try
Dear Marta,
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
On
Behalf Of martanair
Sent: July-14-10 10:21 AM
To: r-help@r-project.org
Subject: Re: [R] levene.test
how do I calculate the differences from the mean?
Hi,
Thanks a lot.
here is a fraction of my df:
Sample Season Area Gear Depth
1 W 1 5 1
2 Sp 1 3 1
2 Sp 1 5 1
2 Sp 1 11 1
Hello there,
is there a way to update a model, which was called by bugs()? For
instance starting with few iterations and then updating more and more,
as is possible inside the WinBUGS-window. If set debug=TRUE, then the
window remains open and updating is possible, but it is no longer
Hi everyone:
I did a search over the internet and still couldn't find answer to my problem.
I have a series of prices that I'm trying to clean up by removing any
prices greater than 3 times the standard deviations. So, say that
prices are:
price1
2010-06-18 08:00:06.916
Hi,
I used str() on my data set:
$ X1: num 1 1 0 1 1 1 1 1 1 1 ...
$ X2: num 0 1 0 2 1 2 0 2 2 0 ...
$ X3: Factor w/ 4 levels 0,1,2,NA: 2 1 3 1 1 1 1 1 1 3
...
The difference to your str() output is that in your case NA columns are
num columns
and in
Please, tell what is the best way to create an R glm object with parameters etc
estimated in SAS?
I have a large dataset and bigglm fails to converge, so estimation is done is
SAS. However, there are a lot of predictions that are much more easily done in
R and I would like to use glm.predict
Hi,
I just installed version 2.11.1 on my Mac OS X 10.5.2. When I try
running R from my xterm, I get the following error:
Error in loadNamespace(name) : there is no package called 'lme4'
Fatal error: unable to restore saved data in .RData
I am returned to the terminal prompt and can not run
I figured this one out. I'm sending the solution back to the help
list so that there is a record of how to deal with this problem, since
it does not seem to be documented elsewhere.
The mi.info object that you pass to the the mi() function contains a
value called params which allows you
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
On Behalf Of Marc Schwartz
Sent: Wednesday, July 14, 2010 7:05 AM
To: vikrant
Cc: r-help@r-project.org
Subject: Re: [R] Error while connecting to Oracle using RODBC package
On Jul 13,
Well, as the author of two CRAN packages with short names (tis and
fame), I maintain that short names can be fairly informative. The fame
package is an interface to FAME time series databases, and the tis
package implements the tis (TimeIndexedSeries) class and support classes
that it needs.
Hi Peter,
Thanks for your response. Yes, I am interested in P-values smaller
than 1e-16. Below a certain value they may not tell much about
significance but are useful for ordering (ranking), for example,
differentially expressed genes in microarray data. Something similar
is done by sequence
Dear all,
how can I use R on a 64-bit Windows Server 2003 machine (24GB RAM) with more
than 3GB of working memory and make full use of it.
I started R --max-mem-size=3G since I got the warning that larger values are
too large and ignored.
In R I got:
memory.size(max=FALSE)
[1] 10.5
More importantly than just that they are factors, NA is actually a
level of X3. If it was a factor column, but NA was not a level, than
in the conversion to numeric, it would not change into a 4, but it is
a level (in fact the 4th level), so it becomes a 4. From ?factor here
is the recommended
Hi,
I can't seem to install R from source. I've downloaded the latest
Rtools211.exe from http://www.murdoch-sutherland.com/Rtools/ done a
full installation of that and Inno Setup.
I have set R_HOME as C:\R (and also tried using C:\R\R-2.11.1)
After successfully running 'tar xf
You need to understand the difference between how a value is stored in an R
object with full floating point precision versus how a value in R is displayed
(printed) in the console with a print method.
In this case, wilcox.test() returns an object of class 'htest' (as noted in the
Value section
On Wed, Jul 14, 2010 at 11:17 AM, Andrea Foulkes
foul...@schoolph.umass.edu wrote:
Hi,
I just installed version 2.11.1 on my Mac OS X 10.5.2. When I try running R
from my xterm, I get the following error:
Error in loadNamespace(name) : there is no package called 'lme4'
Fatal error: unable
Thanks again for your quick reply.
I understood your procedure but now it is even more strange why my
conversion does not work.
In your example, the NA values are in brackets NA and what your
procedure does is to
convert these NA values into NA and then it seems to be possible to use
data.matrix
On Wed, Jul 14, 2010 at 05:51:17PM +0200, will.ea...@gmx.net wrote:
Dear all,
how can I use R on a 64-bit Windows Server 2003 machine (24GB RAM) with more
than 3GB of working memory and make full use of it.
I started R --max-mem-size=3G since I got the warning that larger values are
too
Frédéric Holzwarth frederic.holzwarth at uni-leipzig.de writes:
Hello there,
is there a way to update a model, which was called by bugs()? For
instance starting with few iterations and then updating more and more,
as is possible inside the WinBUGS-window. If set debug=TRUE, then the
On Jul 14, 2010, at 10:17 AM, Andrea Foulkes wrote:
Hi,
I just installed version 2.11.1 on my Mac OS X 10.5.2. When I try running R
from my xterm, I get the following error:
Error in loadNamespace(name) : there is no package called 'lme4'
Fatal error: unable to restore saved data in
I'm using R x64 2.11.0(windows)
I was trying to load workspace I saved some days ago, but got the
error:
ReadItem: unknown type 63, perhaps written by later version of R.
Has anyone come across the same problem? Any solutions?
Many thanks
yan
syrvn wrote:
Thanks again for your quick reply.
I understood your procedure but now it is even more strange why my
conversion does not work.
In your example, the NA values are in brackets NA and what your
procedure does is to
convert these NA values into NA and then it seems to be possible to
Hello R community:
Here is another question,
How can I estimate a differential equation parameters based on a data set?
If you know where I can find some examples will be better,
Thanks again, and cheers,
Oscar Rodriguez Gonzalez
Mobile: 519.823.3409
PhD Student
Canadian
On 14/07/2010 12:01 PM, Steve Pederson wrote:
Hi,
I can't seem to install R from source. I've downloaded the latest
Rtools211.exe from http://www.murdoch-sutherland.com/Rtools/ done a
full installation of that and Inno Setup.
I have set R_HOME as C:\R (and also tried using C:\R\R-2.11.1)
Hi all,
Maybe I missed some crucial context (I did not follow the example all
the way through). But of course ggplot will make legends based on
integers. For example:
dat - data.frame(x=sample(1:10, 100, replace=TRUE),
y=sample(1:10, 100, replace=TRUE),
id pID50 apol a_acca_acid a_aro a_base a_count
1 mol.11 3.63 -0.882267 -0.527967 -0.298197 -1.032380 0 -1.063410
2 mol.14 3.38 -1.007330 -0.527967 -0.298197 -1.032380 0 -1.063410
3 mol.19 3.18 1.153560 1.407910 -0.298197 1.254100 0 1.160080
4 mol.20
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