Hello,
I'm using R2.10 on Windows 2000 and I'm having trouble installing the 'hash'
library. This is the error I get:
library(hash)
_ _
___ _ __ ___ _ __ __| | __ _| |_ __ _
/ _ \| '_ \ / _ \ '_ \ / _` |/ _' | __/ _' |
| (_) | |_) | __/ | | |
Hi again List:
This time I have the following:
setClass(dog,representation(breed=numeric))
[1] dog
woof - function(x=1:10) {
+ if(!is.numeric(x))stop(Must have numeric data)
+ y - new(dog,breed=x)
+ return(y)
+ }
setMethod(plot,dog,
+ function(x,y,...) {
+ plot(x@breed,col=blue,type=l)
+ }
+ )
Thanks Dennis,
The code works for perfectly for the data in the example. For some reason,
however, I get the following error message when I use a different data set:
preds - expand.grid(age = c(30,36,42), Subject = unique(mydata$id))
predict(lmemodel, preds, na.action=na.omit)
Error in
Thank you so much for your help Dennis, Pete and D Kelly!
In the meantime I tried to do a loop and came up with this:
l-0
for (i in 0:((length(lakewil$Year)/12)-1)) {
l[i+1]- mean(lakewil$MeanTemp[((i*12)+7):((i*12)+9)])
}
print(l)
This gives me the summer averages over the 3 months for each
I really appreciate your help Prof Harrell!
I followed your instruction and re-ran the second model without strat but
with surv=TRUE, time.inc=30, and u=30 to validate, the Dxy was really the
same as that in the first model output! But this confused me...shouldn't the
Dxy be positive in this
On Tue, 22 Feb 2011, Albert-Jan Roskam wrote:
Hello,
I'm using R2.10 on Windows 2000 and I'm having trouble installing the 'hash'
We've not seen that for a long time, and as Microsoft no longer
supports it, we don't test there.
library. This is the error I get:
library(hash)
I have seen this issue reported by others though I don't know what the
root cause is. Others have solved it by removing the .Rdata file
causing the problem (there must be one if it says so). It would
usually, I think, be in the folder where you start R.
Regards,
Graham
On 20 February 2011
Hi List,
Does any body know how I can see the code behind qbeta function?
thanks
Alireza
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
Hi,
I am looking for some help regarding the use of the mle function.
I am trying to get mle for 3 parameters (theta0, theta1 and theta2) that
have been defined in the the log-likelihood equation as theta0=theta[1],
theta1=theta[2] and theta2=theta[3].
My R code for mle is:
mle(Poisson.lik,
Hi,
I am fitting a random effects model and I am interested in the 95%
confidence interval of the variance components.
When I use the intervals() command it gives me the 95% confidence interval
of the standard deviation. Is there anyway of getting the 95% confidence
interval of the variance?
Vanessa Francisco vanewagen at gmail.com writes:
Hello! I'm a PhD student working with coral reef fish diversity in Mexico.
I want to do species accumulation curves but I have differential sampling
effort for each sample.
Do you know or have developed an R script that consider the
Hi
When we use the sav_gol command in R , it shows an error which says:
error in as.matrix. We've downloaded the necessary packages. Kindly
help us with this issue. If there is any other function to perform
Savitzky-Golay smoothing in R, please let me know.
With Regards
Reynolds
Hi,
I am looking for some help regarding the use of the mle function.
I am trying to get mle for 3 parameters (theta0, theta1 and theta2) that
have been defined in the the log-likelihood equation as theta0=theta[1],
theta1=theta[2] and theta2=theta[3].
My R code for mle is:
mle(Poisson.lik,
-BEGIN PGP SIGNED MESSAGE-
Hash: SHA1
On 02/22/2011 10:49 AM, Graham Williams wrote:
I have seen this issue reported by others though I don't know what the
root cause is. Others have solved it by removing the .Rdata file
causing the problem (there must be one if it says so). It would
Dear all,
I would like to estimate a system of regression equations of the following
form:
y1 = a1 + b1 x1 + b2x2 + e1
y2 = a2 + c1 y1 + c2 x2 + c3 x3 + e2
Specifically the dependent variable in Equation 1 appears as an independent
variable in Equation 2. Additionally some independent variables
Hi Group,
I am having a strange problem for this simple task.
I am using read.table to read a plan 3 column CSV file . the file is getting
read .
But the first column has datetime in the csv file in the following format:
20110221.114041
But this is being read as 20110221 only . the
Hi Matthew, thanks for your help. There are some things going wrong still.
Consider this (slightly extended) example:
library(data.table)
DT = data.table(read.table(textConnection(A B C
1 1 a 1999
2 1 b 1999
3 1 c 1999
4 1 d 1999
5 2 c 2001
6 2 d 2001
7 3 a 2004
8 3
I am using read.table to read a plan 3 column CSV file . the file is getting
read .
But the first column has datetime in the csv file in the following format:
20110221.114041
But this is being read as 20110221 only . the time portion (decimal is
missing) in the data frame
My guess is
On Tue, Feb 22, 2011 at 10:09:51AM +, Dr. Alireza Zolfaghari wrote:
Hi List,
Does any body know how I can see the code behind qbeta function?
As the code seems to be internal, you'll need to download the r-source
code and find it in there. In my copy of R it is here:
Dear David,
short answer: no. Although an MA(4) correlation structure makes perfect
sense in an econometric panel model, the treatment of (relatively) rich
covariance structures in a likelihood framework is done so well in the
'nlme' and 'lme4' packages that we decided not to duplicate
Does any body know how I can see the code behind qbeta function?
As the code seems to be internal, you'll need to download the r-source
code and find it in there. In my copy of R it is here:
R-2.11.1/src/nmath/qbeta.c
An alternative is to view the source code online. The code for qbeta is
reynolds pravindev reynoldspravindev at gmail.com writes:
Hi
When we use the sav_gol command in R , it shows an error which says:
error in as.matrix. We've downloaded the necessary packages. Kindly
help us with this issue. If there is any other function to perform
Savitzky-Golay smoothing
On 22.02.2011 09:15, Laura Smith wrote:
Hi again List:
This time I have the following:
setClass(dog,representation(breed=numeric))
[1] dog
woof- function(x=1:10) {
+ if(!is.numeric(x))stop(Must have numeric data)
+ y- new(dog,breed=x)
+ return(y)
+ }
setMethod(plot,dog,
+
With the new example, what is the full output, and
what do you need instead? Was it correct for the
previous example?
Matthew
mathijsdevaan mathijsdev...@gmail.com wrote in message
news:1298372018181-3318939.p...@n4.nabble.com...
Hi Matthew, thanks for your help. There are some things going
Use colClasses to specify that the column is character so you don't
lose any significance. You are close to the 15 digits of significance
for a floating point number.
On Tue, Feb 22, 2011 at 6:08 AM, Santosh Srinivas
santosh.srini...@gmail.com wrote:
Hi Group,
I am having a strange problem
Hi
I want to have a rectangular plot of size 0.5*0.3 inches. I am having
surprisingly a difficult time to do it... Since I will export it, I use
also pdf(). The plot works fine, but once I specify the size in pdf() I
get problems... see:
Say I specify my plot as following:
par(pin=c(0.5,
On 02/22/2011 10:34 AM, reynolds pravindev wrote:
Hi
When we use the sav_gol command in R , it shows an error which says:
error in as.matrix. We've downloaded the necessary packages. Kindly
help us with this issue. If there is any other function to perform
Savitzky-Golay smoothing in R,
Dear All,
I'm looking an appropriate way in R to compute/estimate points of intersection
between a line and a curve and will really appreciate for any suggestion or
ideas?
Thank you,
Fir
__
R-help@r-project.org mailing list
Hi Dennis and [R]users!
as I said last week, I need more info about xyplot.
Is it possible to change the color of the intestation of xyplot? By default is
pale-pink, but light-gray is better for a paper.
Thanks,
Francesco
From: nutini.france...@gmail.com
To: djmu...@gmail.com
CC:
Hello
Is it possible to get summary statistics (inc mean, sd etc) from a
text file that has the following info stored in it?
Height Frequency
123 5
124 8
125 3
126 9
127 7
etc etc
Dear Jari,
For what it's worth, I could see the need in my own work for species
accumulation curves with variable sampling effort.
Scott Chamberlain
On Tuesday, February 22, 2011 at 2:26 AM, Jari Oksanen wrote:
Vanessa Francisco vanewagen at gmail.com writes:
Hello! I'm a PhD student
On 22.02.2011 12:27, FMH wrote:
Dear All,
I'm looking an appropriate way in R to compute/estimate points of intersection
between a line and a curve and will really appreciate for any suggestion or
ideas?
Sounds like second level school homework. If not, please explain your
problem in more
The output for the new example should be:
project v
1 0
2 0.5
3 1.5
4 0.5
The output you calculated was correct for the v per year, but the v per
group would be incorrect. I think the problem lies in the fact that
expand.grid(B,B) doesn't take into account that combinations of B can only
From: ui...@hotmail.it
To: djmu...@gmail.com
CC: r-help@r-project.org
Subject: RE: [R] [r] align xyplot
Date: Tue, 22 Feb 2011 12:23:55 +
Hi Dennis and [R]users!
as I said last week, I need more info about xyplot.
Is it possible to change the color of the intestation of xyplot? By
I think it should be the negative of the first Dxy but this is all why the
posting guide says to create the simplest self-defined example that shows
the problem. That way I could run it and get to the bottom of this. See
the help file for cph which has examples of simulating test data. Try to
What about using read.table() and applying summary() on the result?
Uwe Ligges
On 22.02.2011 13:20, Daniel Harris wrote:
Hello
Is it possible to get summary statistics (inc mean, sd etc) from a
text file that has the following info stored in it?
Height Frequency
123
Daniel, how is the data stored? The answer to your question may be as
simple as
df - read.csv(filename.csv)
summary(df)
See ?read.csv for info on reading various file formats.
HTH, Bryan
Prof. Bryan Hanson
Dept of Chemistry Biochemistry
DePauw University
602 S. College
What you are describing is a path model (e.g., http://bit.ly/f4siTs). You can
fit such a model with the sem package
(http://cran.r-project.org/web/packages/sem/index.html).
Best,
--
Wolfgang Viechtbauer
Department of Psychiatry and Neuropsychology
School for Mental Health and Neuroscience
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On 02/22/2011 02:33 PM, Mike Marchywka wrote:
Date: Tue, 22 Feb 2011 11:12:26 +0100
From: r.m.k...@gmail.com
To: graham.willi...@togaware.com
CC: r-help@r-project.org
Subject: Re: [R]
Sorry, I mean heading.
Thanks for the tip.
Francesco
CC: djmu...@gmail.com; r-help@r-project.org
From: dwinsem...@comcast.net
To: ui...@hotmail.it
Subject: Re: [R] [r] align xyplot
Date: Tue, 22 Feb 2011 08:33:07 -0500
I don't know the term intestation, but from context it appears you
Dear mailing list,
I am using the cforest() method from the party package to train a
randomForest with ten input parameters which sometimes contain NAs.
The predicted variable is a binary decision. Building the tree works
fine without warnings or error messages, but when using the predict()
Date: Tue, 22 Feb 2011 11:12:26 +0100
From: r.m.k...@gmail.com
To: graham.willi...@togaware.com
CC: r-help@r-project.org
Subject: Re: [R] problem installing R in Ubuntu 10.04 -HELP
-BEGIN PGP SIGNED MESSAGE-
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On 02/22/2011
Hi all,
When I detect the spatial point pattern, I want to use the Cramer-von Mises
statistic to assess the curve-wise significance of deviations from null
hypotheses. Who can tell me which function in R package Spatstat can do
this work?
Thanks a lot
Jeff
[[alternative HTML version
I don't know the term intestation, but from context it appears you
might need:
?trellis.par.set
--
David.
On Feb 22, 2011, at 7:23 AM, Francesco Nutini wrote:
Hi Dennis and [R]users!
as I said last week, I need more info about xyplot.
Is it possible to change the color of the intestation
--- On Tue, 2/22/11, D Kelly O'Day ko...@processtrends.com wrote:
From: D Kelly O'Day ko...@processtrends.com
Subject: Re: [R] Calculate a mean for several months for several years
To: r-help@r-project.org
Received: Tuesday, February 22, 2011, 12:21 AM
Pete
The original question I
Yes John
My editing mistake. Thanks!!
--
View this message in context:
http://r.789695.n4.nabble.com/Calculate-a-mean-for-several-months-for-several-years-tp3318363p3319272.html
Sent from the R help mailing list archive at Nabble.com.
__
I am having problems with forward prediction using the output of the
Basic Structural Model from StructTS. The following snippet
illustrates the problem:
t_end - 139
nahead - 20
data(AirPassengers)
ap - log10(AirPassengers)-2
fit - StructTS(ts(ap[1:t_end], freq=12), type=BSM)
p -
library(zoo)
library(tseries)
library(quantmod) #for access to FRED
require(quantmod)
require(TTR)
secA - getSymbols(DEXUSEU,src=FRED)
secB - getSymbols(DEXUSUK,src=FRED)
secA - zoo(DEXUSEU[,1])
secB - zoo(DEXUSUK[,1])
t.zoo - merge(secA, secB, all=FALSE)
t - as.data.frame(t.zoo)
cat(Date
Hey there,
I tried to count the number of rows, where my data isn't NaN in a
certain column.
this was my guess:
(given is a data frame with 2069 rows and 17 cols)
NROW(data[jan,16] != NaN)
(jan is defined this way: jan - which(data[,2]==1, arr.ind= TRUE))
but I only get the number of
On Mon, Feb 21, 2011 at 10:06 PM, dadrivr dadr...@gmail.com wrote:
Thanks Dennis,
The code works for perfectly for the data in the example. For some reason,
however, I get the following error message when I use a different data set:
preds - expand.grid(age = c(30,36,42), Subject =
Date: Tue, 22 Feb 2011 14:53:07 +0100
From: r.m.k...@gmail.com
To: marchy...@hotmail.com
CC: graham.willi...@togaware.com; r-help@r-project.org
Subject: Re: [R] problem installing R in Ubuntu 10.04 -HELP
-BEGIN PGP SIGNED MESSAGE-
Hi,
I have the following input file.
$ cat main.txt
CEL_A CELL_B
1 4
2 5
2 6
Then I run read.table in R.
f=read.table('main.txt', header=T, check.names=F, sep='\t')
head(f)
\ufeffCEL_A CELL_B
11 4
22 5
32 6
f$CEL_A
NULL
I'm not sure where the special character
Sandra,
Please provide a small, reproducible example of this issue.
You probably want to use ?is.nan and not the inequality
operator.
Similar example, contrast:
x - NA
is.na(x)
x == NA
Sandra Stankowski wrote:
Hey there,
I tried to count the number of rows, where my data isn't NaN in a
On 2011-02-22 05:53, Francesco Nutini wrote:
Sorry, I mean heading.
Thanks for the tip.
I'm not quite certain what you mean by heading,
but it sounds to me as though you might want
xyplot( ... your stuff ...,
par.settings = list(
strip.background = list(col =
?is.nan
Peter Ehlers
On 2011-02-22 07:11, Sandra Stankowski wrote:
Hey there,
I tried to count the number of rows, where my data isn't NaN in a
certain column.
this was my guess:
(given is a data frame with 2069 rows and 17 cols)
NROW(data[jan,16] != NaN)
(jan is defined this way: jan-
Hi Sandra,
What about ?is.na function ?
Hope this help
Regards,
ML
Le 22/02/11 16:11, Sandra Stankowski a écrit :
NROW(data[jan,16] != NaN)
--
Mohamed Lajnef,IE INSERM U955 eq 15#
Pôle de Psychiatrie#
Hôpital CHENEVIER
On 22/02/2011 10:43 AM, John Edwards wrote:
Hi,
I have the following input file.
$ cat main.txt
CEL_A CELL_B
1 4
2 5
2 6
Then I run read.table in R.
f=read.table('main.txt', header=T, check.names=F, sep='\t')
head(f)
\ufeffCEL_A CELL_B
11 4
22 5
32 6
What you describe could be a bug (in which case providing your OS and R version
info per the posting guidelines would be a minimum requirement to get it fixed)
or a control character that is actually in your file (which you might need a
binary editor to see).
On Tue, Feb 22, 2011 at 7:43 AM, John Edwards jhnedwards...@gmail.com wrote:
Hi,
I have the following input file.
$ cat main.txt
CEL_A CELL_B
1 4
2 5
2 6
Then I run read.table in R.
f=read.table('main.txt', header=T, check.names=F, sep='\t')
head(f)
\ufeffCEL_A CELL_B
1 1 4
To R community:
I've been pulling my hair for the past few days over this issue now, and I
may be at the point where I just can't spot my error. So I thought to reach
out to the community and hope someone could kindly help me.
I'm trying to create a correlation matrix and plot it. However, I'm
Thanks for all the people that replied my message. The text file indeed has
\uFEFF. I have fixed the text file by using 'gvim -b'.
On Tue, Feb 22, 2011 at 10:03 AM, Jeff Newmiller
jdnew...@dcn.davis.ca.uswrote:
What you describe could be a bug (in which case providing your OS and R
version
Did you try
RSiteSearch(QuadTree)
?
It does seem to give some hits.
On Sun, Feb 20, 2011 at 7:54 PM, Jaimin Dave davejaim...@gmail.com wrote:
Could any one tell me how to implement QuadTree in R?
Or are there any packages avaialble to implement it in R.
[[alternative HTML version
Sandra Stankowski wrote:
is.na function does'nt seem to work, but maybe I'm just dealing with it
in a wrong way.
here's an example
m - c(2, 3, 5, 6, 3, 7, -99, -99, 6)
n - c(1,1,1,1,1,2,2,2,2)
so my matrix contains certain missing values
Thank you for the example.
You're constructing
did you try
RSiteSearch(t-regression)
?
That seems to give some usefull hits.
On Mon, Feb 21, 2011 at 7:42 AM, Rosario Garcia Gil
m.rosario.gar...@slu.se wrote:
Hello
I have a data set with outlier and it is not normally distributed. I would
instead like to use a more robust distribution
On Mon, Feb 14, 2011 at 12:22 PM, mathijsdevaan mathijsdev...@gmail.com wrote:
Hi,
I have a large dataset with info on individuals (B) that have been involved
in projects (A) during multiple years (C). The dataset contains three
columns: A, B, C. Example:
A B C
1 1 a 1999
2 1 b
Dear all,
I need to perform a two-way unbalanced ANOVA on my data set. The unbalancing
is due to missing values (NA) for some subjects. My data set concerns the
evaluation of 4 different prototypes tested by subjects three times and it
is organized as follows (column by column):
number of
On 2011-02-21 02:42, Rosario Garcia Gil wrote:
Hello
I have a data set with outlier and it is not normally distributed. I would
instead like to use a more robust distribution like t-distribution.
My question is if the coefficients of the regression are different from zero,
but assuming a
Thanks for the replies
The file is below
Height Frequency
62 3
63 20
64 24
65 40
66 85
67 122
68 139
69 179
70 139
71 107
72 55
73 47
74 22
75 12
76 5
77 1
I use the following
data - read.table(file,header=T)
is.na function does'nt seem to work, but maybe I'm just dealing with it
in a wrong way.
here's an example
m - c(2, 3, 5, 6, 3, 7, -99, -99, 6)
n - c(1,1,1,1,1,2,2,2,2)
so my matrix contains certain missing values
m[m==-99] - NA
o - data.frame(m, n)
o
m n
1 2 1
2 3 1
3 5 1
4 6 1
5
Thanks.
I made it!
Best wishes,
S.
Am 22.02.2011 17:41, schrieb Erik Iverson:
Sandra Stankowski wrote:
is.na function does'nt seem to work, but maybe I'm just dealing with
it in a wrong way.
here's an example
m - c(2, 3, 5, 6, 3, 7, -99, -99, 6)
n - c(1,1,1,1,1,2,2,2,2)
so my matrix
You do not need the regions with the double densities near the center
(1/2,1/2), you can use just the parallel 45 degree borders in that
region also.
x-x
|/*\\\|
|---/***\\|
|--/*\|
|-/**/|
Dear R-users,
I am in the process of creating new custom functions and am quite puzzled by
some discrepancies in execution time when I run some R scripts that call
those new functions. So here is the situation:
- let's assume I have created two custom functions, called myg and myf;
- myg is
You could try
install.packages(sos, dep=T)
library(sos)
h - finfFn(formal concept analysis)
h
but it does not seem to find anything relevant.
On Wed, Feb 16, 2011 at 6:21 PM, Mark Heckmann mark.heckm...@gmx.de wrote:
I am looking for an R package for formal concept analysis
searching using
library(sos)
h - ???Parzen fractional estimator
h
leads to
library(fracdiff) # on CRAN
?fdSperio
On Wed, Feb 16, 2011 at 5:19 PM, Fologo Dubois fologodub...@yahoo.com wrote:
Does R have a function for Parzen fractional degree of differencing
estimator? I am referring to the
Hi, R users,
I'm wondering if I can identify an element in a column by an element in
another column. For example:
x-1:10
y-11:20
z-cbind(x,y)
z
x y
[1,] 1 11
[2,] 2 12
[3,] 3 13
[4,] 4 14
[5,] 5 15
[6,] 6 16
[7,] 7 17
[8,] 8 18
[9,] 9 19
[10,] 10 20
What I want to do is:
Is this what you mean?
z[which(z[,x] == 5) - 1, y]
?which is probably what you're looking for...
Hongwei Dong wrote:
Hi, R users,
I'm wondering if I can identify an element in a column by an element in
another column. For example:
x-1:10
y-11:20
z-cbind(x,y)
z
x y
[1,] 1 11
[2,] 2
try this:
x - 1:10
y - 11:20
z - cbind(x, y)
ind - x == 5
z[ind, y] - z[ind, y] - 1
z
I hope it helps.
Best,
Dimitris
On 2/22/2011 6:18 PM, Hongwei Dong wrote:
Hi, R users,
I'm wondering if I can identify an element in a column by an element in
another column. For example:
x-1:10
Hi Gary,
Try
transform(z, y = ifelse(x == 5, y-1, y))
HTH,
Jorge
On Tue, Feb 22, 2011 at 12:18 PM, Hongwei Dong wrote:
Hi, R users,
I'm wondering if I can identify an element in a column by an element in
another column. For example:
x-1:10
y-11:20
z-cbind(x,y)
z
x y
[1,] 1
Hi Gary,
Another possibility besides Erik's (although I suspect his is what you
are really after):
## easier way to data
z - cbind(x = 1:10, y = 11:20)
z[z[,x] == 5, y] - 1
## To see what is going on, break it into pieces
## logical; does column 'x' of 'z' equal 5?
z[, x] == 5
## all values in
Another way is with ifelse:
z-data.frame(x,y)
z$y2 - ifelse(z$x==5,z$y-1,z$y)
HTH,
Ivan
Le 2/22/2011 18:27, Erik Iverson a écrit :
Is this what you mean?
z[which(z[,x] == 5) - 1, y]
?which is probably what you're looking for...
Hongwei Dong wrote:
Hi, R users,
I'm wondering if I can
And how to read a file with a BOM is actually discussed in detail in
the 'R Data Import/Export' manual of 2.12.2 RC.
What should be ASCII files with BOMs seem to be cropping up rather
frequently these days: the recent culprits are Mac applications with
origins on Windows (SPSS was one, some
I found an easy way to do it using trans3d() and the transformation matrix.
Maybe in the future somebody would ask about it:
# For plotting the bivariate gaussian density
library(mvtnorm)
x-seq(-5,5,by=0.1)
y-seq(-3,7,by=0.1)
# Joint density
f-function(x,y)
On 2011-02-22 08:10, Daniel Harris wrote:
Thanks for the replies
The file is below
Height Frequency
62 3
63 20
64 24
65 40
66 85
67 122
68 139
69 179
70 139
71 107
72 55
73 47
74 22
75 12
76 5
77 1
I use the
The objects functions for kernel methods are unrelated to the area
under the ROC curve. However, you can try to choose the cost and
kernel parameters to maximize the ROC AUC.
See the caret package, specifically the train function.
Max
On Mon, Feb 21, 2011 at 5:34 PM, Angel Russo
Using R2.12.1 on Ubuntu 10.04.1 I've tried to run the following code chunk in
odfWeave
fig1, echo=TRUE,fig=TRUE,width=7,height=4=
x-seq(1:100)/10
y-sin(cos(x/pi))
imageDefs - getImageDefs()
imageDefs$dispWidth - 4.5
imageDefs$dispHeight- 4.5
setImageDefs(imageDefs)
X11(type=cairo)
plot(x,y)
By luck I was able to solve my own problem! (Big phw.)
As a reference, I simple change my value of z in image.plot to be X[,n:1],
where X = t(lower). Everything else remains the same.
Cheers,
Manussawee
On Tue, Feb 22, 2011 at 10:03 AM, Manussawee Sukunta
msuku...@illinoisalumni.org
Well, it should be difference by ID and TIME for q1:
something like:
for ID 1187
in TIME 1 q1=3
and TIME 2 (for same ID) q1=3
so diff would be 3-3=0
TIME ID q1
1 1187 3
1 1187 3
And I don't know how to make R to find pairs and calculate diff?
2011/2/21 Dennis
Dear All,
I would like any information about lacunarity analyis in R. Does anyone know
if the sliding-box lacunarity analysis of Allain and Cloitre (1991) or Plotnick
et al. (1996) has been implemented by anyone in R? Or any R package useful for
that? I have seen anything in R mail list
Hi Max and Andrew,
Thanks so much for your reply. Indeed I found your link last night using
steps shown below.
My first question is if the following two steps are right and AUC is 51% as
shown below.
My seond question is that currently I am using cost parameter=1 (the default
in R-SVM;
In addition's to Max's suggestion about caret, look at ROCR which visualizes
ROC charts for any binary classifier. I have an example of e1071::SVN and ROCR
here
https://heuristically.wordpress.com/2009/12/23/compare-performance-machine-learning-classifiers-r/
-Original Message-
Hi,
Sorry for the very short explanation about the problem of intersection.
I have a wave function monitored from the heart beat in a particular interval
of
times. Apart fom that, there is a line with positive slope (e.g: y = x+2) which
lies across the wave and intersect on a number of
Hi, R users,
I'm wondering how I can aggregate data in R with different functions for
different columns. For example:
x-rep(1:5,3)
y-cbind(x,a=1:15,b=21:35)
y-data.frame(y)
I want to aggregate a and b in y by x. With a, I want to use
function mean; with b, I want to use function sum. I tried:
How is the curve defined? If the curve is y=f(x) and the line is y=mx+b, you
look for the roots of f(x)-mx-b.
?polyroot
?uniroot
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of FMH
Sent: Tuesday, February 22, 2011 6:28 AM
To:
My surmise would be that you have not analyzed the situation correctly, and you
are making a false assumption about your code. Since you can't show the code,
it's pretty hard to figure out what that is. I think you're going to have to
produce a simple example that you can share that has the
Hi,
Sorry for the very short explanation about the problem of intersection.
I have a wave pattern monitored from the heart beat in a particular interval of
times. Apart fom that, there is a line with positive slope (e.g: y = x+2) which
lies across the wave and intersect on a number of
Hi,
Sorry for the very short explanation about the problem of intersection.
I have a wave function monitored from the heart beat in a particular interval
of
times. Apart fom that, there is a line with positive slope (e.g: y = x+2) which
lies across the wave and intersect on a number of
Hello all,
my first post to this list. I do a lot of experiments using a paired
sampling design and I would get a lot of mileage out of figures like
this, if I can make it work! Any advice would be appreciated.
my email is: cory.champ...@gmail.com.
Thanks!
#define dummy variables and a
On 19 February 2011 07:24, Duncan Temple Lang dun...@wald.ucdavis.edu
wrote:
Do you mean that the R variable page gives information about the request
error
and contains the 500 error code? Not sure what you mean by screen
here.
Yes that's exactly what I mean
Client-server
I've tried grouping the real and imaginary parts as a single complex number,
e.g.
z1 - complex(real=r1, imaginary=i1)
Although complex variables are not allowed in lm, I can run regsubsets just
fine:
z - cbind(z1, z2, z3, ..., z10)
bestsubs - regsubsets(z, y, nbest=1, nvmax=5, intercept=T,
I'm not sure I'm using appropriate tools for what I'm trying to do; a
reason for my lack of certainty is that I'm encountering difficulty with
what I thought would be fairly simple: labeling the X axis of my graphs
with human-readable timestamps.
I'm using R 2.12.1, running in a FreeBSD
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