Dear all I have two 10*10 matrixes and I would like to compare
theirs contents. By the word content I mean to check visually (not
with any mathematical formulation) how similar are the contents.
If they are really only 10x10 you can simply print them both to the
screen and look at them. I'm
On Thu, Mar 03, 2011 at 06:23:36PM -0800, Folkes, Michael wrote:
Perhaps somebody could clarify for me if the following is a floating
point matter or otherwise, and how am I to correct for it?
floor(100*.1)
[1] 10
100*(1.0-.9)
[1] 10
floor(100*(1-0.9))
[1] 9
As others pointed
Dear expeRts,
I would like to add two points to a wireframe plot. The points have (x,y,z)
coordinates
where z is determined to be on the wireframe [same z-value]. Now something
strange
happens. One point is perfectly plotted, the other isn't shown at all. It only
appears if I move it upwards
Dear Peter,
nice approach!
Of course it's a bit tedious because you have to specify where the ticks are
drawn yourself. But it solves the problem.
Thanks!
Marius
On 2011-03-04, at 01:32 , P Ehlers wrote:
Marius Hofert wrote:
Dear expeRts,
How can I increase the space between the ticks
Carrie Li wrote:
...
In my loop, I have some random generation of data, but if the data doesn't
meet some condition, then I want it to go next, and generate data again
for
next round.
# just an example..
# i want to generate the data again, if the sum is smaller than 25
temp=rep(NA,
The R usage survey goo.gl/jw1ig has been updated with the following changes:
Addition of -
Disclaimer :
This data will not be used for any commercial purposes
Do not include any personally identifiable information
Contact: Harsh Singhal (singhalblr AT gmail DOT com) for any queries
Removal of -
Dear all,
I've tried a multiple regression, and now I want to try a cross-validation.
I obtain this error (it must be sth related to df) that I don't understand,
any help would be appreciated.
cv.lm(df= dat, lm2.52f, m=3)
Error en `[.data.frame`(df, , ynam) : undefined columns selected
Hello
I'm a new in R
I have a large data.frame s (this is actualy just a table in mysql) :
names(s)
[1] symbols, day, value
I need to convert it to simple matrix. I have define this matrix like this:
data.matrix - matrix(nrow=nDays, ncol=nSymbols, dimnames=list(days,
symbols))
then i just
Hi all,
I know Chi-squared test can be done with the frequency data by R function
chisq.test(), but I am not sure if it can be applied to the percentage
data ? The example of my data is as follow:
#
KSL MHL MWS CLGC
I am currently fitting the following distributions using JMP and looking for
ways to fit the same distributions in R:
Zero Inflated Lognormal
Zero Inflated Loglogistic
Zero Inflated Frechet
Zero Inflated Weibull
Threshold Frechet
Threshold Loglogistic
Threshold Lognormal
Log Generalized Gamma
On 03/02/2011 11:38 PM, Anthony Dick wrote:
Hello all,
I am re-posting my previous question with a simpler, more transparent,
commented code.
I have been ramming my head against this problem, and I wondered if
anyone could lend a hand. I want to make parallel a bootstrap of a
linear mixed
Hi,
I am trying to model credit risk data using decision trees. Since the
number of defaulters is less compared to non-defaulters (defaulters around
10%), we have the class imbalance problem. Consequently, the confusion
matrix shows that the number of misclassified non-defaulters is large.
Hi, I am trying to scramble items in a matrix so that no item repeats on
consecutive rows. This generates the matrix:
LevelsOfA = 2
LevelsOfB = 2
LevelsOfC = 3
Items = 10
FactorA = rep(1:LevelsOfA, each=(LevelsOfB*LevelsOfC*Items))
FactorB = rep(rep(1:LevelsOfB,
That's the problem
Even a 10*10 matrix does not fit to the screen (10 columns do not fit in one
screen's row) and thus I do not get a well aligned matrix printed.
This is that makes comparisons not that easy to the eye.
From the other hand with edit(mymatrix) I get scrolls so I can scroll to
Please ask the author of parts() in the partitions package or the author
of the function that calls the former:
your function calls generate a call
parts(J) where J is 1272.
Internally, a J*P(J) (1272 * 1.514126e+19) vector is generated (and
that one is too large for R).
Uwe Ligges
On
Dear R-list member,
I'm using the function pmnorm() (--library(mnormt)) within a for-loop.
Certain parameter values leads to an error message:
(In sqrt(diag(S)) : NaNs produced, In sqrt(1/diag(V)) : NaNs
produced, In cov2cor(S) : diag(.) had 0 or NA entries; non-finite result
is doubtful)
On 04.03.2011 08:42, Alaios wrote:
Dear all I have two 10*10 matrixes and I would like to compare theirs contents.
By the word content I mean to check visually (not with any mathematical
formulation) how similar are the contents.
I also know edit that prints my matrix in the scree but still
On Fri, Mar 04, 2011 at 01:49:29AM -0800, Alaios wrote:
That's the problem
Even a 10*10 matrix does not fit to the screen (10 columns do not
fit in one screen's row) and thus I do not get a well aligned matrix
printed.
This is that makes comparisons not that easy to the eye. From the
Hello list.
This is from an R session (admittedly, I'm still using R 2.11.1):
print
function (x, ...)
UseMethod(print)
environment: namespace:base
showMethods(print)
Function print:
not a generic function
Don't the two results contradict each other? Or do I have a terrible
Assume that the 5th iteration (subject=5) leads to the error
message. How can I tell R to continue with the 6th iteration?
try or tryCatch are probably what you want.
cu
Philipp
--
Dr. Philipp Pagel
Lehrstuhl für Genomorientierte Bioinformatik
Technische Universität München
Dear All.
I was trying to connect java and R using jri but i have received some
errors. Operating system - windows7, Java version = java 1.6.0_23, R
version = R 2.12.1.
JAVA_HOME and R_HOME variables are set in user variables and system
variables. I have also added JRI .jar path in the system
Hi,
Let's say your data.frame is called df:
df - data.frame(a=rnorm(10), b=rnorm(10))
data.matrix - as.matrix(df)
This should work, but be careful with coercion if you have different
modes in your data.frame
HTH,
Ivan
PS: next time, provide a reproducible example, using dput() for example
library(sos)
findFn(Zero Inflated Lognormal)
ir. Thierry Onkelinx
Instituut voor natuur- en bosonderzoek
team Biometrie Kwaliteitszorg
Gaverstraat 4
9500 Geraardsbergen
Belgium
Research Institute for Nature and Forest
Hi,
I know this forum is for R-related issues, but the question I have is a
statistical question I was wondering if anyone could recommend a good
statistics forum where I can ask the question? My question is relating to
bootstrapping of binary data (ecology data) - I can give more detail,
Hi Clare,
you want to go here:
http://stats.stackexchange.com/questions
HTH
Stephan
Am 04.03.2011 12:08, schrieb Clare Embling:
Hi,
I know this forum is for R-related issues, but the question I have is a statistical
question I was wondering if anyone could recommend a good statistics
Dear Nick,
Dear Philipp,
Thanks for quick responses - it worked!
Below the implemented solution - in case others are interested:
## This will lead to an error message
library (mnormt)
p = matrix(NA,9,1)
for (subject in 2:10) {
p[subject]=pmnorm(x = subject*c(-.3,1), varcov =
r-sig-ecology (https://stat.ethz.ch/mailman/listinfo/r-sig-ecology) is
also a good source when the stats is related to R, they are usually
quite open.
Rainer
On Fri, Mar 4, 2011 at 12:08 PM, Clare Embling
clare.embl...@plymouth.ac.uk wrote:
Hi,
I know this forum is for R-related issues, but
?image
?matrix
z-matrix(rnorm(100),nrow=10)
image(1:10,1:10,z)
heatmap(z)
Date: Fri, 4 Mar 2011 09:04:41 +0100
From: p.pa...@wzw.tum.de
To: r-help@r-project.org
Subject: Re: [R] How two compare two matrixes
Dear all I have two 10*10
Dear R colleagues,
I face a seemingly simple problem I couldn't find a solution for myself
so far:
I have to sum the digits of numbers. Example: 1010 -2 100100110 - 4
Unfortunately there seems not to be a function for this task. So my idea
was to use sum(x) for it. But I did not figure out how
Hi Nick,
I think showMethods is for s4 classes (which I know nothing about). I
think you want
methods(print)
Best,
Ista
On Fri, Mar 4, 2011 at 10:14 AM, Nick Sabbe nick.sa...@ugent.be wrote:
Hello list.
This is from an R session (admittedly, I'm still using R 2.11.1):
print
function
one way is using function strsplit(), e.g.,
x - c(100100110, 1001001, 1101, 00101)
sapply(strsplit(x, ), function (x) sum(x == 1))
I hope it helps.
Best,
Dimitris
On 3/4/2011 2:18 PM, drflxms wrote:
Dear R colleagues,
I face a seemingly simple problem I couldn't find a solution for myself
Hi,
Here is the best I've found:
x - 100100110
sum(as.numeric(unlist(strsplit(as.character(x), split=
It first converts x to character, then splits every character, unlist()s
the results, then reconverts to numeric and sums it.
HTH,
Ivan
Le 3/4/2011 14:18, drflxms a écrit :
Dear R
Dear Subscribers,
I did fit an equation of the form 1 = f(x1,x2,x3) using a minimization
scheme. Now I want to compute the coefficient of determination. Normally
I would compute it as
r_square = 1- sserr/sstot with sserr = sum_i (y_i - f_i) and sstot =
sum_i (y_i - mean(y))
sserr is clear to me
Hi Dimitris,
thank you very much for your quick an efficient help! Your solution is
perfect for me. Does exactly what I was looking for if combined with
unlist and as.numeric before using sum.
Now I can keep on with my real problem ;)...
Thanx Again!!!
Best, Felix
Am 04.03.2011 14:25, schrieb
Hello
Have a problem with a function I'm trying to implement in order to calculate
weighted means on semi-aggregated data since tapply doesn't work.
I've found a good solution to this using the following syntax:
splitted.value-with(dataframe,split(value_var,group_var))
Can't you just convert you df as follow matrix - as.matrix(s) ?
Double check it as I am a newbie too. :-)
Regards,
Alberto
On 4 March 2011 06:08, Dmitrij Kudriavcev dimitrij.kudriav...@ntsg.ltwrote:
Hello
I'm a new in R
I have a large data.frame s (this is actualy just a table in mysql)
Hi again, dear Dennis,
i checked the spelling in Zuur et al. and they wrote it like i did.
I tried your suggestion but now i have another warning message:
D1- data.frame(L.AREA= Loyn$L.AREA[Loyn$fGRAZE==1], fGraze = 1)
Error in data.frame(L.AREA = Loyn$L.AREA[Loyn$fGRAZE == 1], fGraze = 1) :
Hello
Let's say, my data.frame is
symbol,day,value
A, 2010-01-01, 0.
A, 2010-01-02, 0.
B, 2010-01-01, 0.
i need to get matrix as
, A, B
2010-01-01, 0., 0.
2010-01-02, 0., NA
where A and B is columns name and date used as row name
I found a way how to do it with tapply
Hi everyone
I am trying to do some time series analysis with daily temperature data
(40 years). I have created a zoo object and ts object but can't apply
stl function. It says the series is not periodic or has less than two
periods. I've searched through google and found a lot of messages
str(getCRANmirrors(all=FALSE,local.only=FALSE))
gives -- chr(0)
--
View this message in context:
http://r.789695.n4.nabble.com/message-please-select-CRAN-mirror-tp3331711p3334943.html
Sent from the R help mailing list archive at Nabble.com.
__
Dear collegues!
Given a matrix, I would like to remove columns, that do not fulfill a certain
condition. The condition is, that the median of the column is higher than a
certain value.
I've seen the help on removing NA columns, but I cannot figure out how to
change the function part of the
Thanks, Thierry.
Has anyone used the bayescount for estimating zero inflated distributions?
It states that it is a crude function. Does that mean the estimates are
only approximate???
The example they have given seems to work only with Gamma Poisson.
data - rpois(100, rgamma(100, shape=1,
Hi Nick,
There is a difference between the newer S4 generic functions/methods and S3
generic functions. See for example:
methods(print)
showMethods(show)
?Methods
HTH,
-Francisco
On Fri, Mar 4, 2011 at 10:14 AM, Nick Sabbe nick.sa...@ugent.be wrote:
Hello list.
This is from an R
Hello, no. I need to change data format, so i can build covariance matrix on
it
Cheers,
Dima
2011/3/4 Alberto Negron albertoneg...@gmail.com
Can't you just convert you df as follow matrix - as.matrix(s) ?
Double check it as I am a newbie too. :-)
Regards,
Alberto
On 4 March 2011
For our animals we are comfortable with saying that body condition
represents a roughly 30 day period, plus and minus 15 days from
measurement. However, we have monitored individuals for longer periods and
during those periods we do not wish there to be any values for body
condition. There are
I really like RStudio ...
... but I wish it wouldn't automatically reload the last .RData it had.
Anyone know how to fix this ... ?
Also - does anyone know is there an Rstudio-user email-list forum thingy
out there ?
ta.
Robert Kinley
[[alternative HTML version
Dear R users,
I have been using rsympy to solve a set of simultaneous equations from
R. There are two solutions for the variable I'm interested in, xx[0] and
xx[1], which are in terms of symbols called lam and conc. I'd like to
pick out the one which is positive at (lam=0, conc=0) and call it
Hey,
I'm trying to create an image file with the results of a regression
analysis. In TeX, the line would be something like:
$ size = 0.34 + 4.3 var_1 $
Can I create a plot window with just this line in it? I tried playing
around with plot.new() or dev.new(), but didn't really find something
Why don't you post the question to the RStudio support forum? The
folks there are quite responsive and very helpful.
Shige
On Fri, Mar 4, 2011 at 9:05 AM, Robert Kinley kinley_rob...@lilly.com wrote:
I really like RStudio ...
... but I wish it wouldn't automatically reload the last .RData it
Dear Subscribers,
I did fit an equation of the form 1 = f(x1,x2,x3) using a minimization
scheme. Now I want to compute the coefficient of determination. Normally
I would compute it as
r_square = 1- sserr/sstot with sserr = sum_i (y_i - f_i) and sstot =
sum_i (y_i - mean(y))
sserr is clear to me
Rnoob here.
I have a matrix of zeroes ond ones. I want to delete the rows whose sum of
values is not =5, alternatively extract the rows who sum up to 5.
Thank you/Mikael
--
View this message in context:
http://r.789695.n4.nabble.com/delete-rows-whose-sum-is-X-tp3335254p3335254.html
Sent from
Hi,
Sorry for the naive question, but what exactly does the 'Adjusted R-squared'
coefficient in the summary of linear model adjust for?
Sample code:
x - rnorm(15)
y - rnorm(15)
lmr - lm(y~x)
summary(lmr)
Call:
lm(formula = y ~ x)
Residuals:
Min 1Q Median 3Q Max
-1.7828
Hi all,
I know Chi-squared test can be done with the frequency data by R function
chisq.test(), but I am not sure if it can be applied to the percentage
data ? The example of my data is as follow:
#
KSL MHL MWS CLGC
Colleagues,
I am trying to understand how R (2.12.1) obtains the PATH environment variable
in Windows (7 or Vista). Startup {base} directs one to:
R_ENVIRON -- which equals in my systems
R_HOME/etc/Renviron.site -- which does not exist
Next, it directs to:
Seconded. Go to the support forum at www.rstudio.org and post your
question/bug/suggestion. Those folks have been excellent in their
response times and feedback.
On 3/4/2011 9:14 AM, Shige Song wrote:
Why don't you post the question to the RStudio support forum? The
folks there are quite
On Mar 4, 2011, at 1:24 AM, Jeff Fang wrote:
Hi all,
I know Chi-squared test can be done with the frequency data by R
function
chisq.test(), but I am not sure if it can be applied to the
percentage
data ? The example of my data is as follow:
#
On Fri, Mar 4, 2011 at 8:50 AM, purna mij...@live.se wrote:
Rnoob here.
I have a matrix of zeroes ond ones. I want to delete the rows whose sum of
values is not =5, alternatively extract the rows who sum up to 5.
Thank you/Mikael
I think you would greatly benefit from reading some of the
Dear Martin,
I'm not sure I understood you well, because you basically have the
answer already...
What about this?
A[,apply(A, 2, function(x) median(x)0), drop=FALSE]
(drop=FALSE ensures that you keep it as column even if only one column
is selected)
HTH,
Ivan
Le 3/4/2011 11:11,
I think this would be rather something like
abline(v=mean(degree(G)))
Best,
Gabor
On Thu, Mar 3, 2011 at 8:04 PM, Scott Chamberlain
scttchamberla...@gmail.com wrote:
library(igraph)
G - erdos.renyi.game(1000, 1/1000) # a random graph
dd1 = degree.distribution(G)
plot(dd1, xlab = degree,
Hi Mikael
You really need to provide a reproducible example in the future, it will
help people to better understand what you want to do and help you, and
help you better understand the answers as well.
Try something like this:
mat[apply(mat, 1, FUN=function(x) sum(x)=5),]
HTH,
Ivan
Le
I have never used it, but I think the reshape and/or reshape2 packages
are designed for it.
Check the melt() and cast() functions in these packages... I guess...
Ivan
Le 3/4/2011 11:33, Dmitrij Kudriavcev a écrit :
Hello, no. I need to change data format, so i can build covariance matrix on
Oops, forgot one =:
mat[apply(mat, 1, FUN=function(x) sum(x)==5),]
Le 3/4/2011 15:36, Ivan Calandra a écrit :
Hi Mikael
You really need to provide a reproducible example in the future, it
will help people to better understand what you want to do and help
you, and help you better understand
On 04.03.2011 15:16, Dennis Fisher wrote:
Colleagues,
I am trying to understand how R (2.12.1) obtains the PATH environment variable
in Windows (7 or Vista). Startup {base} directs one to:
R_ENVIRON -- which equals in my systems
R_HOME/etc/Renviron.site -- which does not
On Mar 4, 2011, at 4:47 AM, Heike Schmitz wrote:
Hi again, dear Dennis,
i checked the spelling in Zuur et al. and they wrote it like i did.
I tried your suggestion but now i have another warning message:
D1- data.frame(L.AREA= Loyn$L.AREA[Loyn$fGRAZE==1], fGraze = 1)
Error in
On 04.03.2011 11:38, Dmitrij Kudriavcev wrote:
Hello
Let's say, my data.frame is
symbol,day,value
A, 2010-01-01, 0.
A, 2010-01-02, 0.
B, 2010-01-01, 0.
i need to get matrix as
See ?reshape, in this case if you data.frame is in dat:
reshape(dat, v.names=value,
On 04.03.2011 15:41, Ivan Calandra wrote:
Oops, forgot one =:
mat[apply(mat, 1, FUN=function(x) sum(x)==5),]
Yes, but since floating point issues may ba apparent in the end, I'd
vote for:
mat[apply(mat, 1, FUN = function(x) isTRUE(all.equal(sum(x), 5))),]
Le 3/4/2011 15:36, Ivan
True, I didn't think about it because the matrix is supposed to be
filled with 0 and 1, and I automatically thought about integers. It
wouldn't be a problem with integers, right?
Le 3/4/2011 15:47, Uwe Ligges a écrit :
On 04.03.2011 15:41, Ivan Calandra wrote:
Oops, forgot one =:
On 04.03.2011 15:52, Ivan Calandra wrote:
True, I didn't think about it because the matrix is supposed to be
filled with 0 and 1, and I automatically thought about integers. It
wouldn't be a problem with integers, right?
If the matrix is really an integer matrix, right, otherwise not.
Best,
On Mar 4, 2011, at 8:31 AM, Alexx Hardt wrote:
Hey,
I'm trying to create an image file with the results of a regression
analysis. In TeX, the line would be something like:
$ size = 0.34 + 4.3 var_1 $
Can I create a plot window with just this line in it? I tried
playing around with
On Fri, Mar 4, 2011 at 12:33 PM, Paco Pastor p...@ceam.es wrote:
Hi everyone
I am trying to do some time series analysis with daily temperature data (40
years). I have created a zoo object and ts object but can't apply stl
function. It says the series is not periodic or has less than two
On 04.03.2011 16:12, David Winsemius wrote:
On Mar 4, 2011, at 8:31 AM, Alexx Hardt wrote:
Hey,
I'm trying to create an image file with the results of a regression
analysis. In TeX, the line would be something like:
$ size = 0.34 + 4.3 var_1 $
Can I create a plot window with just this line
On Mar 4, 2011, at 10:12 AM, David Winsemius wrote:
On Mar 4, 2011, at 8:31 AM, Alexx Hardt wrote:
Hey,
I'm trying to create an image file with the results of a regression
analysis. In TeX, the line would be something like:
$ size = 0.34 + 4.3 var_1 $
Can I create a plot window with
Hello R-help
I am working with large data table that have the occasional label,
a particular time point in an experiment. E.g:
Time (min), R1 R1, R2 R1, R3 R1, R4 R1
.909, 1.117, 1.225, 1.048, 1.258
3.942, 1.113, 1.230, 1.049, 1.262
3.976, 1.105, 1.226, 1.051, 1.259
4.009, 1.114, 1.231, 1.053,
Hello,
I'm using GLMM on the pscl package and i'm not getting the AIC on the
summary.
The code i'm using is (example) :
mmall3 -glmmPQL(allclues ~ cycloc + male, data=dados, family=poisson,
random=~1|animal/idfid)
and the results:
Linear mixed-effects model fit by maximum likelihood
Data:
Hello there,
I am trying to compute the 3 months return momentum with the timeSeries x.ts,
which is just a subset of simple returns from a much bigger series,
class(x.ts)
[1] timeSeries
attr(,package)
[1] timeSeries
dim(x.ts)
[1] 20 3
x.ts[1:8,]
GMT
MS.US AAPL.US
Dear all,
Since I installed the x64 version of R (v2.12.1), I got a problem with tcltk
that I did not achieve to resolve.
When loading the library, it gives me the following error message:
Loading Tcl/Tk interface ...Error : .onLoad failed in loadNamespace() for
'tcltk', details:
call: inDL(x,
On Mar 4, 2011, at 9:50 AM, Asan Ramzan wrote:
Hello R-help
I am working with large data table that have the occasional label,
a particular time point in an experiment. E.g:
Time (min), R1 R1, R2 R1, R3 R1, R4 R1
.909, 1.117, 1.225, 1.048, 1.258
3.942, 1.113, 1.230, 1.049, 1.262
3.976,
See:
http://en.wikipedia.org/wiki/Coefficient_of_determination#Adjusted_R2
and the implementation in summary.lm :
ans$adj.r.squared - 1 - (1 - ans$r.squared) * ((n -
df.int)/rdf)
Brian Smith wrote:
Hi,
Sorry for the naive question, but what exactly does the 'Adjusted
The coefficient of determination, R^2, is a measure of how well your
model fits versus a NULL model, which is that the data are constant.
In nonlinear models, as opposed to linear models, such a null model
rarely makes sense. Therefore the coefficient of determination is
generally not meaningful
Hi,
I am attempting to write code which will read in my data which is of this
form:
X1Y1X2 Y2 XnYn
0 0 0 00 0
1 0 1 255 1 0
2 255
Carrie,
If your while-loop condition depends only on dt, and you don't change dt in
your loop, your loop won't terminate.
The only thing inside your loop is next.
Perhaps you mean to write:
temp=rep(NA, 10)
for(i in 1:10)
{
dt=sum(rbinom(10, 5, 0.5))
while (dt25) {
dt=sum(rbinom(10, 5, 0.5))
}
Hi!
Is there a way to manually costumize the color legend in an spplot() -
especially where to draw ticks and labels for the ticks?
The reason I'm asking: Usually spplot() automatically divides the data
into fitting slices and makes a color legend (also automatically).
I want to assign the
Hi!
Is there a way to manually costumize the color legend in an spplot() -
especially where to draw ticks and labels for the ticks?
The reason I'm asking: Usually spplot() automatically divides the data
into fitting slices and makes a color legend (also automatically).
I want to assign the
As far as I can tell, Uwe is not even fitting a model, but instead just
solving a nonlinear equation, so I don't know why he wants a R^2. I
don't see a statistical model here, so I don't know why one would want a
statistical measure.
Andy
-Original Message-
From:
Hi,
I'm afraid it's not clear to me what you are trying to do. Can you
clarify what result you are trying to achieve?
Best,
Ista
On Fri, Mar 4, 2011 at 11:18 AM, mattnixon m.r.ni...@ex.ac.uk wrote:
Hi,
I am attempting to write code which will read in my data which is of this
form:
X1
You still don't say what organization you are associated with. Your domain
name and e-mail address give no hint. How do we know that Harsh Singhal is
even a real person? An e-mail address at a university (for example) would go a
long way to establish that. Gmail doesn't cut it for me.
The
On 04.03.2011 11:14, Nick Sabbe wrote:
Hello list.
This is from an R session (admittedly, I'm still using R 2.11.1):
print
function (x, ...)
UseMethod(print)
environment: namespace:base
showMethods(print)
Function print:
not a generic function
Don't the two results
Dear all
I have some problem to execute jri package. R.dll file has to copped to jri
directory for the execution of jar file in eclips. But R.dll file is not
available in the R version 2.12.1 . Is there any chance to get this
file. Thanks in advanced
Kind regards
W. Mathew
On 04.03.2011 18:15, wesley mathew wrote:
Dear all
I have some problem to execute jri package. R.dll file has to copped to jri
directory for the execution of jar file in eclips. But R.dll file is not
available in the R version 2.12.1 .
It is, at least in the Windows binary distribution.
Uwe
Andy,
You may well be right. I assumed fitting an equation means that he
had data to which the equation was being fitted. Maybe that's wrong --
re-reading the post still does not clarify the point for me. In any
case, either way, fitting R^2 makes no sense.
-- Bert
On Fri, Mar 4, 2011 at 8:44
On 04.03.2011 10:11, agent dunham wrote:
Dear all,
I've tried a multiple regression, and now I want to try a cross-validation.
I obtain this error (it must be sth related to df) that I don't understand,
any help would be appreciated.
cv.lm(df= dat, lm2.52f, m=3)
Error en `[.data.frame`(df,
Hello, I am looking for an elegant one-liner for the following
operation:
x - rnorm(10)
y - runif(10)
c(mean(x)-mean(y), mean(x)+mean(y))
I thought about
apply(data.frame(x, y), 2, mean)
but I don't know how to apply the +- operation on the result of
apply. Thanks, *S*
--
Sascha Vieweg,
Dear list,
is it somehow possible to retrieve the x and y coordinates of points in
a scatterplot after it has been plotted? identify() somehow seems to
manage this, so I was wondering whether it is possible?
I am asking as I wrote a function that identifies points inside a
polygon and I
On 04.03.2011 18:22, Sascha Vieweg wrote:
Hello, I am looking for an elegant one-liner for the following operation:
x - rnorm(10)
y - runif(10)
c(mean(x)-mean(y), mean(x)+mean(y))
I thought about
apply(data.frame(x, y), 2, mean)
but I don't know how to apply the +- operation on the result
At 9:52 AM -0700 3/4/11, Shari Clare wrote:
Hi Bill and Josh:
When I run any principal code with scores=TRUE, I get the following Error:
Error in principal (my.data,3,scores=TRUE) : unused argument (scores=TRUE)
Thoughts?
What version of psych are you using?
Does it work on the example I
Alaios wrote:
That's the problem
Even a 10*10 matrix does not fit to the screen (10 columns do not fit in one
screen's row) and thus I do not get a well aligned matrix printed.
I don't see why you would want to do this, but you
could always invoke two instances of R and create
one matrix in
On Fri, Mar 4, 2011 at 12:22 PM, Sascha Vieweg saschav...@gmail.com wrote:
Hello, I am looking for an elegant one-liner for the following operation:
x - rnorm(10)
y - runif(10)
c(mean(x)-mean(y), mean(x)+mean(y))
I thought about
apply(data.frame(x, y), 2, mean)
but I don't know how to
Hi Sascha,
As Uwe said, I am not sure you will get more elegant. If you want it
to be simple because you do it a lot and the typing is a burden,
consider writing a function. Here is a little example:
##
f - function(x, y, ...) {
mx - mean(x, ...)
my - mean(y, ...) * c(-1, 1)
mx
jannis-2 wrote:
is it somehow possible to retrieve the x and y coordinates of points in
a scatterplot after it has been plotted? identify() somehow seems to
manage this, so I was wondering whether it is possible?
locator might be the more basic function you are looking for.
Dieter
The message
Error in profile$Y : object of type
'closure' is not subsettable
means R thinks you are attempting to subset the function profile.
Pick a different name for your variable to avoid the name clash.
On Fri, Mar 4, 2011 at 11:18 AM, mattnixon m.r.ni...@ex.ac.uk wrote:
Hi,
I am
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