Statement 9 using sapply does not seem to give the correct answer (or at
least to me). Yet I do what I think is the same thing with statement 11 and
I get the answer I'm looking for.
9 : s -sapply(unlist(v[c(1:length(v))]), max)
11: for(i in 1 :length(v)) v1[i] - max(unlist(v[i]))
Shouldn't I
hi, I want to know how about r package Robust CP in all possible regression
method...can you help me??
thanks before...
[[alternative HTML version deleted]]
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R-help@r-project.org mailing list
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Dear R-help,
Can anybody tell me which R package has Lo-Mendell Rubin LR test and Bootstrap
LR test to compare the model fit between k class and k+1 class model for Latent
class analysis?
Thanks in advance,
warn regards,Ms.Karunambigai M
PhD Scholar
Dept. of Biostatistics
NIMHANS
Bangalore
Hi,
On Thu, May 26, 2011 at 12:49 AM, eric ericst...@aol.com wrote:
Statement 9 using sapply does not seem to give the correct answer (or at
least to me). Yet I do what I think is the same thing with statement 11 and
I get the answer I'm looking for.
9 : s -sapply(unlist(v[c(1:length(v))]),
Hi Eric,
Hopefully the following addresses your question:
library(XML)
## please do not include rm(list=ls()) in code other's might copy and paste
## it could remove things precious to them
url -
http://webapp.montcopa.org/sherreal/salelist.asp?saledate=05/25/2011;
tbl
On May 26, 2011 Andrew Halford wrote:
I am using ordiellipse to plot the ellipses and it works fine except one
of my groups
contains only 2 sites and I cannot get an ellipse around them. I'm
assuming
that 2 points is not enough to perform the relevant calculations here,
however I would
Dear RGroup
I have a requirement for which I am seeking help.
I am looking at automating the last column calculation through R when
having the data of the other columns as a dataframe, In excel I can do
using the formula function as given below, however, hereagain for the
number of observations
On 26 May 2011, at 08:02, Vijayan Padmanabhan wrote:
I have a requirement for which I am seeking help.
Best to just ask, compactly. This is a very straightforward question: best to
read on how to use R: You are just set 1 column of a dataframe to a value based
on the others, applying this to
Or without plyr:
# Dennis's sample data but with shortened names
ds - data.frame(id = rep(1:3, each = 10),
value1 = sample(seq_len(100), 30, replace = TRUE))
k - data.frame(id = 1:3, sv = c(1, 3, 5))
do.call(rbind,
mapply( function(a,b) subset(ds, id==a)[-1:-b,],
Hi,
I've read through the FAQs and in the R FAQ for Windows I found a
valuable section on how to configure R to work with a proxy server. A
colleague tested and confirms the solution works but now I have other
colleagues connecting via the same proxy server (requiring
authentication) using
the current version of nlme depends on R=2.13, according to CRAN. I
would guess that this is the problem. So I think you'll either need to
re-install an older R 2.12.2 compatible version of nlme, or upgrade R.
On 25/05/11 17:18, gbre...@ssc.wisc.edu wrote:
Sorry, I forgot to be more
On 26.05.2011 05:51, David Winsemius wrote:
On May 25, 2011, at 10:21 PM, Rafael Terra wrote:
Dear R-project members,
I'm a newbie in R and I'm trying to install the splm package to
analyze spatial panel data. I have the R x64 2.12.0 beta version
installed in my computer. When I try to
On 26.05.2011 10:57, Simon Wood wrote:
the current version of nlme depends on R=2.13, according to CRAN. I
would guess that this is the problem. So I think you'll either need to
re-install an older R 2.12.2 compatible version of nlme, or upgrade R.
Although upgrading is never a bad idea,
Dear all,
I am quite new with R and I have a problem with plotting a binomial
regression line in a plot.
This is what I type in:
model-glm(Para~Size,binomial)
par(mfrow=c(1,1))
xv-seq(3.2,4.5,0.01)
yv-predict(model,list(area=xv),type=response)
plot(Size,Para)
lines(xv,yv)
The error
Hi ,
that's what I did:
I am connected to internet
I selected the option choisir le site miroir de CRAN...a list of choices
comes I chose France (Toulouse), since it is the nearest to my country, but
an error message comes:
Notification Message:
In open.connection (con, r):
connection to
Phil Spector wrote:
Steven -
Does typing
Sys.setlocale('LC_ALL','C')
before the offending command suppress the message?
- Phil Spector
Statistical Computing Facility
On 26.05.2011 10:42, rgui wrote:
Hi ,
that's what I did:
I am connected to internet
I selected the option choisir le site miroir de CRAN...a list of choices
comes I chose France (Toulouse), since it is the nearest to my country, but
an error message comes:
Notification Message:
In
Hello,
I would like to split the attached data frame based on the DATE
variable. I'm having a real problem doing this. I am able to split
iso-read.table(datuh.dat, header=TRUE, sep=, dec=.) #load
mylist=split(iso,iso$DATE) #split
str(mylist) #result seems a bit odd
However, after splitting
On Thu, 26 May 2011, Jörgen Svan wrote:
Dear all,
I am quite new with R and I have a problem with plotting a binomial
regression line in a plot.
This is what I type in:
model-glm(Para~Size,binomial)
par(mfrow=c(1,1))
xv-seq(3.2,4.5,0.01)
yv-predict(model,list(area=xv),type=response)
Dear List,
I am currently running R-2.10.1. I wish to install R-2.13.0 or update my
R-2.10.1 to the R-2.13.0.
I have downloaded R-2.13.0 but wish to seek your advice before installing
that.
Please is there a better way of updating to the newer version other than
downloading and installing the
On 26.05.2011 10:45, Jörgen Svan wrote:
Dear all,
I am quite new with R and I have a problem with plotting a binomial
regression line in a plot.
This is what I type in:
model-glm(Para~Size,binomial)
par(mfrow=c(1,1))
xv-seq(3.2,4.5,0.01)
yv-predict(model,list(area=xv),type=response)
On 26/05/2011 6:02 AM, ogbos okike wrote:
Dear List,
I am currently running R-2.10.1. I wish to install R-2.13.0 or update my
R-2.10.1 to the R-2.13.0.
I have downloaded R-2.13.0 but wish to seek your advice before installing
that.
Please is there a better way of updating to the newer version
On 26.05.2011 12:01, Mathew Brown wrote:
Hello,
I would like to split the attached data frame based on the DATE
variable. I'm having a real problem doing this. I am able to split
iso-read.table(datuh.dat, header=TRUE, sep=, dec=.) #load
mylist=split(iso,iso$DATE) #split
str(mylist) #result
I am using read.xls command from the gdata package. I get the following error
when I try to read a work sheet from an excel sheet.
Error in xls2sep(xls, sheet, verbose = verbose, ..., method = method, :
Intermediate file 'C:\Tmp\RtmpYvLnAu\file7f06650f.csv' missing!
In addition: Warning
Hi,
how can I import a document whose type is. txt using the package tm?
it is the command to know that my document is not placed in the library
package tm.
thanks.
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Sent from the R help mailing
On May 25, 2011, at 10:31 PM, Sparks, John James wrote:
Dear R Helpers,
I was looking at the email help threads in trying to find a calculation in
R of Thiel's uncertainty coefficient. One of the writers offered to send
the function in custom code to the inquirer. Can I get a copy of
I am trying to develop a prognostic model using logistic regression. I
built a full , approximate models with the use of penalization - design
package. Also, I tried Chi-square criteria, step-down techniques. Used
BS for model validation.
The main purpose is to develop a predictive model
Hi list,
Using the script below, I have generated two lists (c and h) containing
yearly matrices. Now I would like to divide the matrices in c into multiple
matrices based on h. The number of matrices should be equal to:
length(unique(DF1$B))*length(h). So each unique value in DF1$B get's a
On May 26, 2011, at 2:26 AM, Marvin Mellem wrote:
Hi,
I've read through the FAQs and in the R FAQ for Windows I found a
valuable section on how to configure R to work with a proxy server. A
colleague tested and confirms the solution works but now I have other
colleagues connecting via the
karuna m m_karuna2002 at yahoo.com writes:
Can anybody tell me which R package has Lo-Mendell Rubin LR test and
Bootstrap
LR test to compare the model fit between k class and k+1 class model
for Latent class analysis?
I don't know, but
library(sos)
findFn(Lo-Mendell)
findFn({latent
On May 25, 2011, at 6:25 PM, Mikkel Grum wrote:
I have a loop that regularly checks for new data to analyse in my database.
In order to facilitate this, the database table has a timestamp column with
the time that the data was inserted into the database. Something like this:
while ()
Al,
I'd redo everything and report in the paper that your peculiar predictor
was contributing strongly to models that were built without excluding
this predictor. This is an important information: your models get
confused by the predictor (I'd consider this a lack of a certain kind
of
Federico,
You've asked this a couple times. Did you try to find the answer yourself?
If you search at rseek.org for Thiessen or Voronoi several functions
appear that should do what you need.
You didn't tell us anything about your data, so there's no possible
way we can provide more specific
Hi Duncan,
Thanks for your time.
Using ./configure as specified in the installation manual, I attempted to
install R-2.13.0 but it reported an error message:
checking for IceConnectionNumber in -lICE... no
checking X11/Intrinsic.h usability... no
checking X11/Intrinsic.h presence... no
checking
Hi,
On Thu, May 26, 2011 at 10:05 AM, ogbos okike ogbos.ok...@gmail.com wrote:
Hi Duncan,
Thanks for your time.
Using ./configure as specified in the installation manual, I attempted to
install R-2.13.0 but it reported an error message:
checking for IceConnectionNumber in -lICE... no
On 26/05/2011 10:05 AM, ogbos okike wrote:
Hi Duncan,
Thanks for your time.
Using ./configure as specified in the installation manual, I attempted to
install R-2.13.0 but it reported an error message:
checking for IceConnectionNumber in -lICE... no
checking X11/Intrinsic.h usability... no
Sorry, my question was: Are these two functions (Stata and fastbw
(rule=p) R function) should give the same results to the same data? Maybe
I need to run these two functions on more than one datasets to answer
myself.
Many thanks,
Linda
2011/5/25 David Winsemius dwinsem...@comcast.net
On May
Hello JCFaria,
I have the same problem Tinn-R (Marcos' problem), and your comments help me.
tanks
PereiraGA
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Hi Steve,
Many thanks.
I added :deb http://cran.at.r-project.org/bin/linux/ubuntu lucid/ in my
source.list and then tried sudo apt-get update. The last lines of the result
says:
Reading package lists... Done
W: GPG error: http://cran.at.r-project.org lucid/ Release: The following
signatures
Ogbos,
I don't use Ubunto too, but X-11 headers should be installable running
apt-get xorg-dev
and/or (possibly)
apt-get libx11-dev xlibs-dev
Best
On Thursday 26 May 2011 16:13:36 Duncan Murdoch wrote:
On 26/05/2011 10:05 AM, ogbos okike wrote:
Hi
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
project.org] On Behalf Of ogbos okike
Sent: Thursday, May 26, 2011 7:42 AM
To: Steve Lianoglou
Cc: r-help@r-project.org
Subject: Re: [R] R-2.10.1 to R-2.13.0
Hi Steve,
Many thanks.
I added :deb
Hi,
On Thu, May 26, 2011 at 10:42 AM, ogbos okike ogbos.ok...@gmail.com wrote:
Hi Steve,
Many thanks.
I added :deb http://cran.at.r-project.org/bin/linux/ubuntu lucid/ in my
source.list and then tried sudo apt-get update. The last lines of the result
says:
Reading package lists... Done
W:
On May 26, 2011, at 7:42 AM, El-Tahtawy, Ahmed wrote:
I am trying to develop a prognostic model using logistic regression. I
built a full , approximate models with the use of penalization - design
package. Also, I tried Chi-square criteria, step-down techniques. Used
BS for model
Hi all
Just a quick question which I can't find an answer for in the usual places:
I would like to create a table of regression output, with one or more
regressions in the columns, a la xtable. But I am using models from the
Design package. Is there anything out there that will play nicely with
Thanks Marc,
I had just come up with another, slightly more convoluted solution. Add as.is =
TRUE to the query and then get the timetoken with
timetoken - df$timestamp[df$timestamp == max(as.POSIX(df$timestamp))]
While it looks like options(digits.secs = 6) works, I worry that theoretically
Hi,
Sorry if this is to wrong mailing list. In that case, please point me
to correct mailing list.
Please also excuse rather long mail - I am not sure what piece of
information would be useful for anybody who could help me.
Couple of days back I had put a query about box-plots using GUI. I
Hello,
This tread helped me to finally move somewhere with rgraphviz installation.
But it seems there is a problem with vignette creation. I have the same
configuration as Ben (Win7 -64bit,R-2.13.0, Rtools version
2.13.0.1901,graphviz from goodies) and did the changes suggested by Martin.
The
On May 26, 2011, at 5:09 AM, vioravis wrote:
I am using read.xls command from the gdata package. I get the following error
when I try to read a work sheet from an excel sheet.
Error in xls2sep(xls, sheet, verbose = verbose, ..., method = method, :
Intermediate file
Dear All,
I am creating 4 plots (files) but I could see only 3. Here is a simple code
d=data.frame(age=rnorm(100,40,8),ht=rnorm(100,170,15))
tiff(file=paste(test,%03d,.tif,sep=))
hist.data.frame(d)
datadensity(d)
par(mfrow=c(1,2),mar=c(3,3,3,3))
boxplot(d$age)
hist(age)
dev.off()
PDF
On May 26, 2011, at 10:01 AM, David Hugh-Jones wrote:
Hi all
Just a quick question which I can't find an answer for in the usual places:
I would like to create a table of regression output, with one or more
regressions in the columns, a la xtable. But I am using models from the
Design
Another workaround if you don't need to batch the process up is to
highlight the cells of the excel file in question, copy it to the
clipboard, and use read.table(clipboard).
I also use this often when people pass me huge, unwieldy excel files
that have multiple sets of data, summaries, formula,
On 26/05/2011 10:25 AM, jirivoller wrote:
Hello,
This tread helped me to finally move somewhere with rgraphviz installation.
But it seems there is a problem with vignette creation. I have the same
configuration as Ben (Win7 -64bit,R-2.13.0, Rtools version
2.13.0.1901,graphviz from goodies) and
Dear list,
We have three time course profiles with very different scales, and we want
to show them in one plot. Is it possible to have three y axis? I guess not,
then what would be other options? something like two 2-y axis plots on a
three dimensional view? Appreciate any comment.
Jun Shen
On Thu, May 26, 2011 at 11:09 AM, Marc Schwartz marc_schwa...@me.com wrote:
On May 26, 2011, at 5:09 AM, vioravis wrote:
I am using read.xls command from the gdata package. I get the following error
when I try to read a work sheet from an excel sheet.
Error in xls2sep(xls, sheet, verbose =
Well, when I try to run your sample code, I get one figure and a bunch
of error messages.
How about an actual executable example and the requested basic
information on your OS, version of R, etc? That would make it a lot
easier to offer useful suggestions (by which I mean possible).
There is nothing to prevent you from putting 3 y-axis on your plot;
might be confusing, but it can be done. What have you tried and why
do you say guess not? With the use of par(new=TRUE) or by doing
your own scaling, you can use 'axis' to put as many axises as you want
on your graph.
On Thu,
On May 26, 2011, at 10:16 AM, Gabor Grothendieck wrote:
On Thu, May 26, 2011 at 11:09 AM, Marc Schwartz marc_schwa...@me.com wrote:
On May 26, 2011, at 5:09 AM, vioravis wrote:
I am using read.xls command from the gdata package. I get the following
error
when I try to read a work sheet
Hi, Jim,
Thanks for the information. But I am still not clear how to show the 3
separated Y axis. If I just call par(new=TRUE), the three axes are
overlapped.
attached some test data. Thanks.
Jun
=
structure(list(Time =
Try this:
plot(x$Time, x$y1, type='l', bty = 'c', col = 'red')
par(new = TRUE)
plot(x$Time, x$y2, type = 'l', axes = FALSE, xlab = '', ylab = '', col
= 'green')
axis(4, col='green')
par(new = TRUE)
plot(x$Time, x$y3, type = 'l', axes = FALSE, xlab = '', ylab = '', col = 'blue')
axis(4,
Hello All,
I'm trying to create a matrix from a dataframe (let's call it df):
..a..b.c.d
a inputs output
b inputs output
c inputs output
d inputs output
e inputs output
The inputs are represented by columns a and b
The outputs are represented by
Hi, jim
That's exactly what I wanted. One more trivial thing. How do I get rid the
border line on the top? Thanks again.
Jun
On Thu, May 26, 2011 at 11:20 AM, jim holtman jholt...@gmail.com wrote:
Try this:
plot(x$Time, x$y1, type='l', bty = 'c', col = 'red')
par(new = TRUE)
plot(x$Time,
On May 26, 2011, at 10:04 AM, Mikkel Grum wrote:
Thanks Marc,
I had just come up with another, slightly more convoluted solution. Add as.is
= TRUE to the query and then get the timetoken with
timetoken - df$timestamp[df$timestamp == max(as.POSIX(df$timestamp))]
While it looks like
I just found out by setting bty='l' to get rid of the border line on the
top.
On Thu, May 26, 2011 at 11:41 AM, Jun Shen jun.shen...@gmail.com wrote:
Hi, jim
That's exactly what I wanted. One more trivial thing. How do I get rid the
border line on the top? Thanks again.
Jun
On Thu, May
Jim,
One more question, how do I put a label on the axes I added? Thanks. I don't
see any argument in axis() for that? Thanks
Jun
On Thu, May 26, 2011 at 11:20 AM, jim holtman jholt...@gmail.com wrote:
Try this:
plot(x$Time, x$y1, type='l', bty = 'c', col = 'red')
par(new = TRUE)
On May 26, 2011, at 1:25 PM, Jun Shen wrote:
Jim,
One more question, how do I put a label on the axes I added? Thanks.
I don't
see any argument in axis() for that? Thanks
You don't see the `labels` argument in the help page for `axis`?
Jun
David Winsemius, MD
West Hartford, CT
Hello!
I am trying import data into R and im running into a snag.
GOAL:
Import a 4 column, 8,000 row table into R including headers.
WHAT I'VE ATTEMPTED:
Original data was in Excel format.
Converted data to both a .txt and .csv (to see which worked better)
Imported data into R via commands as
Hi,
I'm going to try to do some species distribution modeling in R using
Mahalanobis distance. I have presence point locations for the species
and I have ASCII files for each of the WorldClim variables for North
America. My question is how do I bring these into R?
If this is too complex, I have
Hello R gurus, I have a data set from which i have to extract the gender and
age matched rows from controls and disease group
disease-paste(rep(c('y','n'),11))
gender-paste(rep(c('m','f'),11))
mcp-rnorm(700,1400)
age-rnorm(32,34)
Dear Sarah,
I have a grid in which 8 raingauges are locted, in my case the dataset is
composed by 8 hourly timeseries, one for each raingauge. I would like to
obtain from these timeseries using the Thiessen method the values of the
precipitation in all the grid. In particular I would like to
Hello,
I have a x,y,z file.
Z is not corresponding to a simple analytical function of x and y.
I am trying to find the minimum value of z by a spline interpolation or from a
polynomial fit.
I tried the akima package but as the location of the point I am looking for
(the minimum) is outside of
On Thu, May 26, 2011 at 10:03 AM, StatBat2
nstruckme...@harryanddavid.com wrote:
Hello!
I am trying import data into R and im running into a snag.
GOAL:
Import a 4 column, 8,000 row table into R including headers.
WHAT I'VE ATTEMPTED:
Original data was in Excel format.
Converted data to
On May 26, 2011, at 11:19 AM, 1Rnwb wrote:
Hello R gurus, I have a data set from which i have to extract the
gender and
age matched rows from controls and disease group
You need to define what you mean by age-matched. Your example
creates a very narrow age range which further adds
On May 26, 2011, at 1:59 PM, Peter Langfelder wrote:
On Thu, May 26, 2011 at 10:03 AM, StatBat2
nstruckme...@harryanddavid.com wrote:
Hello!
I am trying import data into R and im running into a snag.
GOAL:
Import a 4 column, 8,000 row table into R including headers.
WHAT I'VE ATTEMPTED:
That is the strange thing... I DON'T get a warning message. R behaves as
if all data is being imported successfully. I don't receive a memory
warning, or warning of any kind. I've scanned my data for potential
problems and I do not have any ('). However...
The .txt version of my file does use ()
That is the strange thing... I DON’T get a warning message. R behaves as if
all data is being imported successfully. I don't receive a memory warning,
or warning of any kind. I've scanned my data for potential problems and I do
not have any ('). However...
The .txt version of my file does use ()
Hello list,
I am not sure if the terminology that I am using here is widely used,
however, I provide an example in the hopes that my problem will become
clear. My basic problem is that I am unsure of how to 'constrain' my
model estimates to reproduce the aggregate (by factor levels) observed
Federico,
That's an improvement, but a long way from the reproducible example
requested by the posting guide. I and others who might help are more
interested in the way the data and coordinates are organized and a
detailed explanation of what you expect the results to look like, etc,
than in a
David,
I surely tried the labels argument. But it seems for tick marks not for a
text label. Did you see a different outcome? Thanks.
Jun
On Thu, May 26, 2011 at 12:38 PM, David Winsemius dwinsem...@comcast.netwrote:
On May 26, 2011, at 1:25 PM, Jun Shen wrote:
Jim,
One more question,
You can use mtext()
par(mar=c(5.1,4.1,4.1,5.1))
plot(x$Time, x$y1, type='l', bty = 'c', col = 'red')
par(new = TRUE)
plot(x$Time, x$y2, type = 'l', axes = FALSE, xlab = '', ylab = '', col=
'green')
axis(4, col='green')
mtext(side=4, text=label green, line=2)
par(new = TRUE)
plot(x$Time, x$y3,
On May 26, 2011, at 2:18 PM, Jun Shen wrote:
David,
I surely tried the labels argument. But it seems for tick marks not
for a text label. Did you see a different outcome? Thanks.
`labels` is for labels, `at` is for tick (and label) locations. They
should be the same length. One label
Federico,
I understand what you are after — you want time-series estimates based on the
Thiessen polygon estimates
taken from the station time-series data. My recommendation is that the process
of doing this would be far
easier using something like GRASS GIS, possibly in conjunction with R
Dat:
1. you can use as.matrix to convert data.frame to matrix;
2. it is likely that the internal representation of your data.frame may not be
numerical value; matrix can only take on numeric.
--- On Thu, 5/26/11, Dat Mai dat.d@gmail.com wrote:
From: Dat Mai dat.d@gmail.com
Subject:
Dear all,
I am having a (really) hard time getting pyears to work together with a
ratetable to give me the number of expected events (deaths).
I have the following data:
dos, date of surgery, as.Date
dof, date of last follow-up, as.Date
dos, date of surgery, as.Date
sex, gender, as.factor
Dear all,
I have a question about how to suppress intermediate results in a function
on console. For example, I will use summary() in my own function that looks
like:
myfunction - function(…)
{
…
Summary(x)
…
}
Then myfunction() will print “x” on console that is intermediate result and
Duncan,
installing MikTeX solved the problem. thank you.
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Thank you both. These solutions are far more elegant than anything I could
have come up with, and I appreciate the opportunity to learn new commands
within the context of my own data.
I think I've got it working now. :)
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On May 26, 2011, at 1:53 PM, Andy Zhu wrote:
Dat:
1. you can use as.matrix to convert data.frame to matrix;
2. it is likely that the internal representation of your data.frame
may not be numerical value; matrix can only take on numeric.
Not true. Can be any single mode, including
Well, since we have no idea what x is, that is going to be hard to do.
Are you calling summary because you want the info on the last
iteration of a loop? If so, just put the summary call outside the
loop. Otherwise, why are you calling summary if you don't want a
summary?
Also, the posting guide
HI,
I do it like this :
setwd(C:/Users/mpavlic/Desktop/Temp)
library(tm)
tekst - Corpus(DirSource(.),readerControl = list(language =ansi))
where *.txt files are stored in a folder Temp in my desktop,
HTH, m
-Original Message-
From: r-help-boun...@r-project.org
Hi all,
Is there any way for me to to string in the argument of qplot or ggplot? for
example
qplot(x='carat',y='price',data=diamonds,geom=c('point','smooth'))
instead of
qplot(x=carat,y=price,data=diamonds,geom=c('point','smooth'))
Thanks!!
Regards,
TszKin Julian
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Wierd... sorry about the double posting...
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When I use the as.matrix, the data.frame does turn into a matrix, but I
cannot change the dimensions of the matrix. I'd still want it to have that
pseudo cartesian format (e.g. [a1,b1], [a2,b2])
On Thu, May 26, 2011 at 6:58 PM, David Winsemius dwinsem...@comcast.netwrote:
On May 26, 2011, at
Please...
?[
Online tutorial An Introduction to R.
I think you'll find everything you need in these.
-- Bert
On Thu, May 26, 2011 at 12:39 PM, Dat Mai dat.d@gmail.com wrote:
When I use the as.matrix, the data.frame does turn into a matrix, but I
cannot change the dimensions of the
Hi,
I want to recode all Inf and NaN values to NA, but I;m surprised to see the
result of the following code. Could anybody enlighten me about this?
df - data.frame(a=c(NA, NaN, Inf, 1:3))
df[is.infinite(df) | is.nan(df)] - NA
df
a
1 NA
2 NaN
3 Inf
4 1
5 2
6 3
Thanks!
I think the IOTT is more a general testing framework rather than a single test
(like maximum likelihood, least squares, bootstrap, etc.) so a single function
won't capture the whole IOTT. There are already many functions available to do
IOTT for many cases (well the user needs to provide the
df$a[is.infinite(df$a) | is.nan(df$a) ] - NA
df
a
1 NA
2 NA
3 NA
4 1
5 2
6 3
On 5/26/11 3:18 PM, Albert-Jan Roskam fo...@yahoo.com wrote:
Hi,
I want to recode all Inf and NaN values to NA, but I;m surprised to see
the
result of the following code. Could anybody enlighten me about
Thanks a bunch, Walmes.
One more concern, the new Y axes added do not extend all the way down to
cross with x axis. Is there anyway to make them look like the very first Y
axis on the left?
Jun
On Thu, May 26, 2011 at 1:24 PM, Walmes Zeviani walmeszevi...@gmail.comwrote:
You can use mtext()
Hello-
I am looking for R function that will give me some proper confidence
intervals on un-transformed mean prediction when performing a linear
regression on log-transformed data. I am referring to the UMVU estimate, the
el-shaarawi and viveros (1997) estimate, or the Wu, wong, and Wei (2005)
Thanks for your comments and suggestion. I didn’t show all my own function
here because it has many lines. “x” is the results of another function. I am
calling summary because I want to extract some values from the results.
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The strong predictor is the country/region where the study was
conducted. So it is not important/useful for a clinician to use it (as
long he/she is in USA or Europe).
Excluding that predictor will make another 2 insignificant predictors to
become significant!! Can the new model have a
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