*Hi all,*
I'm trying to filter a file through the columns. This file below is a
example of my data frame. My true data frame has seven hundred thousand
columns and 500 hundred lines. I need to identify and to remove all columns
that all elements equal a number 1. In this my case, columns were
HI,
I have this code:
BAGA - c(10,20,20,30,30,30,30,40,
40,40,40,50,50,50,50,50,
60,60,60,60,60,70,70,70,
70,80,80,80,90,90,100)
BAGB - c(10,10,10,10,10,20,20,20,
20,30,30,30,40,40,50,60,
70,70,80,80,80,90,90,90,
Dear all,
I have two vectors
x - c(1:20)
y - c(1,5,10,14)
Now I would like to extract
x[ (y[n] + 2):(y[n+1] - 1) ]
for all elements except last one in y. This means I want to have
x[ c( (y[1]+2):(y[2]-1), (y[2]+2):(y[3]-1), (y[3]+2):(y[4]-1) ) ]
How is this possible if y is a vector of
Grace:
Confession: I loved that error message! -- and it seems pretty clear to me.
What does to no avail mean -- in particular, what happened when you
changed your NA's to 0? Presumably you did not get the same error
message, again, but something else, right? What else?
Modulo the above
Dear Uwe,
I appreciate that if you let me know why, when using the attached file, the
following script (two lines) doesn't work once in 10s of times.
Best, Reza
svm.pol4 - ksvm(class.labs ~ ., data = train.data, prob.model = T, scale =
T, kernel = polydot)
svm.pol.prd4 - predict(svm.pol4,
Hi,
I am new to R, I need your help. I have been said to create a GUI in
R,
I started using Tcltk package which was very easy to learn and code,
but i am unable to arrange the GUI's in proper order in the window
they are always arranged one below the other, please can anyone
On 25-08-2012, at 02:11, Kate Dresh wrote:
*Hi all,*
I'm trying to filter a file through the columns. This file below is a
example of my data frame. My true data frame has seven hundred thousand
columns and 500 hundred lines. I need to identify and to remove all columns
that all
Hi,
?cat
Read item sep in argument section.
And try:
cat(X = , B, sep = )
--
Noia Raindrops
noia.raindr...@gmail.com
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Hi,
try below:
x - c(1:20)
y - c(1, 5, 10, 14)
x[ c( (y[1]+2):(y[2]-1), (y[2]+2):(y[3]-1), (y[3]+2):(y[4]-1) ) ]
x[unlist(lapply(1:(length(y) - 1), function (i) (y[i] + 2) : (y[i + 1] - 1)))]
x[unlist(mapply(seq, y[-length(y)] + 2, y[-1] - 1, SIMPLIFY = FALSE))]
--
Noia Raindrops
1. get programming grapgical user interfaces in R. lawrence and verzani.
2. if you used gwidgets on gtk i could tell you exactly what to do.
3. with the toolkit youve selected i think tlpack controls the way children
are placed in a container. default is top to bottom
On Aug 24, 2012 11:27 PM,
Hello,
Try this:
idx-sapply(file,function(x) all(unique(x)==1))
file[!idx]
# V2 V3 V4 V6 V7 V8 V9
#1 0 2 2 1 5 1 1
#2 0 2 2 1 5 1 1
#3 0 2 2 2 5 2 2
#4 0 2 2 1 5 1 1
#5 0 2 2 0 5 0 2
#6 0 2 2 1 5 1 0
A.K.
- Original Message -
From: Kate Dresh
I've attached the data to this message.
http://r.789695.n4.nabble.com/file/n4641291/2005pip.csv 2005pip.csv
--
View this message in context:
http://r.789695.n4.nabble.com/mgcv-package-problems-with-NAs-in-gam-tp4641253p4641291.html
Sent from the R help mailing list archive at Nabble.com.
If you are going to convert a column from character to POSIXct, I
would assume that you would do it this way and get the results that
you want:
x - data.frame(times = c('2012-08-14 12:00', '2011-01-04 08:00', 'b')
+ , stringsAsFactors = FALSE
+ )
x
times
1 2012-08-14 12:00
'gam' doesn't know what to do with the model formula '1 ~ 1' (i.e. one
tilde one). What is it supposed to mean? 'glm' also does nothing
meaningful in this case...
## code to load you data file into 'dat' omitted
model-glm(1~1, data=dat)
model
Call: glm(formula = 1 ~ 1, data = dat)
Hi,
thanks for your quick answers! These solve my problem.
Now I have another question. I think I can use
head(y, -1)
instead of
y[-length(y)]
Are there differences in terms of performance?
Best regards
Joseph
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Thank you steven,
tkpack is helping me in arranging the components in container.
and yes, i went through gwidgets package, i found it also good to design GUI
in R.
--
View this message in context:
Hi,
I want to take a look at the sourcecode for balloonplot. I would appreciate it
if I could get help on overcoming the following problem :
methods(balloonplot)
[1] balloonplot.default* balloonplot.table*
Non-visible functions are asterisked
balloonplot.default
Error: object
On 12-08-22 5:32 PM, Rui Barradas wrote:
Hello,
It makes sense. And should be easy to change.
I don't think it is easy to change. The Extensions manual doesn't have
access to the numbering (er, lettering) of appendices in the other
manual. So we'd have to hard code A and D, and we don't
I have an intensity pattern of the laser beam at the image plane of a optical
relay cum spatial filtering system. I wish to know the field and intensity
distribution at the spatial filtering plane. Requesting suggestions.
--
View this message in context:
HI,
Try this:
dat1-01/04/2006 1:10:60 PM
dat1-as.character(dat1)
strptime(dat1,%m/%d/%Y %I:%M:%S %p)$yday+1
#[1] 4
A.K.
- Original Message -
From: Veerappa Chetty chett...@gmail.com
To: r-help@r-project.org
Cc:
Sent: Friday, August 24, 2012 11:30 PM
Subject: [R] date
Hi,
I have
Hi Simon,
I'm trying to fit a negative binomial gam with no covariates, that therefore
looks at the detection/non-detection data and nothing else. I thought having
1~1 as formula would allow the model to just estimate occurrence without
looking at relationship between variables.
On 25 Aug
punitha punitha.c87 at wipro.com writes:
Thank you steven,
tkpack is helping me in arranging the components in container.
and yes, i went through gwidgets package, i found it also good to design GUI
in R.
Try `tkraise`:
library(tcltk)
w1 - tktoplevel()
tkpack(ttkbutton(w1, text=w1,
Using system.time() you can check out the performance yourself. E.g.,
the following compares head(y,-1), y[-length(y)], and y[seq_len(length(y)-1))].
y - 1:10
all.equal(head(y,-1), y[-length(y)])
[1] TRUE
all.equal(head(y,-1), y[seq_len(length(y)-1)])
[1] TRUE
On Aug 25, 2012, at 4:23 AM, Sepp Tannhuber sepp.tannhu...@yahoo.de wrote:
Hi,
thanks for your quick answers! These solve my problem.
Now I have another question. I think I can use
head(y, -1)
instead of
y[-length(y)]
Are there differences in terms of performance?
The latter
Use getAnywhere() or getS3method().
Michael
On Aug 25, 2012, at 4:13 AM, ravi rv...@yahoo.se wrote:
Hi,
I want to take a look at the sourcecode for balloonplot. I would appreciate
it if I could get help on overcoming the following problem :
methods(balloonplot)
[1] balloonplot.default*
Hi,
Yes you can. As William says, the 'seq_len' approach seems to be better.
'head' function is the wrapper for 'seq_len' approach and slower.
I didn't know that '-length(x)' approach is slow for long vectors
--
Noia Raindrops
noia.raindr...@gmail.com
Use triple colon operator:
gplots:::balloonplot.default
--
Noia Raindrops
noia.raindr...@gmail.com
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thanks
it seems to be a good idea. a also find the PK package with the biexp
function.
2012/8/23 Peter Ehlers ehl...@ucalgary.ca
Have you checked help(SSbiexp) ?
Peter Ehlers
On 2012-08-23 04:54, vincent guyader wrote:
Hi everyone,
I'm trying to perform a bi exponential Fit with
Noia,
Nope. Although sep is helpful for my output, I still get that source echo
that I want to suppress. Here is the code with Noia's suggestion.
BAGA - c(10,20,20,30,30,30,30,40,
40,40,40,50,50,50,50,50,
60,60,60,60,60,70,70,70,
70,80,80,80,90,90,100)
BAGB -
Sorry,
How about this?
invisible(capture.output(source(...)))
# or
sink(/dev/null)
source(...)
sink()
--
Noia Raindrops
noia.raindr...@gmail.com
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PLEASE do read the
On 25-08-2012, at 21:31, Noia Raindrops wrote:
Sorry,
How about this?
invisible(capture.output(source(...)))
Makes all output invisible.
# or
sink(/dev/null)
source(...)
sink()
Doesn't seem to do what is desired. The line with source still appears.
In future would you please
On 25-08-2012, at 17:59, darnold wrote:
Noia,
Nope. Although sep is helpful for my output, I still get that source echo
that I want to suppress. Here is the code with Noia's suggestion.
BAGA - c(10,20,20,30,30,30,30,40,
40,40,40,50,50,50,50,50,
Berend,
Yes, I did ask this question on RStudio help page. Josh suggested that I try
to find some package that pops up a window with the results I want. Anyone
know how to do that? Is there a package or a tutorial that will instruct me
as to how to do that?
Here is my code:
BAGA -
This is not an RStudio issue. The RConsole echoes commands and then the
output. If you want to open a window to display the output of a command, you
might look at package tcltk.
--
David L Carlson
Associate Professor of Anthropology
Texas AM University
On 2012-08-25 09:30, Noia Raindrops wrote:
Use triple colon operator:
gplots:::balloonplot.default
To the OP:
You'll probably find it easier to decipher the code if you
have access to the included comments. For that, download the
source file (gplots_2.11.0.tar.gz) from CRAN and unzip with
Hi,
I have problem getting the standard deviation from the manova output.
I have used the manova function: myfit - manova(cbind(y1, y2) ~ x1
+ x2 + x3, data=mydata) .
I tried to get the predicted values and their standard deviation by using:
predict(myfit, type=response,
On 2012-08-24 09:12, ravi wrote:
Hi,
I am interested in implementing a special variant of
balloonplot. Let me
explain with an example dataset from the reference manual :
library(gplots)
data(Titanic)
dframe-as.data.frame(Titanic)
survived-dframe[dframe$Survived==Yes,]
attach(survived)
Hello,
I need help comparing two variables and producing a third variable with the
result.I have this data:
id -c(1,2,3,4,5,6,7,8,9,10)
vi -c(1,0,1,1,1,1,1,2,2,0)
vi2 -c(0,1,1,1,1,1,1,2,0,0)
data-cbind(id,vi,vi2)
For the data in the example, I need to generate:
id -c(1,2,3,4,5,6,7,8,9,10)
I will very appreciate if anyone can provide some materials to draw a
simplex plot of a Dirichlet distribution in R as shown in the page at
http://en.wikipedia.org/wiki/File:Dirichlet_distributions.png .
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