Hello,
I am trying to generate random survival times by inverting the function, S(t)=
exp(b*F(t)), where b is constant and F(t) is some cumulative distribution
function, let say that F(t) is cdf of normal distribution or any others
distributions.
as we know that S(t) has uniform distribution
Dear all,
Is anybody knows simple method for creation norm tables for
psychological tests for several groups distinguished by sex and age?
best regards,
Krzysztof
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Dear All,
If possible please let me know whether I can find solution of following
problem using R or not?
I have to select 6-10 parameters whose range are given but I need to select
the parameter values which satisfies 5-6 known conditions
i.e. to find a suitable parameters satisfying given
On Sun, Sep 30, 2012 at 7:15 AM, ghoshm ghosh ghoshm2...@gmail.com wrote:
Dear All,
If possible please let me know whether I can find solution of following
problem using R or not?
I have to select 6-10 parameters whose range are given but I need to select
the parameter values which
On Sat, Sep 29, 2012 at 6:23 PM, Salma Wafi salmawaf...@yahoo.com wrote:
Hello,
I am trying to generate random survival times by inverting the function,
S(t)= exp(b*F(t)), where b is constant and F(t) is some cumulative
distribution function, let say that F(t) is cdf of normal distribution
On Sep 29, 2012, at 10:23 AM, Salma Wafi wrote:
Hello,
I am trying to generate random survival times by inverting the function,
S(t)= exp(b*F(t)),
This looks a bit confused.
S(t) = 1- exp( -integral( h(t)dt )
where h(t) is the instantaneous hazard. That integral is the cumulative hazard
On 09/29/2012 11:33 PM, Sabine Dietmann wrote:
Hi All,
I wonder whether it is possible to use the plot function and reduce
the scales on both +/- quadrants, i.e.
plot the data from -15. -8 and 8..15 only.
Hi Sabine,
As David noted, you might want gap.plot:
library(plotrix)
Dear All,
Thank you very much for your kind and response.
Actually, S(t) = exp(b* F(t)) represent one of survival models, where F(t) is
known cumulative distribtion function. So, that is why I need to generate the
survival times T based on this model. Then for generating time I have to invert
Hi David,
Yes, I agree that the results are very similar but I don't
understand why they are not exactly equal given that the data sets are
identical.
And yes, this 1% numerical difference is hugely important to me. I
have another data set (much larger than this toy example) that works
on the
On Sun, Sep 30, 2012 at 10:51 AM, Salma Wafi salmawaf...@yahoo.com wrote:
Dear All,
Thank you very much for your kind and response.
Actually, S(t) = exp(b* F(t)) represent one of survival models, where F(t) is
known cumulative distribtion function. So, that is why I need to generate the
On 30.09.2012 04:28, eliza botto wrote:
Dear useRs,Is there a command or package in R to do heirarchical clustering by
modified ward method??regardseliza
No idea - maybe someone can help given you explain us which modification
of the ward method is
I don't quite understand what you are asking. It sounds more like a
psychometrics or test construction question than an R question.
Do you have the data and just need to analyse it?
You might want to have a look at CRAN Task View: Psychometric Models and
Methods for some of the available
Hi Meredith,
Why not just use paste()?
cuyahoga_nf$newcolumn - paste(cuyahoga_nf[,1], cuyahoga_nf[,2],
cuyahoga_nf[,3], . , cuyahoga_nf[,4])
Best,
Steve Politzer_ahles
- Original Message -
From: Meredith Ballard LaBeau mmbal...@mtu.edu
To: r-help@r-project.org
Cc:
Sent:
I haven't followed this thread closely, but if perfect separation in a
binomial glm is the problem, google it. e.g.
http://www.ats.ucla.edu/stat/mult_pkg/faq/general/complete_separation_logit_models.htm
This presumably explains your concerns about coefficient agreement.
-- Bert
On Sun, Sep
Hi,
I got your data from Nabble. I meant to do it by dput() because the .csv files
may not get through the R-help mailing list.
This is what I got:
dat1-read.delim(typohne.csv)
str(dat1)
#'data.frame': 60 obs. of 3 variables:
# $ typ : Factor w/ 5 levels A,B,C,D,..: 1 2 3 4 5 1 2 3 4 5
Hello,
I am reaching out for a problem I have seem to hit wall on. I am trying to
build a rare event model:- Default event occurred in NY/NJ area.
Some key statistics: 138 default aka 4bp (.04%).
Obviously my logistic and robust logistic models are failing Hosmer GOF tests
and so I am
typohne.csv http://r.789695.n4.nabble.com/file/n4644635/typohne.csv
Hello arun kirshna,
I checked str() but I do not see any mistake.
Find attached a subset of my data (did you mean this with dput() ?)
Typ= treatment
abun= abundance
div= diversity, number of species
best wishes.
--
View
On Sep 30, 2012, at 5:34 AM, R. Michael Weylandt wrote:
On Sun, Sep 30, 2012 at 10:51 AM, Salma Wafi salmawaf...@yahoo.com wrote:
Dear All,
Thank you very much for your kind and response.
Actually, S(t) = exp(b* F(t)) represent one of survival models, where F(t)
is known cumulative
Hello again !
It worked exactly the same way as yours!
I'm kind of astonished, because in my opinion our skripts are the same
(obviously not...).
Whatever! It works :-D
Tomorrow (as where I live it's already evening...sunday) will be a great
day, indeed, and I can go on with analysis !
I really
Dear All,
I have reviewed some examples over the net on this issue, but still not getting
the results. I have the following text and code i would like to place into a
pdf with sweave, but I would like to change the margins on the produced
document. The options(width=60) I guess should do
As this does not appear to be an R question. I suggest you post on a
statistics list, like stats.stackexchange.com instead.
-- Bert
On Sun, Sep 30, 2012 at 8:22 AM, Mehul Makwana makwan...@yahoo.com wrote:
Hello,
I am reaching out for a problem I have seem to hit wall on. I am trying to
Bert Gunter gunter.berton at gene.com writes:
I haven't followed this thread closely, but if perfect separation in a
binomial glm is the problem, google it. e.g.
http://www.ats.ucla.edu/stat/mult_pkg/faq/general
/complete_separation_logit_models.htm
This presumably explains your
On 12-09-30 2:18 PM, Andras Farkas wrote:
Dear All,
I have reviewed some examples over the net on this issue, but still not getting
the results. I have the following text and code i would like to place into a
pdf with sweave, but I would like to change the margins on the produced
document.
Hi Josh,
I would not trust either result in this case. Additional numerical
precision is not likely to help (well, perhaps agreement between the
two sets of results, but agreement doesn't help if neither results are
meaningful). If this were my data, I would try an approach like this:
# load
On Sep 30, 2012, at 4:47 AM, Josh Browning wrote:
Hi David,
Yes, I agree that the results are very similar but I don't
understand why they are not exactly equal given that the data sets are
identical.
And yes, this 1% numerical difference is hugely important to me.
I believe you will
I have spatial data on a sphere (the Earth) for which I would like to run an
gls model assuming that the errors are autcorrelated, i.e. including a
corSpatial correlation in the model specification.
In this case the distance metric should be calculated on the sphere, therefore
metric =
Hello,
I work with time series data. From time to time I run programs to
produce results that are in time series form (e.g., quarterly or monthly
data). After a few days I might need to access part of the results and to
run another program. Is there any function or package (like dataframe or
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