On 11/07/2012 12:31 AM, kun...@gfz-potsdam.de wrote:
Hi,
I have a question about the computation of confidence intervals in the zyp
package, in particular using the functions zyp.sen and confint.zyp, or
zyp.yuepilon.
(1) I'm a bit confused about the confidence intervals given by zyp.sen and
Hi,
Color of my step plot is now by default. Now I'd like to change the color as
the grey scale I specified. I don't know why I got three black plot. Here I
attach two version of codes. The first one produces a step plot with color
by default. The second one, modified from the first one, is not
Hi David,
Thanks for the reply. sorry for typo in the R script ...what I meant to
write was
testdata - read.csv(adstest.csv,header=TRUE,sep=,)
attach(testdata)
library(lme4)
options(contrasts = c(factor = contr.SAS,ordered = contr.poly))
lmm.2=lmer(y~X1+X2+X3 +
On Nov 7, 2012, at 6:07 AM, Rolf Turner rolf.tur...@xtra.co.nz wrote:
On 07/11/12 18:35, Erin Hodgess wrote:
Dear R People
I have a simple list question, please:
I have vectors x.1, x.2,...x.n (each of different lengths) and I would
like to combine them into a list.
However, I'm
On Nov 6, 2012, at 11:38 PM, sandip1006 wrote:
Hi David,
Thanks for the reply. sorry for typo in the R script ...what I meant to
write was
testdata - read.csv(adstest.csv,header=TRUE,sep=,)
attach(testdata)
library(lme4)
options(contrasts = c(factor = contr.SAS,ordered = contr.poly))
Sam == Sam Steingold s...@gnu.org
on Tue, 6 Nov 2012 13:08:30 -0500 writes:
Sam The question is even more pressing for me now given that I no longer
can
Sam convert some csr matrices to the regular ones for scaling.
Sam
On 11/07/2012 03:44 AM, Pauli wrote:
Hello,
I am a R beginner and I have a question about a litte function I found.
Here is the code:
# Gambler's Ruin Problem.
# seed capital:k
# rounds: n
# probability of success: p
# number of trials:
Hello All,
Having some issue with local machine, I need to locate myself on Amazon
for running R and Hadoop with Amazon instance. After searching a lot, I
can't able to take a decision for choosing Image for Amazon instance. Can any
one using R + Hadoop on Amazon.
Thanks
[[alternative
Hello,
Try the following.
x.1 - 1:3
y.1 - 1:4
x.2 - 5:10
vecs - ls()[grep(^x\\.[[:digit:]]+$, ls())]
lapply(vecs, function(.x) assign(.x, get(.x)))
Then you can use vecs to attribute names() to the result.
Hope this helps,
Rui Barradas
Em 07-11-2012 05:35, Erin Hodgess escreveu:
Dear R
Dear All
I would like to convert matrix rows to columns. I am thinking the t() function
should help, but am having a hard time converting the matrix into the
dimensions I would like them to. Example:
a -matrix(c(1:30),ncol=3) gives me:[,1] [,2] [,3]
[1,]1 11 21
[2,]2 12 22
try this:
a - matrix(1:30, ncol= 3 )
t(a)
I hope it helps.
Best,
Dimitris
On 11/7/2012 12:50 PM, Andras Farkas wrote:
Dear All
I would like to convert matrix rows to columns. I am thinking the t()
function should help, but am having a hard time converting the matrix into
the
Hello,
You are using an Excel feature documented as bug by Microsoft. See
http://support.microsoft.com/kb/214230
It warns that both function LINEST() and the regression tool in Analysis
ToolPack may give incorrect results.
Search the help pages to get long discussions on this. Among others
Hello,
I'm using and testing different possibility to use GMM. And I would like to
test it in R.
Anyone know how to use GMM in R ? Maybe with the package BGMM ?
Thank's in advance for your answer !
Regards
Jerome
[[alternative HTML version deleted]]
Hi Experts,
As i am a new in this forum, let me introduce myself:- i am
Debaranjan, from India, Assam.
I have heard many things about R and its statistical Magic
feature. i am really have nothing knowledge about R language nor have
ever used before. i am only a nursery in R.
Hi everyone.
what´s the basic package to perform association (linear regression) between 1
marker and quantitatve pohenotypes?
Thanks
luca
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PLEASE do read the posting
Dear All,
As i am a new in this forum, let me introduce myself:- i am
Debaranjan, from India, Assam.
I have heard many things about R and its statistical Magic
feature. i am really have nothing knowledge about R language nor have
ever used before. i am only a nursery in R. please help
Hi,
I am using the package PTAK and in particular the command Candpara to
perform the Parafac factorizationor of a tensor.
The results are not encouraging as I expected, I'm starting a phase of
analysis to see if there are errors.
I pose a question and I hope you can help me.
The command to run
Hello,
I was using the functino kgs of maptree and I've realized maptree has been
removed from CRAN repository.
Anybody knows why has it been removed? or where can I find the function kgs
that computes the Kelley-Gardner-Sutcliffe penalty function for a
hierarchical cluster tree
Thank you.
Hi,
is.matrix(a)
#[1] TRUE
#You don't need t(matrix(a))
t(a)
# [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10]
#[1,] 1 2 3 4 5 6 7 8 9 10
#[2,] 11 12 13 14 15 16 17 18 19 20
#[3,] 21 22 23 24 25 26 27 28 29 30
It doesn't look like 'survplot' allows you to control the yaxis formatting in
that way. You can edit the function survplot.survfit directly if you really
need to: fix(survplot.survfit). The relevant line to change is (I believe)
mgp.axis(2, at = pretty(ylim)) to mgp.axis(2, at = pretty(ylim),
Don't change the code. Just use survplot(..., fun=function(y)100*y,
ylim=c(0,100)).
But note that percent is not recommended as it is more confusing than
proportions, especially when talking about differences in percents.
Frank
Andrews, Chris wrote
It doesn't look like 'survplot' allows you to
Dear Debaranjan,
What's your field of specialisation or study?
Regards,
José
José Iparraguirre
Chief Economist
Age UK
T 020 303 31482
E jose.iparragui...@ageuk.org.uk
Twitter @jose.iparraguirre@ageuk
Tavis House, 1- 6 Tavistock Square
London, WC1H 9NB
www.ageuk.org.uk | ageukblog.org.uk |
HI,
If you want to combine vectors x and y into a list,
may be this also helps:
x.1-1:3
x.2-1:4
x.3-5:10
y.1-5:6
y.2-8:10
ls()
# [1] a a1 L mat1 n vecs x.1 x.2 x.3 y.1
#[11] y.2
lapply(strsplit(ls()[grep(x|y,ls())],),function(x)
get(paste(x,collapse=)))
#[[1]]
#[1] 1 2 3
#
Hi Debaranjan,
I'm not really sure what you mean by statistical magic feature -- R
is good, but not quite magic. (Though occasional sarcastic references
are made to its capabilities by members of this list when questions
push things beyond the realm of responsible statistics)
The canonical first
On 07/11/2012 11:27, xavier maresma wrote:
Hello,
I was using the functino kgs of maptree and I've realized maptree has been
removed from CRAN repository.
Anybody knows why has it been removed? or where can I find the function kgs
That's not true: see
I calculated a homerange using the adehabitatHR-packaged, plotted it and
now I want to export the image (image with the contourlines) to google maps.
I just don't get how to do that.
Here is something like my image:
library(adehabitatHR)
kudl - kernelUD(puechabonsp$relocs[, 1], h = LSCV)
Is this a bug:
Trying to update when the where condition gives zero rows throws an error on MS
SQL server
sqlQuery(pipe,select * from ComDetailCurrent where RateTypeId is null;)
[1] ProcessDate SourceSystemIdAccountNumber Xref1
0 rows (or 0-length row.names)
Dear all,
I am interested to evaluate reclassification using net
reclassification improvement and Integrated Discrimination Index IDI after
survival analysis (Cox proportional hazards using stcox). I search a R
package or a R code that specifically addresses the categorical NRI for
time-to-event
* Martin Maechler znrpu...@fgng.zngu.rgum.pu [2012-11-07 10:10:51 +0100]:
Sam == Sam Steingold s...@gnu.org
on Tue, 6 Nov 2012 13:08:30 -0500 writes:
Sam The question is even more pressing for me now given that I no longer
can
Sam convert some csr matrices to the regular ones
Dear Member list,
is there a weblink or a paper where the total number of citations for R
project is report?
Thanks in advance
Gianni
[[alternative HTML version deleted]]
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R-help@r-project.org mailing list
Hello,
My solution is too complicated, the assign() is not needed.
lapply( ls()[grep(^x\\.[[:digit:]]+$, ls())], get)
Hope this helps,
Rui Barradas
Em 07-11-2012 11:44, Rui Barradas escreveu:
Hello,
Try the following.
x.1 - 1:3
y.1 - 1:4
x.2 - 5:10
vecs - ls()[grep(^x\\.[[:digit:]]+$,
http://scholar.google.be/scholar?q=www.R-project.orgbtnG=hl=nlas_sdt=0
http://scholar.google.be/scholar?q=%22R+Core+Team%22btnG=hl=nlas_sdt=0
http://scholar.google.be/scholar?q=%22R+Foundation+for+Statistical+Computing%22btnG=hl=nlas_sdt=0
ir. Thierry Onkelinx
Instituut voor natuur- en
Combining your, Rolf, and Michael's suggestions makes it possible
to eliminate the lappy():
mget(ls()[grep(^x\\.[[:digit:]]+$, ls())], .GlobalEnv)
--
David L Carlson
Associate Professor of Anthropology
Texas AM University
College Station, TX
And the
ls()[grep(^x\\.[[:digit:]]+$, ls())]
can be simplified to
grep(^x\\.[[:digit:]]+$, ls(), value=TRUE)
Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf
Of David L
Hi David, hi Rui,
thanks for your quick replies. I have replicated David's R results and
confirmed them with Minitab. Though I'm not sure what you are trying to tell
me with the code you wrote, David. Do you mean, I should use a dataframe
rather than a matrix, or use the data= part of the lm()
Dear list I'd like to have your opinion about my case study.
I'm analizing a dataset of 9 experiments and 15 variables with the aim to
highlight the variables that can majorly explain the variance between the
experiments.
This is an example with only 3 rows and 5 variables
We want to compute a pseudo R-squared for a model whose parameter
estimation was based on maximum likelihood (function likfit, package geoR).
I tried to compute the R2 proposed by Maddala (1983) which compare the
maximized likelihood for the model without any predictor and the
maximized
This is basically a statistics question, despite the fact that you
refer to an R implementation. You should therefore probably post on a
statistics list, like stats.stackexchange.com, especially the part
about asking for alternative R^2.
-- Bert
On Wed, Nov 7, 2012 at 9:01 AM, Marion Jacquot
... and you might also wish to try the R-sig-geo list, for obvious reasons.
-- Bert
On Wed, Nov 7, 2012 at 9:01 AM, Marion Jacquot
marion.jacq...@univ-fcomte.fr wrote:
We want to compute a pseudo R-squared for a model whose parameter
estimation was based on maximum likelihood (function likfit,
On Nov 7, 2012, at 6:54 AM, petre...@unina.it wrote:
Dear all,
I am interested to evaluate reclassification using net
reclassification improvement and Integrated Discrimination Index IDI after
survival analysis (Cox proportional hazards using stcox). I search a R
package or a R code that
Folks,
I have a data frame with columns 200401, 200402, ..., 201207, 201208.
These represent years/months. What would be the best way to sum these columns
by year? What about by quarter?
Thanks for your time,
KW
--
[[alternative HTML version deleted]]
Have you read the Introduction to R tutorial? This is discussed there,
I believe. If you have not, please do so before posting here further.
But ...
?tapply
?aggregate
?ave
Also the plyr package for user-friendlier approaches.
-- Bert
On Wed, Nov 7, 2012 at 9:32 AM, Keith Weintraub
Hi,
I am looking for a way to generate a matrix of random numbers in a way that
each row of the matrix would sum to 1 and that the numbers in the columns of
the matrix would have a uniform distribution. So far I have found several
ways to create random numbers that would sum to 1, but then the
i am connecting R 2.15 with Eclipse IDE 3.7,using [StatET] -:
http://www.walware.de/
i have installed rjava,rj-1.1,rj.gd-1.1,installed new software StatET
3.0-3.1 in eclipse ,etc as prerequisite,
i done all procedure as per eclipse says(Configure Launch R console
panel),but at end,when
Dear Prof Harell, great thanks for your solution to this. I have been trying
to figure this out last four weeks by reading loads of manuals and forums
around the net without success.
Once again thank you for the solution and the great option of shadowed Conf
int in the survplot
Best Regards
Dear all,
a program that worked well for weeks today gave me consistently the error
message
no lines available in input
referring to the lines
for (i in (0:(timeintervals-1)))
{ j=subjectquantity+6+i*(subjectquantity+7)
print (j)
results-read.table(file, header=F, skip=j,
Iam using R version 2.15 in a linux operating system. I have a matrix
consisting of the gene ids and their specific signal intensity values as
follows( a subset of the whole matrix) :
probes GSM362180GSM362181 GSM362188GSM362189 GSM362192
244901 5.094871713 4.626623079
I know when I enter this into R:
x = c(15, 10, 13, 7, 9, 8, 21, 9, 14, 8)
y = c(15, 14, 12, 8, 14, 7, 16, 10, 15, 12)
t.test(x,y,alt=less,var.equal=TRUE)
it shows:
Two Sample t-test
data: x and y
t = -0.5331, df = 18, p-value = 0.3002
alternative hypothesis: true difference in
Hi,
Can you please help me with this please?
What I am trying to do is call a vector from R function and used in the new
function
So I create 4 functions with these arguments
M11 - function(TrainData,TestData,mdat,nsam) {
ls - list()
I have few statments one of them is
vectx -
Thanks to David Winsemius for the replay. i use the latest update of
Hmisc package and I try as reported in the example:
set.seed(1)
library(survival)
x1 - rnorm(400)
x2 - x1 + rnorm(400)
d.time - rexp(400) + (x1 - min(x1))
cens - runif(400,.5,2)
death - d.time = cens
d.time - pmin(d.time,
Could someone explain to me what namespaces are loaded/saved when objects
are saved?
Specifically, I'm using this:
save(list = ls(all.names = TRUE, envir = envir), file = name, envir =
envir)
to save out everything from an environment.
Later, loading it on another machine, I'm surprised to see
HI,
Without data, it is a bit hard to know how your data looks like.
Anyway, try this:
set.seed(1)
dat2-data.frame(matrix(sample(10:150,50,replace=TRUE),ncol=10))
names(dat2)-c(paste0(20040,1:4),paste0(20050,1:3),paste0(20080,1:3))
library(reshape)
dat3-melt(dat2)
The best way to get an answer is to provide sample data and desired results
(computed by hand or by any other available means). See
http://stackoverflow.com/questions/5963269/how-to-make-a-great-r-reproducible-example.
In the vague question begets a vague answer department, I would use melt
On Nov 7, 2012, at 8:53 AM, frauke wrote:
Hi David, hi Rui,
thanks for your quick replies. I have replicated David's R results and
confirmed them with Minitab. Though I'm not sure what you are trying to tell
me with the code you wrote, David. Do you mean, I should use a dataframe
rather
Dear Frauke, good afternoon,
Could you tell me which excel function didnt work for regression analysis
and what excel version where you using?
Best regards,
Paul
El 07/11/2012 11:55, frauke fh...@andrew.cmu.edu escribió:
Hi David, hi Rui,
thanks for your quick replies. I have replicated
Is there a way of executing SAS codes in R environment?
Peter Maclean
Department of Economics
UDSM
[[alternative HTML version deleted]]
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PLEASE do read the
On Wed, Nov 7, 2012 at 3:31 PM, frespider frespi...@hotmail.com wrote:
Hi,
Can you please help me with this please?
What I am trying to do is call a vector from R function and used in the new
function
So I create 4 functions with these arguments
M11 -
On Nov 7, 2012, at 9:59 AM, petre...@unina.it wrote:
Thanks to David Winsemius for the replay. i use the latest update of Hmisc
package and I try as reported in the example:
set.seed(1)
library(survival)
x1 - rnorm(400)
x2 - x1 + rnorm(400)
d.time - rexp(400) + (x1 - min(x1))
cens -
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
project.org] On Behalf Of Paul Bernal
Sent: Wednesday, November 07, 2012 10:17 AM
To: frauke; r-help@r-project.org
Subject: [R] Excel Regression Function
Dear Frauke, good afternoon,
Could you tell
Dear list members!
I am looking for ''nice solution'' for (maybe) simple problem. I need a code
(small program) to calculate row index for max value (example below:
df1$values) by groups (example below: df1$groups).
df1 - data.frame(
groups = c(1,1,1,1,1,2,2,2,3,3,3,3),
values =
HI,
Forgot about the 2nd part (by quarter):
set.seed(1)
dat2-data.frame(matrix(sample(10:250,96,replace=TRUE),ncol=24))
names(dat2)-c(paste0(2004,paste0(0,1:9),sep=),paste0(2004,10:12),paste0(2005,paste0(0,1:9),sep=),paste0(2005,10:12))
library(reshape)
dat3-melt(dat2)
HI,
Could you tell me which version of R you are using? I guess paste0() works
from R.2.14.
YOu can use instead:
colnames(res1)[-1]-gsub([\\_],.,paste(Lab,colnames(res1)[-1],sep=))
res1
# ID Lab1.A Lab1.N Lab2.N Lab3.N
#1 a 1 1 1 0
#2 b 1 0 0 1
A.K.
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
project.org] On Behalf Of Peter Maclean
Sent: Wednesday, November 07, 2012 10:25 AM
To: R mailing list
Subject: Re: [R] Executing SAS Codes in R
Is there a way of executing SAS codes in R environment?
What uniform distribution do you want for the columns? The average
value of X_k given \sum X_i = 1 must be 1/n. If you start with
X_i ~ U(0,1), the result must be skewed.
If you generate X_i uniformly distributed on (0, 2/n), the conditional
distribution given the sum is 1 will be less skewed.
Hi,
One method will be:
row.names(df1[unlist(tapply(df1$values,df1$groups,FUN=function(x) x==max(x))),])
#[1] 4 8 11
#or
row.names(df1[as.logical(ave(df1$values,df1$groups,FUN=function(x)
x==max(x))),])
#[1] 4 8 11
A.K.
- Original Message -
From: Omphalodes Verna
Hi,
This is a humble try.
Matrix=function(n){Tab=cbind(runif(n,0,1))
for(i in 2:n)
{x=NULL
for(j in 1:n)
{x=c(x,runif(1,0,1-sum(Tab[j,])))}
Tab=cbind(Tab,x)
}
Could someone explain to me what namespaces are loaded/saved when objects
are saved?
Specifically, I'm using this:
save(list = ls(all.names = TRUE, envir = envir), file = name, envir =
envir)
to save out everything from an environment.
Later, loading it on another machine, I'm surprised to see
Hello,
If you have any advice on how to code a time-series HLM model in R?
The code I have right now is:
glmer(sale ~ agent_techmc*CultDistmc + ismc*CultDistmc + contactsmc*CultDistmc
+ pfmc + warranty + engineering_diff_res + Cust_internet +
Cust_mobility_mobile + durationmc + (1|
I've been using Amazon Elastic Mapreduce combined with RHadoop with great
success. The only real problem is that the default JAVA_HOME doesn't
points to a jdk that works with rJava, so you have to correct it. I've
been meaning to do a writeup on it and will update you once it's up.
Jamie Olson
Hi there,
Thanks forhelping. I really appreciate it.
The only thing is I get this error: Error in gsub([\\_], ., paste0(Lab,
colnames(res2)[-1])) :
could not find function paste0
Thanks.
Best,Farnoosh Sheikhi
Cc: R help r-help@r-project.org
Sent:
I certainly hope not!
There are of course many resources on R for SAS users and the like.
-- Bert
On Wed, Nov 7, 2012 at 10:24 AM, Peter Maclean pmaclean2...@yahoo.com wrote:
Is there a way of executing SAS codes in R environment?
Peter Maclean
Department of Economics
UDSM
This is a modified code if it helps.
Matrix=function(n,simulations){Tab=cbind(runif(n,0,1))
for(i in 2:simulations)
{x=NULL
for(j in 1:n)
Hello,
Though my function is equal to Arun's, it's wrapped by a different way
of returning the index.
which(unlist(tapply(df1$values, df1$groups, FUN=function(x) x == max(x
Hope this helps,
Rui Barradas
Em 07-11-2012 18:54, arun escreveu:
Hi,
One method will be:
Note that the unlist(tapply()) algorithm depends on the groups column
being in order. Here is one that works no matter how the
data frame is ordered.
which( with(df1, {tmp - logical(length(groups)) ; split(tmp, groups) -
lapply(split(values, groups), function(x)x==max(x)) ; tmp}))
[1] 4 8
Okay. Sorry for being vague in my earlier message. I had missed a few lines
from your message because they were hiding well in my own email. I am really
on the learning side with this, so it will take some time. Sorry.
There seem to be two issues: (1) Me preparing the data incorrectly and (2)
the
On Nov 7, 2012, at 10:48 AM, Albyn Jones wrote:
What uniform distribution do you want for the columns? The average
value of X_k given \sum X_i = 1 must be 1/n. If you start with
X_i ~ U(0,1), the result must be skewed.
If you generate X_i uniformly distributed on (0, 2/n), the
On Nov 7, 2012, at 19:34 , Bert Gunter wrote:
I certainly hope not!
fortune(reverse the procedure)
There are of course many resources on R for SAS users and the like.
-- Bert
On Wed, Nov 7, 2012 at 10:24 AM, Peter Maclean pmaclean2...@yahoo.com wrote:
Is there a way of executing SAS
Hello,
I have a time series dataset in long format (15 minute data over
approximately 2 years). The data set is composed of time series of multiple
sensors; much of the time series are duplicate dates and times, but of
different lengths.
I can plot the data converting the datetime to
I'm using Revolution R Enterprise.
This command worked perfectly.
Thank you so much for your help and time:-)
Best,Farnoosh Sheikhi
Cc: R help r-help@r-project.org
Sent: Wednesday, November 7, 2012 10:47 AM
Subject: Re: [R] pivot table
HI,
Could you tell
Hi,
I've successfully used it on a Linux setup, but when I try to load
rJava on Windows 7 64-bit (session info below) I get:
% R --vanilla
library(rJava)
Error : .onLoad failed in loadNamespace() for 'rJava', details:
call: dirname(this$RuntimeLib)
error: a character vector argument
Stop being surprised. Loaded packages are not part of envir (whatever that
is), nor are they part of the global environment. You have to reload any
packages needed separately from the load call.
---
Jeff Newmiller
Others have shown you ways to do what you asked, and what you asked happens
to also be FAQ 7.22 (but with terms different enough that that FAQ is not
obvious).
However the solutions that you are tending towards are running into the
problems addressed in fortune(106) and fortune(236), the
is there a way to avoid c() appending .0 and .1 to seed?
--8---cut here---start-8---
c(nons=1, seed=3)
nons seed ## good!
13
c(nons=1, seed=tab[1])
nons seed.0 ## don't want .0!
1 2344600
c(nons=1,
On Nov 7, 2012, at 9:50 AM, Jamie Olson wrote:
Could someone explain to me what namespaces are loaded/saved when objects
are saved?
None. That's what require() or library() or source() are for.
Specifically, I'm using this:
save(list = ls(all.names = TRUE, envir = envir), file = name,
Thibault,
It would be nice if LiblineaR() accepted data in the form of a sparse
matrix (it does not accept whatever e1071::read.matrix.csr returns).
It would also be nice if there were functions to read/write files in the
native liblinear file format; I am sure the original liblinear library
On 07/11/2012 3:53 PM, Sam Steingold wrote:
is there a way to avoid c() appending .0 and .1 to seed?
Don't give it a named vector. You can use the unname() function to
strip the names from tab:
c(nons=1, seed=unname(tab[1]))
--8---cut here---start-8---
On Nov 7, 2012, at 10:34 AM, Bert Gunter wrote:
I certainly hope not!
There are of course many resources on R for SAS users and the like.
One could even think of R-help as a distributed support group for
recovering-SAS-users.
-- Bert
On Wed, Nov 7, 2012 at 10:24 AM, Peter Maclean
On 08/11/12 09:09, peter dalgaard wrote:
On Nov 7, 2012, at 19:34 , Bert Gunter wrote:
I certainly hope not!
fortune(reverse the procedure)
See also fortune(SAS to R parser).
cheers,
Rolf
__
R-help@r-project.org mailing list
Thank you for your help.
That's an interesting point, I haven't thought about that.
Altough I would find it strange that I get a model, where just some
observations are missing, if the problem is due to invalid variable names.
That's the first thing I will try to change.
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Hi, I've followed these steps:
I set the MYSQL_HOME environmental variable like this:
c:\PROGRA~1\MySQL\MYSQLS~1.5, then I opened a command prompt, got to the
folder that contains the RMySQL_0.9-3.tar.gz file, and run the command:
c:\Program Files\R\R-2.15.1\bin\x64\R CMD INSTALL
Dear all,
I was wondering if you could give me any suggestions/help on the following
issue. So I carried out the analysis of my data using generalized linear
model (glm). After that, to check for multiple comparisons, I applied the
glht function from the multcomp package in R. The output,
Ben,
Can you provide a small example data set for
inds
so that we can run the code you have supplied?
It's difficult for me to follow what you've got and where you're trying to
go.
Jean
Benjamin Ward (ENV) b.w...@uea.ac.uk wrote on 11/06/2012 03:29:52 PM:
Hi all,
I have a list
On 07/11/2012 12:50 PM, Jamie Olson wrote:
Could someone explain to me what namespaces are loaded/saved when objects
are saved?
None are loaded or saved when you save the object, but the names of some
are saved. For example,
library(Hmisc) # not normally loaded/attached
x - zoom # copy a
Restoring some context:
DB wrote:
The fuction plm only uses 286 of these observations (also if the model is
changed to first differences and the effect to individual) and omits 23
observations due to na.action, but in my dataset they do not contain NAs.
Is this due to the Transformation
Hello
I have a large dataset to make a cluster analysis and I'm trying to use
Rclusterpp to do so.
Nevertheless in a sample matrix analysis (see
http://dl.dropbox.com/u/755659/gillnet.txt) I'm getting different results
from Rclusterpp and hclust.
Following the example from An Introduction to
Your example doesn't work here - you didn't show what 'tab' was.
Perhaps it was an output of table:
tab - table(c(16,16,17,17,17))
c(n=1, seed=tab[2])
n seed.17
1 3
c(n=1, seed=unname(tab[2]))
n seed
13
Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com
Or use [[ instead of [ (assuming you are only selecting one item)
tab - table(c(16,16,17,17,17))
c(n=1, seed=tab[2])
n seed.17
1 3
c(n=1, seed=unname(tab[2]))
n seed
13
c(n=1, seed=tab[[2]])
n seed
13
c(n=1, seed=tab[[17]])
n seed
13
Bill
Dear list members:
I am using the package fdrtool to calculate qval from my input p values.
My input pvalue ranged from 0.5-0. And the result I got for qval and lfdr are
all much less than 0.01, I feel very confused about the result. The command
used there is very easy:
fdrtool(pvalue,
It sounds like you are trying to generate a uniform distribution on the
simplex (e.g. compositional analysis where the values represent the
proportion of each constituent in the whole). If so, you probably want the
compositions package. Here's a simple example with just 3 parts so we can
plot the
On Wed, Nov 7, 2012 at 4:03 PM, Rolf Turner rolf.tur...@xtra.co.nz wrote:
On 08/11/12 09:09, peter dalgaard wrote:
On Nov 7, 2012, at 19:34 , Bert Gunter wrote:
I certainly hope not!
fortune(reverse the procedure)
See also fortune(SAS to R parser).
Yes, all delightful and amusing! But
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