Hi
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
project.org] On Behalf Of bgnumis
Sent: Sunday, March 17, 2013 4:12 PM
To: r-help@r-project.org
Subject: [R] zero line
Hi all,
I´m plotting cf (with two axis) and addind a shaded color up and
hi R users:
I have a dataset including u wind in x-axis and v wind in y-axis.
How can I plot the u,v wind data in vector or barb figure?
which command ?
thank you .
--
TANG Jie
[[alternative HTML version deleted]]
__
On 03/18/2013 08:50 PM, Jie Tang wrote:
hi R users:
I have a dataset including u wind in x-axis and v wind in y-axis.
How can I plot the u,v wind data in vector or barb figure?
which command ?
thank you .
Hi Jie,
Maybe the vectorField function (plotrix)?
Jim
As it turns out, I am working on this right now, and it's a bit of a challenge
to get the color gradient correct. I don't think this is really the right kind
of question for this list, so let's see if anyone has attempted it or has
ideas, and then take the conversation private. I can send you
ishi soichi soichi777 at gmail.com writes:
Has anyone plotted or is it possible to plot
CIE *xy* chromaticity diagram
http://en.wikipedia.org/wiki/File:CIE1931xy_blank.svg
I need this plot in color.
ishida
I think that plotting the spectral locus and the line of purples is trivial,
ishi soichi soichi777 at gmail.com writes:
Has anyone plotted or is it possible to plot
CIE *xy* chromaticity diagram
http://en.wikipedia.org/wiki/File:CIE1931xy_blank.svg
I need this plot in color.
ishida
sermon
And following up on my previous mail (diatribe), after
having
I am, unfortunately, well-aware of the limitations that Ken points out (and I
do appreciate him making these points). One can readily demonstrate the gamut
limitations by printing the diagram Ishida links to on different devices. My
hope is to get something close and include a disclaimer.
Unfortunately, a bad idea that looks good never dies.
That said, I still think that it is an interesting challenge
to create this graph by programming. I can imagine that if
you specified the coordinates at a certain number of points
in the interior and along the spectrum locus, you could use
At 14:56 17/03/2013, Wim Kreinen wrote:
Hello,
I have chi2-values from 2x2 contingency tables, each degree of freedom =1.
But I dont know the values of the contingency table. All I have in addtion:
The allelic odds ratio.
Now I would like to do a Q-Q-plot. Is that possible?
If I understand
Dear All,
is there a simple way that covers all regression models to extract the number
of samples from a data frame/matrix actually used in a regression model?
For instance I might have a data of 100 rows and 4 colums (1 response + 3
explanatory variables). If 3 samples have one or more NAs
Hi,
I have a 2 x 1 matrix of confidence intervals. The first column is the
lower and the next column is the upper. I want to cont how many times a
number say 12 lies in the interval. Can anyone assist?
--
Thanks,
Jim.
[[alternative HTML version deleted]]
Bert Gunter gunter.berton at gene.com writes:
But this has nothing to do with 7.31 and everything to do with operator
precedence and automatic casting from integers to logical and vice-versa.
I also think it fair to say that all (??) languages have these sorts of
malapropisms due to
Federico Calboli f.calboli at imperial.ac.uk writes:
is there a simple way that covers all regression models to extract
the number of samples from a data
frame/matrix actually used in a regression model?
For instance I might have a data of 100 rows and 4 colums
(1 response + 3
Hi Jim,
Try either of the following (untested):
sum( x[1, ] 12 x[2, ] 12)
sum(apply(x, 2, function(x) x[1] 12 x[2] 12))
where x is your 2x1000 matrix.
HTH,
Jorge.-
On Tue, Mar 19, 2013 at 12:03 AM, Jim Silverton wrote:
Hi,
I have a 2 x 1 matrix of confidence intervals. The
sum(M[1]12 12=M[2]) untested, no data
---
Jeff NewmillerThe . . Go Live...
DCN:jdnew...@dcn.davis.ca.usBasics: ##.#. ##.#. Live Go...
--
Thanks Regards,
Kamal Kishore
Research Scholar
Department of Biostatistics
National Institute of Mental Health and Neuro Sciences (NIMHANS)
Banglore-560029
Mob-+91-9591349768
Email:kamalkishorest...@gmail.com
[[alternative HTML version deleted]]
Hi All,
I have tried every fix on my try or tryCatch that I have found on the
internet, but so far have not been able to get my R code to continue with
the for loop after the lmer model results in an error.
Here is two attemps of my code, the input is a 3D array file, but really
any function
Hi Everyone,
I have a problem that keeps occurring using the biclust function (info
below).
Does anyone have an idea what is going wrong?
Best Wishes and thank you,
Bart
library(biclust)
data-read.table(file.choose(), header = T, sep = \t)
data2-as.matrix(data[,-1])
Dear All,
I would be very grateful for your help concerning the following question:
Below mentioned programme is available on net to generate longitudinal
data. Usually we get almost same parameter estimates as used to generate
the data. The problem here is I am not able to get it for data used
Hi Arun,
Thank u so much for your help. It helped me solve the problem
THANK YOU
-Yashvardhan Kajaria
On Thu, Mar 14, 2013 at 11:28 PM, arun smartpink...@yahoo.com wrote:
HI,
1.
date1-c(5 jan 2013, 1 jan 2013)
date1-as.Date(date1,format=%d %b %Y)
date1[1]-date1[2]
#Time difference of 4
I'm not aware of any routine that those the job, although I think that
it could be relatively easily done by multiplication the manifest
variable vector with the estimates for the specific effect.
To make an example:
v1; v2; v3; v4 are manifest variables that loads on one y latent
variablein
Hi, is there a way to assign observations from a dataset to nodes of a tree? Â
For example, if I have a data frame like the following:
ID Var1 Var2 Var3 ⦠VarX
1 Â Â Â Â Â
. Â Â Â Â Â
. Â Â Â Â Â
. Â Â Â Â Â
n     Â
And then run a classification tree with
Hi,
Try this:
set.seed(25)
mat1-
matrix(cbind(sample(1:15,20,replace=TRUE),sample(16:30,20,replace=TRUE)),ncol=2)
nrow(mat1[sapply(seq_len(nrow(mat1)),function(i)
any(seq(mat1[i,1],mat1[i,2])==12)),])
#[1] 17
set.seed(25)
mat2-
Hi everyone,
I'm trying to create unique filenames and then write a data frame into
these files. This is the code I am using.
str1-fname
str2-.ext.txt;
FILENAME-paste0(str1,str2);
write.table(df,
file=FILENAME,col.names=FALSE,row.names=FALSE,quote=FALSE,sep=\t);
Ideally, a file called
Thanks.
Jeff
On Mon, Mar 18, 2013 at 9:30 AM, Jeff Newmiller jdnew...@dcn.davis.ca.uswrote:
sum(M[1]12 12=M[2]) untested, no data
---
Jeff NewmillerThe . . Go Live...
Thats cumbersome, Arun.
sum(mat1[,1] 12 mat1[,2] 12)
[1] 17
will do the job and even faster:
system.time(replicate(1, sum(mat1[,1] 12 mat1[,2] 12)))
# user system elapsed
# 0.067 0.001 0.078
HTH,
Jorge.-
On Tue, Mar 19, 2013 at 1:06 AM, arun wrote:
Hi,
Try this:
Hi,
Jorge's method will be faster.
#system.time(res1-sum(apply(mat2,1,function(x) x[1]12 x[2]12))) #instead
of 2, it should be 1
# user system elapsed
# 0.440 0.000 0.445
system.time(res1-sum(apply(mat2,1,function(x) x[1]=12 x[2]12))) #
# user system elapsed
# 0.500 0.000
If you don't use apply() it would be even faster:
system.time(sum(mat2[,1] 12 mat2[,2] 12))
user system elapsed
0.004 0.000 0.003
Regards,
Jorge.-
On Tue, Mar 19, 2013 at 1:21 AM, arun wrote:
Hi,
Jorge's method will be faster.
#system.time(res1-sum(apply(mat2,1,function(x)
On Mar 18, 2013, at 7:36 AM, Federico Calboli f.calb...@imperial.ac.uk wrote:
Dear All,
is there a simple way that covers all regression models to extract the number
of samples from a data frame/matrix actually used in a regression model?
For instance I might have a data of 100 rows and
Dear Marko,
I can't quite tell whether this is an original question (as suggested by no
Re: in the subject field and no text from an earlier message) or an answer to
a question already posed (as suggested by the phrasing of the message); if the
latter, I apologize for missing the original
Hi
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
project.org] On Behalf Of Sahana Srinivasan
Sent: Monday, March 18, 2013 3:04 PM
To: r-help@r-project.org
Subject: [R] Problem with write.table
Hi everyone,
I'm trying to create unique filenames
Perhaps a crude but reliable way is to check the number of residuals, e.g.,
length(my.model$resid).
Brian
Brian S. Cade, PhD
U. S. Geological Survey
Fort Collins Science Center
2150 Centre Ave., Bldg. C
Fort Collins, CO 80526-8818
email: ca...@usgs.gov brian_c...@usgs.gov
tel: 970 226-9326
Hi R-help,
I am using the sem package to run confirmatory factor analysis (cfa) on some
questionnaire data collected from 307 participants. I have been running
R-2.15.3 in Windows in conjunction with R studio. The model I am using was
developed from exploratory factor analysis of a separate
On 18/03/2013 14:51, Cade, Brian wrote:
Perhaps a crude but reliable way is to check the number of residuals, e.g.,
length(my.model$resid).
Not very reliable (what about zero weights, for example?), and the
component is usually 'residuals'.
No one has so far mentioned nobs(), which seems to
On 18 Mar 2013, at 15:07, Prof Brian Ripley rip...@stats.ox.ac.uk wrote:
On 18/03/2013 14:51, Cade, Brian wrote:
Perhaps a crude but reliable way is to check the number of residuals, e.g.,
length(my.model$resid).
Not very reliable (what about zero weights, for example?), and the component
It would help if you told us what type of error you are getting and to also
provide sample data so that we could run it to see what happens. I use
'try' a lot to catch errors and have not had any problems with it.
On Mon, Mar 18, 2013 at 6:11 AM, lisa wang.li...@gmail.com wrote:
Hi All,
I
Dear Kevin,
See ?summary.objectiveML, and in particular the description of the fit.indices
argument. By default, the summary() method doesn't print many fit indices, but
many are available optionally.
I hope this helps,
John
John Fox
Sen.
I want to cont how many
times a number say 12 lies in the interval. Can anyone assist?
Has anyone else ever wished there was a moderately general 'inside' or 'within'
function in R for this problem?
For example, something that behaves more or less like
within - function(x, interval=NULL,
Ben Bolker bbolker at gmail.com writes:
Maybe FAQ 7.31 was referred to not for its direct relevance but as
a measure of the old-hand-ness of the people who will get the joke.
!1i|!0
Chuck
__
R-help@r-project.org mailing list
Dear John,
Thank you for taking the time to help me with this, I have been able to obtain
fit indices using the information that you provided.
Note to users searching archived R-help posts about this issue: The
instructional video I looked at (http://vimeo.com/38941937) gave fit indices
using
* Bert Gunter thagre.ore...@trar.pbz [2013-03-17 20:30:56 -0700]:
I also think it fair to say that all (??) languages have these sorts
of malapropisms due to operator precedence.
Except for those languages which do _not_ have operator precedence.
Like, e.g., Lisp.
--
Sam Steingold
Sam:
Yes. Good point. (which is why my ?? was necessary).
-- Bert
On Mon, Mar 18, 2013 at 10:05 AM, Sam Steingold s...@gnu.org wrote:
* Bert Gunter thagre.ore...@trar.pbz [2013-03-17 20:30:56 -0700]:
I also think it fair to say that all (??) languages have these sorts
of malapropisms
Besides what others have suggested, there are at some packages for writing
Excel files directly, and either of those might have a way to write
something that Excel will recognize as a hyperlink.
xlsx, XLConnect are both Java-based; I would start with these.
-Don
--
Don MacQueen
Lawrence
## Can someone suggest a simpler expression than either of these, with the
goal
## of taking a long matrix into a wide one with exactly one of the factors
converted to
## columns and all the rest retained as factors. I want something that
generalizes beyond
## the three factors illustrated here.
here is the error:
aa-metatrialstry(beta_5_50)
Error in asMethod(object) : matrix is not symmetric [1,2]
metatrials, the function that i am attempting to convert with try/tryCatch,
gives me back a matrix with as many rows are there are simulations (z) in
the aray with dim(x,y,z). with the
Hello
I am trying to find an automated way of fitting a mixture of normal and
log-normal distributions to data which is clearly bimodal.
Here's a simulated example:
x.1-rnorm(6000, 2.4, 0.6)x.2-rlnorm(1, 1.3,0.1)X-c(x.1, x.2)
hist(X,100,freq=FALSE, ylim=c(0,1.5))lines(density(x.1), lty=2,
I have this little data.frame
http://dl.dropbox.com/u/102669/nanotna.rdata
Two column contains NA, so the best thing to do is use na.locf function (with
fromLast = T)
But locf function doesn't work because NA in my data.frame are not recognized as
real NA.
Is there a way to substitute fake NA
Hi Kevin,
With sem package use : summary(X,fit.indices=c(RMSEA,...)) to get
RMSEA or anothers fit indices.
See the section ML.methods in sem.pdf
Hervé
Hervé
Le 18/03/2013 16:00, Kevin Cheung a écrit :
Hi R-help,
I am using the sem package to run confirmatory factor analysis (cfa) on some
I have several rasters that I want to do some calculations ,basically
calculating the moving average.
dir2 - list.files(D:\\2010+2011, *.bin, full.names = TRUE)
saf=stack(dir2)
movi - overlay(stack(saf),fun=function(x) movingFun(x, fun=mean,
n=3, na.rm=TRUE))
I'm sorry for the really vague subject line but I am not sure how to
succinctly describe what I am doing and what the problem is.
But, here goes:
1. I have data with two-way data with frequencies. Below is an
example, though in reality I am looking at about 10 different variables
that I am
On 18-03-2013, at 16:49, Pete freeri...@gmail.com wrote:
I have this little data.frame
http://dl.dropbox.com/u/102669/nanotna.rdata
Two column contains NA, so the best thing to do is use na.locf function (with
fromLast = T)
But locf function doesn't work because NA in my data.frame
Hi,
library(reshape2)
dcast(tmp.n,X1~X2,value.var=Y)
# X1 0 2 4
#1 0 83 12 14
#2 1 107 25 27
#3 2 47 14 28
#4 3 27 4 13
#5 4 38 9 18
#6 99 1 0 0
A.K.
- Original Message -
From: plessthanpointohf...@gmail.com plessthanpointohf...@gmail.com
To: r-help@r-project.org
On Mar 18, 2013, at 12:44 PM, plessthanpointohf...@gmail.com wrote:
I'm sorry for the really vague subject line but I am not sure how to
succinctly describe what I am doing and what the problem is.
But, here goes:
1. I have data with two-way data with frequencies. Below is an example,
Dear Kevin,
In earlier versions of the sem package, the summary() method for model objects
produced many (and from version to version, an increasing number of) fit
indices by default. For various reasons, I decided to provide only the LR
chisquare test for the model, the BIC, and the AIC by
Trying to make a strip in lattice xyplots to display shingle intervals
with a sensible number of digits:
First I make a 2x2 matrix with rounded values of the shingle itnervals:
lec - round(matrix(unlist(levels(equal.count(sd$Frother))), ncol = 2,
byrow = TRUE), 3)
Next I make a custom strip
That works great! I didn't even know there was a reshape2 package.
Thanks!
Jen
On 03/18/2013 01:49 PM, arun wrote:
Hi,
library(reshape2)
dcast(tmp.n,X1~X2,value.var=Y)
# X1 0 2 4
#1 0 83 12 14
#2 1 107 25 27
#3 2 47 14 28
#4 3 27 4 13
#5 4 38 9 18
#6 99 1 0 0
A.K.
Hello!
I am having an issue with the OrgMassSpecR package. I run my HPLC using a
DAD detector. My raw data is exported form chemstation as a csv file. I
then upload the csv into Rstudio no problem. Using the DrawChromatogram
function, I get a nice chromatogram, and my retention time, peak
This works really great, too.
Thanks for this option.
I am glad I have two ways to accomplish this.
I KNEW it was going to be that simple. I was convinced I was making more
out of it than I needed to and I'm glad to see I was right.
Best,
Jen
(It's fun to be new at something when I'm this
Hi list,
I am curious how to stop the set.seed(), I don't want the same repeated
random number. I know I can set it to a different seed, but I don't want
to go through the trouble of setting different seed every time.
Thanks,
Mike
[[alternative HTML version deleted]]
z.boxplot- function(lst){
new.list- lapply(lst,function(x) x[x$FDR0.01,])
print(new.list)
par(mfrow=c(2,2))
b1-lapply(names(new.list),function(x) lapply(new.list[x],function(y)
boxplot(FDR~z,data=y,xlab=Charge,ylab=FDR,main=x)))
}
z.boxplot(ListFacGroup) #prints new.list
If you want to
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
project.org] On Behalf Of C W
Sent: Monday, March 18, 2013 11:27 AM
To: r-help
Subject: [R] How to stop set.seed() besides exiting out of R?
Hi list,
I am curious how to stop the set.seed(), I don't
set.seed(100)
for (i in 1:100){
a - rnorm(1000, mean=0, sd=1)
hist(a)
}
#Now say, I want to simulate without being confined to set.seed(100), I
just want to get a simulation like how R normally does it.
Mike
On Mon, Mar 18, 2013 at 2:40 PM, Nordlund, Dan (DSHS/RDA)
nord...@dshs.wa.gov
If you type DrawChromatogram you can see the method used to calculate the peak
area. Looks to me like you could easily hack it if you wanted. The relevant
part about peak areas is this:
for (j in 1:n) {
k - (j%%n) + 1
x[j] - peakTime[j] * peakIntensity[k] -
Hi Chris,
I am having an issue with the OrgMassSpecR package. I run my HPLC
using a DAD detector.
You are on a statistics IDE related mailing list. Have mercy with
people from other fields and tell them that you are using a diode array
to measure UV/VIS absorption. (And possibly let them know
As I understand it, how R âânormallyâ does it is to use the system clock
to set the seed once per session, unless you use set.seed() to set a new seed.
You chose to set the seed to a different value. But from that point on, the
pseudo random number generation continues in the same way
On 18-03-2013, at 19:57, Pietro freeri...@gmail.com wrote:
Yes, it's true Berend!
What i do is simply use read.xlsx function
db - read.xlsx2(c:/mydb.xlsx,1,as.data.frame=T)
This is excel file i use:
http://dl.dropbox.com/u/102669/mydb.xlsx
I don't have the required packages
Hi All,
I'm developing a ksvm application. I need to use the results obtained from ksvm
in R to construct or restore the ksvm formula and further use this formula to
predict new data.
The ksvm class contains xmatrix, ymatrix, coefficients, alpha, b and fitted
value. Taking linear svm as an
Yes, I agree with you. I guess what I was really looking for is a function
like UNset.seed()?
By having set.seed(), I can have reproducible code. But what if I want to
check my work against what's produced from set.seed(100)?
I really want to escape from the shadow of set.seed(), can I unset
Hi Bryan,
Division by 2 is correct, comes from trapezoid calculation.
The modulo line is a funny way of producing c (2 : n, 1)
Best,
Claudia
Am Mon, 18 Mar 2013 15:00:06 -0400
schrieb Bryan Hanson han...@depauw.edu:
If you type DrawChromatogram you can see the method used to calculate
the
Yes, it's true Berend!
What i do is simply use read.xlsx function
db - read.xlsx2(c:/mydb.xlsx,1,as.data.frame=T)
This is excel file i use:
http://dl.dropbox.com/u/102669/mydb.xlsx
I can't find a way to import as numeric.
My objective is to be able to work (in R) with my NA's
At 18.46
No, you cannot unset the seed. You can set it to a different value, but a the
random number generators always need a starting seed. If you donât set one,
R will set one for you , you just wonât know what it is. And as a practical
matter, given a sequence of random numbers you canât
Hello all,
I have just completed a principal components analysis and now which to create
sub scales out of my factors. Does anyone know how to do this in R?
Thanks!!
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
Hello,
There _is_ a function ?within. Maybe your function can be named 'between'
Rui Barradas
Em 18-03-2013 16:16, S Ellison escreveu:
I want to cont how many
times a number say 12 lies in the interval. Can anyone assist?
Has anyone else ever wished there was a moderately general 'inside'
I am not sure of this, but I think you can unset the seed by removing the
dataset .Random.seed
from the global environment. E.g.,
set.seed(1)
runif(5)
[1] 0.2655087 0.3721239 0.5728534 0.9082078 0.2016819
rm(list=.Random.seed, envir=globalenv())
runif(5)
[1] 0.5952379 0.3355091 0.8820192
Your request is meaningless. The seed itself is effectively overwritten each
time a random number is requested. It is only the repeatability of the sequence
of random numbers following the set.seed call that is reproducible. You can set
the seed to something else, but there is always a seed
Thanks, William. You read my mind.
Cheers,
Mike
On Mon, Mar 18, 2013 at 4:00 PM, Jeff Newmiller jdnew...@dcn.davis.ca.uswrote:
Your request is meaningless. The seed itself is effectively overwritten
each time a random number is requested. It is only the repeatability of the
sequence of
Try this
Open the spreadsheet in Excel. Select all of the data click Copy. Don't
close Excel.
Open R and type the following command:
Foglio1 - read.table(clipboard-128, header=TRUE, sep=\t)
Now take a look at the structure of the data.frame
str(Foglio1)
'data.frame': 1489 obs. of 15
On 18/03/2013 19:59, William Dunlap wrote:
I am not sure of this, but I think you can unset the seed by removing the
dataset .Random.seed
from the global environment. E.g.,
set.seed(1)
runif(5)
[1] 0.2655087 0.3721239 0.5728534 0.9082078 0.2016819
rm(list=.Random.seed, envir=globalenv())
The my.symbols and ms.arrows functions in the TeachingDemos package may
help.
On Mon, Mar 18, 2013 at 3:50 AM, Jie Tang totang...@gmail.com wrote:
hi R users:
I have a dataset including u wind in x-axis and v wind in y-axis.
How can I plot the u,v wind data in vector or barb figure?
Hi all,
I'm having problems finding the correct format for a command.
I would like to write some text on a plot.
I'm using the following command:
text(x,y,text here, srt=90)
I would like the text to read:
capacity 10^3 m^3
(with ^ denoting superscript (i.e. each '3' as superscript).
I've
It appears that you MUST use the colClasses= argument with read.xlsx2:
Foglio1 - read.xlsx2(mydb.xlsx, 1, colClasses=c(Date, rep(numeric,
14)))
However, e and n are converted to NaN not NA so you would need to convert
those columns (at least, I didn't check for missing values in the other
-Original Message-
From: Prof Brian Ripley [mailto:rip...@stats.ox.ac.uk]
Sent: Monday, March 18, 2013 1:22 PM
To: William Dunlap
Cc: r-help
Subject: Re: [R] How to stop set.seed() besides exiting out of R?
On 18/03/2013 19:59, William Dunlap wrote:
I am not sure of this, but I
On Tue, Mar 19, 2013 at 9:29 AM, Benjamin Gillespie gy...@leeds.ac.ukwrote:
Hi all,
I'm having problems finding the correct format for a command.
I would like to write some text on a plot.
I'm using the following command:
text(x,y,text here, srt=90)
I would like the text to read:
Hello,
Something like this?
plot(1, type = n)
text(1,1, expression(capacity ~ 10^3 ~ m^3))
Hope this helps,
Rui Barradas
Em 18-03-2013 20:29, Benjamin Gillespie escreveu:
Hi all,
I'm having problems finding the correct format for a command.
I would like to write some text on a plot.
I'm
HI,
Not sure whether this is what you wanted.
library(reshape2)
result.dcast-dcast(meltTest,A+D~H,value.var=M)
attr(result.reshape,reshapeWide)-NULL
row.names(result.reshape)-1:nrow(result.reshape)
identical(result.reshape,result.dcast)
#[1] TRUE
result.dcast
# A D I J K L
#1 B E 1 2 3
Richard M. Heiberger rmh at temple.edu writes:
## Can someone suggest a simpler expression than either of these, with the
goal
## of taking a long matrix into a wide one with exactly one of the factors
converted to
## columns and all the rest retained as factors. I want something that
Hello
I am trying to find an automated way of fitting a mixture of normal and
log-normal distributions to data which is clearly bimodal.
Here's a simulated example:
x.1-rnorm(6000, 2.4, 0.6)
x.2-rlnorm(1, 1.3,0.1)
X-c(x.1, x.2)
hist(X,100,freq=FALSE, ylim=c(0,1.5))lines(density(x.1), lty=2,
You posted this earlier. Do not repost, please. It was seen.
-- Bert
On Mon, Mar 18, 2013 at 3:28 PM, To . . kid...@hotmail.com wrote:
Hello
I am trying to find an automated way of fitting a mixture of normal and
log-normal distributions to data which is clearly bimodal.
Here's a
Dear all,
I am wondering if what would be the simple way to develop a simple web
application that runs R. That is, the web application allows any user upload a
dataframe as a variable to my web server, a linux-based apache, and then run a
R package (my package) on the variable that should
I can't offer any advice, but I feel like you could probably get a good
start on this by looking through the archives.
On Mon 18 Mar 2013 06:55:33 PM CDT, John linux-user wrote:
Dear all,
I am wondering if what would be the simple way to develop a simple web
application that runs R. That
I've got a complicated semi-parametric model that I'm fitting with
mgcv. I start with a model based on theory. Its got lots of
interaction terms. I want to winnow it down: removing each interaction
term or un-interacted main effect one by one, checking the AIC, and
retaining the model that
Thanks for reply, but which archives?
Thanks again.
John
From: Stephen Sefick ssef...@gmail.com
Cc: r-help@r-project.org r-help@r-project.org
Sent: Monday, March 18, 2013 8:02 PM
Subject: Re: [R] R web application development
I can't offer any advice, but
thank you all.
the dcast formulation is what I am looking for. That version of the
formula A+D ~ H
also works with the original cast function.
result.cast - cast(A+D ~ H, value=M, data=meltTest)
It generalizes to a four-factor example, as requested.
This ftable solution didn't do what I
Just to add, I've been playing around with select=TRUE in mgcv, and it
does seem that it could work if I were to specify all of the nested
two-way interactions in my three-way interactions (see the toy example
below). But the problem is that I don't have enough degrees of freedom
to feed such
I generally use the Markmail search engine but others use the Newcastle
resource. Some of other ones can be found with perusal of the Posting Guide and
Mailing list info page.
http://markmail.org/search/?q=list%3Aorg.r-project.r-help
On Mar 18, 2013, at 5:11 PM, John linux-user wrote:
Hello,
I have a matrix of simulated data that I want to plot as a 3D surface using
RGL. Have followed the documentation carefully, but my plot only contains a
weird single slice of the data.
The actual RGL library and dependance seem fine as all of the demo code plots
beautifully.
The
Hi,
Your example is not reproducible.
What is d in your command?
Regards,
Pascal
On 19/03/13 10:21, Noah Silverman wrote:
Hello,
I have a matrix of simulated data that I want to plot as a 3D surface using RGL. Have
followed the documentation carefully, but my plot only contains a weird
Oops, that was a type.
d is just y.
If you want to reproduce, I put the entire matrix, as a csv here:
http://pastebin.com/gniyD4Rc
Thanks,
--
Noah Silverman, M.S.
UCLA Department of Statistics
8117 Math Sciences Building
Los Angeles, CA 90095
On Mar 18, 2013, at 6:58 PM, Pascal Oettli
Dear R Users,
I have data for more than 3 years. For each year I want to find the day
corresponding to Jaunary 1 of that year. For example:
x - c('5/5/2007','12/31/2007','1/2/2008')
#Convert to day of year (julian date) -
strptime(x,%m/%d/%Y)$yday+1
[1] 125 365 2
I want to know how to
Hi Janesh,
On Mar 18, 2013, at 10:49 PM, Janesh Devkota wrote:
Dear R Users,
I have data for more than 3 years. For each year I want to find the day
corresponding to Jaunary 1 of that year. For example:
x - c('5/5/2007','12/31/2007','1/2/2008')
#Convert to day of year (julian date) -
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