Fine !
Many many thanks!
Mario
-Messaggio originale-
Da: Bernd Weiss [mailto:bernd.we...@uni-koeln.de]
Inviato: venerdì 18 aprile 2014 15.58
A: petre...@unina.it; R-help@r-project.org
Oggetto: Re: [R] interpreting weight in meta-analysis of proportion
On 18.04.2014 13:02,
On 18/04/2014, 6:07 PM, Gene Leynes wrote:
A few years ago R changed the way help was handled so that the HTML
files are no longer available in the library directory. Around that
time the R example files that used to be in some of the libraries also
vanished.
I'm wondering where the r-ex
Hello Milan
It had worked perfectly before, but now I am trying on a different text file
but using the trick you showed I just get the headers in the output and that
too as row.names and X.
*code:*
corr - read.table(E:/temp/corrosion
data.txt,header=T,fileEncoding=UTF-8-BOM)
dput(corr)
On 19.04.2014 14:30, starter wrote:
Hello Milan
It had worked perfectly before, but now I am trying on a different text file
but using the trick you showed I just get the headers in the output and that
too as row.names and X.
*code:*
corr - read.table(E:/temp/corrosion
Thank you for catching that, Boris. I'm surprised, given that there is no
mention of sense of direction in the package documentation.
Scott Waichler
-Original Message-
From: Boris Steipe [mailto:boris.ste...@utoronto.ca]
Sent: Friday, April 18, 2014 3:49 PM
To: Waichler, Scott R;
SOLVED: (mostly)
So I'll post this here in case it helps someone in the future.
fileName - '001.xml'
doc - xmlTreeParse(fileName,
handlers=list(comment=function(x,...){NULL}), asTree = TRUE)
root - xmlRoot(doc)
Connected_To - xmlToDataFrame(getNodeSet(root,
I read the Foreign Function Interface for R.
The documentation does not prescribe the calling convention though.
Does that mean __stdcall on W32 and __cdecl for Linux?
Regards,
Alex van der Spek
__
R-help@r-project.org mailing list
Hi,
The rownames part is not clear as your expected output and input files didn't
show them as rownames.
##Suppose you have all the files in a folder
##here I am creating the names of those files
files1 - paste0(sample, rep(1:777, each=29),chr,1:29,.txt)
length(files1)
#[1] 22533
lst1 -
Dear R-Community,
The cex values in curve seem to be being ignored. I have searched
previous help questions and also the web generally, and cannot find this
being a major problem so I am suspicious of something odd happening but
I am at a loss to work out why.
I am trying to plot this:
b1
Thank you for your reply.
I discovered the OlsonNames() function to get the time-zone names in my
system. Rui get a warning message when using a not recognized tz. On my
system this doesn't succed.
I solved as follow:
dt1 = as.POSIXct(2014-04-18 09.00, format=%Y-%m-%d %H.%M, tz =
Europe/Rome)
Hi,
To convert coerce the data set to transaction data set I used the code
trans4 - as(split(a[,Cust_ID], a[,Parts]), transactions)
but I am getting the following error-
Error in as(split(a[, Cust_ID], a[, Parts]), transactions) : nomethod
or default for coercing “list” to “transactions”
Dear R Developers and Help Specialists;
I downloaded and installed R to learn and use it during solutions of my
scientific studies.
At first, I got in trouble with it with the menu languages. It is in Turkish
and I have to change it to English but I can not find where the language
Hi all,
I am using an old code (probably written for R 2.5) and it stops when
calling rainbow() with gamma argument. I saw that gamma argument is not
present in newer version of R rainbow function. How can I translate this
line of code:
rainbow(100, s = 1.0, v = 0.75, start = 0.0, end = 0.75,
I forgot:
sysname
release
Linux
3.5.0-48-generic
version
#72-Ubuntu SMP Mon Mar 10 23:18:29 UTC 2014
2014-04-19 14:03 GMT+02:00 Nicola Sturaro Sommacal
Hi All,
I need to be able to manipulate the names of the coefficients from
*ranef()*.
If there is any missing data when fitting a mixed model using lmer, no
estimate is returned for the associated level for that random effect. Thus
if the data input for regions had levels
*Region*
Don't know if this helps, but works for me on a PC under Windows 7
with the default graphics device. Try a different device, maybe (e.g.
pdf) ??
-- Bert
Bert Gunter
Genentech Nonclinical Biostatistics
(650) 467-7374(650) 467-7374
Data is not information. Information is not knowledge. And
Search!
Googling on How to set language for R produced this:
https://stat.ethz.ch/pipermail/r-help/2008-October/178503.html
If this is not what you need, a little more searching may be required.
Cheers,
Bert
Bert Gunter
Genentech Nonclinical Biostatistics
(650) 467-7374
Data is not
Have you looked at ?rainbow ?
Is there a reason why you don't simply leave the gamma parameter away?
Try:
pie(rep(1,100), col=rainbow(100, s = 1.0, v = 0.75, start = 0.0, end = 0.75))
Cheers,
B.
On 2014-04-19, at 6:05 AM, Francesco Brundu wrote:
Hi all,
I am using an old code (probably
You may want to read about generalized linear modelling and link
functions for forming appropriate categorical variable/link function.
See documentations in R: ?glm, ?family and ?inverse.gaussian. Also
look at the original paper of Nelder, John; Wedderburn, Robert , it is
available freely with
Not sure how would you do that but there is a package SEM on CRAN for
structural equation models.
On 20 April 2014 01:10, thanoon younis thanoon.youni...@gmail.com wrote:
thank you so much Suzen
i want to use bayesian analysis in structural equation models with ordered
categorical data and i
If it MUST be parameter-compatible with the old call, you could just add ...
to your local version of rainbow. The unused parameter will then be dropped.
Here's how:
# The original creates an error ...
rainbow(100, s = 1.0, v = 0.75, start = 0.0, end = 0.75, gamma = 1.5)
Error in rainbow(100,
Hi,
Without a reproducible example using ?dput() or the package name, it is a bit
difficult to comment.
Assuming that you used:
library(arules)
data(AdultUCI)
AdultUCI$ID - 1:nrow(AdultUCI)
lst1 - split(AdultUCI[,ID], AdultUCI[,marital-status])
as(lst1, transactions)
#transactions in
Hi Satish,
Using your code:
part-read.csv(spares.csv)
str(part)
#'data.frame': 838 obs. of 1 variable:
# $ Cust_ID.Parts: Factor w/ 838 levels 100\tAIR\tFILTER\tHOUSING\t,..: 161
333 495 727 728 768 769 770 784 785 ...
#I guess you have only two columns in the dataset
lines1 -
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