You appear to be using a package that are not even on CRAN, much less base R,
so you need to tell us that in your (missing) reproducible example. It is
self-described as primitive, so don't be surprised when it acts odd.
Note that your creation of an exposed Google account in your previous
Sarah Goslee sarah.gos...@gmail.com writes:
I took a look at apparent gender among list participants a few years ago:
https://stat.ethz.ch/pipermail/r-help/2011-June/280272.html
Same general thing: very few regular participants on the list were
women. I don't see any sign that that has
Dear All,
i need a help on how I can create a new column on my dataset and use it as
argument inside the following function. The column i want to create and
vary is Evapolation. It varies that'S why I need it as argument.
When I make it like this is not working:
On Mon, Nov 24, 2014 at 12:34 PM, Sarah Goslee sarah.gos...@gmail.com wrote:
I took a look at apparent gender among list participants a few years ago:
https://stat.ethz.ch/pipermail/r-help/2011-June/280272.html
Same general thing: very few regular participants on the list were
women. I don't
Dear All,
I am getting this error and don't know why it comes. can you please help ?
Error in if (data$Rain[i_NA] == 60) { :
missing value where TRUE/FALSE needed
The loop is :
indicNAs - which(data$Rain %in% NA)
ind_nonleap = c() # NAs due to non leap years
ind_nonrecord = c() # NAs due
Hi
Error message seems to be clear
Error in if (data$Rain[i_NA] == 60) { :
missing value where TRUE/FALSE needed
data$Rain[i_NA] produces probably NA
x-NA
if(x==60) print(1+1) else print(Errrorrr)
Error in if (x == 60) 1 + 1 : missing value where TRUE/FALSE needed
x-10
if(x==60)
You do not tell us what you are trying to do but I think there is
something wrong in the logic of your thinking as on the one hand you are
selecting just precisely those elements of data$Rain which are NA and
then testing whether any of them equals 60.
On 25/11/2014 12:19, Frederic
If you do not want to use the loop, a function called 'reshape' may be
useful:
df - data.frame(a=1:5,b=letters[1:5],c1=1:5,c2=2:6,c3=3:7,c4=4:8)
out2 - reshape(data=df, direction=long, varying=list(3:6),
times=paste(c,1:4,sep=))
out2
a b time c1 id
1.c1 1 a c1 1 1
2.c1 2 b c1 2
Thanks a lot, guys!
On Tue, Nov 25, 2014 at 9:42 AM, Lee, Chel Hee chl...@mail.usask.ca wrote:
If you do not want to use the loop, a function called 'reshape' may be
useful:
df - data.frame(a=1:5,b=letters[1:5],c1=1:5,c2=2:6,c3=3:7,c4=4:8)
out2 - reshape(data=df, direction=long,
On 24 Nov 2014, at 18:34 , Sarah Goslee sarah.gos...@gmail.com wrote:
I took a look at apparent gender among list participants a few years ago:
https://stat.ethz.ch/pipermail/r-help/2011-June/280272.html
Same general thing: very few regular participants on the list were
women. I don't see
Hi,
I am trying to use rmvDAG in pcalg package to generate data from DAG
structure. One thing I found is that when the number of variables gets
large, there can be really large numbers in the data matrix. I played
around with different parameters and it looks like the same case.
library(pcalg)
Greetings,
I am having a big issue with RStudio segfaulting recently. It is
becoming a very big problem for me. I have attached most of the
information to the support site but no one has responded there. Can
someone please help me fix RStudio?
Thanks for the responses so far.
The gender ratio in R should reflect the gender ratio of the potential
users, as this is the pool the R users / developers are coming from.
I agree with this, but then again I don't think R really has 0% female
users/developers as the R member list suggests.
Dear all,
I can't convert the result of aggregate function in a dataframe. My data
looks like:
mydata - structure(list(ID = c(11, 11, 460, 460, 986, 986, 986, 986, 1251,
1251, 1251, 1251, 1251, 1251, 1251, 1251, 1801, 1801, 1801, 1801
), YEAR = c(2009, 2010, 2010, 2011, 2008, 2009, 2010, 2011,
Hello All,
I am working on BackTesting Strategies on stocks using daily prices.
Initially the size of data was very limited and can be easily handled using
R and SQL, but now my analysis has been extending on large set of data. Can
anyone suggest me the best packages available for handling large
Nice graph, Scott, thanks!
Based on your code I plotted not the absolute numbers but the ratios,
which show slowly increasing relative participation of female Rhelpers
over time (red = women, blue=men, black=unknown). After a c. 5% female
contribution in 1998, this has grown to about 15% now.
Dear list,
I have used the ‘polr’ function in the MASS package to run an ordinal logistic
regression for an ordinal categorical response variable with 15 continuous
explanatory variables.
I have used the code (shown below) to check that my model meets the
proportional odds assumption following
I just saw this comment and I agree with Peter. I have occasion to ask
questions and get help on the R forum but I am not a programmer and use
programs as I need them and I suppose I must comment more often. :)
On 11/25/14, 11:28 AM, peter dalgaard pda...@gmail.com wrote:
On 24 Nov 2014, at
Hello fellow R users,
I have recently updated to R 3.1.2. When trying to plot an hclust object to
generate the dendrogram I get the following error:
Error in .Internal(dend.window(n, merge, height2, hang, labels, ...)) :
there is no .Internal function 'dend.window'
I am indeed using R3.1.2
Hi,All my data is presently locked in a Microsoft access database. This has
huge data in a number of large tables. Using RODBC and connecting to it takes
too long a time, sometimes making the system to hang up.
To make things more manageable, I have tried to transfer the data to manageable
On 25-11-2014, at 00:58, Stack Kororā i.am.st...@gmail.com wrote:
Greetings,
I am having a big issue with RStudio segfaulting recently. It is
becoming a very big problem for me. I have attached most of the
information to the support site but no one has responded there. Can
someone please
On 11/25/2014 04:11 AM, Scott Kostyshak wrote:
On Mon, Nov 24, 2014 at 12:34 PM, Sarah Goslee sarah.gos...@gmail.com wrote:
I took a look at apparent gender among list participants a few years ago:
https://stat.ethz.ch/pipermail/r-help/2011-June/280272.html
Same general thing: very few regular
do.call(rbind, TAB$x)
[,1] [,2]
1 GR.3.8 GR.3.8
2 GR.3.1 GR.3.8
4 GR.3.8 GR.3.8
5 GR.3.7 GR.3.7
6 GR.3.8 GR.3.8
7 GR.3.1 GR.3.8
9 GR.3.8 GR.3.8
10 GR.3.7 GR.3.7
11 GR.3.1 GR.3.1
12 GR.3.8 GR.3.8
13 GR.3.1 GR.3.8
15 GR.3.8 GR.3.8
16 GR.3.1 GR.3.1
17 GR.3.8 GR.3.8
18 GR.3.1 GR.3.8
20
Or just modify your aggregate() command:
TAB - aggregate(mydata$CODE, by=list(ID=mydata$ID,
+YEAR=mydata$YEAR), FUN=paste0, collapse=, )
TAB
ID YEAR x
1 986 2008 GR.3.8
2 1251 2008 GR.3.1, GR.3.8
3 1801 2008 GR.3.8
411 2009 GR.3.7
5
Look at the task view for High Performance Computing (
http://cran.r-project.org/web/views/HighPerformanceComputing.html) there is
a section on packages for large memory and out-of-memory analyses. There
are also sections on parallel computing which is one way to deal with large
data if you have
Counting rows is not something RODBC is supposed to do. That is a very basic
SQL query that you can use RODBC to execute:
SELECT COUNT(*) FROM yourtablename
---
Jeff NewmillerThe .
Reproducible example???
(I know from noddink about hclust, but I tried the example from the help
page and it plotted without any problem.)
cheers,
Rolf Turner
On 26/11/14 06:13, Michael Mason wrote:
Hello fellow R users,
I have recently updated to R 3.1.2. When trying to plot an hclust
Hi,
This problem has me stumped so I thought I'd ask the experts. I'm trying
to create a pretty summary table of some data (which patients have had
what tests at what times). Ideally I'd like to knitr this into a pretty
PDF for presentation.
If anyone has pointers I'll be grateful.
On 11/25/2014 12:09 PM, Berend Hasselman wrote:
If SL is Snow Leopard (no system mentioned by you) this belongs on R-SIG-Mac.
Actually, I did mention it:
My OS: Scientific Linux 6.6
But this is really for RStudio support. If RStudio needs fixing the RStudio
people will have to do that.
I
On 11/25/2014 12:01 PM, Mark Sharp wrote:
Have you tried the current version of R, 3.1.2?
I have not. I haven't had many issues in the past using what was in the
EPEL repos. Let me take one of my dev boxes and give it a try.
I will post back what I find.
Thanks!
signature.asc
Description:
On 26/11/14 08:53, Michael Mason wrote:
Here you are. I expect most folks won't get the error.
N = 100; M = 1000
mat = matrix(1:(N*M) + rnorm(N*M,0,.5),N,M)
h = hclust(as.dist(1-cor(mat)))
plot(h)
Error in .Internal(dend.window(n, merge, height2, hang, labels, ...)) :
there is no
Tom,
If you are wanting PDF as your output, are you wanting to use LaTeX or Markdown
with knitr. LaTeX will give you more options. You have not shown an attempt to
use either for your table construction. Can you define what you mean by pretty?
Is it the underscores in the column names that are
You probably have a local copy of an old version of plot.hclust or
plot.dendrogram in your global environmenet or another package that masks
the one in package:stats. E.g., I fired up R-2.14.2 and copied those 2
plot methods to .GlobalEnv and then saved by workspace when quitting R. I
then fired
Hi Mark,
It is the underscores that are my issue, I'd prefer multiple level row
titles:
|ID1 |ID2
|Time1 |Time2 |Time1 |Time2
|OD |OS |OD |OS|OD |OS |OD |OS
Height | 1| 1 | 1 | 1 | 1 | 1 | 1 | 1
Weight| 1| 1 | 1 | 1 | 1
On 25/11/2014 3:12 PM, Tom Wright wrote:
Hi,
This problem has me stumped so I thought I'd ask the experts. I'm trying
to create a pretty summary table of some data (which patients have had
what tests at what times). Ideally I'd like to knitr this into a pretty
PDF for presentation.
If anyone has
Thanks Duncan,
Dropping the extra columns might be the way forward. I'm sure I can work
out how to embed latex into a markdown document ;-)
On Tue, Nov 25, 2014 at 4:37 PM, Duncan Murdoch murdoch.dun...@gmail.com
wrote:
On 25/11/2014 3:12 PM, Tom Wright wrote:
Hi,
This problem has me stumped
Pebbles in sand are also an alternative to Excel, but that doesn't mean people
want to switch to abaci. Horse, meet water.
If you use LaTeX (or Rmarkdown-to-pdf in RStudio), then you can obtain much
better looking tables using latex.tabular(). Unfortunately, LaTeX is just too
scary for some
Hi,
I am wondering how I can separate whether it is covariate or predictor in the
ANOVA analysis. For example
A-structure(list(Machine = c(1L, 1L, 1L, 1L, 1L, 2L, 2L, 2L, 2L,
2L, 3L, 3L, 3L, 3L, 3L), Diameter = c(20L, 25L, 24L, 25L, 32L,
22L, 28L, 22L, 30L, 28L, 21L, 23L, 26L, 21L, 15L),
On 26/11/14 13:57, Kristi Glover wrote:
Hi,
I am wondering how I can separate whether it is covariate or predictor in the
ANOVA analysis. For example
A-structure(list(Machine = c(1L, 1L, 1L, 1L, 1L, 2L, 2L, 2L, 2L,
2L, 3L, 3L, 3L, 3L, 3L), Diameter = c(20L, 25L, 24L, 25L, 32L,
22L, 28L, 22L,
Yes, Rolf -- she seems to think that covariates must be categorical
and predictors categorical -- or maybe it's vice-versa. Anyway, she
apparently has not done any homework (e.g. by reading an Intro to R)
and so doesn't understand the use of modeling formulas in lm() and
thus does not understand
On 26/11/14 15:49, Bert Gunter wrote:
Yes, Rolf -- she seems to think that covariates must be categorical
and predictors categorical -- or maybe it's vice-versa.
You of course meant ... covariates must be categorical
and predictors numerical -- or maybe it's vice-versa.
(I can't help
Thanks! That worked
From: William Dunlap wdun...@tibco.commailto:wdun...@tibco.com
Date: Tuesday, November 25, 2014 12:53 PM
To: Rolf Turner r.tur...@auckland.ac.nzmailto:r.tur...@auckland.ac.nz
Cc: Michael Mason
mma...@benaroyaresearch.orgmailto:mma...@benaroyaresearch.org, R help
On Tue, Nov 25, 2014 at 8:24 AM, Maarten Blaauw
maarten.bla...@qub.ac.uk wrote:
Nice graph, Scott, thanks!
Based on your code I plotted not the absolute numbers but the ratios, which
show slowly increasing relative participation of female Rhelpers over time
(red = women, blue=men,
On Tue, Nov 25, 2014 at 1:15 PM, Martin Morgan mtmor...@fredhutch.org wrote:
On 11/25/2014 04:11 AM, Scott Kostyshak wrote:
On Mon, Nov 24, 2014 at 12:34 PM, Sarah Goslee sarah.gos...@gmail.com
wrote:
I took a look at apparent gender among list participants a few years ago:
Hi PIKAL,
The error seems to be starnge to me because i access the indices of NAs.
Indices can't be non-applicable.
This is the output of indecs having the NA in my dataset. my dataset is
very big that's why I did not provide it.
indicNAs - which(data$Rain %in% NA)
indicNAs
[1] 426 792
On Nov 26, 2014, at 1:27 AM, Frederic Ntirenganya ntfr...@gmail.com wrote:
The error seems to be starnge to me because i access the indices of NAs.
No you don't. You access the contents of the cell via an index for which you
have previously determined that the contents is NA. Then you compare
Huh
and what is the result of e.g.
data$Rain[indicNAs[1]]
I bet that you will see
[1] NA
and your if question askes if (NA eqals 60) which results in NA and if is
telling you that it expects TRUE or FALSE but not NA.
I do not see how much clearer the error message shall be.
Cheers
Petr
Hola buenas,
estoy en una época convulsa de de dudas, ya que ando pegandome con shiny y
los mapas. Quería pegar un heatmap dinámico (mapa de paises) en una
aplicación shiny.
El problema es que no termino de hayar la manera. Os paso las apps. A ver
si alguien sabe algo. La idea es poder mostrar el
Hola compañeros
Soy Daniel Carrillo, y os escribo porque me ha surgido una duda sobre si
puedo tratar algoritmos de clustering como un factor en un experimento.
Concretamente, tengo un conjunto de datos sin etiquetar, y quiero probar
los siguientes algoritmos sobre él:
1) Extracción de
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