HTML mutilated your email. Please post in plain text.
Although you are playing with some tricky stuff, you seem to have
difficulty understanding the difference between a symbol and the value the
symbol represents. Re-reading section 6.1 of the Introduction to R that
comes with the software
Thank you for attempting to convey your problem clearly using example
code... but your use of HTML email has very nearly undone all your
efforts. Also, use of dput to make an R-readable block of data is more
reliable than read.table to get the data into our R sessions quickly.
First
df is the name of a function in base R. You have not provided a definition
of sample data resembling your real data. In this case I suspect that the
source of your problems is that df may not be what you think it is.
Learning to use the str function may help you.
If df is a data frame
Another solution:
CaseID - c(1015285, 1005317, 1012281, 1015285, 1015285, 1007183,
1008833, 1015315, 1015322, 1015285)
Primary.Viol.Type - c(AS.Age, HS.Hours, HS.Hours, HS.Hours,
RK.Records_CL,
OT.Overtime, OT.Overtime, OT.Overtime, V.Poster_Other,
V.Poster_Other)
library(reshape2)
You are looking for the round_date(), floor_date() or ceiling_date() functions
from the lubridate package. Those functions can round timestamps to weeks.
ir. Thierry Onkelinx
Instituut voor natuur- en bosonderzoek / Research Institute for Nature and
Forest
team Biometrie Kwaliteitszorg / team
Thank you very much for your reply. I really appreciate it. I apologize for
the HTML version, I have made modifications and replied to your
questions/comments below. Thanks again
tmp1 - structure(list(FIPS = c(1001L, 1003L, 1005L), X2026.01.01.1 = c(
285.5533142,
285.5533142, 286.2481079),
Hi all,
I have a data set like this:
Test.cox file:
V1V2 V3 Survival Event
ann 13 WTHomo 41
ben 20 *51
tom 40 Variant 61
where *
First recode the * in NA: death.dat$v3[death.dat$v1==*] - NA
Include this in your model: na.rm=TRUE
Or you could create a new dataset: newdata - na.omit(death.dat)
Shouro
On Fri, Dec 19, 2014 at 11:12 AM, aoife doherty aoife.m.dohe...@gmail.com
wrote:
Hi all,
I have a data set like
Hi Aoife,
I think that if you simply replace each * in the data file
with NA, then it should work (NA is usually interpreted
as missing for those functions for which missingness is
relevant). How you subsequently deal with records which have
missing values is another question (or many questions
Many thanks, I appreciate the response.
When I convert the missing values to NA and run the cox model as described
in previous post, the cox model seems to remove all of the rows with a
missing value (as the number of rows n in the cox output after I
completely remove any row with missing data
Yes, your basic reasoning is correct. In general, the observed variables
carry information about the variables with missing values, so (in some
way) the missing values can be replaced with estimates (imputations)
and the standard regression method will then work as though the
replacements were
Comment inline
On 19/12/2014 11:17, aoife doherty wrote:
Many thanks, I appreciate the response.
When I convert the missing values to NA and run the cox model as described
in previous post, the cox model seems to remove all of the rows with a
missing value (as the number of rows n in the cox
Three responses to your question
1. Missing values in R are denoted by NA. When reading in your data you want to use
the na.strings option so that the internal form of the data has missing values properly
denoted.
2. If this is done, then coxme will notice the missings and remove them,
I am need to install rneos for R 3.1 under Windows 64bit.
However it depends on the package XMLRPC that is not available in
conventional repositories.
In the CRAN R 3.1 online readme
(http://cran.r-project.org/bin/windows/contrib/3.1/ReadMe) there is an
information regarding the installation
Very pretty.
I could have saved myself about 1/2 hour of mucking about if I had thought ot
length.
John Kane
Kingston ON Canada
-Original Message-
From: sven.temp...@gmail.com
Sent: Fri, 19 Dec 2014 10:13:55 +0100
To: chl...@mail.usask.ca
Subject: Re: [R] Make 2nd col of 2-col df
Jacob Warren (RIT Student jjw3952 at rit.edu writes:
Using lme4 how does one define a 2 factor factorial model with both factors
being random?
Specifically I am just trying to recreate the results from Montgomery's
Design of Experiments book (7th edition), example 13.2. In this example
Hello Diogo,
the package is hosted on Omegahat:
http://www.omegahat.org/XMLRPC/
Best wishes,
Bernhard
-Ursprüngliche Nachricht-
Von: R-help [mailto:r-help-boun...@r-project.org] Im Auftrag von Diogo André
Alagador
Gesendet: Freitag, 19. Dezember 2014 14:03
An:
Nice but as this is R forum, is there an R package related to it ?
-Original Message-
From: John McKown [john.archie.mck...@gmail.com]
Date: 12/18/2014 01:38 PM
To: r-help r-help@r-project.org
Subject: [R] Your pardon: An article possibly of interest to statisticians
I do hope this
This morning I was reading Jeff Leek's list of awesome things other
people did in 2014 at http://simplystatistics.org/?p=3696 (thanks to the
Revolution Analytics blog for the pointer). One of the items in his
list had a link to a list of awards for open source software in 2014:
Dear Guillaume,
Please see comments interspersed below:
-Original Message-
From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of
Guillaume Souchay
Sent: Thursday, December 18, 2014 8:50 AM
To: r-help@r-project.org
Subject: [R] Fitting Structural Equation Model with sem
That is the solution I had tried first (yes, it's nice!), but it doesn't
provide the other PViol.Type's that aren't necessarily in my dataset. That's
where my problem is. I'm closer to the cure, though, and think I've thought of
a solution as soon as I have time. I'll update everyone then.
You can use the apply function which applies a function of your choice, and
MARGIN = 2 means you want to do it columnwise:
apply(X = df, MARGIN=2, FUN = mean, na.rm = TRUE)
Latitude Longitude January February March April May
June
26.9380 -109.8125 159.8454 156.4489
Duncan,
Congratulations to you and all the founders and contributors — very much
deserved; thank you!!
Tom
On Fri, Dec 19, 2014 at 9:24 AM, Duncan Murdoch murdoch.dun...@gmail.com
wrote:
This morning I was reading Jeff Leek's list of awesome things other people
did in 2014 at
On Fri, Dec 19, 2014 at 8:48 AM, John Kane jrkrid...@inbox.com wrote:
Hi,
It looks like you are replying to some phantom. Is your correspondent actully
on R-help?
This most likely happens because OP posted the message via Nabble
Hi,
It looks like you are replying to some phantom. Is your correspondent actully
on R-help?
John Kane
Kingston ON Canada
-Original Message-
From: mtr...@buffalo.edu
Sent: Fri, 19 Dec 2014 08:08:29 -0800 (PST)
To: r-help@r-project.org
Subject: Re: [R] Calculating mean, median,
On 19/12/2014 15:10, Pfaff, Bernhard Dr. wrote:
Hello Diogo,
the package is hosted on Omegahat:
http://www.omegahat.org/XMLRPC/
And it installs from the sources on Windows as it has no compiled code.
Something like
options(pkgType = 'source')
setRepositories() # choose omegahat
The over function in the sp package should be able to do this for you.
One of the examples found in ?over says:
# return the number of points in each polygon:
sapply(over(sr, geometry(meuse), returnList = TRUE), length)
In that example, meuse contains the points and sr contains polygons,
On 19/12/2014 17:57, Prof Brian Ripley wrote:
On 19/12/2014 15:10, Pfaff, Bernhard Dr. wrote:
Hello Diogo,
the package is hosted on Omegahat:
http://www.omegahat.org/XMLRPC/
And it installs from the sources on Windows as it has no compiled code.
Something like
options(pkgType =
Hi R User, Would you suggest me on how I can build a pivot table using two
variables? I want to put text in the table instead of value. I have attached
an example data and the type of table (FinalTable) I was looking for. I am
looking for your suggestions. ThanksKG=dat-structure(list(tag =
x - dat
x$time - as.factor(as.Date(x$time, format=%Y-%B%d))
tmp - split(x, x$tag)
tmp1 - do.call(rbind, lapply(tmp, function(x){
+ tb - table(x$time)
+ idx - which(tb0)
+ tb1 - replace(tb, idx, as.character(x$states))
+ }))
print(tmp1, quote=FALSE)
2010-05-27 2011-06-27 2011-06-28
On 20-12-2014, at 05:45, Kristi Glover kristi.glo...@hotmail.com wrote:
Hi R User, Would you suggest me on how I can build a pivot table using two
variables? I want to put text in the table instead of value. I have
attached an example data and the type of table (FinalTable) I was looking
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