Hi Gaspar,
I can see why you are having trouble with this. The "as.inputoutput"
function seems to be the core. While the manual claims you can just input
the "Z", "RS_label" and and "X" matrices to "as.inputoutput" and get the
"InputOutput" object that you need for all the other functions, it
On 11/10/20 5:08 PM, Bert Gunter wrote:
There are around 20,000 specialized packages for R. This list is set up to
help on standard R features and packages, but cannot possibly be expected
to support 20,000 packages. As the posting guide says (did you read it??!):
"If the question relates to
There are around 20,000 specialized packages for R. This list is set up to
help on standard R features and packages, but cannot possibly be expected
to support 20,000 packages. As the posting guide says (did you read it??!):
"If the question relates to a *contributed package* , e.g., one
Hi,
Hope you are doing well, I´m trying to start working
with ioanalysis package, however its being difficult for me
to prepare data from my own input-output table,
import it into R in order to apply the ioanalysis functions
Any help on this will be highly appreciated.
Please note that I do not
Hola chic@s, alguien con experiencia en propensión score matching?
Planteo duda: Clasicamente el PSM se ha utilizado en un intento de homogeneizar
cohortes de enfermos quienes han estado “expuestos” a un tratamiento x Vs
aquellos que no han estado expuestos (no expuestos). Esto aplica para
Hi,
FWIW, I had the same issue at some point in the past, and I have the following
in my .emacs to change the behavior:
(add-to-list 'display-buffer-alist '("*R" (display-buffer-reuse-window
display-buffer-at-bottom)
(window-width . 0.5) (reusable-frames . nil)))
That was provided here on
Christopher W. Ryan via ESS-help writes:
When I execute a line of R code, the R buffer opens up as
expected, but
it opens in a frame adjacent to the frame containing my source
buffer. I
would like it to open the R buffer as a frame below my source
code,
rather than adjacent to it.Â
How can
Hi John,
I was thinking that you created df1 in a way that set the 'year'
column as a factor when this is not what you wanted to do.
The data.frame() function takes an argument stringsAsFactors which
controls this behavior.
For R versions 3.6.3 or earlier, the default setting is
Sure John,
df1<-df1[order(as.character(df1$year),decreasing=TRUE),]
Jim
On Tue, Nov 10, 2020 at 8:05 PM John wrote:
> Thanks Jim. Can we do descending order?
>
> Jim Lemon 於 2020年11月10日 週二 下午4:56寫道：
>
>> Hi John,
>>
>> df1<-sapply(df1,as.character)
>>
>> Should do what you ask. The error
Thanks Jim. Can we do descending order?
Jim Lemon 於 2020年11月10日 週二 下午4:56寫道：
> Hi John,
>
> df1<-sapply(df1,as.character)
>
> Should do what you ask. The error message probably means that you should
> do this:
>
> df1<-df1[order(as.character(df1$year)),]
>
> as "year" is the name of the first
Hi John,
df1<-sapply(df1,as.character)
Should do what you ask. The error message probably means that you should do
this:
df1<-df1[order(as.character(df1$year)),]
as "year" is the name of the first column in df1, not a separate object.
Jim
On Tue, Nov 10, 2020 at 6:57 PM John wrote:
> Hi,
>
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