-- or whatever the first digit is.
Please let me know if there are additional tests I can try .
thanks
Carl Witthoft
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uot;paste"
What I found is that, around 5000 characters, a newline ( "\n") char
showed up. Is this something that the Windows Clipboard does, or
something odd about pasting into a command in R?
Postscript: using
>> bar <- readChar('thefile.txt',1e6)
the import works perfectly
, Carl Witthoft wrote:
When I run the shell command
R CMD BUILD mypackage
the builder converts *.R files to *.rda data files. This seems to
conflict with the information in R-Exts which says a package's /data
directory can contain foo.R files which the function data() will call
source
aining the text
[1] 'dataA'
[2] 'dataB'
Where did I go wrong?
thanks
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c...@witthoft.com
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PLEASE do read the posting guid
As posted to Stack Overflow,
please try this out:
plot(1:10,t='n')
text(1,1,c(intToUtf8(c(1,9684))),cex=3)
text(2,2,c(intToUtf8(c(9684))),cex=3)
text(3,3,c(intToUtf8(c(9679,9684))),cex=3)
text(4,4,c(intToUtf8(c(9679))),cex=3)
text(5,5,c(intToUtf8(c(9685,9684))),cex=3)
Pretty much nothing can convert arbitrary PDF files to unicode. It depends a
lot on what is in the PDF to begin with -- properly encoded text or just
bitmapped images, for example.
I would recommend you search around to see whether there's a related
archive in a different format.
And in any
Seriously?
You should be ashamed of yourself for even considering posting a question
like this.
Charles Thuo wrote
what is the purpose of the subject function
Charles
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See ?legend . you can add a legend directly to an existing plot. An
example:
legend('topright',c('hot','cold'),lty=1,col=c('red','green'),bg='white')
Now if you're trying to place the legend outside the plot area (i.e. in some
other part of the window),
you'll need to invoke par(xpd=TRUE) .
It occurs to me that perhaps you're referring to the 'color bar' on the right
of the plot. AFAIK you cannot get at that from the raster::plot method.
However lattice::levelplot does allow you to manipulate or remove that
colorbar.
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Off the top of my head, I'd suggest trying ggsave() with the extension
.svg . I realize that SVG files are not recognized by some image display
apps (Microsoft Windows I'm looking at YOU), but IMHO it's the best choice
for vectorized images.
Alexander Shenkin wrote
Hi Folks,
Using
I see your desired output has rather fewer data than the input data frame.
Instead of making us pore over a bunch of numbers, can you explain exactly
what filtering you wish to do to get the specific subset
of {male/female} {alcohol/caffeine} you're trying to get?
BHM wrote
Hi,
This is
Pardon the pedantry, but doyou know what a Venn Diagram is? Because there
are two or three
packages at CRAN which will generate Venn diagrams for you given exactly
that sort of source data.
Yi.Zou wrote
Hi all,
I am thinking of making a graph with three dataset A,B,C with shared
common
In R, as.logical() and other functions treat anything 0 as TRUE. Thus:
Rgames foo-sample(0:5,10,rep=TRUE)
Rgames foo
[1] 0 5 1 0 1 5 2 5 4 5
Rgames as.logical(foo)
[1] FALSE TRUE TRUE FALSE TRUE TRUE TRUE TRUE TRUE TRUE
For your case, simply (womensrole$agreewomensrole$disagree)
A couple things:
First, Beginners' lists never work. Beginners invariably can't read (cf.
posting guidelines), so they will post to the main list anyway.
Second, I see some people prefer to receive email-lists of the topics, and
others prefer to work via a webbrowser interface. I'd have to say
you didn't show us the code you used to generate the legend.
I'm guessing you want to add to the legend list something like lty=0:7 .
KB wrote
I recently started using R, so I'm not really experienced with it. My
question is on adjusting xyplots to get lty lines instead of coloured
lines.
What the Data Munger Guru said.
Plus: this is almost certainly a job for ddply or data.table.
Noah Silverman-2 wrote
Hello,
I have a fairly large data.frame. (About 150,000 rows of 100
variables.) There are case IDs, and multiple entries for each ID, with a
date stamp. (i.e. records of
What this message means is that a { showed up when some other bracket was
unpaired. In this case, if you check your code, you'll see that
if(MatriceDist[i,j] 0 ((vectorID[i] 0 | vectorID[j] 0)) is
lacking a closing ) for the if clause.
Phalaen wrote
Hi!
I am a Phd student in the
see ?par . Use the argument asp=TRUE.
Mercutio Florid wrote
I use several different versions of R, including RGui on Windows and
rstudio on Linux. In all cases, I use graphical commands, such as
image().
image() displays rectangles, but I want to be able to guarantee that the
There are several problems here. The first is that it's rather unlikely you
really need 10-place accuracy to fit your data. This suggests you may be
doing something inappropriate such as fitting the wrong function or trying
to extrapolate. Since you haven't explained what process you have
I think it'd be easier and safer to save the matrix, either as an .Rdata
binary or as a text file, zip that file, and use the sendmailR tools to
attach the file to your message.
Fuchs Ira-3 wrote
I have a matrix which has colnames and I would like to send this matrix
using sendmailR. How can I
OK, I'm pre-coffee, but what's wrong with using upper.tri to create a new
matrix and then multiplying that matrix by the original dat matrix (direct
multiplication, not matrix multiply) to get the desired answer?
Bert Gunter wrote
I believe matrix indexing makes Arun's complex code wholly
See my answer at Stack Overflow -- repeated here for anyone else who wants a
trivial function.
# coordinate transform: cartesian plane rotation
xyrot-function(pairs,ang){
# pairs must be Nx2 matrix w/ x in first column and y in second
xrot - pairs[,1]*cos(ang) - pairs[,2]*sin(ang)
Well, given that an upvoted question on math.stackexchange got no answers,
I'd say you're asking a very difficult question. Perhaps this paper
http://www.geometrictools.com/Documentation/IntersectionOfEllipsoids.pdf
will be of some help. It's possible that you could do:
1) find the ellipse
Please post the packages from which 'barabasi' and 'layout.fruch'
originate (not to mention whatever the plot() method is for whatever class
your 'g' is). Further, without seeing what your data look like we have no
way of knowing whether you've fed the appropriate elements of L to chull.
We would need to see the contents of the mplus file that is read in. Quite
possibly it's overwriting either iter or count with an incompatible data
type.
I would also recommend contactingWalter Leite directly to verify you have a
proper mplus source file.
/* partial quote follows */
The
Here's a rather extreme solution:
foo-rep(1:6,each=2)
Rgames foo
[1] 1 1 2 2 3 3 4 4 5 5 6 6
Rgames foo[rep(c(1,3,2,4),3)+rep(c(0,4,8),each=4)]
[1] 1 2 1 2 3 4 3 4 5 6 5 6
In the general case, then, it would be something like
foo- rep(1:N, each = 2) # foo is of length(2*N)
I agree w/ lubridate.I also would like to mention that date handling
is amazingly difficult in ALL computer languages, not just R. Take a stroll
through sites like thedailywtf.com to see how quickly people get into
tarpits full of thorns when trying to deal with leap years, weeks vs month
Just to clarify: I'm guessing the OP is referring to the CRAN package C50
here. A quick skim suggests the rules are a list element of a C5.0-class
object, so maybe that's where to start?
David Winsemius wrote
In my role as a moderator I am attempting to bypass the automatic mail
filters
You already asked this on StackOverflow.
The answer remains the same, pretty much what David W. wrote: this is
not a question about fitting lines to data. You need to step back and think
about what message you want to deliver to those who will view your graph,
and what the meaning of your
In the absence of any description of the computers themselves, it's hard to
say, but there's a good chance that there is some object in your working
environment that's being accessed by your function -- and that object exists
on only one of the machines.
I would suggest you use debug() or
First of all, use readBin to verify you get the desired data back.
Second, that '00' is, I believe the EOF character you'll find at the end
of any file.
Harutyun Khachatryan wrote
Dear R project officials,
I have found that in R 3.0.1 version writeBin function of base package
might not
If you could, please identify which responder's idea you used, as well as the
strsplit -- related code you ended up with.
That may help someone who browses the mail archives in the future.
Carl
SPi wrote
I'll answer myself:
using strsplit with fixed=true took like 2minutes!
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Why would you need to? The whole point of :: and ::: is to specify the
origin of a function.
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Sent from the R help mailing list archive at Nabble.com.
My feeling is that the **result** you want is far more easily achievable via
a substitution table or a hash table. Someone better versed in those areas
may want to chime in. I'm thinking more or less of splitting your character
strings into vectors (separate elements at whitespace) and chunking
Why would you want to impose this restriction? Perhaps if you explain what
you are trying to do, we can suggest approaches that will satisfy your
specific needs.
(note- one can always redefine whatever variables are to be excluded. E.g.
to keep the body of a function from referring to 'foo' in
Pretty much exactly what it says. Now, keep in mind that a warning message
does not indicate a failure or error. Presumably you successfully read your
file into filedata. What it's saying is that the EOL character exists
inside some character string in one of the elements of your file.
Rule Number One: Don't use pie charts.
Rule Number Two: NEVER EVER USE PIE CHARTS!
To learn how to create graphs in R, start with ?plot , ?points, ?lines.
Later on you can investigate ?lattice, ?grid, and ?ggplot2 .
The fact that you're looking 'online' instead of in R's builtin help
That is not an ENVI file. That's an image file... or something.
If you can post a small, reproducible sample of the data array containing
the dates you wish to manipulate, we may be able to help.
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Your question doesn't make much sense if you really believe that the best fit
is to draw a horizontal line at every unique value of y. What is the
actual problem you are trying to solve? Clearly it's not a matter of
linear fits, so forget about using lm or other regression tools.
--
View
Did you run the identical code on the identical machine, and did you verify
there were no other tasks running which might have limited the RAM available
to R? And equally important, did you run these tests in the reverse order
(in case R was storing large objects from the first run, thus chewing
Dunno how to break this to you, but R reads exactly what is in that file,
with the data in exactly the proper row/column locations.
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Sent from the R help mailing list
Which suggests the OP should verify that the data in ...$Frequency is the
data he expects to be there.
Rui Barradas wrote
Hello,
I can't reproduce your error:
windfreq -
c(1351L, 2147L, 3317L, 4378L, 5527L, 6667L, 7865L, 8970L, 9987L,
10907L, 11905L, 12642L, 131000L, 14983L, 15847L,
Both PBurns and DWin are correct. I just thought I'd add a clunky safety
check approach I use now and then:
Before doing the actual subset, i.e. df[-which(something),] , do
something like
if (length(which(something)) 1 ) {skip the subsetting} else
df[-which(something)]
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Obviously row 11 is incomplete.
It may contain nothing more than a space or an EOL.
Using the fill=TRUE argument to 'scan' or 'read.table' is your friend
here.
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Sent from the R help mailing
What's the range of data you are trying to plot? The error message is pretty
clear: you've selected a set of breaks which don't span the data range.
Maybe try breaks = c(min(x),seq(4,30,2),max(x))
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According to ?merge, you could try adjusting the default value of the
tolerance argument.
Nora Ernst wrote
I'm working with raster data (satellite imagery) and the raster package.
The
idea is to merge two raster files that are partially overlaping, do
have the
same coordinate system
Barry Rowlingson wrote
On Mon, Oct 21, 2013 at 10:51 PM, David Winsemius
lt;
dwinsemius@
gt; wrote:
On Oct 21, 2013, at 2:15 PM, Hurr wrote:
May I send a .zip file attached to a post?
No.
That's not explicit from the posting guide:
No binary attachments except for PS, PDF, and
What is the exact code you are using to try to load this file?
I strongly suspect the problem is a mixture of spaces and multiple tabs in
your text file.
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Sent from the R
If you have over a thousand files on your desktop, you have bigger problems
than just how to load them into R.
Where do these files come from, and why do you want to merge them into a
single entity?
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Steve E. wrote
Hi R users,
I am having some trouble with a very simple function that I hope that you
might be able to help me with (and, really, to shed some light on how
functions work generally). I have a series of very small 2-column data
frames of which I need to change the column
You created a bunch of 'x' items but call for X in your formula. That's
part of it. Next, you don't provide a data=x argument in your lm() call,
so it goes off and looks for various capital-X items (I suspect).
Hint: start with a small, simple dataset and work with it until you know
how to
mattbju2013 wrote
Hi guys this is my first post, i need help summing the number of NA's in a
few vectors
for example..
c1-c(1,2,NA,3,4)
c2-c(NA,1,2,3,4)
c3-c(NA,1,2,3,4)
how would i get a result that only sums the number of NA's in the vector?
the.result.i.want-c(2,0,1,0,0)
See
This is the world-famous fizzbuzz problem. You should be able to find
lots of implementations by Googling that word. Here's a pointless
collection I wrote once:
# a really dumb fizzbuzz alg competition
#fbfun1 is 2.5x faster than fbfun2
# fbfun3 is 10x faster than fbfun1
# fbfun1 is 2x faster
foo - as.numeric(as.character(your_factors) ).
It's a common mistake to forget the first conversion, in which case you end
up with an integer sequence rather than the desired values.
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FMRPROG wrote
I am generating random numbers from a normal distribution using
[snip]
I need to optimize the speed WITHOUT using the rnorm function but have no
idea how to do this. I assume I should minimise what goes in the loop?
Any help would be very much appreciated.
Looks like
Hi,
I have two integers a and b (with ab), as well as a function f(x). Is there
a way of getting the vector (f(a), ..., f(b)) from R without having to
explicitly write it out? as my a and b vary.
Thanks for your help
lt;/quote
What did you try?Further, without knowing what your function
Jeffrey Flint wrote
Good news. I installed 3.0.2, and the parallel package examples ran
successfully. This time a firewall window popped up. Probably the
firewall was the problem with the snow package too, but for some reason
the
window didn't pop up with the snow package.
Thanks for the
Never mind -- after getting detailed help at SO, I rebooted Windows and
makeCluster() worked just fine. I have no idea what cruft in my system was
getting in the way, but all's well.
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I am trying to use the parallel package, and found that makeCluster
hangs (and no apparent actions have taken place). This is Windows7-64,
Enterprise, R 3.0.1 .
I've traced the hang to the following line in newPSOCKnode :
con - socketConnection(localhost, port = port, server = TRUE,
?file.copy
Or ?system
From: sagarnikam123 sagarnikam123_at_gmail.com
Date: Sun, 22 Apr 2012 01:25:21 -0700 (PDT)
i want to cut file from e.g. abc folder put it into another location
with folder name e.g. xyz
how should i proceed?
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Quidvis recte factum, quamvis
I think the OP wants to fill values in an arbitrarily large matrix.
Now, first of all, I'd like to know what his real problem is, since this
seems like a very tedious and unproductive matrix to produce. But in
the meantime, since he also left out important information, let's
assume the input
Apologies -- I meant to translate that code (which is what the OP
provided, albeit in longer form) into a *apply one-liner.
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Ok, how's this:
Rgames foo
[,1] [,2] [,3] [,4]
[1,]361 16
[2,] 10 14 125
[3,] 117 159
[4,]84 132
Rgames sapply(1:4,FUN=function(k){
foo[k,which(foo==k,arr.ind=T)[2]]-100;return(foo)})-bar
Rgames bar
[,1] [,2] [,3] [,4]
[1,]3
Thanks, Chuck. That looks about right.
And I would have provided repro code, but I was forced to write it in
Matlab on account of corporate rules, and haven't translated to R yet.
Carl Witthoft carl at witthoft.com writes:
Hi,
While playing with quantile-quantile plots, I wrote up some
Hi,
While playing with quantile-quantile plots, I wrote up some code which
plots something strangely different. Here's the pseudocode:
testhist - hist(sample_data)
refhist - hist(rnorm(n, mean=0,sd=1)) # for some large-ish n
cumtest - cumsum(testhist)
cumref - cumsum(refhist)
This was actually answered a couple times in StackOverflow. Someone and
I indpendently wrote up the following function, stolen directly from the
source for rle().
# extended version of rle to find all sorts of sequences
# if incr=0, this is rle
seqle- function (x,incr=1)
{
if
Well, I have to say, how nice to find a valid use for string theory :-) .
Now that we all know you are in fact the mistress of skulls, guess we
better tread lightly!
Carl
quote
From: Sarah Goslee sarah.goslee_at_gmail.com
Date: Thu, 02 Feb 2012 17:54:04 -0500
I thought some of you might
There are two packages which may be useful: venneuler and VennDiagram.
One of them allows up to four sets; the other is pretty much
unlimited. I forget which is which :-( .
Oops: there's another, evenn. I haven't used that one.
--
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According to the help file for 'outlier' , (quoting)
x a data sample, vector in most cases. If argument is a dataframe, then
outlier is
calculated for each column by sapply. The same behavior is applied by apply
when the matrix is given. (endquote)
Looks like you could create a matrix that
Did you look thru http://addictedtor.free.fr/graphiques/ ? There's a
lot of stuff there.
sos plot DNA
suggests maybe packages ape, forensim , genoPlotR . I have never used
those so can't comment further.
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Like the t-shirt says, There's no place like 127.0.0.1
quote
Though I wasn't familiar with this I check the repositories list and
CRAN (extras) is selected in my installation (R-2.14.1). By the way,
when trying Ryacas after what seemed to be a successful install, for a
simple example of
It was supposed to be a joke :-(
On 1/24/12 4:15 PM, Gabor Grothendieck wrote:
On Tue, Jan 24, 2012 at 4:07 PM, Carl Witthoftc...@witthoft.com wrote:
Like the t-shirt says, There's no place like 127.0.0.1
quote
Though I wasn't familiar with this I check the repositories list and CRAN
AlanM said,
Consider the pair {X, 1-X} where X is sampled from a uniform(0,1)
distribution. The quantity 1- X also comes from a uniform(0,1)
distribution and therefore is probabilistic and not deterministic. The
sum of independent random variables is itself a random variable. If X1,
X2 X3
Or package(BB) , depending on exactly what you want to do.
quote
From: David Winsemius dwinsemius_at_comcast.net
Date: Sun, 08 Jan 2012 16:54:28 -0500
On Jan 8, 2012, at 4:51 PM, Ricardo Bandin wrote:
Esteemed colleagues
I wonder if there is a package in R that performs the functions of the
This question *screams* for the standard response: What is the problem
you are trying to solve?
I can think of two related problems off the top of my head.
1) Write a function which generates the four bridge hands from a
well-shuffled deck.
2) Throw 100 pennies into a big shaker with four
Now that we've all satisfied our curiosity :-) about force() in for and
while loops, I suppose it would be impolite to ask Rolf whether there
isn't a much neater and simpler way to make his internal functions grab
whatever the index 'i' is pointing them to?
--
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Hi,
I just started playing w/ venneuler, and have a question about the last
method listed for creating inputs. This is the method where the source
is a matrix X, for which each column represents a set, and the
co-occurrence is defined by the rows. So, for example:
Rgames foo
[,1]
Let me put my vote in for imageJ as well. It's designed to do (gosh)
image analysis stuff, whereas R is not.
Of course you can write whatever algorithms you like in R :-), but for
specialized work it's often better to use a specialized tool.
quote
From: Andrés Aragón armandres_at_gmail.com
That only puts different colors on different axes. I was wondering
about the (silly) possibility of having a range of colors for the ticks
on a given axis.
quote
From: Hans W Borchers hwborchers_at_googlemail.com
Date: Tue, 13 Dec 2011 14:21:31 +
Carl Witthoft carl at witthoft.com writes
Hi,
So far as I can tell, the 'col.ticks' parameter for axis() only uses the
first value provided. E.g.:
plot(0:1,0:1, col.ticks=c('blue','red','green')) #all ticks are blue
Just wondering if there's a different option in the basic plot commands
that can handle multiple colors, and also
Please read the posting guide and provide a (small) reproducible example
of your data.
The statement ...output does not seem good. is not very useful.
Please explain what you would like the polygon area to look like, and
why you don't like the way it came out. Links to posted images of the
If you 'don't speak computer,' what are you doing trying to run R in the
first place?
Your email address suggests this is homework, but even if it isn't
please go talk to your professor or teaching assistant.
quote
From: Jasmine007 magee20v_at_uregina.ca
Date: Mon, 05 Dec 2011 16:32:00 -0800
Not that it really matters, but
Can someone explain how the row numbers get assigned in the following
sequence? It looks like something funky happens when rbind() coerces
'bar' into a dataframe.
In either sequence of rbind below, once you get past the first two rows,
the row numbers count
Sorry -- I meant to write 'row names,' but the question specifically is
where those unlikely numbers come from. So I guess it comes down to
why, when 'bar' is the first item, the row name is assigned '2' rather
than '1' .
On 12/1/11 6:26 PM, Sarah Goslee wrote:
Those are row *names*, not
As the Kroger Data Munger Guru would say, What is the problem you
are trying to solve?
The datasets look just fine from a structural point of view. What do you
want to do and what is wrong with the results you get?
quote
From: Kaiyin Zhong kindlychung_at_gmail.com
Date: Thu, 24 Nov 2011
Excellent. That's what I was looking for.
Thanks, Rolf.
Carl
On 11/19/11 11:16 PM, Rolf Turner wrote:
On 20/11/11 16:27, Carl Witthoft wrote:
This question attacked me as I was thinking about matrix value updates.
I probably will never need to do this, but wanted to ask
Another few data points, just for the heck of it. This is on a 2.66GHz
Intel Core Duo iMac.
Rgames system.time(plot(runif(1e6),runif(1e6)))
user system elapsed
34.405 0.079 34.432
Rgames system.time(plot(runif(1e6),runif(1e6),pch='.'))
user system elapsed
12.602 0.032 12.596
This question attacked me as I was thinking about matrix value updates.
I probably will never need to do this, but wanted to ask if there are
efficient methods to perform the for-loop in the following sequence.
%xymat-matrix(rep(0,100) nr=10,nc=10) # empty matrix
%x-1:10
Not too difficult.
Rgames bar-c(3,5,7)
Rgames foo-c(1,3,5,6,8,9,7)
Rgames match(bar,foo)
[1] 2 3 7 # these are the matching positions
Rgames foo[-(match(bar,foo))]
[1] 1 6 8 9
quote
Dear list,
I have been struggling for some time now with this code... I have this
vector of unique ID EID
If in fact this is homework, you will do yourself, your classmates, and
possibly your teacher if you let them know that, at least in R, almost
anything you can do in a for() loop can be done easier and faster with
vectorization. If you teacher can't comprehend this, get him fired.
a-c(4,6,3)
My answer is similar: how much data? All of it.
And shame on the OP for ever using Excel.
From: Rolf Turner rolf.turner_at_xtra.co.nz
Date: Thu, 03 Nov 2011 22:20:17 +1300
On 03/11/11 15:59, Nicholay Anne Caumeran wrote:
Would like to know how much data can R process - number of rows and
I have to admit to not doing careful timing tests, but I often eliminate
if() lines as follows (bad/good is just my preference)
BAD: b[i] - if(a[i]1) a[i] else a[i-1]
GOOD: b[i] - a[i]* (a[i]1) + a[i-1] * (a[i]=1)
On Thu, Nov 3, 2011 at 12:10 PM, hihi v.p.mail_at_freemail.hu wrote:
Dear
Before you pick out a palette: you are aware that their are several
different types of color-blindness, aren't you?
http://en.wikipedia.org/wiki/Color_blind
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R-help@r-project.org
If you just want the same symbol at each point, you could use Weylandt's
approach, tho' personally I think it's tidier to create a new vector
x10 - x[seq(1,length(x),by=10)] and plot that.
If you would like a different symbol at each point, then take a look at
?text.
quote
From: R.
You misused nls(). Observe:
x- 1:101
y2 - 5*exp(x/20) + runif(101)/100 # nls will NOT converge for perfect data.
nls(y2 ~ exp(A*x), start=list(A=.1))
Nonlinear regression model
model: y2 ~ exp(A * x)
data: parent.frame()
A
0.06709
residual sum-of-squares: 136703
Number of
Thank you! That bit about Re(z) + Im(z) was what I missed.
Carl
On 10/15/11 12:00 PM, Deepayan Sarkar wrote:
On Fri, Oct 14, 2011 at 3:07 AM, Carl Witthoftc...@witthoft.com wrote:
Hi all,
I'd like to plot the Real and Imaginary parts of some f(z) as two different
surfaces in wireframe (the
,y)sin(x*y)))
cheers.
Am 13.10.2011 23:37, schrieb Carl Witthoft:
Hi all,
I'd like to plot the Real and Imaginary parts of some f(z) as two
different surfaces in wireframe (the row/column axes are the real and
imag axes). I know I can do it by, roughly speaking, something like
plotz
You guys are working too hard.
Rgames y - c(0,1,1,3,3,3,5,5,6)
Rgames rle(sort(y))
Run Length Encoding
lengths: int [1:5] 1 2 3 2 1
values : num [1:5] 0 1 3 5 6
--
-
Sent from my Cray XK6
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R-help@r-project.org mailing list
Hi all,
I'd like to plot the Real and Imaginary parts of some f(z) as two
different surfaces in wireframe (the row/column axes are the real and
imag axes). I know I can do it by, roughly speaking, something like
plotz - expand.grid(x={range of Re(z)}, y={range of Im(z), groups=1:2)
On 10/8/11 6:11 PM, (Ted Harding) wrote:
Carl Witthoft's serendipitous discovery is a nice example
of how secrets can be guessed by wondering what if ... ?.
So probably you don;t need to tell the secrets.
Taking the negative digits to their logical extreme:
round(654.321,2)
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