Hi
I'd like to remove a leading "3" if my number is 7 digits long, if it is
only 6 I don't want to anything.
I think this should be possible with a 1-liner using sub() but I am not
sure how to define the number of characters following the leading one.
For example my vector:
a <-
Dear R-User!
This is a question to all of you that are familiar with the 'dismo'
package, in particular we are interested in the gbm.step() function to
create a boosted regression tree model in R. From the model output object we
can use the $cv.statistics to get information on the
On Sat, Mar 21, 2015 at 3:41 PM, Prof Brian Ripley rip...@stats.ox.ac.uk
wrote:
On 21/03/2015 14:27, Johannes Radinger wrote:
Thanks for the fast response. The fitdistr() function works well for the
predefined density functions. However, what is the recommended approach
to optimize/fit
the standard R distribution:
library(MASS)
?fitdistr
No optimization is needed to fit a normal distribution, though.
On 21/03/2015 13:05, Johannes Radinger wrote:
Hi,
I am looking for a way to fit data (vector of values) to a density
function
using an optimization (ordinary least squares
Hi,
I am looking for a way to fit data (vector of values) to a density function
using an optimization (ordinary least squares or maximum likelihood fit).
For example if I have a vector of 100 values generated with rnorm:
rnorm(n=100,mean=500,sd=50)
How can I fit these data to a Gaussian density
Hi,
I'd like to arrange two wireframe plots (library lattice) next to each
other using the grid.arrange function of the library gridExtra. However
the two wireframe plots should be closer to each other and the outer 2D box
should be removed (to save space).
To remove the outer box for a single
Hi,
I'd like to match the beginning and the end of a string. E.g. I want to
extract all strings from a vector that beginn with 12 and end with
Apples:
a - 2 green Apples
b - 12 green Apples
c - 12 Apples and 2 green Bananas
d - 12 yellow Bananas
fruitlist - c(a,b,c,d)
# This is how to extract
Hi,
I am wondering if it is possible to set the path to the output file of the
function
BIOMOD_Modeling() from the 'Biomod2' package. I can see the option
SaveObj to state if the output should be save to the hard disk. When this is
enabled, all files are printed to the working directory. So is
77840-4352
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
On Behalf Of Johannes Radinger
Sent: Wednesday, July 9, 2014 7:07 AM
To: R help
Subject: [R] Cutting hierarchical cluster tree at specific height fails
Hi,
I'd like to cut
Department of Anthropology
Texas AM University
College Station, TX 77840-4352
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
On Behalf Of Johannes Radinger
Sent: Wednesday, July 9, 2014 7:07 AM
To: R help
Subject: [R] Cutting
Hi,
I'd like to cut a hierachical cluster tree calculated with hclust at a
specific height.
However ever get following error message:
Error in cutree(hc, h = 60) :
the 'height' component of 'tree' is not sorted (increasingly)
Here is a working example to show that when specifing a height in
Hi,
I have data in a dataframe in following structure
var1 - c(a,b,c,a,b,c,a,b,c)
var2 - c(X,X,X,Y,Y,Y,Z,Z,Z)
var3 - c(1,2,2,5,2,6,7,4,4)
df - data.frame(var1,var2,var3)
Now I'd like to calculate relative values of var3. This values
should be relative to the base value (where var1=c) which is
Hi,
I found follwowing example of pnorm here:
http://www.r-tutor.com/elementary-statistics/probability-distributions/normal-distribution
Problem
Assume that the test scores of a college entrance exam fits a normal
distribution. Furthermore, the mean test score is 72, and the standard
-help-boun...@r-project.org [r-help-boun...@r-project.org] ;
meghatalmaz#243;: Johannes Radinger [johannesradin...@gmail.com]
Küldve: 2013. december 12. 14:56
To: R help
Tárgy: [R] Solving a normal distribution pnorm for q
Hi,
I found follwowing example of pnorm here:
http://www.r
)pnorm(q=x,sd=sd1)*r+pnorm(q=x,sd=sd2)*(1-r)-X,c(-1e6,1e6))
Cheers
Am 12.12.2013 15:58, schrieb Johannes Radinger:
Thanks for the fast response. Of course I totally overlooked qnorm as I
had
a more complex task in my head.
I wanted to reverse following equation:
r=0.67
q=-150
sd1
Hi,
I'd like to plot a boxplot and use a scatter.smooth line plot as an overlay
for this plot.
This works except for the problem that the x-axis ticks for both plots are
differently spaced:
The boxplot ticks are closer and the space between the outer most boxplots
and the plot region (box) is
:43 AM, Johannes Radinger
johannesradin...@gmail.com wrote:
Hi,
I'd like to plot a boxplot and use a scatter.smooth line plot as an
overlay
for this plot.
This works except for the problem that the x-axis ticks for both plots are
differently spaced:
The boxplot ticks are closer
Hi,
I'd like to follow up an older discussion on adding significance stars to
boxplots.
(
http://r.789695.n4.nabble.com/indicating-significant-differences-in-boxplots-td862335.html
)
As suggested by Jim Lemon, there is following solution for a single boxplot:
boxplot(count ~ spray, data =
Hi,
I'd like to use Latin Hypercube Sampling (LHC) in the the context of
uncertainty / sensitivity analysis of a complex model with approximately 10
input variables. With the LHC approach I'd like to generate parameter
combinations for my model input variables.
Therefore I came across an simple
Hi,
I'd like to get mean values for the margins of my casted data.frame.
For the casting I am using dcast() from reshape2. However, when I set
the margins parameter (margins=c(grand\_row)) I get following error
concerning
an unrecognized escape character '\_'. So what is the correct command
to
Hi,
I am trying to calculated various summary statistics using the dcast
function
of reshape2. This works perfectly for getting the mean, sum, length, sd. But
when I want to calculate the median I get an error. I tried it with and
without removing
NAs:
my_median - function(x) median(x, na.rm =
, Johannes Radinger wrote:
This email has already been sent to the R-mailing list,
but maybe you as the author of the package sets can help here best
Hi,
I am trying to use the fuzzy_inference system on multiple input values.
Basically I combine two variables (depth, velocity
Hi,
I just discovered the package sets and its ability to perform fuzzy
systems calculations.
The example in the manual of fuzzyinference() gives an overview how to
develop rules.
However my rules are already available as data.frame and I'd like to
convert them into the format
that is needed by
Following my last mail, I found a simple solution using eval(parse)):
df -
data.frame(depth=c(low,medium,high),velocity=c(medium,medium,low),suitability=c(low,medium,low))
df$rule - paste(fuzzy_rule(depth %is% ,df[,depth], ,velocity
%is% ,df[,velocity],, ,suitability %is%
Hi,
I am trying to use the fuzzy_inference system on multiple input values.
Basically I combine two variables (depth, velocity) into the variable
suitability.
Both depth and velocity have 3 trapezoid classes (verylow,medium,high) each.
The consequent (suitability) has 4 fuzzy levels
Hi,
I have a vector of strings like:
c(a1b1,a2b2,a1b2) which I want to spilt into two parts like:
c(a1,a2,a2) and c(b1,b2,b2). So there is
always a first part with a+number and a second part with b+number.
Unfortunately there is no separator I could use to directly split
the vectors.. Any idea
substr(x, 3, 4)
[1] b1 b2 b2
HTH,
Jorge.-
On Wed, Mar 13, 2013 at 7:37 PM, Johannes Radinger wrote:
Hi,
I have a vector of strings like:
c(a1b1,a2b2,a1b2) which I want to spilt into two parts like:
c(a1,a2,a2) and c(b1,b2,b2). So there is
always a first part with a+number
Hi,
is there a way to color the branches or text label of the branches of
dendrograms e.g. from hclust() according to a grouping variable. Here
I have something in mind like:
Hi,
I am running an ANCOVA model like:
aov(Y ~ Var1 + Var2 + Var3 + Var4 + CoVar1 + CoVar2)
where Y is the response (metric, 1.0-1000.0), VarX are all
metric predictors, and CoVarX are two Covariates each a
factor of 4-5 levels.
So far as I can remember results of an ANCOVA for a Covariate
of
Hi,
I'd like to merge mutliple dataframes from a list of dataframes by some common
columns. The approach for simply merging 2 dataframes is working with:
merge(df1,df2,by=c(col1,col2,col3),all=TRUE)
For mutliple dataframes in a list I try to use the merge_all command
from the package reshape.
Hope this helps,
Rui Barradas
Em 11-01-2013 10:08, Johannes Radinger escreveu:
Hi,
I'd like to merge mutliple dataframes from a list of dataframes by some
common
columns. The approach for simply merging 2 dataframes is working with:
merge(df1,df2,by=c(col1,col2,col3),all=TRUE
Hi,
I would like to split dataframe based on one colum and want
to connect the two dataframes by rows (like rbind). Here a small example:
# The orgininal dataframe
df1 - data.frame(col1 = c(A,A,B,B),col2 = c(1:4), col3 = c(1:4))
# The datafame how it could look like
df2 - data.frame(A.col2 =
Hi,
I have a dataframe containing 3 columns:
data.frame(X=c(100,102,104,102,103),Y=c(12,14,14,13,16),Time=c(1,2,3,4,5))
where X and Y are coordinates and Time refers to an index of a timestep.
Now I would like to get the distance between the consecutive timesteps.
This should actually provide
Hi Ray,
thank you very much. That one-line approach is what I was looking for.
A very simple but very efficient way without loading any other packages.
/j
On Tue, Dec 18, 2012 at 11:17 AM, Ray Brownrigg
ray.brownr...@ecs.vuw.ac.nz wrote:
On 18/12/2012 10:56 p.m., Johannes Radinger wrote:
Hi
Hi,
I've got a dataframe having a code as column name.
Addtionally I have another dataframe with a two columns (and lots of
rows), the first
containing the code and the second some Text (real name).
Now I'd like to use the information (pairs of code and name) of the
second dataframe to rename
.
- Original Message -
From: Johannes Radinger johannesradin...@gmail.com
To: r-help@r-project.org
Cc:
Sent: Tuesday, December 11, 2012 5:55 AM
Subject: [R] Renaming column names according to another dataframe
Hi,
I've got a dataframe having a code as column name.
Addtionally I have
Hi,
I have a dataframe with multiple (appr. 20) columns containing
vectors of different values (different distributions).
Now I'd like to create a crosstable
where I compare the distribution of each vector (df-column) with
each other. For the comparison I want to use the ks.test().
The result
Barradas
Em 28-09-2012 11:10, Johannes Radinger escreveu:
Hi,
I have a dataframe with multiple (appr. 20) columns containing
vectors of different values (different distributions).
Now I'd like to create a crosstable
where I compare the distribution of each vector (df-column) with
each
Hi,
I am using colsplit (package = reshape) to split all strings
in a column according to the same patterns. Here
an example:
library(reshape2)
df1 - data.frame(x=c(str1_name2, str3_name5))
df2 - data.frame(df1, colsplit(df1$x, pattern = _, names=c(str,name)))
This is nearly what I want but I
Thank you,
this works perfectly...
best regards,
Johannes
On Thu, Sep 27, 2012 at 1:43 PM, Ista Zahn istaz...@gmail.com wrote:
Hi Johannes,
On Thu, Sep 27, 2012 at 7:25 AM, Johannes Radinger
johannesradin...@gmail.com wrote:
Hi,
I am using colsplit (package = reshape) to split all
Hi,
I just recently changed my OS to Ubuntu 12.04 (32bit). Now I tried to install
some packages required by my old and working scripts. Unfortunately I fail when
trying to install the package xslx. Maybe it is related to the 32bit version
of my R (its not possible to install a 64 bit version).
for
it. Please do as the posting guide suggests and update to R 2.15.1 (or
R-patched).
On 25/07/2012 09:47, Johannes Radinger wrote:
Hi,
I just recently changed my OS to Ubuntu 12.04 (32bit). Now I tried to
install some packages required by my old and working scripts. Unfortunately I
Hi,
I used to use reshape and moved to reshape2 (R 2.15.1). Now I tried some of my
older scripts and was surprised that my cast function wasn't working like
before.
What I did/want to do:
1) Melt a dataframe based on a vector specifying column names as measure.vars.
Thats working so far:
dfm -
Hi,
I've kind of a tricky question, which I don't know how to solve yet:
I get multiple dataframes loaded (readRDS) in a loop function. Each loaded
dataframe contains two columns one with a var-name and one with a value. The
rownumber (order) is very important as it is a value of the rank
Hi,
I have a 1-column dataframe with rownames and I want to sort it
based on the single column. The typical procedure that is recommended
in diverse posts is to use order in the index. But that destroys my
dataframe structure. Probabaly it is a very simple solution. Here is a
short reproducable
Hi Achim,
thank you for your good explanation and the solution to my
question...
cheers,
/j
Original-Nachricht
Datum: Fri, 8 Jun 2012 09:30:42 +0200 (CEST)
Von: Achim Zeileis achim.zeil...@uibk.ac.at
An: Johannes Radinger jradin...@gmx.at
CC: R-help@r-project.org
Betreff
Hi,
I have a dataframe with around 100 columns. Now I want
to redefine some of the columns as factors (using as.factor).
Luckily all the names of the columns I want to redefine start with
crast. Thus I thought I can use grep() for that purpose...
...I found an example for redefining a single
Hi,
I am looking for a very easy way to transform
a column in a dataframe from counts (eg. c(1,0,21,2,0,0,234,2,0))
into a binary form to get presence/absence values
e.g. c(1,0,1,1,0,0,1,1,0). Is there a simple built-in function?
or do I have do to it with a replaceement funciton using IF x 0
Original-Nachricht
Datum: Thu, 31 May 2012 11:16:32 +
Von: ONKELINX, Thierry thierry.onkel...@inbo.be
An: Johannes Radinger jradin...@gmx.at, R-help@r-project.org
R-help@r-project.org
Betreff: RE: [R] Transform counts into presence/absence
Just use the logical
Hi,
I have a dataframe and want to remove columns from it
that are populated with a similar value (for the total
column) (the variation of that column is 0). Is there an
easier way than to calculate the statistics and then
remove them by hand?
A - runif(100)
B - rep(1,100)
C - rep(2.42,100)
D -
with name B.
I have to think about this
/Johannes
Original-Nachricht
Datum: Thu, 31 May 2012 09:20:27 -0500
Von: J Toll jct...@gmail.com
An: Johannes Radinger jradin...@gmx.at
CC: R-help@r-project.org
Betreff: Re: [R] Remove columns from dataframe based on their statistics
Hi,
I would like to plot some extra text in my plot.
This should be a two line text including a special character (sigma).
I tried so far a to use expression in combination with paste and \n...
but I can't get the line break...
Here what I've done so far:
plot(1,type=n, xaxt='n', yaxt='n',
Hi,
I am using ggplot2 and arrange differnet plots into
one viewport by dividing it into rows and columns:
pushViewport(viewport(layout = grid.layout(nrow=2,ncol=2,widths = unit(c(50,
50), mm),heights = unit(c(50, 50), mm
with following function I can extract the legend of a previously
Hi,
I am really confused how ddply work, so maybe you can help me.
I created a function that sorts a vector etc.
fn - function(x){
x1 - sort(x)
x2 - seq(length(x))
x3 - x2/max(x2)
df - data.frame(x1,x2,x3)
df
}
Probably this is not the best form of the
Hi,
I have two variables ranging both from 0 to 1 (n=500 each).
Now I am interested in plotting them both in one plot (using ggplot2).
So far I used ecdf() (from an example I found with google) to get
values for the cumulatice distribution function which gives a relative
curve. I also want to do
Hi,
it is easiest to explain what I want to do by an example:
lets assume there are two factors/variables:
A - c(1,2,3)
B - c(1,3,3)
Now I would like to generate a list of strings that should look like
(A1_B1,A1_B2,A2_B1,A2_B2). So actually the string
contains all possible combinations of A and
Thank you Steve,
thats the thing I was looking for
/Johannes
Original-Nachricht
Datum: Thu, 3 May 2012 08:20:51 -0400
Von: Steven Wolf wolfs...@msu.edu
An: \'David Winsemius\' dwinsem...@comcast.net, \'Johannes Radinger\'
jradin...@gmx.at
CC: R-help@r-project.org
Hi,
i want to plot empirical cumulative density functions for two variables in
one plot. For better visualizing the differences in the two cumulative curves
I'd like to log-scale the axis.
So far I found 3 possible functions to plot ecdf:
1) ecdf() from the package 'stats'. I don't know how to
Hi,
I am wondering if anybody has experience with
scatterplot matrices where some (but NOT all) axis
are transformed and the labels are nicely plotted.
So far I looked into
1) pairs()
2) scatterplotMatrix() from package 'car'
3) splom() from packagae 'lattice'
4) plotmatrix() from 'ggplot2'
I
Hi,
I try my first time to write a summary method for my function. The result of my
function is a list of two objects (2 arrays). In my summary both objects should
be displayed but with a some introductory text like:
ls - list(A=A123,B=B123)
summaryout=function(x,...){
cat(This is
Hello,
I already posted that on stackoverflow[1], but although it's crossposting,
I think this question can probably easier to be answered by other R-users on
this list, which maintain packages etc.
I would like to make a package out of a function. The function
is working in a script, but when
Hi,
I want to create a pdf of my Man-pages from my package.
Therefore I run in the terminal Rd2pdf on the package and
a pdf of all the pages is created.
After the titlepage there is the general package page, which includes
Description and Details etc. Unfortunately after the Subtitle Details
Hi,
I am trying to do plot a scatterplot matrix using pairs() from
the package graphics. There are now a few things I'd like to improve
for a better understanding.
1) My scatterplot uses two log-scaled axis...as I
don't know how to set them in pairs() I calculated the log before but now
the
Hi,
I am looking for a way to save the result of a function, e.g the lm()-function
to a file and reload it afterwards again. I'd like to do that in order to
minimize the used memory when running the function in a loop. The actual
function I want to store is the evaluate() from the dismo
Original-Nachricht
Datum: Thu, 08 Mar 2012 09:51:01 -0500
Von: Duncan Murdoch murdoch.dun...@gmail.com
An: R. Michael Weylandt michael.weyla...@gmail.com
CC: Johannes Radinger jradin...@gmx.at, R-help@r-project.org
Betreff: Re: [R] Save/Load function()-result to file
Hi,
I'd like to know if it is possible to use wildcards * for indexing...
E.g. I have a vector of strings. Now I'd like to select all elements
which start with A_*? I'd also need to combine that with logical operators:
Select all elements of a vector that start with A (A*) OR that start with B
Hi,
Original-Nachricht
Datum: Tue, 14 Feb 2012 09:59:39 -0500
Von: R. Michael Weylandt michael.weyla...@gmail.com
An: Johannes Radinger jradin...@gmx.at
CC: R-help@r-project.org
Betreff: Re: [R] Wildcard for indexing?
I think the grep()-family (regular expressions
Original-Nachricht
Datum: Tue, 14 Feb 2012 10:18:33 -0500
Von: Sarah Goslee sarah.gos...@gmail.com
An: Johannes Radinger jradin...@gmx.at
CC: R-help@r-project.org
Betreff: Re: [R] Wildcard for indexing?
Hi,
You should probably do a bit of reading about regular
Hi,
I am importing dataframe from an Excel file (xlsx package).
The columns contain acutally measurements for single species and
the column-length is of variable. As it is imported as a dataframe the
difference to the longest column is filled with NA.
To explain it with an example, my dataframe
Hi,
lapply(df, function (x) x[!is.na(x)])
thats is really great!
Thank you!
Original-Nachricht
Datum: Wed, 08 Feb 2012 12:01:17 +0100
Von: Dimitris Rizopoulos d.rizopou...@erasmusmc.nl
An: Johannes Radinger jradin...@gmx.at
CC: R-help@r-project.org
Betreff: Re: [R] remove
Hi,
I want to melt my list and get certain deskriptive factors (length of a
vector etc.) into a dataframe. Best to describe it with an example:
A - seq(4)
B - seq(6)
C - seq(9)
ls - list(A,B,C) # this is my list with vectors of different length
# thats the dataframe how it should look like:
to have them as an own column and no row
names...
like for the list:
list - list(A=1:4, B=1:6, C=1:9)
t(sapply(list, function(x) c(length(x), sum(x 5), sum(x 5
/Johannes
HTH,
Jorge.-
On Wed, Feb 8, 2012 at 8:50 AM, Johannes Radinger wrote:
Hi,
I want to melt my list and get
Hi,
I want to split a dataframe based on a grouping variable (in one column). The
resulting new
dataframes should be stored in a new variable. I tried to split the dataframe
using split() and
to store it using a FOR loop, but thats not working so far:
df -
Am 08.02.2012 um 22:19 schrieb David Winsemius:
On Feb 8, 2012, at 4:11 PM, Johannes Radinger wrote:
Hi,
I want to split a dataframe based on a grouping variable (in one column).
The resulting new
dataframes should be stored in a new variable. I tried to split the
dataframe using
Am 08.02.2012 um 23:47 schrieb David Winsemius:
On Feb 8, 2012, at 5:06 PM, Johannes Radinger wrote:
Am 08.02.2012 um 22:19 schrieb David Winsemius:
On Feb 8, 2012, at 4:11 PM, Johannes Radinger wrote:
Hi,
I want to split a dataframe based on a grouping variable (in one column
to variables and
coercing these to a list.
Any suggestions are mostly welcomme.
Thank you,
best regards,
Johannes Radinger
--
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R
:22:30 -0800
Von: Joshua Wiley jwiley.ps...@gmail.com
An: Johannes Radinger jradin...@gmx.at
CC: r-help@r-project.org
Betreff: Re: [R] Assigning objects to variable and variable to list in a for
loop
Hi Johannes,
There is a relatively elegant solution if you assign in a list:
reslist
hi,
Original-Nachricht
Datum: Fri, 3 Feb 2012 09:04:19 -0500
Von: Steve Lianoglou mailinglist.honey...@gmail.com
An: Johannes Radinger jradin...@gmx.at
CC: Joshua Wiley jwiley.ps...@gmail.com, r-help@r-project.org
Betreff: Re: [R] Assigning objects to variable and variable
rainer.schuerm...@gmx.net
An: Johannes Radinger jradin...@gmx.at
CC: r-help@r-project.org r-help@r-project.org
Betreff: Re: [R] reshape dataframe to array (pivot table)
Hi,
I wouldn't know how to fill the data into the array form you want, but
you can get the aggregated data with
dfm - melt( df
Hello,
I am wondering about the X11() graphic device on Windows.
I try to plot a raster image but nothing gets displayed. I
found some pages where it is mentioned that x11() not
always supports raster rendering.
Is there any add on for x11, any update or any R-package
which solves that
On 25.01.2012 12:45, Johannes Radinger wrote:
Hello,
I am wondering about the X11() graphic device on Windows.
I try to plot a raster image but nothing gets displayed. I
found some pages where it is mentioned that x11() not
always supports raster rendering.
Is there any add
On 25.01.2012 13:42, Johannes Radinger wrote:
On 25.01.2012 12:45, Johannes Radinger wrote:
Hello,
I am wondering about the X11() graphic device on Windows.
I try to plot a raster image but nothing gets displayed. I
found some pages where it is mentioned that x11() not
always
Hello,
I would like to reshape a dataframe into an array. This is kind a similar task
as Excel performs with a Pivot table. To illustrate it:
LOC - factor(c(1,2,2,3,1,1))
SPEC1 - c(0,0,23,0,12,11)
SPEC2 - c(1,2,0,0,0,4)
df - data.frame(LOC,SPEC1,SPEC2) # original dataframe
a -
Hello,
this is a very simple question:
How can I find out if a word is part of a list of words
like:
a - word1
b - word4
vector - c(word1,word2,word3)
I tried it with match(a,vector)
but this gives the position of the word.
I am not sure if and how that can be
done with a logical operator
Hi,
thank you very much... %in% is the operator I was looking for.
cheers,
johannes
Original-Nachricht
Datum: Fri, 20 Jan 2012 13:01:54 +0100
Von: Rainer M Krug r.m.k...@gmail.com
An: Johannes Radinger jradin...@gmx.at
CC: R-help@r-project.org
Betreff: Re: [R] test
...
best regards,
/johannes
Original-Nachricht
Datum: Thu, 19 Jan 2012 13:42:24 +0100 (MET)
Von: Gerrit Eichner gerrit.eich...@math.uni-giessen.de
An: Johannes Radinger jradin...@gmx.at
CC: R-help@r-project.org
Betreff: Re: [R] Split values in vector
Hi, Johannes,
maybe
-Nachricht
Datum: Thu, 19 Jan 2012 13:42:24 +0100 (MET)
Von: Gerrit Eichner gerrit.eich...@math.uni-giessen.de
An: Johannes Radinger jradin...@gmx.at
CC: R-help@r-project.org
Betreff: Re: [R] Split values in vector
Hi, Johannes,
maybe
X - unlist( strsplit( as.character( x$ART
Hello,
I have a vector which looks like
x$ART
...
[35415] 0001-1;02-1;05-1;
[35417] 01-1; 01-1;02-1;
[35419] 01-1; 00
[35421] 01-1;04-1;05-1;
-giessen.de
An: Johannes Radinger jradin...@gmx.at
CC: R-help@r-project.org
Betreff: Re: [R] Split values in vector
Hi, Johannes,
maybe
X - unlist( strsplit( as.character( x$ART), split = ;, fixed = TRUE))
X - strsplit( X, split = -, fixed = TRUE)
X - sapply( X, function( x
Dear Jean,
Thank you, expand.grid was the function I needed.
/johannes
See
?expand.grid
For example,
df - expand.grid(L=L, AR=AR, SO=SO, T=T)
df$y - fun(df$L, df$AR, df$SO, df$T)
Jean
Johannes Radinger wrote on 01/13/2012 12:28:46 PM:
Hello
Hello,
probably it is quite easy but I can get it: I have
mulitple numeric vectors and a function using
all of them to calculate a new value:
L - c(200,400,600)
AR - c(1.5)
SO - c(1,3,5)
T - c(30,365)
fun - function(L,AR,SO,T){
exp(L*AR+sqrt(SO)*log(T))
}
How can I get an array or
Hello,
I know that it'll be quite easy to do what I want but somehow I am lost as I am
new to R. I want to get summary results arranged by groups. In detail
I'd like get the number (levels) of Species per Family like for this dataset:
SPEC - factor(c(a,a,b,b,c,c,c,d,e,e,e,e))
FAM -
Original-Nachricht
Datum: Mon, 2 Jan 2012 14:29:07 +0100
Von: Petr PIKAL petr.pi...@precheza.cz
An: Johannes Radinger jradin...@gmx.at
CC: r-help@r-project.org
Betreff: Re: [R] summary per group
Hi
Hello,
I know that it'll be quite easy to do what I want
Am 10.12.2011 um 16:50 schrieb Uwe Ligges:
On 09.12.2011 14:15, Johannes Radinger wrote:
Hi,
I am trying to get write my first own package.
I followed the instructions in Creating R Packages: A Tutorial
and Writing R Extensions. So far everything works really
fine, the script works
Hi,
I am trying to get write my first own package.
I followed the instructions in Creating R Packages: A Tutorial
and Writing R Extensions. So far everything works really
fine, the script works and even the man-pages don't show
any problems during the check process.
During check there is also
Hi,
I just started with writing functions in R and so some questions popped up.
I provide some values as argument to my function such as:
function(a,b,c){}
Now i want that the function first checks if the arguments are valid for the
function. E.g argument a has to be a number in the range 0-1.
(a)) stop(a is not numeric)
if(0 a a 1) stop(a must be a value between 0 and 1)
a
}
/Johannes
Original-Nachricht
Datum: Tue, 6 Dec 2011 07:04:59 -0500
Von: R. Michael Weylandt michael.weyla...@gmail.com
An: Johannes Radinger jradin...@gmx.at
CC: r-help@r
-Nachricht
Datum: Tue, 6 Dec 2011 07:57:44 -0500
Von: R. Michael Weylandt michael.weyla...@gmail.com
An: r-help r-help@r-project.org, Johannes Radinger jradin...@gmx.at
Betreff: Re: [R] Argument validation within functions
Use the ! (not) operator.
Not sure what you mean
Hello,
assume we have following dataframe:
group -c(rep(A,5),rep(B,6),rep(C,4))
x - c(runif(5,1,5),runif(6,1,10),runif(4,2,15))
df - data.frame(group,x)
Now I want to select all cases (rows) for those groups
which have more or equal 5 cases (so I want to select
all cases of group A and B).
How
Hello,
I'd like to add custom labels to my pair() plot. These
labels include math expression but they aren't correctly
displayed...
Further, I want that the boxes for the text.panel (diagonal)
have an other background color (grey80). Is that generally
possible? If yes how do I have to set it?
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