Still doesn't work.
When using rbind to build the data.frame, it get a structure mostly full
of NA.
The data is correct, so something about pushing into the data.frame is
breaking.
Example code:
results - data.frame()
for(i in 1:n){
#do all the work
#a is a test label. b,c,d are
Langfelder
Sent: Thursday, November 11, 2010 12:25 PM
To: Noah Silverman
Cc: r-help@r-project.org
Subject: Re: [R] Populating then sorting a matrix
and/or data.frame
On Thu, Nov 11, 2010 at 11:33 AM, Noah Silverman
n...@smartmediacorp.com
wrote:
Still doesn't work.
When using rbind to build
That makes perfect sense. All of my numbers are being coerced into
strings by the c() function. Subsequently, my data.frame contains all
strings.
I can't know the length of the data.frame ahead of time, so can't
predefine it like your example.
One thought would be to make it arbitrarily long
David,
Great solution. While a bit longer to enter, it lets me explicitly
define a type for each column.
Thanks!!!
-N
On 11/11/10 4:02 PM, David Winsemius wrote:
On Nov 11, 2010, at 6:38 PM, Noah Silverman wrote:
That makes perfect sense. All of my numbers are being coerced
Hi,
I have a process in R that produces a lot of output. My plan was to
build up a matrix or data.frame row by row, so that I'll have a nice
object with all the resulting data.
I started with:
results - matrix(ncol=3)
names(results) - c(one, two, three)
Then, when looping through the data:
That was a typo.
It should have read:
results[results$one 100,]
It does still fail.
There is ONE column that is text. So my guess is that R is seeing that
and assuming that the entire data.frame should be factors.
-N
On 11/10/10 11:16 PM, Michael Bedward wrote:
Hello Noah,
If you set
Hi,
I'm trying to figure out how to use capturing parenthesis in regular
expressions in R. (Doing this in Perl, Java, etc. is fairly trivial,
but I can't seem to find the functionality in R.)
For example, given the string:10 Nov 13.00 (PFE1020K13)
I want to capture the first to digits
:
On Thu, 4 Nov 2010, Noah Silverman wrote:
Hi,
I'm trying to figure out how to use capturing parenthesis in regular
expressions in R. (Doing this in Perl, Java, etc. is fairly trivial,
but I can't seem to find the functionality in R.)
For example, given the string:10 Nov 13.00
Thanks!
-N
On 7/9/10 2:20 AM, Noah Silverman wrote:
Hi,
I am trying to figure out a short way to access two values output from
the sort function.
x - c(3,4,3,6,78,3,1,2)
sort(x, index.return=T)
$x
[1] 1 2 3 3 3 4 6 78
$ix
[1] 7 8 1 3 6 2 4 5
It would be great
Hi,
I am trying to figure out a short way to access two values output from
the sort function.
x - c(3,4,3,6,78,3,1,2)
sort(x, index.return=T)
$x
[1] 1 2 3 3 3 4 6 78
$ix
[1] 7 8 1 3 6 2 4 5
It would be great to do something like this (doesn't work.):
c(y, indexes) - sort(x,
Steve,
Couldn't he also just use the decision.value property to see the
equivilent of t(x) %*% b for each row?
-N
On 7/9/10 7:11 PM, Steve Lianoglou wrote:
Hi,
On Fri, Jul 9, 2010 at 12:15 PM, manuel.martin
manuel.mar...@orleans.inra.fr wrote:
Dear all,
after having calibrated a svm
Hi,
I have a dataset where the results are coded (yes, no) We want to
do some machine learning with SVM to predict the yes outcome
My problem is that if I just use the as.factor function to convert, then
it reverses the levels.
--
x - c(no, no, no, yes, yes, no, no)
Hi,
I have a dataset where the results are coded (yes, no) We want to
do some machine learning with SVM to predict the yes outcome
My problem is that if I just use the as.factor function to convert, then
it reverses the levels.
--
x - c(no, no, no, yes, yes, no, no)
I'm reading Gellman's book Data Analysis Using Regression and
Multilevel-Hierarchical Models
In Chapter 7 (and later), he makes frequent referent to a function names
sim.
I can't find the function anywhere, not in my standard R install, or in
any of the packages.
Doe anyone have a
Hi,
I'm working on a project using the kernlab library.
For one phase, I want the decision values from the SVM prediction, not
the class label. the e1071 library has this function, but I can't find
the equivalent in ksvm.
In general, when an SVM is used for classification, the label of an
I'm running a long MCMC chain that is generating samples for 22 variables.
I have each run of the chain as a row in a matrix.
So: Chain[,1] is the column with all the samples for variable one.
Chain[,2] is the column with all the samples for variable 2, etc.
I'd like to fit all 22 on a single
Hi,
I used the term run, as each iteration of the Gibbs sampler produces
22 variables (coefficients for Beta in a regression model)
The example wont work
On 6/1/10 5:54 AM, Ben Bolker wrote:
Noah Silverman noah at smartmediacorp.com writes:
I'm running a long MCMC chain
AM, Noah Silverman wrote:
Hi,
Working on a report that is going to have a large number of graphs and
summaries. We have 80 groups with 20 variables each.
Ideally, I'd like to produce ONE page for each group. It would have two
columns of 10 graphs and then the 5 number summary
Hi,
I want to add a box at the bottom of a lattice window (device/page?).
Lattice has drawn a nice group of panels with all the plots I need. How
do I add my own summary text at the bottom (several lines worth?)
__
R-help@r-project.org mailing list
On Tue, Jun 1, 2010 at 9:37 AM, Noah Silverman
n...@smartmediacorp.com mailto:n...@smartmediacorp.com wrote:
Hi,
I used the term run, as each iteration of the Gibbs sampler produces
22 variables (coefficients for Beta in a regression model)
The example wont work
, 2010 at 10:51 AM, Noah Silverman
n...@smartmediacorp.com mailto:n...@smartmediacorp.com wrote:
You are correct,
I initially missed the as.mcmc step. Without it, R doesn't want
to squeeze so many plots onto a page.
I've had that problem before with lattice...which makes me wonder
::splitTextGrob
function might help.
HTH,
baptiste
On 1 June 2010 19:37, Noah Silverman n...@smartmediacorp.com wrote:
Hi,
I want to add a box at the bottom of a lattice window (device/page?).
Lattice has drawn a nice group of panels with all the plots I need. How
do I add my own summary text
- matrix(runif(2200),ncol=22)
m - as.mcmc(x)
p = xyplot(m, layout = c(2, 11))
pdf(,height=15)
arrange(p, tableGrob(as.matrix(summary(iris)), theme=theme.white()),
heights= unit(c(3,1),null))
dev.off()
HTH,
baptiste
On 1 June 2010 20:52, Noah Silverman n...@smartmediacorp.com wrote
We're running Monte Carlo repeated measures for several groups.
The goal is to determine the number of time each group has the highest
score.
A toy example:
[,1] [,2] [,3]
0.1 0.2 0.3
0.1 0.2 0.3
0.1 0.2 0.3
0.1 0.3 0.2
0.1 0.3 0.2
0.2 0.3 0.1
For this example:
Hi,
Working on a report that is going to have a large number of graphs and
summaries. We have 80 groups with 20 variables each.
Ideally, I'd like to produce ONE page for each group. It would have two
columns of 10 graphs and then the 5 number summary of the variables at
the bottom.
So, perhaps
Lattice looks nice, but how can I put some summary text at the bottom?
On 5/31/10 11:27 AM, RICHARD M. HEIBERGER wrote:
Use lattice.
require(lattice)
?lattice
?xyplot
__
R-help@r-project.org mailing list
Hello,
I need to build a list of lists
We have 20 groups we are generating MCMC samples for. There are 10
coefficients, and 1 MCMC iterations.
I would like to store each iteration by-group in a list. My problem is
with the first iteration.
Here is a toy example:
Chain - list()
for (j in
]], coef)
If it does, this has the additional advantage that it tends to be
faster to initialize the list at size rather than expanding it as
needed.
HTH,
Josh
On Sun, May 30, 2010 at 2:52 PM, Noah Silverman n...@smartmediacorp.com
wrote:
Hello,
I need to build a list of lists
We
)
}
}
On Sun, May 30, 2010 at 6:05 PM, Noah Silverman n...@smartmediacorp.com
wrote:
That would be great, except I just realized I made a typo when sending
my code.
I'm tracking 20 coefficents for 10 groups. So I need a top list of 10
groups. Then each of the 10,000 samples for each of the 20
to lm, but not actually doing any regression?
Thanks again!
-N
On 5/15/10 11:17 AM, Thomas Stewart wrote:
Maybe this?
group - factor(c(A, B,B,C,C,C))
model.matrix(~0+group)
-tgs
On Sat, May 15, 2010 at 2:02 PM, Noah Silverman
n...@smartmediacorp.com mailto:n...@smartmediacorp.com wrote
1 0
4 4 3 0 0 1
5 5 4 0 0 1
6 6 5 0 0 1
Any ideas?
-N
On 5/15/10 11:02 AM, Noah Silverman wrote:
Hi,
I'm looking for an easy way to discretize factors in R
I could, but with close to 100 columns, its messy.
On 5/16/10 11:22 AM, Peter Ehlers wrote:
On 2010-05-16 11:06, Noah Silverman wrote:
Update,
I have it working, but now its producing really ugly labels. Must be a
small adjustment to the code. Any ideas??
##Create example data.frame
Hi,
I'm looking for an easy way to discretize factors in R
I've noticed that the lm function does this automatically with a nice
result.
If I have
group - c(A, B,B,C,C,C)
and run:
lm(result ~ x1 + group)
The lm function has split the group into separate binary variables {0,1}
before
Hi,
An example data set is:
grouplevelcolor
A1blue
A1Red
B1blue
B2Red
A2Red
B2Red
B2blue
B2blue
A2blue
A2Red
I'd like to
Hi,
I'm calculating a conditional logit on some data stratified by group.
My understanding was that a conditional logit by definition returns a
value between 0 and 1 a a probability. Can anyone suggest why I'm
seeing results outside of the {0,1} range??
The call in R is:
m - clogit(score ~
Thanks David,
That explains a lot. I appreciate it.
--
Noah
On 4/20/10 3:48 PM, David Winsemius wrote:
On Apr 20, 2010, at 5:59 PM, Noah Silverman wrote:
Hi,
I'm calculating a conditional logit on some data stratified by group.
My understanding was that a conditional logit
On 4/20/10 4:22 PM, Noah Silverman wrote:
Thanks David,
That explains a lot. I appreciate it.
--
Noah
On 4/20/10 3:48 PM, David Winsemius wrote:
On Apr 20, 2010, at 5:59 PM, Noah Silverman wrote:
Hi,
I'm calculating a conditional logit on some data stratified by group.
My
David,
That helps me a lot. Thanks!!!
-N
On 4/12/10 9:06 PM, David Winsemius wrote:
dat - as.data.frame(matrix( rnorm(200), 100 , 2)) # bivariate normal
n=100
ab - matrix( c(-5,-5,5,5), 2, 2) # interval [-5,5) x [-5,5)
nbin - c( 20, 20) # 400 bins
bins - bin2(dat, ab, nbin) # bin
Hi,
I'm trying to setup some complicated binning with statistics and could
use a little help.
I've found the bin2 function from the ash package, but it doesn't do
everything I need. My intention is to copy some of their code and then
modify as needed.
I have a vector of two columns:
Hi,
I'm learning more about SVMs and kernels in general. I've gotten used
to using the svm function in the e1071 package. It works great.
Now, I want to do/learn some more interesting stuff. (Perhaps my own
kernel and/or scoring system). So I want to better understand
1) how calculation of
Thanks Steve,
1) I get that the kernel is a normal function. But my understanding
was that the kernel created a higher dimensional space than the original
data, thus allowing the SVM to be a pseudo-linear classifier in that
higher dimension. So, if the the kernel is the dot_product do I iterate
I'm just starting to learn about GAM models.
When using the lm function in R, any factors I have in my data set are
automatically converted into a series of binomial variables.
For example, if I have a data.frame with a column named color and values
red, green, blue. The lm function
-project.org] On Behalf Of
Noah Silverman [n...@smartmediacorp.com]
Sent: March 19, 2010 12:54 PM
To: r-help@r-project.org
Subject: [R] Factor variables with GAM models
I'm just starting to learn about GAM models.
When using the lm function in R, any factors I have in my data set are
automatically
Corey,
Thanks for the quick reply.
I cant give any sample code as I don't know how to code this in R.
That's why I tried to pass along some pseudo code.
I'm looking for the best beta that maximize likelihood over all the
groups. So, while your suggestion is close, it isn't quite what I need.
Hi,
Looking for a function in R that can help me calculate a parameter that
maximizes the likelihood over groups of observations.
The general formula is:
p = exp(xb) / sum(exp(xb))
So, according to the formulas I've seen published, to do this by group is
product(p = exp(x_i * b_i) /
Hi,
I'm just learning about poison links for the glm function.
One of the data sets I'm playing with has several of the variables as
factors (i.e. month, group, etc.)
When I call the glm function with a formula that has a factor variable,
R automatically converts the variable to a series of
should be equal to the
fitted value. Here it is not. I don't understand why. Any insight?
-N
On 3/2/10 12:47 AM, (Ted Harding) wrote:
On 02-Mar-10 08:02:27, Noah Silverman wrote:
Hi,
I'm just learning about poison links for the glm function.
One of the data sets I'm playing with has
I'm a bit confused on how to use lapply with a data.frame.
For example.
lapply(data, function(x) print(x))
WHAT exactly is passed to the function. Is it each ROW in the data
frame, one by one, or each column, or the entire frame in one shot?
What I want to do apply a function to each row
I'm a bit confused on how to use lapply with a data.frame.
For example.
lapply(data, function(x) print(x))
WHAT exactly is passed to the function. Is it each ROW in the data
frame, one by one, or each column, or the entire frame in one shot?
What I want to do apply a function to each row
Hi,
I'm trying to normalize some data.
My data is organized by groups. I want to normalize PER GROUP as
opposed to over the entire data set.
The current double loop that I'm using takes almost an hour to run on
about 30,000 rows of data in 2,500 groups.
I'm currently doing this:
/ data$sum
data
.. or even
transform(data, norm=ave(y, group, FUN = function(x) x/sum(x)))
I hope it helps.
Best,
Dimitris
Noah Silverman wrote:
Hi,
I'm trying to normalize some data.
My data is organized by groups. I want to normalize PER GROUP as
opposed to over
Hi,
I've search rseek.org high and low and can't seem to find an answer to this.
I want to maximize likelihood for a set of training data, but the data
is grouped. (Think multiple trials.)
It would probably be possible to do this with some nested for loops
manually, but would be painfully
Hi,
I have a process using svm from the e1071 library. it works.
I want to try using the KSVM library instead. The same data used wiht
e1071 gives me an error with KSVM.
My data is a data.frame.
sample code:
svm_formula - formula(y ~ a + B + C)
svm_model - ksvm(formula, data=train_data,
Hi,
It looks like you are potentially dealing with two separate issues.
1) Access - Mysql has very find grained permissions as to who can access
what and from where. You need to make sure that your username in mysql
is allowed to access the database/tables from your location.
2) Corruption
Hi,
This is probably going to be one of those, It depends what you want
kind of answers, but I'm very curious to see if the group has an opinion
or some general suggestions.
The actual experiment is too complicated for a quick e-mail, but I'll
summarize well enough(hopefully) to get the
Hi,
This is probably going to be one of those, It depends what you want
kind of answers, but I'm very curious to see if the group has an opinion
or some general suggestions.
The actual experiment is too complicated for a quick e-mail, but I'll
summarize well enough(hopefully) to get the
Hi,
I'm experimenting with a few learners that require a matrix as their
input. (Currently svmpath, vbmp, etc.)
I currently have a dataframe with 50 columns and 20,000 rows.
I tried using:
x - as.matrix(my_data.frame)
If I then as, is.matrix(x), I get TRUE.
However everywhere I've tried
:
On Fri, Oct 16, 2009 at 01:33:14AM -0700, Noah Silverman wrote:
Hi,
I'm experimenting with a few learners that require a matrix as their
input. (Currently svmpath, vbmp, etc.)
I currently have a dataframe with 50 columns and 20,000 rows.
I tried using:
x- as.matrix(my_data.frame)
If I
Hi,
I have a data.frame that I need to scale.
I've been using the scale function and it works nicely.
Some of the libraries I'm testing won't accept negative values for data,
so I need to find a way to scale the data from 0 to 1
Any ideas?
Thans!
I think I've come across a bug in the command line switches.
From R --help
--vanillaCombine --no-save, --no-restore, --no-site-file,
--no-init-file and --no-environ
--slave Make R run as quietly as possible
-q, --quiet
Hi,
I've been testing some models with the MCMCpack library.
I can run the process and get a nice model object. I can easily see
the summary and even plot it.
I can't seem to figure out how to:
1) Access the final coefficients in the model
2) Turn the coefficients into a model so I can then
this:
apply(foo, 2, mean) or
apply(foo, 2, median)
Thanks,
Deb
Noah Silverman n...@smartmediacorp.com 22/09/2009 12:34 pm
Hi,
I've been testing some models with the MCMCpack library.
I can run the process and get a nice model object. I can easily see
the summary and even plot it.
I can't
Hi,
I'm not sure of the correct nomenclature or function for what I'm trying
to do.
I'm interested in calculated a logistic regression on a binary dependent
variable (True,False).
There are a few ways to easily do this in R. Both SVM and GLM work easily.
The part that I want to add is
have to be adjusted to look per group.
I would call this something like grouped maximum liklihood if I got
to make up the name.
-N
On 9/17/09 11:06 AM, (Ted Harding) wrote:
On 17-Sep-09 17:28:16, Noah Silverman wrote:
Hi,
I'm not sure of the correct nomenclature or function for what
Hello,
I have a very unusual situation with an SVM and wanted to get the
group's opinion.
We developed an experiment where we train the SVM with one set of data
(train data) and then test with a completely independent set of data
(test data). The results were VERY good.
I found and error
...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Noah Silverman
Sent: Monday, September 14, 2009 1:00 PM
To: r help
Subject: [R] Strange question/result about SVM
Hello,
I have a very unusual situation with an SVM and wanted to get the
group's opinion.
We developed an experiment
Hi,
I'm a daily user of both mac and Linux so wanted to offer some thoughts:
1) R runs great on a Mac. There is a standard install from the cran
website that has a nice GUI built into it. You can do things like drag
files to the console and it will fill in the path name.
2) I like using
Steve,
You make a good point. I confused 64 bit with a multi-core setup.
That said, I don't belive the pretty packaged up GUI has a 64 bit
version, just the raw terminal version does.
On 9/11/09 12:38 PM, Steve Lianoglou wrote:
Hi,
On Sep 11, 2009, at 3:08 PM, Noah Silverman wrote:
3) I
Thanks Steve,
That's a big help.
On 9/11/09 12:48 PM, Steve Lianoglou wrote:
Hi,
On Sep 11, 2009, at 3:40 PM, Noah Silverman wrote:
Steve,
You make a good point. I confused 64 bit with a multi-core setup.
That said, I don't belive the pretty packaged up GUI has a 64 bit
version, just
Hi,
Our discussions about 64 bit R has led me to another thought.
I have a nice dual core 3.0 chip inside my Linux Box (Running Fedora 11.)
Is there a version of R that would take advantage of BOTH cores??
(Watching my system performance meter now is interesting, Running R will
hold a single
Hi,
Is there an alternative to the scale function where I can specify my own
mean and standard deviation?
I've come across an interesting issue where this would help.
I'm training and testing on completely different sets of data. The
testing set is smaller than the training set.
Using
sure that a value is transformed the same regardless of
which data set it is in.
Do I have this correct, or can anybody contribute any more to the concept?
Thanks!
--
Noah
On 9/11/09 1:10 PM, Noah Silverman wrote:
Hi,
Is there an alternative to the scale function where I can specify my
own
Genius,
That certainly is much faster that what I had worked out on my own.
I looked at sweep, but couldn't understand the rather thin help page.
Your example makes it really clear
Thank You!!!
--
Noah
On 9/11/09 1:57 PM, Gavin Simpson wrote:
On Fri, 2009-09-11 at 13:10 -0700, Noah
Hi,
I have a strange one for the group.
We have a system that predicts probabilities using a fairly standard svm
(e1017). We are looking at probabilities of a binary outcome.
The input data is generated by a perl script that calculates a bunch of
things, fetches data from a database, etc.
You both make good points.
Ideally, it would be nice to know WHY it works.
Without digging into too much verbiage, the system is designed to
predict the outcome of certain events. The broken model predicts
outcomes correctly much more frequently than one with the broken data
withheld. So,
You both make good points.
Ideally, it would be nice to know WHY it works.
Without digging into too much verbiage, the system is designed to
predict the outcome of certain events. The broken model predicts
outcomes correctly much more frequently than one with the broken data
withheld. So,
Interesting point.
Our data is NOT continuous. Sure, some of the test examples are older
than others, but there is no relationship between them. (More Markov
like in behavior.)
When creating a specific record, we actually account for this in our SQL
queries which tend to be along the lines
Erin,
Linux supports many scripting languages.
Which language are you interested in: Perl, PHP, Bash, Python, etc???
--
Noah
On 9/2/09 10:35 PM, Erin Hodgess wrote:
Dear R People:
I know that this is off topic, but could anyone recommend a good book
on Linux scripting please?
Any help
Hi,
There are good books by O'Reilly for both sed and awk.
That said, neither is what I would call a complete scripting language.
Without knowing the details of your requirements, I STRONGLY suggest
that you learn perl. It allows you do almost anything with data, fetch
web pages, access
Hi,
I use the max function often to find the top value from a matrix or
column of a data.frame.
Now I'm looking to find the top 2 (or three) values from my data.
I know that I could sort the list and then access the first two items,
but that seems like the long way. Is there some way to
Department of Statistics
UC Berkeley
spec...@stat.berkeley.edu
On Thu, 3 Sep 2009, Noah Silverman wrote:
Hi,
I use the max function often to find the top value from a matrix or
column of a data.frame.
Now I'm looking to find the top 2 (or three) values
Steve,
That doesn't work.
I just trained an SVM with 80 variables.
svm_model$coefs gives me a list of 10,000 items. My training set is
30,000 examples of 80 variables, so I have no idea what the 10,000 items
represent.
There should be some attribute that lists the weights for each of the
(significance.) the SVM assigned to each variable.
On 8/31/09 12:54 AM, Achim Zeileis wrote:
On Mon, 31 Aug 2009, Noah Silverman wrote:
Steve,
That doesn't work.
I just trained an SVM with 80 variables.
svm_model$coefs gives me a list of 10,000 items. My training set is
30,000 examples
Hello,
I want to start testing using the MNP probit function in stead of the
lrm function in my current experiment.
I have one dependant label and two independent varaibles.
The lrm is simple
model - lrm(label ~ val1 + val2)
I tried the same thing with the mnp function and got an error
was
that they were using the same for this application.
Any thoughts?
--
Noah
On 8/31/09 5:07 PM, Achim Zeileis wrote:
On Mon, 31 Aug 2009, Noah Silverman wrote:
Hello,
I want to start testing using the MNP probit function in stead of the
lrm function in my current experiment.
I have one
I get that.
Still trying to figure out what the multi nominal labels they used
were. That's why I passed on the reference to the seminar summary.
On 8/31/09 5:40 PM, Achim Zeileis wrote:
On Mon, 31 Aug 2009, Noah Silverman wrote:
Thanks Achim,
I discovered the Journal article just after
multiple discreet choices, I'm not sure how the probit model
would. Hence my inquiry.
On 8/31/09 6:23 PM, Achim Zeileis wrote:
On Mon, 31 Aug 2009, Noah Silverman wrote:
I get that.
Still trying to figure out what the multi nominal labels they used
were. That's why I passed on the reference
rank, would you please show me where that is in
their paper.
Thanks!
-N
On 8/31/09 7:17 PM, Achim Zeileis wrote:
On Mon, 31 Aug 2009, Noah Silverman wrote:
Um. I did my research. Have been for years. I assume you're
referring to Boltman and Chapmanm A multinomial logit model
Hi,
I need a bit of guidance with the sapply function. I've read the help
page, but am still a bit unsure how to use it.
I have a large data frame with about 100 columns and 30,000 rows. One
of the columns is group of which there are about 2,000 distinct groups.
I want to normalize (sum
Hello,
I'm using the svm function from the e1071 package.
It works well and gives me nice results.
I'm very curious to see the actual coefficients calculated for each
input variable. (Other packages, like RapidMiner, show you this
automatically.)
I've tried looking at attributes for the
Deb,
I generally run my larger R tasks on a server.
Here is my workflow.
1) Write an R script using a text editor. (There are many popular ones.)
2) FTP the R script to your server.
3) SSH into the server
4) Run R
5) Run the script that you uploaded from the R process you just started.
On
Hi,
I'm trying to find an easy way to do this.
I want to select the top three values of a specific column in a subset
of rows in a data.frame. I'll demonstrate.
ABC
x21
x41
x32
y15
y26
y38
I want the top 3 values of B from the
I only have a few values in my example, but the real data set might have
20-100 rows with A=X. So how do I pick just the three highest ones?
-N
On 8/26/09 2:46 AM, Ottorino-Luca Pantani wrote:
df.mydata[df.mydata$A==X AND df.mydata$C 2, ]
will do the job ?
8rino
Noah Silverman ha
summary function
head(df.mydata[df.mydata$A==X df.mydata$C 2, ],3)
Colin.
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
On Behalf Of Noah Silverman
Sent: 26 August 2009 10:54
To: ottorino-luca.pant...@unifi.it
Cc: r help
Subject: Re: [R
Hi,
Is there a way to build up a vector, item by item. In perl, we can
push an item onto an array. How can we can do this in R?
I have a loop that generates values as it goes. I want to end up with a
vector of all the loop results.
In perl it woud be:
for(item in list){
result -
?
In general, the for loop construct can be avoided so you don't have to
think about messy indexing. What exactly are you trying to do?
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Noah Silverman
Sent: Wednesday, August 26, 2009 2:20
of Statistics
UC Berkeley
spec...@stat.berkeley.edu
On Wed, 26 Aug 2009, Noah Silverman wrote:
The actually process is REALLY complicate, I just gave a simple example
for the list.
I have a lot of steps to process the data before I get a final
score
reference didn't help me much
with that so if you know of others, please let me know. Thanks.
Mark
On Aug 25, 2009, *Noah Silverman* n...@smartmediacorp.com wrote:
Hello
I believe that I'm getting
is the exact value of the strata saved as part of the
model, or is it just used for grouping?)
On 8/22/09 10:57 AM, Charles C. Berry wrote:
On Fri, 21 Aug 2009, Noah Silverman wrote:
Hi,
For fun, I'm trying to throw some horse racing data into either an
svm or lrm model. Curious to see what
options. (I can see
one that is a probability option.)
Thanks!!
-N
On 8/22/09 10:57 AM, Charles C. Berry wrote:
On Fri, 21 Aug 2009, Noah Silverman wrote:
Hi,
For fun, I'm trying to throw some horse racing data into either an
svm or lrm model. Curious to see what comes out as there are so
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