Am Montag, den 12.12.2011, 09:41 -0500 schrieb R. Michael Weylandt :
Why can't you just replace temp/data with filename (no quotes)? I'm not
sure I get the question...
… no I am feeling silly and I do not know where I screwed up before.
Here is the full working example.
#!/usr/bin/env
Dear Jose,
Am Montag, den 12.12.2011, 19:44 + schrieb Jose Bustos Melo:
Hello everyone,
I want make a variable selection from a dataframe, but when I build this new
object (using cbind) the new table (which is a matrix) I lost all the
original factor names in the variables. I get
Dear R folks,
I would like to use un-/a-/non-symmetric centered, i. e. the expectation
vanishes/is zero, distributions.
Searching for that is not that easy since all three words un-, a-,
non-symmetric seem to be common.
Do I need to create such a distribution myself by for example composing
a
Dear Dennis and Steve,
Am Sonntag, den 31.07.2011, 23:32 -0400 schrieb Steve Lianoglou:
[…]
How about trying to write the of this `f4` function below using the
rcpp/inline combo. The C/C++ you will need to write looks to be quite
trivial, let's change f4 to accept an x argument as a vector:
Dear R folks,
having simulation data in a vector n2off, I know that they should be
similar to a power function f [1], f(n) = n^(-1/r), r ∈ ℕ\{0}, and I
want to find the value for r best fitting the simulation data.
Furthermore I know that this is only true for big n, that means n2off(n)
~ f(n) ⇔
Am Sonntag, den 31.07.2011, 23:32 -0500 schrieb R. Michael Weylandt :
Glad to help -- I haven't taken a look at Dennis' solution (which may be far
better than mine), but if you do want to keep going down the path outlined
below you might consider the following:
I will try Dennis’ solution
Am Montag, den 01.08.2011, 12:43 -0400 schrieb R. Michael Weylandt :
I've only got a 20 minute layover, but three quick remarks:
1) Do a sanity check on your data size: if you want a million walks of
a thousand steps, that already gets you to a billion integers to
store--even at a very low
Dear responders,
thank you very much for all your answers, suggestions and corrections. I
will try to give feedback and share my findings.
Am Donnerstag, den 28.07.2011, 01:56 + schrieb William Dunlap:
[…]
You might try using sample(c(-1,1), size=length, replace=TRUE)
instead of
Dear R folks,
I am sorry to ask this simple question, but my search for the right
way/command was unsuccessful.
I have a vector
x - c(2, 2, 3, 3, 4, 6)
Now the values of x should be considered the index of another vector
with possible greater length, say 8, and the value should be how often
Dear Sarah,
Am Sonntag, den 31.07.2011, 18:10 -0400 schrieb Sarah Goslee:
I would use something like this:
x - c(2,2,3,3,4,6)
table(x)
x
2 3 4 6
2 2 1 1
x - factor(x, levels=1:8)
table(x)
x
1 2 3 4 5 6 7 8
0 2 2 1 0 1 0 0
awesome. Thank you.
Looking further I found the
Am Sonntag, den 31.07.2011, 15:19 -0700 schrieb Jeffrey Dick:
Here's an attempt using sapply:
x - c(2, 2, 3, 3, 4, 6)
ys - 1:8
sapply(ys, function(y) { length(which(x==y)) } )
[1] 0 2 2 1 0 1 0 0
The last piece for my trials missing was `sapply()` which I overlooked
reading `?lapply()`
Am Mittwoch, den 27.07.2011, 19:59 -0400 schrieb R. Michael Weylandt :
Some more skilled folks can help with the curve fitting, but the general
answer is yes -- R will handle this quite ably.
Great to read that.
Consider the following code:
--
n = 1e5
Am Freitag, den 29.07.2011, 15:28 +0200 schrieb Paul Menzel:
wanting to compare different implementations of a solution I want to
script it to iterate over the different implementations. Is there a way
to do this in the R shell/command line?
$ more /tmp/iterf.r
f1
Am Donnerstag, den 28.07.2011, 09:12 +0200 schrieb Martin Maechler:
PM == Paul Menzel paulepan...@users.sourceforge.net
on Wed, 27 Jul 2011 23:53:51 +0200 writes:
[…]
PM So my newest suggestion is to add a comment to
PM plot(sin, -pi, 2*pi)
PM in `?plot`. Like
Dear R folks,
wanting to compare different implementations of a solution I want to
script it to iterate over the different implementations. Is there a way
to do this in the R shell/command line?
$ more /tmp/iterf.r
f1 - function(n = 10,
l = 10)
Dear Eik,
Am Freitag, den 29.07.2011, 15:46 +0200 schrieb Eik Vettorazzi:
how about this
for (i in 1:2) { print( do.call(paste(f,i,sep=),list(2, 3) )) }
or using get
for (i in 1:2) { print( get(paste(f,i,sep=))(2, 3) ) }
works great for me. Thank you very much. Regarding search machines
Dear Simon,
Am Freitag, den 29.07.2011, 12:32 -0700 schrieb Crock:
i`m trying to use the plot function to show more variable-funktions in one
graphic. so for example i would like to show Chinas Income in different
sectors in one graphic. obviousely typing plot(ChinaIncome) the graphics are
Dear R webmasters,
my browser defaults to the charset UTF-8 and since [1] seems to be
encoded in ISO-8859-1 the umlauts are not displayed correctly. It would
be great if the encoding could be added to the header [2]. (Or the page
converted to UTF-8 and the problem would be solved for me. ;-) )
Dear R folks,
I am having problems getting good results when searching for R related
topics, that means I have not found out yet what keywords I should use
to get only relevant results. Most of the time I get also MATLAB related
things and nothing related at all. The nature of this is of course
Am Mittwoch, den 27.07.2011, 14:36 -0400 schrieb David Winsemius:
On Jul 27, 2011, at 10:12 AM, Paul Menzel wrote:
I am having problems getting good results when searching for R related
topics, that means I have not found out yet what keywords I should use
to get only relevant results
Dear R folks,
currently the section Examples contains the following as an example on
how to plot a “normal” function.
plot(sin, -pi, 2*pi)
Since it does not contain the argument for the function it would be
helpful to add for example the following.
## plots the graph of f(x) =
Dear Bert,
Am Mittwoch, den 27.07.2011, 13:26 -0700 schrieb Bert Gunter:
Paul:
No such change is needed.
Well the fact is, that I as a beginner was looking for who I could plot
normal functions, so one more example would have helped me.
You do not understand S3 methods.
That is probably
Am Mittwoch, den 27.07.2011, 17:21 -0400 schrieb David Winsemius:
On Jul 27, 2011, at 4:53 PM, Paul Menzel wrote:
Am Mittwoch, den 27.07.2011, 13:26 -0700 schrieb Bert Gunter:
Paul:
No such change is needed.
Well the fact is, that I as a beginner was looking for who I could
plot
Am Mittwoch, den 27.07.2011, 18:04 -0400 schrieb David Winsemius:
On Jul 27, 2011, at 5:53 PM, Paul Menzel wrote:
as `plot.function` is not explicitly mentioned in `?plot`.
Right, but the fact that it _is_ described as a generic function
will tell the clueful that other methods other
Dear R folks,
I need to simulate first passage times for iterated partial sums. The
related papers are for example [1][2].
As a start I want to simulate how long a simple random walk stays
negative, which should result that it behaves like n^(-½). My code looks
like this.
8
Dear R folks,
Am Donnerstag, den 28.07.2011, 01:36 +0200 schrieb Paul Menzel:
I need to simulate first passage times for iterated partial sums. The
related papers are for example [1][2].
As a start I want to simulate how long a simple random walk stays
negative, which should result
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