Hi,
I am wanting to complete 2 stage least squared regression with a binary
outcome. I have found and implemented a continuous outcome with tsls() from
the sen package or ivreg() from the AER package.
However I am struggling to find a package/function that implements a
function for a binary
Dear R-Community,
The cex values in curve seem to be being ignored. I have searched
previous help questions and also the web generally, and cannot find this
being a major problem so I am suspicious of something odd happening but
I am at a loss to work out why.
I am trying to plot this:
b1
Robinson
Cc: r-help@r-project.org
Subject: Re: [R] ROCR package not installing
Hello,
What is the version of R you use ?
Regards,
Pascal
Le 22/11/2012 15:02, Philip Robinson a écrit :
I have tried installing the package (ROCR) with this command:
Install.packages(ROCR
...@statkart.no]
Sent: Thursday, 22 November 2012 6:02 PM
To: Philip Robinson
Cc: r-help@r-project.org
Subject: Re: [R] ROCR package not installing
try:
install.packages(ROCR,dep=T)
M.O
On to., 2012-11-22 at 16:02 +1000, Philip Robinson wrote:
I have tried installing the package (ROCR
I have tried installing the package (ROCR) with this command:
Install.packages(ROCR)
And with this command on the command line
R CMD INSTALL ROCR_1.0-4.tar.gz
But both times I get exactly the same error shown below, I don't understand
what is wrong, is this an error in the package
Hi,
I have a large matrix (SNPs) that I want to cycle over with logistic
regression with interaction terms. I have made a loop but I am struggling
to identify to the formula the name of the column in a way which is
meaningful to the formula. It errors becasue it is not evaluated proporly.
(below
I have a vector of 2,1,0 I want to change to 0,1,2 respectively (the data
is allele dosages)
I have tried multiple nested if/else statements and looked at the ?if help
and cannot work out what is wrong, other people have posted code which is
identical and they state works.
Any help would be
Hi,
I have a data frame:
class(B27.vec)
[1] data.frame
head(B27.vec)
AGE Gend B27 AgeOn DD uveitis psoriasis IBD CD UC InI BASDAI BASFI Smok UV
1 571 119 38 2 1 1 1 1 1 5.40 8.08 NA 1
2 351 133 2 2 1 1 1 1 1 1.69 2.28
Hi,
I am struggling, I have 2 lists with shared elements, one ~600, one
~1000, and I need to determine the difference between them.
They are character strings, and to use setdiff(), or unique() I need
vectors. I don't know how to force these character strings into a form
where you can use
Hi
I have a problem with this error, I have searched the archives and found
previous discussion about this, can I cannot understand how the explanations
apply to what I am trying to do.
I am trying to do Log_rank Survival analysis, I have included tables and str
command, is it a
I am having a problem with creating a vector from a rows or columns, I
searched around and found as.vector(x), but it does not seem to do what it
says it does
I have included an example below, of doing what would seem to be the method
required to create a vector, but instead it creates a
That's fantastic, thank you very much, the qnorm option is interesting, I
will have to play around with it.
Many thanks again
Philip
-Original Message-
From: R. Michael Weylandt [mailto:michael.weyla...@gmail.com]
Sent: Sunday, 23 October 2011 10:28 AM
To: Philip Robinson
Cc: r-help@r
I have a data frame called e, dim is 27,3, the first 5 lines look like this:
V1 V2 V3V4
1 1673 0.36 0.08 Smith
2 167 0.36 0.08 Allen
399 0.37 0.06 Allen
4 116 0.38 0.07 Allen
595 0.41 0.08 Allen
I am trying to calculate the
http://n4.nabble.com/file/n962784/egraph_rules_list_2.png The red X's that
are listed above represent data points that have been completely ignored in
production of my graph. I know that in a specified sentence length there are
variations in number of Conjunctions
--
View this message in
Sorry to have not provided enough information in my prior post. Here is a
summary of the calculation set that I am doing. The histograms have changed
since my last post, but I am not so concerned about them. The scatter plots
do not show all of the points, they seem to round off to the most
Thank you very much,
-- Philip
David Winsemius wrote:
--
View this message in context:
http://n4.nabble.com/help-with-graphing-Points-in-my-graph-are-not-apparent-always-displayed-in-steps-tp961629p963227.html
Sent from the R help mailing list archive at Nabble.com.
I am trying to graphically represent a large set of data who's result is not
strictly uniform. http://n4.nabble.com/file/n961629/egraph_rules_list_2.png
The scatter plot to the left has all of the data rising in steps however I
know that there are cases within my data that do not fit the dotted
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