Dear R helpers
I have following two data.frames viz. equity_data and param.
equity_data = data.frame(security_id = c(Air, Air, Air, Air, Air,
Air, Air, Air, Air, Air, Air, Air, AB, AB, AB, AB, AB,
AB, AB, AB, AB, AB, AB, AB, AD, AD, AD, AD, AD, AD,
AD, AD, AD, AD, AD, AD), ason_date =
Dear R helpers,
(At the outset I sincerely apologize if I have not put forward my following
query properly, though I have tried to do so.)
Following is a curtailed part of my R - code where I am trying to generate say
100 random no.s for each of the products under consideration.
Dear Mr Weylandt and R helpers,
Thanks a lot for your suggestion. Unfortunately the return statement in my
original R code returns me different results which are obtained after
processing the function I have constructed.
My requirement for storing the product-wise random numbers is just a
Dear R helpers,
I have one trivial problem while writing an output file in csv format.
I have two dataframes say df1 and df2 which I am reading from two different csv
files.
df1 has column names as date, r1, r2, r3 while the dataframe df2 has column
names as date, 1w, 2w.
(the dates in
Dear R helpers,
I have a data.frame as given below -
dat1 = data.frame(date =
as.Date(c(3/30/12,3/29/12,3/28/12,3/27/12,3/26/12,
3/23/12,3/22/12,3/21/12,3/20/12,
3/30/12,3/29/12,3/28/12,3/27/12,
3/26/12,3/23/12,3/22/12,3/21/12,3/20/12,
3/30/12,3/29/12,3/28/12,
original (name) order after melt and cast command
To: Vincy Pyne vincy_p...@yahoo.ca
Cc: r-help@r-project.org
Received: Wednesday, July 18, 2012, 11:18 AM
Hello,
Try the following.
# This is your code
df_sorted = df[order(as.Date(df$date, %m/%d/%Y), decreasing = TRUE),]
# This is my code
nams
file name
To: Vincy Pyne vincy_p...@yahoo.ca, r-help@r-project.org
Received: Wednesday, July 4, 2012, 5:38 AM
You forgot to follow the posting guide and tell us what operating system you
are using (sessionInfo), but I am going to guess that you are on Windows where
the colon (:) is an illegal symbol
Dear R helpers,
I am using Beta distribution to generate the random no.s (recovery rates in my
example). However, each time I need to save these random no.s in a csv format.
To distinguish different csv files, one way I thought was use of Sys.time in
the file name. My code is as follows -
#
Dear R helpers,
I have recently installed R version 2.15.0
I just wanted to calculate
mean(16, 18)
Surprisingly I got answer as
mean(16, 18)
[1] 16
mean(18, 16)
[1] 18
mean(14, 11, 17, 9, 5, 18)
[1] 14
So instead of calculating simple Arithmetic average, mean command is generating
Subject: RE: [R] What's wrong with MEAN?
To: Vincy Pyne vincy_p...@yahoo.ca, r-help@r-project.org
r-help@r-project.org
Received: Tuesday, May 22, 2012, 9:17 AM
You'll need to pass the data as a vector.
mean(16, 18) is asking the mean of 16. 18 is passed to the second argument
which is trim. So
Dear R helpers,
I have two separate data frames. In one data frame the transaction data is
stored and the other data frame has exchange rates stored say rate_A and rate_B
where rate_A and rate_B are series of rates.
rate_A and rate_B are properly defined and I am reading them through the
Dear R helpers
Suppose
x - c(1:3)
y - matrix(1:12, ncol = 3, nrow = 4)
y
[,1] [,2] [,3]
[1,] 1 5 9
[2,] 2 6 10
[3,] 3 7 11
[4,] 4 8 12
I wish to multiply 1st column of y by first element of x i.e. 1, 2nd column of
y by 2nd element of x i.e. 2 an so
multiplication by multple constants
To: Vincy Pyne vincy_p...@yahoo.ca
Cc: r-help@r-project.org
Received: Friday, April 20, 2012, 8:57 AM
try this:
x - 1:3
y - matrix(1:12, ncol = 3, nrow = 4)
y * rep(x, each = nrow(y))
I hope it helps.
Best,
Dimitris
On 4/20/2012 10:51 AM, Vincy Pyne
Dear R helpers,
Following is my R code where I am trying to calculate returns and then trying
to create a data.frame. Since, I am not aware how many instruments I will be
dealing so I have constructed a function. My R code is as follows -
library(plyr)
mydata - data.frame(instru_name =
the required data.frame.
Thanks again.
With warm regards
Vincy
--- On Wed, 1/11/12, jim holtman jholt...@gmail.com wrote:
From: jim holtman jholt...@gmail.com
Subject: Re: [R] Constructing a data.frame from csv files
To: Vincy Pyne vincy_p...@yahoo.ca
Cc: r-help@r-project.org
Received: Wednesday, January
Dear R helpers,
I need to use KS and AD test for Generalized Pareto and Generalized extreme
value.
E.g. if I need to use KS for Weibull, I have teh syntax
ks.test(x.wei,pweibull, shape=2,scale=1)
Similarly, for AD I use
ad.test(x, distr.fun, ...)
My problem is fir given data, I have
Dear R forum
I have two datafarmes with category and cat_val forming one dataframe and cust
and cust_category forming another dataframe.
category = c(C, D, B, A)
cat_val = c(0.10, 0.25, 0.40, 0.54)
cust = c(cust_1, cust_2, cust_3, cust_4, cust_5, cust_6, cust_7,
cust_8, cust_9, cust_10)
Hi,
I have one basic doubt. Suppose X ~ N(50,10).
I need to calculate Probability X = 50.
dnorm(50, 50, 10) gives me
[1] 0.03989423
My understanding is (which is bit statistical or may be mathematical) on a
continuous scale, Probability of the type P(X = .) are nothing but
1/Infinity
Ellison and Mr Mark for your
guidance.
Regards
Vincy
--- On Wed, 9/14/11, S Ellison s.elli...@lgcgroup.com wrote:
From: S Ellison s.elli...@lgcgroup.com
Subject: RE: [R] Question regarding dnorm()
To: Vincy Pyne vincy_p...@yahoo.ca, r-help@r-project.org
r-help@r-project.org
Received: Wednesday
wrote:
From: Prof Brian Ripley rip...@stats.ox.ac.uk
Subject: Re: [R] Autocorrelation using library(tseries)
To: Vincy Pyne vincy_p...@yahoo.ca
Cc: r-help@r-project.org
Received:
Wednesday, August 24, 2011, 9:08 AM
Your understanding is wrong. For a start, there is no function acf
Dear R list
I am trying to understand the auto-correlation concept. Auto-correlation is the
self-correlation of random variable X with a certain time lag of say t.
The article
http://www.mit.tut.fi/MIT-3010/luentokalvot/lk10-11/MDA_lecture16_11.pdf;
(Page no. 9 and 10) gives the methodology
Dear R list, I have one very elementary question regrading correlation between
two variables.
x = c(44,46,46,47,45,43,45,44)
y = c(44,43,41,41,46,48,44,43)
cov(x, y)
[1] -2.428571
However, if I try to calculate the covariance using the formula as
covariance = sum((x-mean(x))*(y-mean(y)))/8
ted.hard...@wlandres.net
Subject: Re: [R] Correlation discrepancy
To: r-help@r-project.org
Cc: Vincy Pyne vincy_p...@yahoo.ca
Received: Tuesday, August 23, 2011, 11:38 AM
In addition, something has gone wrong, Vincy, with your data x,y
between evaluating cov(x,y) and evaluating your explicit
: Re: [R] Correlation discrepancy
To: r-help@r-project.org
Cc: Vincy Pyne vincy_p...@yahoo.ca
Received: Tuesday, August 23, 2011, 11:38 AM
In addition, something has gone wrong, Vincy, with your data x,y
between evaluating cov(x,y) and evaluating your explicit formula.
If I repeat your
commands
Dear r helpers
This may be very elementary question but I couldn't figure out what does the
operator %% do?
E.g.
p - 100
q - 200
p%%q
[1] 100
q%%p
[1] 0
Please guide.
Vincy
[[alternative HTML version deleted]]
__
R-help@r-project.org
, Thierry thierry.onkel...@inbo.be
Subject: RE: [R] Meaning of %%
To: Vincy Pyne vincy_p...@yahoo.ca, r-help@r-project.org
r-help@r-project.org
Received: Wednesday, July 13, 2011, 10:13 AM
help(%%)
ir. Thierry Onkelinx
Dear R helpers,
I am not a statistician and right now struggling with Richards curve. Wikipedia
says
(http://en.wikipedia.org/wiki/Generalised_logistic_function)
The generalized logistic curve or function, also known as Richard's curve is
a widely-used and flexible sigmoid function for growth
Dear R helpers,
I have one basic doubt about the value of pi. In school, we have learned that
pi = 22/7 (which is = 3.142857). However, if I type pi in R, I get pi =
3.141593. So which value of pi should be considered?
Regards
Vincy
[[alternative HTML version deleted]]
That's the beauty of this R forum. This forum is full of knowledgeable wizards
and replies received along-with the related discussions pertaining to a simple
harmless question like this enriches us tremendously. Thanks a lot for all your
comments. I am sticking to the value of 'pi' as provided
Hi!
I wish to know if there is any R forum which is meant only for Statistics? I
mean where we can clarify our statistics doubts and seek knowledge. I know
there are lot many books and internet sites, but 'R forum' has altogether
different standard and very high level and one can learn a lot
Dear R helpers
Suppose I have a vector as
vect1 = as.character(c(ABC, XYZ, LMN, DEF))
vect1
[1] ABC XYZ LMN DEF
I want to reverse the order of this vector as
vect2 = c(DEF, LMN, XYZ, ABC)
Kindly guide
Regards
Vincy
[[alternative HTML version deleted]]
Dear R helpers
Suppose I have a data.frame as given below -
my_dat = data.frame(class = c(XYZ, XYZ, XYZ, XYZ, XYZ,ABC, ABC,
ABC, ABC, ABC ), var1 = c(20, 14, 89, 81, 17, 44, 36, 41, 11, 36), var2
= c(1001, 250, 456, 740, 380, 641, 111, 209, 830, 920))
my_dat
class var1 var2
1 XYZ 20
Dear R helpers
I am resending my mail as the output I desire was not properly visible and I
apologize for the same.
Suppose I have a data.frame as given below -
my_dat = data.frame(class = c(XYZ, XYZ, XYZ, XYZ, XYZ,ABC, ABC,
ABC, ABC, ABC ), var1 = c(20, 14, 89, 81, 17, 44, 36, 41, 11, 36),
Dear sir,
Thanks for the great solution.
Regards
Vincy
--- On Mon, 3/28/11, Henrique Dallazuanna www...@gmail.com wrote:
From: Henrique Dallazuanna www...@gmail.com
Subject: Re: [R] Ordering data.frame based on class
To: Vincy Pyne vincy_p...@yahoo.ca
Cc: r-help@r-project.org
Received: Monday
Dear R helpers
exposure - data.frame(id =
c(1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20),
ead = c(9483.686,5,6843.4968,10509.37125,21297.8905,5,706152.8354,
62670.5625, 687.801995,50641.4875,59227.125,43818.5778,52887.72534,601788.7937,
and writing a csv
To: Vincy Pyne vincy_p...@yahoo.ca
Cc: r-help@r-project.org
Received: Friday, March 25, 2011, 4:02 PM
Hi Vincy,
Please read the help file, particularly the part about write.csv and
write.csv2 where it says These wrappers are deliberately inflexible:
they are designed to ensure
Dear R helpers,
Suppose I have stock returns data of say 1500 companies each for say last 4
years. Thus I have a matrix of dimension say 1000 * 1500 i.e. 1500 columns
representing companies and 1000 rows of their returns.
I need to find the correlation matrix of these 1500 companies.
So I
will
refer to the packages you have suggested.
Thanks again
Vincy
--- On Mon, 3/21/11, Peter Langfelder peter.langfel...@gmail.com wrote:
From: Peter Langfelder peter.langfel...@gmail.com
Subject: Re: [R] Correlation for no of variables
To: Vincy Pyne vincy_p...@yahoo.ca
Cc: r-help@r-project.org
Dear R helpers
Suppose,
x = c(0, 1, 2, 3)
y = c(A, B, C, D)
z = c(1, 3)
For given values of z, I need to the values of y. So I should get B and D.
I tried doing
y[x][z] but it gives
y[x][z]
[1] A C
Kindly guide.
Regards
Vincy
[[alternative HTML version deleted]]
Dear R helpers
Suppose I have a vector as
vect_1 = c(AAA, AA, A, BBB, BB, B, CCC)
vect_1_id = c(1:length(vect_1))
Through some process I obtain
vect_2_id = c(2, 3, 7), then I need a new vector say vect_2 which will give me
vect2 = (AA, A, CCC) i.e. I need the subset of vect_1 as per
Dear R helpers
Suppose I have a data frame as given below
mydat = data.frame(x = c(1,1,1, 2, 2, 2, 2, 2, 5, 5, 6), y = c(10, 10, 10, 8,
8, 8, 7, 7, 2, 2, 4))
mydat
x y
1 1 10
2 1 10
3 1 10
4 2 8
5 2 8
6 2 8
7 2
Thanks sir for your reply. Unfortunately I couldn't figure out the solution.
Vincy
--- On Sat, 3/12/11, Dennis Murphy djmu...@gmail.com wrote:
From: Dennis Murphy djmu...@gmail.com
Subject: Re: [R] Identifying unique pairs
To: Vincy Pyne vincy_p...@yahoo.ca
Cc: r-help@r-project.org
Received
.ff.cuni.cz wrote:
From: Petr Savicky savi...@praha1.ff.cuni.cz
Subject: Re: [R] Identifying unique pairs
To: r-help@r-project.org
Received: Saturday, March 12, 2011, 2:10 PM
On Sat, Mar 12, 2011 at 03:20:01AM -0800, Vincy Pyne wrote:
Dear R helpers
Suppose I have a data frame as given below
Dear R helpers
I have following data.frame and for each product_name, I have associated mean
and standard deviation. I need to generate 1000 random no.s for each of these
products and find the respective mean and standard deviation.
My R code is as follows.
library(plyr)
library(reshape2)
Dear R helpers
Suppose
val1 = c(10, 20, 35, 80, 12)
val2 = c(3, 8, 11, 7)
I want to select either val1 or val2 depending on value of third quantity val3.
val3 assumes either of the values Monthly or Yearly.
If val3 = Monthly, then val = val1 and if val3 = Yearly, then val = val2.
I tried the
complex I'd prefer the latter.
Duncan Murdoch
Single = is for setting arguments within a function call. If you want
to test equality, then double == is required.
See ?==
HTH,
Ivan
Le 3/10/2011 11:45, Vincy Pyne a écrit :
Dear R helpers
Suppose
val1 = c(10, 20, 35, 80, 12)
val2 = c
Dear R helpers,
xx = data.frame(country = c(USA, UK, Canada), x = c(10, 50, 20), y =
c(40, 80, 35), z = c(70, 62, 10))
xx
country x y z
1 USA 10 40 70
2
UK 50 80 62
3 Canada 20 35 10
I need to arrange this as a new data.frame
Dear R helpers,
Suppose I have following data.frame.
df - data.frame(category = c(treat_A, treat_A, treat_A, treat_A,
treat_A, treat_A, treat_A, treat_A, treat_B, treat_B, treat_B,
treat_B, treat_B, treat_B, treat_B, treat_B), type = c(AA, ,
B, AAA, BB, , BBB, AAA, B, AAA, BBB, AA,
Dear R helpers
I seem to have one trivial problem but can't find solution to it.
Suppose I have following input.
A = c(1, 3, 0, 5, 8) # 3rd element is 0
B = c(100, 30, 0, 25, 40) # 3rd element is 0
C = A/B
C
[1] 0.01 0.10 NaN 0.20 0.20
Obviously, I can't
Dear R helpers
I have a dataframe as
df = data.frame(x = c(1, 14, 3, 21, 11), y = c(102, 500, 40, 101, 189))
df
x y
1 1 102
2 14 500
3 3 40
4 21 101
5 11 189
# Actually I am having dataframe having multiple columns. I am just giving an
example.
I need to subtract all the rows of df
(mydat$date)) : undefined columns selected
Kindly guide
Vincy Pyne
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R
Dear sir,
Thanks a lot for your great guidance. It worked fantastically.
Regards
Vincy Pyne
--- On Thu, 12/30/10, Henrique Dallazuanna www...@gmail.com wrote:
From: Henrique Dallazuanna www...@gmail.com
Subject: Re: [R] Sorting data.frame datewise in a descending order
To: Vincy Pyne vincy_p
Dear R helpers
Wish you all a very Happy and Prosperous New Year 2011.
I have following query.
country = c(US, France, UK, NewZealand, Germany, Austria, Italy,
Canada)
Through some other R process, the result.csv file is generated as
result.csv
var1 var2 var3 var4 var5 var6
Dear R helpers
I have following input
f = c(257, 520, 110). I need to generate a decreasing sequence (decreasing by
100) which will give me an input (in a tabular form) like
257, 157, 57
520, 420, 320, 220, 120, 20
110, 10
I tried the following R code
f = c(257, 520, 110)
yy =
and hope I am able to put up my
problem in a proper manner.
Regards
Vincy Pyne
--- On Thu, 12/9/10, Jan van der Laan rh...@eoos.dds.nl wrote:
From: Jan van der Laan rh...@eoos.dds.nl
Subject: Re: [R] Sequence generation in a table
To: r-help@r-project.org, vincy_p...@yahoo.ca
Received
PIKAL petr.pi...@precheza.cz wrote:
From: Petr PIKAL petr.pi...@precheza.cz
Subject: Re: [R] Sequence generation in a table
To: Vincy Pyne vincy_p...@yahoo.ca
Cc: r-help@r-project.org
Received: Thursday, December 9, 2010, 12:03 PM
Hi
r-help-boun...@r-project.org napsal dne 09.12.2010 12:41:47
Dear R helpers
I have a data which gives Month-wise and Rating-wise Rates. So the input file
is something like
month rating rate
January AAA 9.04
February AAA 9.07
..
: Dimitri Liakhovitski dimitri.liakhovit...@gmail.com
Subject: Re: [R] One silly question about tapply output
To: Vincy Pyne vincy_p...@yahoo.ca
Received: Wednesday, October 27, 2010, 11:28
AM
Assign your result to an object and then write out the object as a csv
file. For example:
x-data.frame
.
Regards
Vincy
--- On Fri, 8/27/10, David Winsemius dwinsem...@comcast.net wrote:
From: David Winsemius dwinsem...@comcast.net
Subject: Re: [R] Band-wise Sum
To: Vincy Pyne vincy_p...@yahoo.ca
Cc: r-help@r-project.org
Received: Friday, August 27, 2010, 2:36 PM
On Aug 27, 2010, at 9:49 AM
wrote:
From: David Winsemius dwinsem...@comcast.net
Subject: Re: [R] Band-wise Conditional Sum - Actual problem
Cc: r-help@r-project.org
Received: Monday, August 30, 2010, 2:43 PM
On Aug 30, 2010, at 4:05 AM, Vincy Pyne wrote:
Dear R helpers,
Thanks a lot for your earlier guidance esp. Mr
learn something from THE WISE like you.
Thanks once again Sir. Your help was great and it means a lot to me and for
other freshers like me.
Regards
Vincy Pyne
--- On Fri, 8/27/10, David Winsemius dwinsem...@comcast.net wrote:
From: David Winsemius dwinsem...@comcast.net
Subject: Re: [R] Band
Hi
I have a large credit portfolio (exceeding 5 borrowers). For particular
process I need to add up the exposures based on the bands. I am giving a small
test data below.
rating - c(A, AAA, A, BBB,AA,A,BB, BBB, AA, AA, AA, A,
A, AA,BB,BBB,AA, A, AAA,BBB,BBB, BB, A, BB, A, AA,
B,A, AA,
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