t(p,aes(v2))+geom_density(aes(x=v2,fill=v1))+geom_histogram(aes(y=..density..),alpha=.5)+
theme(legend.position="none")
g<-g+xlab(x)
return(g)
}
m<-mapply(FUN=plt,x=c("spot_001"),y=c("Cell.Median.CD3"))
So I just want the graphs (g) to be stor
Dear All - I'm trying to integrate the following function via nlsLM - and I
think the problem is something to do with passing the correct arguments
(error is given below) - any help gratefully appreciated - many thanks.
library(minpack.lm)
dOM - function(x, mu = 0, sigma = 1, log = FALSE)
{
The coding I've settled on to save file without clipping is:
library(gridExtra)
gt - ggplot_gtable(ggplot_build(q3))
gt$layout$clip[gt$layout$name==panel] - off
gt4 - arrangeGrob(gt)
ggsave - ggplot2::ggsave; body(ggsave) - body(ggplot2::ggsave)[-2]
## from Baptiste
ggsave(gt.pdf, plot = gt4,
including
IOS 8.2, OS X 10.10, Xcode 6.2. I previously, and fairly recently,
installed X11 (and Xquartz), and also updated R and R Cairo, but none
of this has affected the above behaviour.
Any advice gratefully received.
Yours sincerely,
Jeremy Clark
library(ggplot2)
library(grid)
library(Cairo
Dear All,
First of all, many thanks to all R contributors for a fantastic
program, and especially to Hadley Wickham for creating ggplot2. The
following is intended to be a warning that, if the apparently
superficial problems described are not sorted out, R could well find
itself being superceded.
Dear All,
The following gives a very unpleasant experience with apparently random NAs
- probably it's my bad formatting of the coding - but the effect is
unexpected and if undetected can lead to considerable problems:
myvector1 = NULL
myvector3 = NULL
myvector4 = NULL
myvector5 = NULL
/sqrt(10 - 3)
z - r.z / se
(1 - pnorm(z))*2
[1] 0.04237039
My p-value is different. The help file for cor.test doesn't (seem to)
have any reference to this, and I can see in the source code that it
is doing something different. I'm just not sure what.
Thanks,
Jeremy
selected
I hope I'm doing something foolish,
thanks,
Jeremy
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I've found that if you want really fine control over an issue like this in
a chart, the easiest thing to do is to export it as PDF, and then directly
edit the chart in Illustrator (not free) or Inkscape (free).
On 7 July 2014 10:21, Viechtbauer Wolfgang (STAT)
It exists:
https://play.google.com/store/apps/details?id=com.appsopensource.R
No graphics.
Jeremy
On 8 May 2014 05:44, Kevin E. Thorpe kevin.tho...@utoronto.ca wrote:
This is a question asked purely out of idle curiosity (and may also be in
wrong list). Are there plans for porting R
~~ congressmenPerceptConstiuentAttitudes
rollCallBehav ~~ congressmanAttitudes
And your model runs, with 0 df.
Your latent variable does nothing, becuase you only only have one variable
which relates to it.
Jeremy
P.S. There's a lavaan group on google groups.
On 30 April 2014 08:02, Patzelt, Edward patz
. Do you mean composite
reliability? That's not automatic either, but it can be programmed.
Jeremy
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can I select the correct vector from the list
(ie.F4287) using an object extracted from the dataframe (eg. maxr or maxr2)
??
On Thu, Feb 6, 2014 at 6:20 PM, Duncan Murdoch murdoch.dun...@gmail.comwrote:
On 06/02/2014 10:00 AM, Jeremy Clark wrote:
Dear All,
I would like to be able
Dear All,
I would like to be able to associate a list of vectors (one vector of
which is to be called later) with some other character and numeric
data. I've tried two methods:
1) I can put the vector names in quotes into the dataframe, and then
extract the vector name - but this is just a
)
On Thu, Nov 21, 2013 at 11:57 AM, Jeremy Clark jeremyclark...@gmail.com wrote:
Dear All,
In the following simple case I can't seem to get an improved fit,
despite trying all of the control possibilities. As there seem to be
no examples anywhere which show use of functions such as dnorm
within
)
## plot fitted values
lines(gg, fitted(modLM4), col = 2, lwd = 2)
On Thu, Nov 21, 2013 at 11:57 AM, Jeremy Clark jeremyclark...@gmail.com wrote:
Dear All,
In the following simple case I can't seem to get an improved fit,
despite trying all of the control possibilities. As there seem
Dear All,
In the following simple case I can't seem to get an improved fit,
despite trying all of the control possibilities. As there seem to be
no examples anywhere which show use of functions such as dnorm
within a formula, and as I am not confident at all that my formula is
correctly
are not necessarily AA,AT, or TT.
Any ideas?
Thanks!
Jeremy
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workspace object name.
Is there anyway for each individually read in Rdata object to be assigned a
new name?
Thanks!
JEremy
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looked into several packages
and none seem to interpolate across more than 3-dimensions.
All the best,
Jeremy Beaulieu
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=TRUE)
Jeremy
On 25 February 2013 17:02, Craig J cjohn...@gmail.com wrote:
I'm learning R and am converting some code from SPSS into R. My background
is in SAS/SPSS so the vectorization is new to me and I'm trying to learn
how to NOT use loops...or use them sparingly. I'm wondering what
By MIMIC do you mean multiple indicator/multiple cause? Something like
this: http://www.jeremymiles.co.uk/misc/fun/img059.gif
If so, you can use sem, Lavaan, or openMx.
Jeremy
On 13 February 2013 05:11, Hervé Guyon herve.gu...@yahoo.fr wrote:
I want estimate MIMIC latent variable with R
that do this much better than I could in an
email. But you probably have a favorite of your own.
Jeremy
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Dear all,
Since I upgraded R to the version 2.15.2, I have a strange problem which
implies XLConnect, RODBC and Rcmdr packages.
- If the three packages are loaded in the same R session, the use of
RodbcConnect functions cause R to crash.
- This crash occur only if Rcmdr is loaded.
- If only
chart function, I get the error message 'x' must be
a numeric vector or matrix, which I can understand it to be a result of the
fact that I have characters AA, AG etc as my x-values.
Any idea how I can go about doing this?
Thanks in advanced!
Jeremy
[[alternative HTML version deleted
You can run that as it is. The term to search for on Google is 'dummy
coding'.
Jeremy
On 28 December 2012 07:45, Lorenzo Isella lorenzo.ise...@gmail.com wrote:
where x3 is a dichotomous variable assuming only 0 and 1 values (x1 and x2
are continuous variables).
Is there any particular
Could you provide the code that you're running, so we can see what
you're trying to do? Even better would be a repeatable example.
Jeremy
On 19 December 2012 09:42, Yann Labou yann.la...@outlook.com wrote:
Hey all,
I'm trying to fit a non-linear model y ~ a * constant ^ b * x ^ c
Dear users,
Does anyone have any idea how to generate standardised beta coefficients
for a ZINB model in R to compare which explanatory variables are having the
greatest impact on the dependent variable?
Thanks,
Jeremy
[[alternative HTML version deleted
code
to compute overall marginal effects of each variable?
My model is specified as follows:
ZINB - zeroinfl(Tot.Anglers ~ Location + Season + Daytype + Holiday.not +
CPUE + ShoreType + Access + Source.pop + WindSpeed + offset(beat_length),
dist=negbin, data=anglers)
Many thanks,
Jeremy
same dimensions, except that instead
of a matrix reporting the values I now have a matrix of reporting the
probabilities.
The median and sd is calculated for each row.
Any help/ thoughts on this will be greatly appreciated!
Jeremy
[[alternative HTML version deleted
What are you expecting?
What do you get?
What is the problem?
J
On 4 December 2012 06:01, anoumou teko_maur...@yahoo.fr wrote:
Hello all,
I need a help.
I am modeling a disease and a create a R function like that:
Lambda-function (x,date1,r,h,a){
ndate1 - as.Date(date1, %d/%m/%Y)
t1
You can use ifelse()
#Create data for example
x - matrix(data=c(Inf, 2, 3, 4, Inf, 6, 7, 8, Inf), nrow=3)
#Turn Inf into zero.
x - ifelse(x == Inf, 0, x)
Jeremy
On 14 November 2012 14:13, Nick Duncan nickd...@gmail.com wrote:
Dear All,
I have a matrix in which the diagonal has
- so
check that the same variables have been removed.
Jeremy
On 6 November 2012 13:39, Hui Du hui...@dataventures.com wrote:
Hi group:
I have a data set, which has severe colinearity problem. While running
linear regression in R and SPSS, I got different models. I am wondering if
somebody
1.06653 1.43876 2.15272 0.69042
0.66962 2.02502 0.7646
And this is how file A looks like:
2620456
2830090
2575215
2849041
How do I actually extract and export the corresponding values for A in B?
Thanks in advanced!
Jeremy
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You need to load the dataset.
First, run
data(CO2)
Then it should work.
Jeremy
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Hi,
I'm trying to graph the hazard function using the survreg function with the
distributional assumptions to be loglogistic. If
h(t)=[lambda*alpha*(lambda*t)^(alpha-1)]/[1+(lambda*t)^alpha], what output from
R is alpha?
Thanks
[[alternative HTML version deleted]]
It's fine. Just interpret them as you would any other (lower is better).
On 22 August 2012 16:43, Gary Dong pdxgary...@gmail.com wrote:
Dear R users,
I obtained negative AIC and BIC and positive Loglik values in a gls model.
Is this normal? how should I interpret them? Thanks!
AIC
The test of moderator coefficients (QM) is chi-square distributed.You
can use the change in this value when you add a predictor to the model
as a chi-square test, with df equal to the change in df.
Jeremy
On 2 August 2012 05:54, Bexkens, Anika a.bexk...@uva.nl wrote:
Dear Metafor users,
I'd
I have also reinstalled the MuMIn package as suggested at...
http://r.789695.n4.nabble.com/Error-message-number-of-items-to-replace-is-not-a-multiple-of-replacement-length-td3257893.html
...however, this made no difference.
any help is appreciated.
thank you
--
View this message in context:
of vector length (arg 3).
I am unclear what this means and how to resolve the issue.
If anyone has any idea how to address this error, I would very much
appreciate your response.
Thank you in advance.
Jeremy
My script is as follows :
## LOAD PACKAGES
library(MASS)
library
: int 1 1 1 1 1 1 1 1 1 1 ...
Does this provide any insight?
Thank you
##
Thank you both for your generous time and support, it is greatly
appreciated.
kind regards
Jeremy
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Thanks Jessi,
your insights are extremely helpful.
If you would indulge me one more quick question on your script.
You have written...
newData-data.frame(JVeg5=factor(Jdata[,JVeg5]),scale(Jdata[,c(Elevation,Lat_Y_pos,Coast_dist,Stream_dist)]))
I wish to expand this analysis for all other
'
Does this imply an 'infinite value' and what would this mean?
If anyone has any idea how to address this error, I would very much
appreciate your response.
Thank you in advance.
Jeremy
Date File Attachment (200 rows):
http://r.789695.n4.nabble.com/file/n4635829
Hi Jessica,
thank you for your prompt response. Yes I had deduced it had to do with the
Hessian.
However, I am not clear what all columns having range the order of one
actually means and what this means for my data. Does this mean removing
decimals (ie by shifting the decimal place)?
I would
Dear all
I'm trying to install the Rcompression package under R-2.14.0 on a Windows
plateform.
I need it to use the Ropenoffice package
Because there is no binary available, I'm trying to install it from source
but I have always some error messages.
I have installed zlib and Bzip2 softwares,
I am working on directed network data of the following form:
Origin farm Destination farm Year
Farm 1 - Farm 21999
Farm 1 - Farm 31999
Farm 3 - Farm 22000
Farm 1 - Farm 2
Hi all,
I'm trying to combine exhaustively several character arrays in R like:
x=c(one,two,three)
y=c(yellow,blue,green)
z=c(apple,cheese)
in order to get concatenation of
x[1] y[1] z[1] (one yellow apple)
x[1] y[1] z[2] (one yellow cheese)
x[1] y[2] z[1](one blue apple)
...
x[length(x)]
I'm attempting to create a sequence for an experiment and am hoping I can
use R to create it. It has several constraints:
(1) It is made up of two sequences (red and green) that have 4 different
repeating triplets (e.g. T1=ABC T2=DEF T3=GHI JKL)
(2) Each sequence has the following constraints:
cor(A, B)
[1] 0.9986861
The data are very, very highly correlated. The higher the correlation,
the greater the power of the t-test to detect the same difference
between the means.
Jeremy
On 20 September 2011 10:46, Pedro Mardones mardone...@gmail.com wrote:
Dear all;
A very basic question
Do you mean things like treatment of categorical variables in regression
procedures (which have different defaults in different procedures in SAS),
and different default as to the reference category in logistic regression?
Jeremy
On 29 August 2011 04:46, n nikhil.abhyan...@gmail.com wrote
?
jeremy
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and provide commented, minimal, self-contained, reproducible code.
Sounds like you want a best subsets regression, the bestglm() function,
found in the bestglm() package will do the trick.
Jeremy
On 4 August 2011 12:23, Paul Smith phh...@gmail.com wrote:
Dear All,
Suppose that you are trying to create a binary logistic model by
trying different
Use rseek.org.
Jeremy
On 27 July 2011 07:12, Paul Menzel paulepan...@users.sourceforge.net wrote:
Dear R folks,
I am having problems getting good results when searching for R related
topics, that means I have not found out yet what keywords I should use
to get only relevant results. Most
Will:
result$coef[[2]]
Give you want you want?
Jeremy
On 26 July 2011 08:21, ascoquel ascoq...@yahoo.fr wrote:
Hi,
I've done a linear fit on my data and I would like to get back the a (time)
coefficient ...
mod-lm(res_sql2$Lx0x~0+time)
result-data.frame()
result-coef(mod)
print
This is clearly a message for the R-help mailing list, since it was
sent to the R help mailing list.
fisher.test(x)[1]
Jeremy
On 26 July 2011 14:51, Zmarz, Pawel pawel.zmar...@imperial.ac.uk wrote:
Dear r-helpers,
I would be very grateful if you could post the message below on the r-help
. This would be:
x[[1]][[3]]
x[[2]][[3]]
x[[3]][[3]]
I thought there would be a way of doing this with something like
apply(), but I cannot work it out. Is there a way of doing this
without a loop? Thanks,
Jeremy
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0.5227
Median Median Median Median
0.6169 0.4904 0.4773 0.4779
On Tue, Jun 28, 2011 at 7:22 PM, Jeremy Miles jeremy.mi...@gmail.com wrote:
Hi All,
I want to extract elements of elements in a list.
Here's an example of what I mean:
If I create a list:
x - as.list(100)
for(loop in c(1
in the psych package has more flavors of extraction
and rotation.
Jeremy
On 22 June 2011 14:02, Rosario Garcia Gil m.rosario.gar...@slu.se wrote:
Hello
I seem to find only two types of rotation for the factanal function in R, the
Varimax and Promax, but is it possible to run a orthogonal and oblique
cortest.bartlett() in the psych package.
I've never seen a non-significant Bartlett's test.
Jeremy
On 17 June 2011 12:43, thibault grava thibault.gr...@gmail.com wrote:
Hello Dear R user,
I want to conduct a Principal components analysis and I need to run two
tests to check whether I can
wanted to see if there was an
easy way to do this that I am completely missing.
Thanks and all the best,
Jeremy
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The results weren't BIZARRE (or even bizarre). You didn't understand
them, but that doesn't make them bizarre. (I didn't understand them
either, but thanks to the replies, now I do).
Why not send something more similar to your dataset to ensure you get
relevant answers ?
Jeremy
On 14 June
What do you mean by latent estimate?
The table of variances has variances for each factors.
Is there something different in the sem output that you don't see here?
Yes, this looks normal.
Jeremy
On 8 June 2011 13:14, R Help rhelp.st...@gmail.com wrote:
I've just found the lavaan package
, and sends
me to this page:
http://www.statmethods.net/stats/regression.html
Jeremy
--
Jeremy Miles
Support Dan and Alex's school: Vote for Goethe Charter School to
receive a grant from Pepsi to help build a library:
http://www.refresheverything.com/gicslibrary
and
Halton (1951), and this test is *also* known as the Freeman-Halton
test.
Emphasis mine.
Jeremy
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(
https://groups.google.com/forum/#!forumsearch/sci.stat.*). Perhaps others
have a better feel for which forums are of higher quality. The sci.stat.*
groups look a bit overrun with spam these days.
Jeremy
On Thursday, April 28, 2011 7:26:06 AM UTC-4, Vincy Pyne wrote:
Hi!
I wish to know
parallel() with the .Internal calls reduces the elapsed time by
about 70% on Ubuntu Natty. Multicore is not available for Windows, or at
least not easily available for Windows.
But maybe the true R wizards have better ideas.
Jeremy
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See ?merge.
df.1 - data.frame(year=factor(rep(1:3,3)), level=rep(letters[1:3],3),
number=c(11:19))
df.2 - data.frame(year=factor(c(1:5)), number=c(21:25))
df.3 - merge(df.1, df.2, by = year)
df.3$new - with(df.3, number.x + number.y)
Jeremy
On Wednesday, April 27, 2011 7:30:13 AM UTC-4, E
See ?on.exit
Jeremy
On Wednesday, April 27, 2011 9:16:13 AM UTC-4, Jannis wrote:
Dear list members,
is it possible to set some options only inside a function so that the
original options are restored once the function is finished or aborted due
to an error? Until now I do something
the studentized (which SPSS
calls studentized-deleted).
Jeremy
2011/4/21 Tamas Barjak tamas.barja...@gmail.com:
Remélem valaki ezt is elolvassa, megérti, és válaszol a problémámra.
A gondom a következő:
Kiszámoltattam a maradékokat az R commanderrel, és az SPSS -el is. És itt
kezdődik igazán a gond
Kevin,
The following follows John's suggestion, but without the loop. It's quick
for me.
Jeremy
Jeremy T. Hetzel
Boston University
## Generate sample data
n - 4000
rep - 1000
rate - rnorm(n, mean = 15, sd = 2) / 10 # Mortality rates around
15/100k
## Create an empty matrix
(because they follow the distribution). John Fox's regression book
http://socserv.mcmaster.ca/jfox/Books/Companion/ explains all of
this nicely.
Jeremy
On 20 April 2011 14:36, Tamas Barjak tamas.barja...@gmail.com wrote:
Hy all!
Excuse me for the inaccurate composition, but I do not speak well
write.table()
for the saving the files, or is the problem with splitting a large
file, or generating the 1000 names ...
Jeremy
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Scribus claims to be able to convert RGB/CMYK colors to spot colors:
http://documentation.scribus.net/index.php/Spot_Colors
I've never used Scribus, but it's floss.
Jeremy
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,
convert to spot color in Scribus, then break the PDF apart again for Latex.
Jeremy
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and provide
$eth, unique(simtest$eth), ==) + 0
# Combine
simtest.combined - cbind(simtest, simtest.dichotomous)
head(simtest.combined)
Jeremy
Jeremy Hetzel
Boston University
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)
})
# Combine into new data frame
dat.new - data.frame(dat$outcome, A, B)
head(dat.new)
Jeremy
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and geom_line colour aesthetics as group
g1 + geom_point(aes(colour = group)) + geom_line(aes(colour = group))
Is this what you are after?
Jeremy
Jeremy Hetzel
Boston University
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As I understand it, you are trying to subset the data frame to include only
rows with a non-unique id.
Try this:
x - data.frame(cbind(id=c(1,2,2,2,3,3,4,5,6,6), value=1:10))
id.table - table(x$id)
x_new - subset(x, id %in% id.table[id.table 1])
Jeremy
Sorry, I left out the names() function in the last step.
Try this instead:
x - data.frame(cbind(id=c(1,2,2,2,3,3,4,5,6,6), value=1:10))
id.table - table(x$id)
x_new - subset(x, id %in% names(id.table[id.table 1]))
Jeremy
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manually?
You can use cbind().
cor(cbind(MyDataFrame$variable1, MyDataFrame$variable2,MyDataFrame$variable3) )
Jeremy
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PLEASE do read the posting guide http://www.R
join it here: http://www2.gsu.edu/~mkteer/semnet.html#Joining.
Jeremy
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PLEASE do
morhua*
I'm at wit's end, I tried to read about substitute, expression, and eval
functions in the hopes I can figure it out, but I am lost!
Thanks for any help!
Cheers,
-Jeremy N
Undergraduate Researcher in Macroecology
University of Ottawa
Department of Biology
Ad astra per alia porci
Hi,
Thank you *very* much. I'll remember that in the future!
Cheers,
-Jeremy N
Undergraduate Researcher in Macroecology
University of Ottawa
Department of Biology
Ad astra per alia porci!
On Thu, Mar 31, 2011 at 8:01 AM, Henrique Dallazuanna www...@gmail.comwrote:
Better:
plot(1, main
will help.
http://www.biomedcentral.com/1756-0500/3/267
Might I also suggest you take a look at the semnet list, which is
populated by practitioners of SEM.
Jeremy
On 29 March 2011 12:25, jouba antr...@hotmail.com wrote:
Dear all,
There is some where documentation to understand all indices
That's probably wrong.
x4-x5,gamm4,NA
x7-x6,gamm5,NA
x6-x5,gamm6,NA
Are the above two correct?
x2 -x2 ,sigmma1,NA
x3 -x3 ,simma2,NA
x4 -x4 ,sigmma3,NA
x5 -x5 ,sigmma4,NA
x7 -x7 ,sigmma5,NA
x6 -x6 ,sigmma6,NA
It's a somewhat unusual looking model. What are you trying to do?
Jeremy
of introductory SEM texts,
which will answer this sort of question.
Jeremy
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Can you clarify what you mean? The strength of the correlation is the
correlation. One (somewhat) useful definition is Cohen's, who said 0.1
is small, 0.3 is medium and 0.5 is large.
Or do you (as your subject says) want to get the power for a
correlation? This is a different thing.
Jeremy
Dear all,
I post again my question with a new title ... please, help me!
I build a customized version of R-2.12.1 from source (under windows XP). I
work as explain in the R Installation and Adminstration manual and all
seems to be good... But When I try to uninstall this version I have the
Dear all,
I build a customized version of R-2.12.1 from source (under windows XP). I
work as explain in the R Installation and Adminstration manual and all
seems to be good... But When I try to uninstall this version I have the
error message cannot find utCompiledCode record for this version
the structural equation modeling list
- semnet. This isn't really a sem (the package) or R problem, it's a
more general SEM (the approach) problem.
Jeremy
Chen, F., Bollen, K., Paxton, P., Curran, P.J., Kirby, J. (2001).
Improper solutions in structural equation models: Causes,
consequences
be construed as publishing the
algorithm. (SPSS and WPS both can open SAS files, and I'd be surprised
if SAS licensed to them. [Esp WPS, who SAS are (or were) suing for
all kinds of things in court in London.)
Jeremy
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Hi All,
I was wondering if anyone knew of a function which would generate data
from a pre-specified correlation matrix (as in the Stata command
r2corr) or sampled from a population with a specific
covariance/correlation. (I thought I'd check before I wrote something
inelegant and slow.)
Jeremy
. However, it appears that in R
you did not dummy code them. It also appears you haven't given use
all of the SAS output.
Jeremy
On 27 January 2011 15:52, Belle ping...@gmail.com wrote:
Hi Harold:
I know the outputs are different between SAS and R, but the results that I
got have big difference
some of the variables across the data frames, so in addition to caseid, each
also contains AuthorYr and StudyDesign.
Thanks,
Jeremy
--
Jeremy Miles
Psychology Research Methods Wiki: www.researchmethodsinpsychology.com
[[alternative HTML version deleted
We distribute several R applications using the tcltk package on different
servers or PC (Windows XP). On some machines and in a not reproducible
way, all the R windows disappear when using functions like tkgetSaveFile
or tkchooseDirectory. The R application remains open (the Rgui.exe
processus
You could use cov2cor() to convert from covariance matrix to
correlation matrix. If the correlation is 1, the matrix won't be
positive definite, so you can restandardize the matrix to get a pos
def correlation matrix.
Jeremy
On 21 October 2010 15:50, HAKAN DEMIRTAS demir...@uic.edu wrote:
Hi
not misunderstood. :)
Jeremy
On 21 October 2010 16:14, HAKAN DEMIRTAS demir...@uic.edu wrote:
I know.
Let me re-phrase the question: How do I convert a non-positive definite
correlation matrix to a positive-definite correlation matrix in R? I don't
think cov2cor is relevant here.
Example:
print
element occupies on this map.
Is there a way to do this in 'R'? I am fairly new to this software, so any help
would be much appreciated.
Thank you in advance,
Jeremy
[[alternative HTML version deleted]]
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This is correct. Wikipedia is not bad, and provides some references.
Another web page:
http://courses.ttu.edu/isqs6348-westfall/images/6348/BonHolmBenHoch.htm
http://courses.ttu.edu/isqs6348-westfall/images/6348/BonHolmBenHoch.htm
Jeremy
On 7 October 2010 10:37, will.ea...@gmx.net wrote
Try using cat instead. Then \n is the new line character.
E.g.
cat(1st line\n2nd line\n)
Jeremy
On 30 September 2010 13:30, David LeBauer dleba...@gmail.com wrote:
Can I add a line break to the paste() function to return the following:
'this is the first line'
'this is the second line
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