Hello again,
Let say I have following user defined function:
fn - function(x, y) {
Vec1 - letters[1:6]
Vec2 - 1:5
return(list(ifelse(x 0, Vec1, NA), ifelse(y 0, Vec2, NA)))
}
Now I have following calculation:
fn(-3, -3)
[[1]]
[1] NA
Hello,
You get only one value because ifelse is vectorized, and the condition
has length(x 0) == 1. (You get as many values as there are in the
condition.) Try instead
fn2 - function(x, y) {
Vec1 - letters[1:6]
Vec2 - 1:5
list(if(x 0) Vec1 else NA, if(y 0) Vec2
On 2013-03-22 11:43, Christofer Bogaso wrote:
Hello again,
Let say I have following user defined function:
fn - function(x, y) {
Vec1 - letters[1:6]
Vec2 - 1:5
return(list(ifelse(x 0, Vec1, NA), ifelse(y 0, Vec2, NA)))
}
Now I have
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