Hi,
Thanks to Henrique and Prof. Spector for their kind reply. Indeed, the mean
function does work, but the result I want is an average data vector, not an
scalar, which is the output of mean(). This is, given these two data frames
(each data frame has 500 rows):
Time Pressure
0.0 100
Peter,
Try this:
apply(do.call(merge, c(loadfiles, by = Time))[2:3], 1, mean)
On Thu, Jul 2, 2009 at 10:39 AM, Peter Perez plp...@gmail.com wrote:
Hi,
Thanks to Henrique and Prof. Spector for their kind reply. Indeed, the mean
function does work, but the result I want is an average data
Hi Henrique,
This works perfectly!. Thanks so much for your help.
Best regards,
Peter
Henrique Dallazuanna wrote:
Peter,
Try this:
apply(do.call(merge, c(loadfiles, by = Time))[2:3], 1, mean)
On Thu, Jul 2, 2009 at 10:39 AM, Peter Perez plp...@gmail.com wrote:
Hi,
Thanks to
Dear all,
I know it is as simple as c - (a + b)/2 to compute the average
(element-wise) of two data vectors. However, I can't work out to compute the
average when you have many data vectors in a directory. I have done this:
setwd(/.../data/)
listfiles -
The mean function works in data.frames:
lapply(loadfiles, mean)
[[1]]
Time Pressure
1. 323.
[[2]]
Time Pressure
1. 323.
On Wed, Jul 1, 2009 at 1:50 PM, plpd00 plp...@gmail.com wrote:
Dear all,
I know it is as simple as c - (a + b)/2 to compute the average
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