Hi Philippe,
Ah! Thanks for pointing out the pesky ifelse() issue. I have only recently
been learning (the hard way) that ifelse() is not a tool for the uninformed
like me, but it is ever so tempting!
I would like to offer another way to speed things up. findInterval() can be
quite fast,
Also note that ifelse() should be avoided as much as possible. To define a
piecewise function you can use this trick:
func - function (x, min, max) 1/(max-min) * (x = min x = max)
The performances are much better. This has no impact here, but it is a good
habit to take in case you manipulate
On 31 Jan 2015, at 09:39 , Rolf Turner r.tur...@auckland.ac.nz wrote:
On 31/01/15 21:10, C W wrote:
Hi Bill,
One quick question. What if I wanted to use curve() for a uniform
distribution?
Say, unif(0.5, 1.3), 0 elsewhere.
My R code:
func - function(min, max){
1 / (max - min)
Hi Bill,
One quick question. What if I wanted to use curve() for a uniform
distribution?
Say, unif(0.5, 1.3), 0 elsewhere.
My R code:
func - function(min, max){
1 / (max - min)
}
curve(func(min = 0.5, max = 1.3), from = 0, to = 2)
curve() wants an expression, but I have a constant. And I
On 31/01/15 21:10, C W wrote:
Hi Bill,
One quick question. What if I wanted to use curve() for a uniform
distribution?
Say, unif(0.5, 1.3), 0 elsewhere.
My R code:
func - function(min, max){
1 / (max - min)
}
curve(func(min = 0.5, max = 1.3), from = 0, to = 2)
curve() wants an
Hello,
The following will work, but I don't know if it's what you want. func2
will get x and y from the global environment.
func2 - function(mu){
x + y + mu ^ 2
}
curve(func2, from = 0, to = 10)
Hope this helps,
Rui Barradas
Em 29-01-2015 21:02, C W escreveu:
Hi all,
I want to graph
Hi all,
I want to graph a curve as a function of mu, not x.
Here's the R code:
x - rnorm(10)
y - rnorm(10)
func - function(x, y, mu){
x + y + mu ^ 2
}
curve(f = func(x = x, y = y, mu), from = 0, to = 10)
I know I can change variable mu to x, but is there a way to tell R that mu
is the
Hi Rui,
Thank you for your help. That works for now, but eventually, I need to be
pass in x and y.
Is there a way to tell the curve() function, x is a fix vector, mu is a
variable!
Thanks,
Mike
On Thu, Jan 29, 2015 at 5:25 PM, Rui Barradas ruipbarra...@sapo.pt wrote:
Hello,
The following
Does
help(curve)
talk about its 'xname' argument?
Try
curve(10*foofoo, from=0, to=17, xname=foofoo)
You will have to modify your function, since curve() will
call it once with a long vector for the independent variable
and func(rnorm(10), rnorm(10), mu=seq(0,5,len=501)) won't
work right.
Hi Bill,
You solved by problem. For some reason, I thought xname was only referring
to name of the x-axis.
I remember last time I fixed it, it was something about xname, couldn't get
it right this time.
Thanks! Saved me hours from frustration.
Mike
On Thu, Jan 29, 2015 at 9:04 PM, William
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