Dear all,
I'm looking for a way to replace NA's with 0 for a number of variables
which share the same ending and which constitute a subset of a data frame.
Say, for example, there is
data - data.frame(ax=c(1,2,3,NA,0) , bx=c(3,5,NA,5,1) ,
ay=c(5,NA,2,NA,0) , by=c(4,2,NA,2,1))
data
ax bx ay
On 01/15/2010 07:10 PM, Uli Kleinwechter wrote:
Dear all,
I'm looking for a way to replace NA's with 0 for a number of variables
which share the same ending and which constitute a subset of a data frame.
Say, for example, there is
data- data.frame(ax=c(1,2,3,NA,0) , bx=c(3,5,NA,5,1) ,
Hi,
this works aswell:
for(i in 1:ncol(data)) data[is.na(data[,i]),i] - 0
i am sure there is way doing it with a member of the apply family, maybe
someone else has an idea.
Johannes
On Fri, Jan 15, 2010 at 9:51 PM, Jim Lemon j...@bitwrit.com.au wrote:
On 01/15/2010 07:10 PM, Uli
Jim Lemon schrieb:
On 01/15/2010 07:10 PM, Uli Kleinwechter wrote:
Dear all,
I'm looking for a way to replace NA's with 0 for a number of variables
which share the same ending and which constitute a subset of a data
frame.
Say, for example, there is
data- data.frame(ax=c(1,2,3,NA,0) ,
In grep use: grep(x$, names(data)).
'$' matchs 'x' in the end of string
On Fri, Jan 15, 2010 at 11:14 AM, Uli Kleinwechter
u.kleinwech...@uni-hohenheim.de wrote:
Jim Lemon schrieb:
On 01/15/2010 07:10 PM, Uli Kleinwechter wrote:
Dear all,
I'm looking for a way to replace NA's with 0 for a
Uli Kleinwechter a écrit :
data[,grep(x,names(data))][is.na(data[,grep(x,names(data))])]-0
thanks a lot. I'm just afraid that grep matches any occurence of x in
the variable name. So variables which would contain x at any position,
not necessarily only at the last one would be selected,
That's it, thanks a lot to all of you!
Uli
Henrique Dallazuanna schrieb:
In grep use: grep(x$, names(data)).
'$' matchs 'x' in the end of string
On Fri, Jan 15, 2010 at 11:14 AM, Uli Kleinwechter
u.kleinwech...@uni-hohenheim.de wrote:
Jim Lemon schrieb:
On 01/15/2010 07:10 PM,
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