Dear list,
I cannot find an elegant solution to this problem. I have a factor f
containing several levels (5) and I wish to create a new factor of the
same length with fewer levels (2). This new factor should therefore
group together some levels of the original data. Ideally this grouping
would
As always the question seems silly after you've learned the answer!
Thanks a lot,
baptiste
On 3 February 2010 15:06, Petr PIKAL petr.pi...@precheza.cz wrote:
# order levels
f.t-factor(f, levels=disorder)
# change levels
levels(f.t) - new.lev
all.equal(f.t,f2)
[1] TRUE
Regards
Petr
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