of the resolution, that is max-min=ineger*resolution. The bbox limits
must just be rounded to the same number of digits as the resolution and include
all available values, of course.
Best regards.
Оригинално писмо
От: arun
Относно: Re: [R] number of decimal places
-Original Message-
From: Martin Ivanov
I have the longitudes (lon) and latitudes (lat), and I have a
resolution (r), for example r = 0.004. The bounding box must
have the same number of digits as resolution.
Surely the issue is not the particular numeric resolution of the
,digits=35))
[1] FALSE
A.K.
- Original Message -
From: Petr Savicky savi...@cs.cas.cz
To: r-help@r-project.org
Cc:
Sent: Sunday, July 8, 2012 2:21 PM
Subject: Re: [R] number of decimal places in a number?
On Sat, Jul 07, 2012 at 01:12:34PM +0100, Ted Harding wrote:
I had
On Mon, Jul 09, 2012 at 07:52:18AM -0500, Jim Plante wrote:
I don't know how significant this is, but WolframAlpha's value of pi
disagrees with R's at about the 16th decimal:
Wpi-3.141592653589793238462643383279502884197169399375105
..^
On Sat, Jul 07, 2012 at 01:12:34PM +0100, Ted Harding wrote:
I had thought of also (as well as my numerical routing) suggesting
a gsub() type solution like Joshua's below, but held back because
the result could depend on how the number arose (keyboard input,
file input, or from computation
On Sun, Jul 08, 2012 at 11:39:22AM -0700, arun wrote:
Hi Petr,
I think sprintf and formatC are identical as it can round 22 decimal places
as opposed to print and signif
print(pi,digits=35)
Hi Arun:
Thank you for pointing this out. Funtion formatC()
is easier to use and uses the same C
On Sat, Jul 07, 2012 at 11:52:35AM +0300, Martin Ivanov wrote:
Dear R users,
I need a function that gets a number and returns its number of actual decimal
places.
For example f(3.14) should return 2, f(3.142) should return 3, f(3.1400)
should also return 2
and so on. Is such function
: [R] number of decimal places in a number?
On Sat, Jul 07, 2012 at 01:12:34PM +0100, Ted Harding wrote:
I had thought of also (as well as my numerical routing) suggesting
a gsub() type solution like Joshua's below, but held back because
the result could depend on how the number arose (keyboard
Dear R users,
I need a function that gets a number and returns its number of actual decimal
places.
For example f(3.14) should return 2, f(3.142) should return 3, f(3.1400) should
also return 2
and so on. Is such function already available in R? If not, could you give me a
hint how to achieve
On 07-Jul-2012 08:52:35 Martin Ivanov wrote:
Dear R users,
I need a function that gets a number and returns its number of
actual decimal places.
For example f(3.14) should return 2, f(3.142) should return 3,
f(3.1400) should also return 2 and so on. Is such function already
available in
Hi Martin,
Ted is spot on about the binary representation. A very different
approach from his would be to convert to character and use regular
expressions:
## the example numbers in a vector
x - c(3.14, 3.142, 3.1400, 123456.123456789, 123456789.123456789, pi, sqrt(2))
I had thought of also (as well as my numerical routing) suggesting
a gsub() type solution like Joshua's below, but held back because
the result could depend on how the number arose (keyboard input,
file input, or from computation within R).
However, I now also realise that (again because of
Dear Mr Harding,
Thank You very much for Your responsiveness.
There would seem to be no clean general solution to this
question. An important issue would be: What use do you
want to put the result to?
I need this trick for the following task.
I am writing a function which has to determine
using
as.character.
A.K.
- Original Message -
From: ted.hard...@wlandres.net ted.hard...@wlandres.net
To: r-help@r-project.org
Cc: Martin Ivanov tra...@abv.bg
Sent: Saturday, July 7, 2012 8:12 AM
Subject: Re: [R] number of decimal places in a number?
I had thought of also (as well as my
mod Ted's comments, I believe that for your situation (not too many digits
to represent, decimal point always present)
countDecDigits -
function(x)nchar(sapply(strsplit(as.character(x),\\.),[,2))
is simple and should work. No need for regular expressions here.
-- Bert
On Sat, Jul 7, 2012 at
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