Rolf Turner [EMAIL PROTECTED] wrote:
I have often wanted to suppress these row numbers and for that purpose
wrote the following version of print.data.frame()
[...]
The ``srn'' argument means ``suppress row numbers'';
[...]
I once suggested to an R Core person that my version of
Hi!
I'm an R newbie and this should be a trivial problem, but I can't make it
work and cannot find what I'm doing wrong in the literature.
I entered the the command:
table-data.frame(x, scientific=F, digits=4)
table
This prints a column of x with 16 useless decimal places after the decimal
point.
Without knowing what your 'x' is, it's hard to see what is happening
that you don't like.
Your data.frame function creates a data.frame containing columns
scientific and digits, equal to FALSE and 4 for all rows, respectively.
Is that what you want?
cvandy wrote:
Hi!
I'm an R newbie and
Those are parameter to 'print'; what you want is something like:
x - data.frame(a=runif(10))
print(x)
a
1 0.713705394
2 0.715496609
3 0.629578524
4 0.184360667
5 0.456639418
6 0.008667156
7 0.260985437
8 0.270915631
9 0.689128652
10 0.302484280
print(x,scientific=F,
Can you give a working example of what is happening
and explain what is x?
With a simple x vector of x - rnorm(20, 5, 2)
I don't get anything like what you seem to be getting.
My code
===
x - rnorm(20, 5, 2)
table-data.frame(x, scientific=F,
On 27/02/2008, at 11:01 AM, John Kane wrote:
Can you give a working example of what is happening
and explain what is x?
With a simple x vector of x - rnorm(20, 5, 2)
I don't get anything like what you seem to be getting.
My code
===
x -
Thanks, Erik,
This is a partial copy of my code. I want to get rid of the left column of
integers and I want to control the number of decimal places after the
decimal point.
j-0.4
for(i in 1:20){
+ j=j+0.1;cp[i]-pnorm(-j*3)*10^6;ratio[i]-j}
table-data.frame(ratio,cp)
table
ratio
While we're at it, and since you're new...
Your example will be much easier for r-help folks to read if you do
it like this:
j - 0.4
for(i in 1:20) {
j=j+0.1
cp[i] - pnorm(-j*3)*10^6
ratio[i] - j
}
table - data.frame(ratio,cp)
table
But the loop is unnecessary. Try
j - seq(0.5,
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