Pls advise how I can use R in conjoint analysis??
regds
Faisal Afzal Siddiqui
Karachi, Pakistan
Looking for last minute shopping deals?
__
Dear Simone,
you can use the package 'drc' to fit a logistic model, that is a non-linear
regression
model based on the equation c+(d-c)/(1+exp(b(x-e))), to your data (below named
'simone'):
## Fitting a 4-parameter logistic model (also called Boltzmann model)
simone.m1 - drm(size~x,
You could use the qqnorm function to obtain the correlation, as:
qqp=qqnorm(rstudent(regrname))
cor(qqp$x,qqp$y)
If you do not want see the plot (as the qq.plot is richer):
qqp=qqnorm(rstudent(regrname), plot.it=F)
domenico vistocco
Tom Fitzhugh wrote:
Hi,
I am trying to figure out
Hello,
I'm missing two features in R CMD build:
1) Easy building of Windows/zip packaged package version alongside the
*nix-style *.tar.gz.
Right now I'm doing a scripted version of
R CMD build PACKAGE
R CMD INSTALL PACKAGE
mkdir tmp
cp -r
Hi Deepayan!
thank you! panel.violin with the following modification works as I want:
grid.polyline(x = dx.list[[i]], y = dy.list[[i]], ...
instead of
grid.polygon(x = c(dx.list[[i]], rev(dx.list[[i]])),
y = c(dy.list[[i]], -rev(dy.list[[i]])), ...
From examples I would
Hi Dieter,
I actually solved *my* problem:
Key(x = 0.667, y = 0.833, lev = c(expression(italic(b)),
expression(italic(c)), expression(italic(d))),
other = list(title = expression(italic(v)), cex.title = 1))
I was able to figure this out only by looking at the code for Key(),
because
Dear all
I tried to make a biplot with color coded labels but I was not successful.
Searching archives I found that it is probably not so simple.
I found
http://tolstoy.newcastle.edu.au/R/help/05/01/10661.html
which recommends eqscplot
eqscplot(fit$score[,1], fit$score[,2], pch = 20,
Dear Brendan,
I am not sure to understand your code..
It seems to me that your are interested in fitting a one-breakpoint
segmented relationship in each level of your grouping variable
If this is the case, the correct code is below.
In order to fit a segmented relationship in each group you
Hello,
I'm trying to integrate example data in the shape of a tab delimited ASCII
file into my package and therefore dropped it into the data subdirectory.
The build works out just fine, but when I attempt to install I get:
** building package indices ...
Error in scan(file, what, nmax, sep,
http://tolstoy.newcastle.edu.au/R/help/05/06/6104.html
http://tolstoy.newcastle.edu.au/R/help/05/06/6103.html
domenico
faisal afzal siddiqui wrote:
Pls advise how I can use R in conjoint analysis??
regds
Faisal Afzal Siddiqui
Karachi, Pakistan
Faisal,
can you elaborate further on your conjoint design
there is bayesm which offers a hierarchical bayes approach to analysing
choice data
MLogit available through zelig (see below)
http://gking.harvard.edu/zelig/docs/index.html
MNP as a standalone package for the probit model
thanks
Johannes Graumann wrote:
Hello,
I'm trying to integrate example data in the shape of a tab delimited ASCII
file into my package and therefore dropped it into the data subdirectory.
The build works out just fine, but when I attempt to install I get:
** building package indices ...
Error in
MS == Marc Schwartz [EMAIL PROTECTED]
on Wed, 05 Dec 2007 12:43:50 -0600 writes:
[]
MS Martin,
MS Thanks for the corrections. In hindsight, now seeing the intended use of
MS ecdf() in the fashion you describe above, it is now clear that my
MS approach in
G'day Peter,
On Thu, 06 Dec 2007 11:52:46 +0100
Peter Dalgaard [EMAIL PROTECTED] wrote:
If you had looked at help(data), you would have found a list of which
file formats it supports and how they are read. Hint: TAB-delimited
files are not among them. [...]
On the other hand, Writing R
If you are using correspondence analysis you could see the plot.ca
function in the ca library.
Petr PIKAL wrote:
Dear all
I tried to make a biplot with color coded labels but I was not successful.
Searching archives I found that it is probably not so simple.
I found
Dear Christian,
it works great, and it is simple to understand, thank you very much.
just a detail, is it possible to plot just the fitted curve and not
the data? it's because I would like to have data in black and the
fitted curve in red.. I don't know how to pick up the single parts, if
Dear Christian,
it works great, and it is simple to understand, thank you very much.
just a detail, is it possible to plot just the fitted curve and not
the data? it's because I would like to have data in black and the
fitted curve in red.. I don't know how to pick up the single parts, if
Dear all,
Starting from a recent version of R, the $ became unusable on atomic vectors,
e.g.
x - c(a=1,b=2)
x$a
NULL
Warning message:
In x$a : $ operator is invalid for atomic vectors, returning NULL
I can of course do
x['a']
- but that requires more typing (5 characters rather than 2).
I have a series of question about methods and generics.
The questions are interspersed in some text which explains
what I want to do, how it works now and why I do not
understand well why it works. Questions are written
Q1 and so on up to Q9 and always start a new line.
The concrete problem is
On Thu, 6 Dec 2007, Søren Højsgaard wrote:
Dear all,
Starting from a recent version of R,
From R 2.5.0, not so recent.
the $ became unusable on atomic vectors, e.g.
x - c(a=1,b=2)
x$a
NULL
Warning message:
In x$a : $ operator is invalid for atomic vectors, returning NULL
I can of course
On Dec 6, 2007 6:11 AM, Martin Maechler [EMAIL PROTECTED] wrote:
MS == Marc Schwartz [EMAIL PROTECTED]
on Wed, 05 Dec 2007 12:43:50 -0600 writes:
[]
MS Martin,
MS Thanks for the corrections. In hindsight, now seeing the intended use
of
MS ecdf() in the fashion
On 06-Dec-07 12:04:56, Søren Højsgaard wrote:
Dear all,
Starting from a recent version of R, the $ became unusable
on atomic vectors, e.g.
x - c(a=1,b=2)
x$a
NULL
Warning message:
In x$a : $ operator is invalid for atomic vectors, returning NULL
I can of course do
x['a']
- but that
Berwin A Turlach wrote:
G'day Peter,
On Thu, 06 Dec 2007 11:52:46 +0100
Peter Dalgaard [EMAIL PROTECTED] wrote:
If you had looked at help(data), you would have found a list of which
file formats it supports and how they are read. Hint: TAB-delimited
files are not among them. [...]
Dear all,
Is there *any* reason explaining what I describe below?
I have the following line
myfun(x)
If I type them directly in R (or copy/past), it works..
However if I type in R 2.6.1
source(code.R) ##code.R includes the above line
Error in inherits(x, data.frame) : object d not found
Dear list,
i have this problem:
how to pair a graphic.png and a table in R2HTML ?
The better showing of a mutiple analysis is sometimes to mate graphic and
table
Can anyone help me in this task ??
In the example below graphisc and table are subsequent and not pair..
directory=getwd()
Hi, All;
I've compiled and installed successfully presumably 64-bit R on
Leopard.
But when I tried to run R, I got the following error:
/usr/bin/R: line 179: /Library/Frameworks/R.framework/Resources/etc/
i386/ldpaths: No such file or directory
Here is the configuration I used:
Johannes Graumann wrote:
On Thursday 06 December 2007 11:52:46 Peter Dalgaard wrote:
Johannes Graumann wrote:
Hello,
I'm trying to integrate example data in the shape of a tab delimited
ASCII file into my package and therefore dropped it into the data
subdirectory. The build works out
Hi Roberto,
here is a way that presumes you know some (basic) HTML tags:
library(R2HTML)
directory=getwd()
myfile-file.path(directory,testHTML.html)
HTMLoutput=file.path(directory,testHTML.html)
graf=graf.png
png(file.path(directory,graf))
plot(c(1:12))
dev.off()
tab-as.matrix(c(1:12))
On 12/6/2007 7:04 AM, Søren Højsgaard wrote:
Dear all,
Starting from a recent version of R, the $ became unusable on atomic
vectors, e.g.
x - c(a=1,b=2)
x$a
NULL
Warning message:
In x$a : $ operator is invalid for atomic vectors, returning NULL
I can of course do
x['a']
- but that
affy snp wrote:
Dear list,
I am using heatmap.2(x) to draw a heatmap. Ideally, I want to the matrix
x clustered only by columns and keep the original order of rows unchanged.
Is there a way to do that in heatmap.2()?
Thanks a lot! Any suggestions will be appreciated!
From the help
You could use a table with one row and two columns:
HTML(TABLETD,file=HTMLoutput)
HTML(tab,file=HTMLoutput)
HTML(/TDTD,file=HTMLoutput)
HTMLInsertGraph(graf,file=HTMLoutput,caption=Esempio di grafico)
HTML(/TD/TABLE,file=HTMLoutput)
domenico
PS:
You could create a function if this is a common
Johannes Graumann wrote:
Johannes Graumann wrote:
On Thursday 06 December 2007 11:52:46 Peter Dalgaard wrote:
Johannes Graumann wrote:
Hello,
I'm trying to integrate example data in the shape of a tab delimited
ASCII file into my package and therefore dropped it into the
Loren Engrav wrote:
Thank you
As per advice from several R users I have set
r-project.org, stat.math.ethz.ch,fhcrc.org, stat.ethz.ch, math.ethz.ch,
hypatia.math.ethz.ch
all to be safe domains
But still some R emails go to Junk and require to be found manually
I have explored
Hi,
Consider this simple plot:
plot(1:25,runif(25,0,1),ylab=First Y-axis label,xaxt=n)
I want to add an additional axis as
axis(4,at=seq(0.2,1,.2), labels=1:5)
I have no idea how to add now the title of the new axis as Second
Y-axis label. I want this text to be vertically directed from
Hi, All;
I've compiled and installed successfully presumably 64-bit R on
Leopard.
But when I tried to run R, I got the following error:
/usr/bin/R: line 179: /Library/Frameworks/R.framework/Resources/etc/
i386/ldpaths: No such file or directory
Here is the configuration I used:
Peter Dalgaard wrote:
Answering to myself and staying with the same example:
system.file(data/stroke.csv,package=ISwR)
allows direct access to the example file (name).
Yes, but...
This works right until you turn on LazyData for your package, then you
end up with only
Eric,
your code work well for my need,
i'm not skillful in html environment, but your functions in R2HTML give
simple many
output requirements
thanks
Roberto
Eric Lecoutre wrote:
Hi Roberto,
here is a way that presumes you know some (basic) HTML tags:
library(R2HTML)
I know that there is a function, (spectro3D), that produces the Power
Spectrogram. Are there R functions that produce the Frequency Spectrogram and
the Phase Spectrogram? Thank you for your time.
[[alternative HTML version deleted]]
__
Thanks Ashoka!
Allen
On Dec 6, 2007 12:27 AM, Ashoka Polpitiya [EMAIL PROTECTED]
wrote:
Check the Rowv, Colv options to heatmap.2
data(mtcars)
x - as.matrix(mtcars)
heatmap.2(x, Rowv=FALSE, dendrogram=column)
-Ashoka
Scientist - Pacific Northwest National Lab
On Dec 5, 2007
Thanks James!
Allen
On Dec 6, 2007 9:21 AM, James W. MacDonald [EMAIL PROTECTED] wrote:
affy snp wrote:
Dear list,
I am using heatmap.2(x) to draw a heatmap. Ideally, I want to the matrix
x clustered only by columns and keep the original order of rows
unchanged.
Is there a way to
There is an example in the example section of
library(zoo)
?plot.zoo
starting at:
## plot with left and right axes
On Dec 6, 2007 10:16 AM, Marcin Kozak [EMAIL PROTECTED] wrote:
Hi,
Consider this simple plot:
plot(1:25,runif(25,0,1),ylab=First Y-axis label,xaxt=n)
I want to add an
An alternative solution that allows you to break it down by categories is in
the functions below. Comments/suggestions welcome and encouraged.
Note that much thanks is due to those who responded to an earlier post of
mine on a similar topic.
To use (assuming you have a data.frame falled
huang min wrote:
Hi,
I have searched the lists but still can not solve the problem. I am using
a
windows machine. After I sweave some Rnw file, I got a tex file. However,
the tex file can not be compiled. I know the problem is in the line
I want to run deconvolution of a time series by an impulse or point-spread
function through Wiener filter, regularized filter, Lucy-Richardson method, or
any other approaches. I searched the CRAN website and the mailing list archive,
but could not find any package for such a deconvolution
Hi,
I installed the snow package on a unix box that has multiple cores. To be
able to exploit the multiple cores (on one pc) do I still need to install
the rmpi package (or rpvm). Another question, if i run a bayesian simulation
on the multiple core after setting them up correctly (using snow),
The RTisean package has wiener filter functions (wiener1 and wiener2).
Regards,
Richie.
Mathematical Sciences Unit
HSL
Chen, Gang (NIH/NIMH) [C] [EMAIL PROTECTED]
Sent by: [EMAIL PROTECTED]
06/12/2007 16:20
To
r-help@r-project.org
cc
Subject
[R] Any package for deconvolution?
I want
hi gabor,
i was able to get your suggestion to work. i have been going through
the R help tools to figure out what each step actually does because i
have something similar but hours 2,5,8,11,14,17 and 20 are missing. i
haven't had any luck. each mean value that is calculated is the
same.
On 12/6/07, Christopher Oezbek [EMAIL PROTECTED] wrote:
But is there a technical reason for making this distinction? It seemed to
me that most panel functions can deal with x and y parameters and that
panel.densityplot could make use of the same mechanisms as panel.violin to
subdivide based
Hey Folks,
Could somebody help me rewrite the following code?
I am looping through all records across 5 fields to calculate the cumulative
percentage of each record (relative to each individual field).
Is there a way to rewrite it so I don't have to loop through each individual
record?
#
The error message says you have duplicate row names and that
is not allowed. Make sure you have the same number of elements
on each line of data as in the header. If you have one more on each line
than on the header then the first data item on each line will be regarded
as the row name. See
It sounds like you should sample x and y together using the
block bootstrap. If you have the usual situation, x and y in columns
and observations in rows, then sample blocks of rows.
Even though observations in y are independent, you would take
advantage of that only for bootstrapping statistics
--- begin included message
I am running R 2.6.1 on windows xp
I am trying to fit a cox proportional hazard model with a shared
Gaussian frailty term using coxme My model is specified as:
nofit1-coxme(Surv(Age,cen1new)~ Sex+bo2+bo3,random=~1|isl,data=mydat)
With x1-x3 being dummy variables, and
R-help users,
Thanks in advance for any assistance ... I truly appreciate your expertise.
I searched help and could not figure this out, and think you can probably offer
some helpful tips. I apologize if I missed something, which I'm sure I probably
did.
I have data for many samples.
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of Michael Kubovy
Sent: Thursday, December 06, 2007 2:12 AM
To: Dieter Menne
Cc: [EMAIL PROTECTED]
Subject: Re: [R] Using expression in Hmisc Key()
[snip]
This is one of the cases where I wish there
Thanks a lot for the quick pointer, Richie. I will take a close look of the
RTisean package.
Gang
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
Sent: Thu 12/6/2007 11:46 AM
To: Chen, Gang (NIH/NIMH) [C]
Cc: r-help@r-project.org
Subject: Re: [R] Any package
On Wed, 2007-12-05 at 22:33 -0800, Bin Yue wrote:
Dear all:
By comparing glmresult$y and model.response(model.frame(glmresult)), I
have found out which one is
set to be TRUE and which FALSE.But it seems that to fit a logistic
regression , logit (or logistic) transformation has to be
How about this example?
## sample data frame with two columns
df - data.frame(x = abs(rnorm(20)), y=abs(rnorm(20,2)))
## create new variables in df with an lapply call
df[c(cpctx,cptcty)] - lapply(df, function(x) cumsum(x)/sum(x))
A possible improvement would be to construct the new column
Is this basically what you want to do? (Please include commented,
minimal, self-contained, reproducible code so we don't have to guess
at what you want)
x - data.frame(a=runif(10), b=runif(10))
# do for one column
cumsum(x$a)/sum(x$a)
[1] 0.05892073 0.08129611 0.11067218 0.28640268 0.28969826
Thank you all. That's exactly what I was looking for.
TLowe wrote:
Hey Folks,
Could somebody help me rewrite the following code?
I am looping through all records across 5 fields to calculate the
cumulative
percentage of each record (relative to each individual field).
Is there a
Hi,
I am trying to use stepAIC to do forward stepwise selection for a logistic
model.
I did
hi - glm(melanoma ~ ., family = binomial, data=data)
lo - glm(melanoma ~ 1, family = binomial, data=data)
stepAIC(lo, scope=list(upper = hi , lower = lo), direction = forward )
But the full model
Thanks Ben, that fixed the display within R. However, even after changing
the display settings, the matrix elements still appear to be exported in
single precision. The matrix object is being passed into my C routines as
an SEXP Numeric type, and somewhere along the way, some of the digits are
Todd Remund tkremund98 at hotmail.com writes:
I know that there is a function, (spectro3D), that produces the Power
Spectrogram. Are there R functions
that produce the Frequency Spectrogram and the Phase Spectrogram? Thank you
for your time.
fft in stats gives you all you need, possibly
I have a dataset with two variables that are factors:
1) Decision Making Satisfaction (DMS), values = A - Completely, B -
Mostly, C - Partly, D - Not at all
2) IT Satisfaction values (ITS), values = A - Completely, B - Mostly, C
- Partly, D - Not at all
I would like to produce a table (matrix)
Hi,
I need to fit a general generalized linear model, for observations
on a response Y which is Gamma-distributed and observed in clusters. So, if
E(Y) = mu,
then for a suitable link function f, f(mu) is a (linear) function of
both fixed and random effects. Are there R packages or
This will give you the percents in the same order as your original data (as
this is what your original code did)
apply(tdat, 2,
function(x) {
o - order(x)
oldo - order(o)
prc - cumsum(x[o]) / sum(x)
prc[oldo]
})
Jason Law
Statistician
City of Portland, Bureau of
Try inserting \n into the title where you would like it to start on a
new line, e.g.:
plot(A,main=This is my really long title\nand it's so long\nthat I can
see just about half of it.)
You may need to give yourself more room in the margin for multi-line
titles (see ?par and the mar entry) and
On Thu, 2007-12-06 at 07:16 -0800, Svempa wrote:
I want to fit a fairly long main title for a plot, supposedly by changing row
after a while. As for now it starts way outside the picture margin at the
left and continues way out right passed the right margins.
plot(A,main=This is my really
On 12/6/2007 8:01 AM, vito muggeo wrote:
Dear all,
Is there *any* reason explaining what I describe below?
Probably, but you're unlikely to get a correct explanation if you don't
give us code to reproduce the problem.
From the look of things, your real example is quite complex, which is
try this:
plot(0, main=paste(strwrap(This is my really long title and it's so
long that I can see just about half of it., width=50),
collapse=\n))
On Dec 6, 2007 7:16 AM, Svempa [EMAIL PROTECTED] wrote:
I want to fit a fairly long main title for a plot, supposedly by changing row
after a
On Thu, 2007-12-06 at 09:27 -0800, qian z wrote:
I used merge() in a function, but it doesn't return correct data frame.
add.name - function(data, x)
{
...
...
newfile - merge(data, resid, by =0, all.x=TRUE, all.y= FALSE)
newfile
}
You are
I wrote a little utility function for exactly this reason, which I use with
long titles. You may want to add calls to par to adjust the upper margin if
you are using raw graphical functionality (plot et al) - but lattice adjusts
the upper margin automatically so you wouldn't need to add anything
I have huge data file, and I would like randomize just one column at a time ,
is there any easy way?
Thanks a lot.
--
View this message in context:
http://www.nabble.com/Randomizing-one-column-in-the-dataMatrix-tf4957535.html#a14197423
Sent from the R help mailing list archive at Nabble.com.
Michael Kubovy kubovy at virginia.edu writes:
This is one of the cases where I wish there were a function that
exercised all the arguments of a graphics function by visualizing
the effect of changing two or three levels of each argument (one by
one, of course). This might have the
op - par(mar=(c(5, 4, 4, 4) + 0.1))
plot(1:25,runif(25,0,1),ylab=First Y-axis
label,xaxt=n)
axis(4,at=seq(0.2,1,.2), labels=1:5)
mtext(Second Y-axis label,side=4, line=2)
par(op)
--- Marcin Kozak [EMAIL PROTECTED] wrote:
Hi,
Consider this simple plot:
plot(1:25,runif(25,0,1),ylab=First
Try this:
df - data.frame(DMS=factor(rep(LETTERS[1:4], 10)),
ITS=factor(rep(LETTERS[1:4], 10)))
table(df)
plot(table(df))
--
Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40 S 49° 16' 22 O
On 06/12/2007, christopher snow [EMAIL PROTECTED] wrote:
I have a dataset with two variables that
Hello,
I am not only interested in finding out which genes are the most highly up-
or down-regulated (which I have done using the linear models and Bayesian
statistics in Limma), but I also want to know which genes are consistently
highly transcribed (ie. they have a high intensity in the
Try This:
plot(A,main=paste(This is my really long title and,\n,it's so long that
I can see
just about half of it., sep = ))
-- Bert Gunter
Genentech
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read
Greetings!
Recently when I tried to use lm.influence I get the following error:
Error in .Fortran(lminfl, model$qr$qr, n, n, k, as.integer(do.coef), :
Fortran symbol name lminfl not in DLL for package base
This occurs on both Linux and Windows platforms (details below).
Searching the mail
The 'table' function will give you the simple counts. Plotting a table
with the 'plot' function gives common charts for this. The 'CrossTable'
function in the gmodels package creates the table along with additional
information. There are a lot of other functions for creating/working
with tables
Hello:
How can I work around the conflict between the S3 and S4
illustrated in the example below? I'm developing a package that
requires a function in 'stats4', but when 'stats4' is attached, it
breaks my AIC function. I could give my AIC function another name so it
no longer uses
On Thu, 2007-12-06 at 12:51 +, christopher snow wrote:
I have a dataset with two variables that are factors:
1) Decision Making Satisfaction (DMS), values = A - Completely, B -
Mostly, C - Partly, D - Not at all
2) IT Satisfaction values (ITS), values = A - Completely, B - Mostly, C
On 12/5/07 12:15 PM, Prof Brian Ripley [EMAIL PROTECTED] wrote:
On Wed, 5 Dec 2007, David Coppit wrote:
Or, given that I'm dealing with just a single array, would it be better to
roll my own I/O using write.table or write.matrix from the MASS package?
It would be much easier. The save()
Hello R users,
I have been looking through Help files and Nabble list for the answers for
these simple questions, but it seems to be fruitless.
1- in a data frame with two columns, x and y, how do I get the corresponding
value of x to, let's say, the minimum value of the y column (min (data$y)) ?
?table should work
table (DMS, ITS)
I am not clear on what kind of chart you want.
will
plot(DMS, ITS) do what you want?
--- christopher snow [EMAIL PROTECTED] wrote:
I have a dataset with two variables that are
factors:
1) Decision Making Satisfaction (DMS), values = A -
Completely,
On Thu, 2007-12-06 at 09:28 -0800, Jim Price wrote:
I wrote a little utility function for exactly this reason, which I use with
long titles. You may want to add calls to par to adjust the upper margin if
you are using raw graphical functionality (plot et al) - but lattice adjusts
the upper
On Thu, 2007-12-06 at 14:00 -0500, Gerard Tromp wrote:
Greetings!
Recently when I tried to use lm.influence I get the following error:
Error in .Fortran(lminfl, model$qr$qr, n, n, k, as.integer(do.coef), :
Fortran symbol name lminfl not in DLL for package base
This occurs on both
Happy Holidays Folks!
XLSolutions Corporation has scheduled 2 great R/Splus Advanced
programming courses. More course can be viewed on our website.
R/Splus Advanced Programming* San Francisco January 21-22,
2008
R/Splus Advanced Programming* New York City January 24-25,
I have learned something new - thanks for the strwrap info.
The problem with posting from Nabble is that by the time your post actually
gets to the list (2 hours after you posted it in this case) and you've
written some line like Knowing the R list, someone can probably reduce this
function to 2
I'd say that was pretty clearly a bug in stats4 (which as I recall was
needed to get around the scoping awkwardnesses of S4).
But could you not write a logLik method for your class? E.g.
logLik.bar - function(object, ...) structure(pi, class=logLik, df=1)
AIC(bar.tmp)
[1] -4.283185
Dear David,
You may also consider using the biocep project' tools and frameworks. they
provide an advanced bridge that allow you to exchange between R and Java
any standard R Object and any mapped S4 object.
the object extracted to Java (an RList for you data) can be serialized to
a file (saved
Hi,
Could somebody help me with the following. I want to calculate the integral
over an implicit function. I thought to integrate over a function depending on
uniroot. In previous topics I found a thread about finding the root of an
integral. And that works. But the other way around, does not
Hello:
I would like to run a Cox proportional hazards regression on crayfish
dislodgement at different water velocities by crayfish size class and
substrate (rock) type. Additionally, there is a covariate variable, rock
movement that may be influencing crayfish dislodgment. So...
I have
marciarr wrote:
Hello R users,
I have been looking through Help files and Nabble list for the answers for
these simple questions, but it seems to be fruitless.
1- in a data frame with two columns, x and y, how do I get the corresponding
value of x to, let's say, the minimum value of the y
Dear list,
I am wondering if there are any parameters in heatmap.2
to be able to adjust the size of row labels. Or the size
of the plot can be made smaller. The plot I got is big
and cannot see the full row labels completely.
And what is the maximum of rows which could allow row
labels visible
The chi-square does not need your two categorical variables to have equal
levels, nor limitation for the number of levels.
The Chi-square procedure is as follow:
χ^2=∑_(All Cells)▒〖(Observed-Expected)〗^2/Expected
Expected Cell= E_ij=n((i^th RowTotal)/n)((j^th RowTotal)/n)
Degree of Freedom=df=
The chi-square does not need your two categorical variables to have equal
levels, nor limitation for the number of levels.
The Chi-square procedure is as follow:
χ^2=∑_(All Cells)▒〖(Observed-Expected)〗^2/Expected
Expected Cell= E_ij=n((i^th RowTotal)/n)((j^th RowTotal)/n)
Degree of Freedom=df=
Hi list,
Sorry for the vague title, but here is the scenario.
I’m writing an R package, let’s say, ‘pkg1’, which contains 3 functions: f1,
f2, f3. f2 and f3 are helper functions for f1, i.e. f1 calls f2 which in turn
calls f3.
f1 - function(…) {
….
f2()
…
}
f2 -
On Dec 6, 2007 3:26 PM, marciarr [EMAIL PROTECTED] wrote:
Hello R users,
I have been looking through Help files and Nabble list for the answers for
these simple questions, but it seems to be fruitless.
1- in a data frame with two columns, x and y, how do I get the corresponding
value of x
If you are using namespaces see:
?assignInNamespace
On Dec 6, 2007 5:38 PM, Tao Shi [EMAIL PROTECTED] wrote:
Hi list,
Sorry for the vague title, but here is the scenario.
I'm writing an R package, let's say, 'pkg1', which contains 3 functions: f1,
f2, f3. f2 and f3 are helper functions
Hi,
I am having trouble plotting the graph I need given the follow kind of data
xxx - data.frame(
x=c(1,2,3,4,5),
y1=c(2,4,3,5,6),
y2=c(3,4,6,3,1),
y3=c(1,3,5,7,3),
z1=c(1,NA,3,5,NA),
z2=c(2,NA,4,6,NA) )
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