I have a function called nnmf which takes in one matrix and returns two
matrices. for example,
X
[,1] [,2] [,3] [,4]
[1,]147 10
[2,]258 11
[3,]369 12
z=nnmf(X,2)
z$W
[,1] [,2]
[1,] 0.8645422 0.6643681
[2,] 1.7411863 0.5377504
thank you. I need learn it, after that, maybe I can understant it well.
thank Nikhil
Nikhil Kaza-2 wrote:
You need dim(cor.matrix)[1]
Following might be better instead of a loop, to to get the row ids of
a matrix
(which(cor.matrix =0.95) %/% dim(cor.matrix)[1])+1
for column ids
Hello, every one,
Using the qt() function in R, I got a different Student t-value with the
Student t table.
e.g. the return value of function qt(0.95,9) is 1.833, while in table it is
2.262.
I do not know why the difference exists. I guess it may be a bug in R.
--
Íõ»¯Èå ²©Ê¿Ñо¿Éú
Hi Huaru,
Are you sure you are looking at 0.95 and NOT 0.975?
as qt(0.975,9) = 2.262
generally tables are given for alpha/2 (alpha=0.05 in your case)
significance.
Please check carefully.
Thx,
S.
On Sat, Nov 7, 2009 at 4:02 AM, huaru wang huaru.w...@gmail.com wrote:
Hello, every one,
Hi, Sunny,
Sorry for my mistake. Thank you for your correction.
Thx,
Huaru
2009/11/7 Sunny Srivastava research.b...@gmail.com
Hi Huaru,
Are you sure you are looking at 0.95 and NOT 0.975?
as qt(0.975,9) = 2.262
generally tables are given for alpha/2 (alpha=0.05 in your case)
On 07-Nov-09 09:02:38, huaru wang wrote:
Hello, every one,
Using the qt() function in R, I got a different Student t-value
with the Student t table.
e.g. the return value of function qt(0.95,9) is 1.833, while in
table it is 2.262.
I do not know why the difference exists. I guess it may
Sunny Srivastava wrote:
Hi Huaru,
Are you sure you are looking at 0.95 and NOT 0.975?
as qt(0.975,9) = 2.262
generally tables are given for alpha/2 (alpha=0.05 in your case)
significance.
Please check carefully.
Or, put differently, tables are often given for two-sided p-values
(especially
Hi Greg
I downloaded the file france.shapefiles.zip
Then i unziped it.
There were 4 files interesting me:
- france_administrative.dbf
- france_administrative.prj
- france_administrative.shp
- france_administrative.shx
How can i do to read the map france_administrative with R
I tried this
Hi Greg,
Thank you very much for your help. The logspline package seems to solve the
problem.
Best regards,
Justine
Original-Nachricht
Datum: Thu, 5 Nov 2009 11:11:31 -0700
Von: Greg Snow greg.s...@imail.org
An: Justine Rochon roc...@gmx.de, r-help@r-project.org
I have problems with Rpad and R 2.10.0 (Windows XP and Windows 7,
browser is Firefox)
Just starting Rpad by
library(Rpad)
Rpad()
opens the browser and displays the
.html files and the .Rpad files in my home directory, but these
files do not have links and are not clickable.
Doing the same in R
On Fri, Nov 6, 2009 at 8:19 PM, Benilton Carvalho bcarv...@jhsph.edu wrote:
this is converging to bioc.
let me know what your sessionInfo() is and what type of CEL files you're
trying to read, additionally provide exactly how you reproduce the problem.
Here is my sessionInfo(). pname is
Perhaps asking on R-sig-geo might help (as well as reading the function help
files, scripts found lying around somewhere may be stale ...)?
If readShapePoly() (deprecated - use readShapeSpatial() instead) says that
the data are not polygons, then they are not. If you want to fill
administrative
If readShapePoly() (deprecated - use readShapeSpatial() instead) says that
the data are not polygons, then they are not. If you want to fill
administrative boundaries polygons, you need polygons, not lines. The source
you are using is based on OpenStreetMaps, so more likely to be lines, and as
you haven't answered how much resource you have available when you try
reading in the data.
with the mouse exon chip, the math is the same i mentioned before.
having 8 GB, you should be able to read in 70 samples of this chip. if
you can't, that's because you don't have enough resources
your could try something like this:
xprocess-function(max_val) {
result - list()
for (iter in 2: max_val) {
zz = sprintf( z%s, iter )
# use 'character' for indexing the list
result[[as.character(iter)]] -nnmf(X,iter)
}
result
}
xprocess(10)
On Fri, Nov 6, 2009 at 6:58
On Fri, Nov 6, 2009 at 11:58 PM, clue_less suhai_tim_...@yahoo.com wrote:
I have a function called nnmf which takes in one matrix and returns two
matrices. for example,
X
[,1] [,2] [,3] [,4]
[1,] 1 4 7 10
[2,] 2 5 8 11
[3,] 3 6 9 12
z=nnmf(X,2)
On Sat, 7 Nov 2009, hadley wickham wrote:
If readShapePoly() (deprecated - use readShapeSpatial() instead) says that
the data are not polygons, then they are not. If you want to fill
administrative boundaries polygons, you need polygons, not lines. The source
you are using is based on
Hi,
Student's T-test is a test that can be used to test ONE SINGLE linear
restriction - which serves the as alternative hypothesis - on a linear model -
which serves as the null hypothesis - AT THE SAME TIME.
Fisher's F test is an extension of the T test. The F test can be used to test
ONE
Most of the 8GB was available, when I run the code, because R was the
only computation session running.
On Sat, Nov 7, 2009 at 7:51 AM, Benilton Carvalho bcarv...@jhsph.edu wrote:
you haven't answered how much resource you have available when you try
reading in the data.
with the mouse exon
Evidently my RSeek capabilities have once again failed me...By any chance is
Scheffe's method
(http://www.itl.nist.gov/div898/handbook/prc/section4/prc472.htm) implemented
independently in any R base packages? If not, is it implemented independently
in any of the add-on packages?
Thanks
rm(list=ls())
yx.df-read.csv(c:/MK-2-72.csv,sep=',',header=T,dec='.')
dim(yx.df)
#get X matrix
y-yx.df[,1]
x-yx.df[,2:643]
#conver to matrix
mat-as.matrix(x)
#get row number
rownum-nrow(mat)
#remove the constant parameters
mat1-mat[,apply(mat,2,function(.col)!(all(.col[1]==.col[2:rownum])))]
vector1 vector2 vector3
vector4
h = 1.2345h = 1.2212h = 1.2065h =
1.3423
x1 = 0.8654y1 = 0.7525z1 = 1.3254x3 =
0.5746
x2 = 0.8642y2 = 0.2458
You can start as many instances of R as you like (except for memory
restrictions, perhaps), hence I do not get your point.
Uwe Ligges
Ivan wrote:
Thanks for that. I seem to be able to only get one R console here though.
Actually that is my question: how to get a different R console?
On
Can you please try to ask the package maintainer who will certainly be
happy to know if his function is broken and may know how to fix it.
Best,
Uwe Ligges
Uwe Ligges
Sunny Srivastava wrote:
Dear R-Helpers,
I am using qtl package to analyze qtl data from QTL cartographer.
I have the map
Yes I noticed the same problem since R 2.10.0, and I don't know why
either. Let's forward the email to the maintainer.
Regards,
Yihui
--
Yihui Xie xieyi...@gmail.com
Phone: 515-294-6609 Web: http://yihui.name
Department of Statistics, Iowa State University
3211 Snedecor Hall, Ames, IA
Hi,
I am tackling a computing problem in R that involves large data. Both time
and memory issues need to be seriously considered. Below is the problem
description and my tentative approach. I would appreciate if any one can
share thoughts on how to solve this problem more efficiently.
I have
ok, i'll take a look at this and get back to you during the week. b
On Nov 7, 2009, at 1:19 PM, Peng Yu wrote:
Most of the 8GB was available, when I run the code, because R was the
only computation session running.
On Sat, Nov 7, 2009 at 7:51 AM, Benilton Carvalho
bcarv...@jhsph.edu wrote:
Hello All,
How would one go about getting Pr(Y ≤ y|X = x) for a Frank copula via
the Copula or other package?
Best Regards,
David
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
Dear R users,
I'm new in R and couldn't find the solution to this in the postings. I want
to be able to use the leaps package to perform an exhaustive regression.
Most of my variables are categorical with many levels. I'd like to restrict
the candidate subsets to either all levels included or all
With the release of R-2.10.0 I have divided the dse bundle into packages. The
bundled package dse1 and part of dse2 are now in the new package dse. The
remaining part of dse2 is in a new package EvalEst. The package dse does
multivariate ARMA and state space time series modelling and
Dear list members,
I try to simulate an incomplete block design in which every participants
receives 3 out of 4 possible treatment. The outcome in binary.
Assigning a binary outcome to the BIB or PBIB dataset of the package
SASmixed gives the appropriate output.
With the code below, fixed
You have a couple of options:
1) typing the name of the function will list the source within your R
console. For example:
ls
will list the source code for the ls() function. So once you load your
package, you can simply enter the name of the function whose source you wish
to see and you will
Well, the problem is that I want those console to be from the same session
(i.e., they share same objects etc.). I do not think multiple instances of R
could do it ...
2009/11/7 Uwe Ligges lig...@statistik.tu-dortmund.de
You can start as many instances of R as you like (except for memory
Hi all,
I'm curious if anyone has coded an Expectation-Maximization algorithm
that could help me model some circular data I have. I'd like to model
it as a mixture of uniform and Von Mises centered on 0, so the only
free parameters is the mixing proportion and the kappa of the Von
Mises. I
Hi Dan,
I think it's because lines() is meant for you to add lines to a plot. Hence
it does not make R redraw the plot. If you wish to set the limits of the
y-axis (or x-axis for that matter), you should do it in the plot function
call, and then call lines() without the ylim=ry part. So your
On 07/11/2009 6:31 PM, Ivan wrote:
Well, the problem is that I want those console to be from the same session
(i.e., they share same objects etc.). I do not think multiple instances of R
could do it ...
No, there's only one console in each instance. That's pretty
fundamental: there is one
Dear all,
I have several response variables estimated from some simulations,
and I would like to identify the thresholds for trend changes.
Fro example, below I forced two different response behaviours
and on x is time unit.
x-1:1500
y-x/exp(x^0.2)
smaller15-y[y15]
Hi Mike,
I have an EM algorithm code for a binary von Mises mixture with 5 parameters:
mixing proportion (p), 2 locations (m1, m2), and 2 dispersion parameters (k1,
k2). Of course, your model is nested within this one, where k1=Inf, m1 =
arbitrary, m2=0. You should be able to modify my code
Dear all,
I am trying to analyze data from an experiment like this:
Factors:
Hormone - Levels: SH, CH (S = without; C=with; H=Hormone)
Time - Levels: 19/08/09, 04/09/09, 18/09/09, 08/10/09, 20/10/09 (DD/MM/YY)
Nutrition - Levels: Completa, Sem (without)
Macronutrition - Levels: Ca, K, Mg, P, Sem
On Nov 7, 2009, at 3:50 PM, Tidal Wave wrote:
Hello All,
How would one go about getting Pr(Y ≤ y|X = x) for a Frank copula
via
the Copula or other package?
Change the limits of integration?
--
David Winsemius, MD
Heritage Laboratories
West Hartford, CT
If you use the replicate or lapply functions then this will be taken care of
for you (a list will be created containing your function output).
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111
-Original Message-
From:
histogram(~ standard | Year, data = all2)
2009/11/7 Lanna Jin lanna...@gmail.com:
Hi all,
First off, thank you for the overwhelming response last time. I'm still
trying to figure out the syntax of R to plot some distributions of some
frequencies. I've managed to plot histograms from the
Hello:
I am trying to understand the method 'hatvalues(...)', which returns something
similar to the diagonals of the plain vanilla hat matrix [X(X'X)^(-1)X'], but
not quite.
A Fortran programmer I am not, but tracing through the code it looks like
perhaps some sort of correction based on
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