DW == David Winsemius dwinsem...@comcast.net
on Fri, 4 Dec 2009 01:18:56 -0500 writes:
DW On Dec 3, 2009, at 10:11 PM, Peng Yu wrote:
x=split(1:1000,1:1000)
str(x)
Although str() can suppress long output for vectors, but it can not
suppress long output for
Hi,
On Fri, Dec 4, 2009 at 3:12 AM, Gaurav Kumar gau...@gauravkumar.org wrote:
Hi R-users,
I'm using igraph for an undirected graph.
i used clusters() igraph function to know the component size(subgraphs) as
shown bellow:
c -clusters(g)
# component sizes
size - sort(c$csize,
On 12/04/2009 03:16 AM, Wells Oliver wrote:
Hello all. I have the following:
plot(salaries$yearID, salaries$salary, type='n', xaxt='n', xlab='',
yaxt='n', ylab='')
axis(1, at=unique(salaries$yearID), labels=unique(salaries$yearID), lwd=.25,
tck=-0.05)
axis(2, axTicks(2), format(axTicks(2),
On Thu, Dec 3, 2009 at 9:52 PM, John Filben johnfil...@yahoo.com wrote:
Can R support data manipulation programming that is available in the SAS
datastep? Specifically, can R support the following:
- Read multiple dataset one record at a time and compare values from
each; then base
Hi everyone. How can I draw a big heatmaps?
png(foo.png,1,1)
heatmap(x)
dev.off()
where x is a big matrix, say 200*200.
The code above generates a small heatmap in the middle of the png file
and leaves big margins. I expect it to take up more space so that the
labels are not
Dear R-users,
i try to solve to following linear programm in R
0 * x_1 + 2/3 * x_2 + 1/3 * x_3 + 1/3 * x_4 = 0.3
x_1 + x_2 + x_3 + x_4 = 1
x_1, x_2, x_3, x_4 0,
x_1, x_2, x_3, x_4 1
as you can see i have no objective function here besides that i use the
following code.
library(lpSolve)
Â
Dear R helpers
Â
Suppose I have two sets of ranges (interest rates) as
Â
Range 1 : (7 â 7.50, 7.50 â 8.50, 8.50 â 10.00) with respective
probabilities 0.42, 0.22 and 0.36.
Â
Â
Range II : (11-12, 12-14, 14-21) with respective probabilities 0.14, 0.56 and
0.30 respectively.
Â
Â
My
Dear all, i want to know if in R exist a method that give a logarithm
interpolation of a two columns of dates. I try to do the lm of logarithm of
the dates:
a-lm(log(vettore)~log(as.numeric(pippo2[3,])))
but this is a
linear correlation and not that i want.
thanks
giuseppe
Are the confidence Intervals for proportion according to Blyth,Still Casella
implemented in R?
Thank you in advance!
Cheers, Patrik
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Hi,
I have a numeric pixel image which I would like to divide into factors
for analysis in Spatstat. I have found that I can use cut.im() function
to divide the range of pixel values into a series of equal length
intervals (e.g. if my pixels values range from 0 to 60,
cut.im(X.im,breaks=2)
Need some help please
I am trying to use this model because I have temporal replication in my data
results-read.table(file=file.choose(),header=T)
attach(results)
names(results)
results-na.omit(results)
library(nlme)
library(lattice)
results-groupedData(weight~date|group,outer=~diet,results)
re [R] matrix^(-1/2)
re the discussion in November on this thread. I don't know about expm but
the problem must be equivalent to solve(B^(1/2)) and a solution will exist
iff B is invertible and has a square root A with A%*%A = B. For 2x2
matrices necessary and sufficient conditions for B to have
On Fri, Dec 4, 2009 at 11:53 AM, Sunny Srivastava
research.b...@gmail.com wrote:
Dear R-Helpers,
I am not very experienced in using lattice and I am still in the learning
stage
I have a data set which looks like this: (I have deleted a few lines in
order to save space)
Chromosome marker
Hi
It sometimes occur if I work on different computers. When I save work on
one and try to start with another it has to have installed all packages
used in a saved session. So I need to add a package(s) yet uninstalled and
than the session is started.
Petr Pikal
petr.pi...@precheza.cz
Dear R helpers
Suppose
M - c(1:10) # length(M) = 10
N - c(25:50) # length(N) = 26
I wish to have an outut file giving M and N. So I have tried
write.csv(data.frame(M, N), 'output.csv', row.names = FALSE)
but I get the following error message
Error in data.frame(M, N) :
On 12/4/2009 5:12 AM, Maithili Shiva wrote:
Dear R helpers
Suppose
M - c(1:10) # length(M) = 10
N - c(25:50) # length(N) = 26
I wish to have an outut file giving M and N. So I have tried
write.csv(data.frame(M, N), 'output.csv', row.names = FALSE)
but I get the
Peter Flom schrieb:
What do you mean by better?
Dear Peter
Thank you for your kind respons as well. You are right, we are in
constant debate whether it makes sense to remove variables (no matter
whether significant or not) from a total dataset which in itself has a
certain meaning and may not
On Fri, Dec 04, 2009 at 02:23:18AM +0100, Timothée Poisot wrote:
I am currently learning how to work with a new shared computer (a Mac pro) in
our lab, that is dedicated to execute R code for large simulations (over a
few days).
We have a VNC option to remote control the computer, with a
Hi all,,I´m using function arima()
I.e
series is my data
model-arima(series,c(1,0,0))
forecast-predict(model,80)
I want to create a variable:
b1-forecast$pred - 1.96*forecast$se
and save in a txt file
but using this:
save(b1, file= b1.txt)
creates afile butwith this inside:
â¹
Dear Mr Signer and Mr Cleland,
Thanks a lot for you great help. However, the output which I am getting is as
given below -
x
1;25
2;26
3;27
4;28
5;29
6;30
7;31
8;32
9;33
10;34
;35
;36
;37
;38
;39
;40
;41
;42
;43
;44
;45
;46
;47
;48
;49
;50
Hi everybody,
I'm trying to create a script that picks a txt file with 2 columns of
coordinates (depth and variable1) and automatically tries to fit several
polynomial with the function nls().
After that, it creates a list of observed, predict, residuals and other, and
then it calculates AIC,
Andreas Wittmann andreas_wittmann at gmx.de writes:
Dear R-users,
i try to solve to following linear programm in R
0 * x_1 + 2/3 * x_2 + 1/3 * x_3 + 1/3 * x_4 = 0.3
x_1 + x_2 + x_3 + x_4 = 1
x_1, x_2, x_3, x_4 0,
x_1, x_2, x_3, x_4 1
as you can see i have no objective function
Are the confidence Intervals for proportion according to Blyth,Still Casella
implemented in R?
Thank you in advance!
Cheers, Patrik
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Hello all,
I have two problems with the ROCR package.
First Problem:
the add=TRUE option does not work for plotting performance objects
The following code is taken from the reference manual (example for
ROCR.hiv, page2)
data(ROCR.hiv)
attach(ROCR.hiv)
pred.svm - prediction(hiv.svm$predictions,
Veronesi, Fabio wrote:
Hi everybody,
I'm trying to create a script that picks a txt file with 2 columns of
coordinates (depth and variable1) and automatically tries to fit several
polynomial with the function nls().
After that, it creates a list of observed, predict, residuals and other, and
Hi
r-help-boun...@r-project.org napsal dne 04.12.2009 12:09:08:
Hi everybody,
I'm trying to create a script that picks a txt file with 2 columns of
coordinates (depth and variable1) and automatically tries to fit several
polynomial with the function nls().
After that, it creates a list
Hi
r-help-boun...@r-project.org napsal dne 03.12.2009 10:45:44:
I would like to ask if there is some simple way for building a hist from
the
following data.
mm -c(2,3,0,4,5,0,2,9,0)
mmm - matrix(mm,ncol=3, nrow=3)
x - c(0,1.45,2.9)
in mmm there are frequencies (each column is
Hi,
I seek to identify those points in/outside a multidimensional convex hull
(geometry::convhulln). Any suggestions?
Background just in case I'm going down a really wrong road:
Given an observed data set with one dependent/observed variable (Y) and
multiple (3 to 10) independent/design
Hello R users,
When I type
d - density(MyData$x)
I obtain a density object I can plot,
But I wonder if there is a way to easily compute the length of the
density curve ?
( I imagine I could compute the distances between the 512 equally
spaced points using their x and y, but does it exist a
Andreas,
I don't know what it is exactly that you want to do, but perhaps you can try
using limSolve,
which solves for the equations Ex=F, Gx=H. In the code below, lsei calculates
the least squares solution (min sum(x^2)), xranges estimates the range of your
variables, and xsample takes a
hi Sylvain,
did you try ?density
regards
milton
On Fri, Dec 4, 2009 at 7:19 AM, sylvain willart
sylvain.will...@gmail.comwrote:
Hello R users,
When I type
d - density(MyData$x)
I obtain a density object I can plot,
But I wonder if there is a way to easily compute the length of the
Dear Amelia,
On 12/4/09, Amelia Livington amelia_living...@yahoo.com wrote:
Dear R helpers
Suppose I have two sets of ranges (interest rates) as
Range 1 : (7 – 7.50, 7.50 – 8.50, 8.50 – 10.00) with respective
probabilities 0.42, 0.22 and 0.36.
Range II : (11-12, 12-14, 14-21) with
The csv file is exactly as you describe it. ;35 represents two columns of
data. If you read it is, you will probably get NA as the value in the first
column. So what problem are you having in reading in the data?
x - read.csv(textConnection(8;32
+ 9;33
+ 10;34
+ ;35
+ ;36
+ ;37
+ ;38),
Yes, sure (and I just did it again)
but I can't see an answer... did I miss sthg ?
regards,
SW
2009/12/4 milton ruser milton.ru...@gmail.com:
hi Sylvain,
did you try ?density
regards
milton
On Fri, Dec 4, 2009 at 7:19 AM, sylvain willart sylvain.will...@gmail.com
wrote:
Hello R
True enough -- ?density does not address the issue of computing
the length pf the curve!
One simple way of implementing the idea you first thought of
would be on the following lines:
d - density(MyData$x)
sum(sqrt(diff(d$x)^2 + diff(d$y)^2))
which simply sums the lengths of the
Dear All,
I have a correlation matrix say 'M' (4000x4000) for 4000 genes and I want to
subset it to 'N' (190x190) for 190 genes.
The list of those 190 genes are in variable 't'. So the idea is to read the
names of genes from variable 't' and subset the matrix M accordingly.
Any thoughts are
On 12/04/2009 02:18 PM, Lee William wrote:
Dear All,
I have a correlation matrix say 'M' (4000x4000) for 4000 genes and I want to
subset it to 'N' (190x190) for 190 genes.
The list of those 190 genes are in variable 't'. So the idea is to read the
names of genes from variable 't' and subset the
Will something like this work for you:
x - matrix(1:100,10)
dimnames(x) - list(letters[1:10], LETTERS[1:10])
x
A B C D E F G H I J
a 1 11 21 31 41 51 61 71 81 91
b 2 12 22 32 42 52 62 72 82 92
c 3 13 23 33 43 53 63 73 83 93
d 4 14 24 34 44 54 64 74 84 94
e 5 15 25 35 45
Dear R community,
I'm using the ,metafor'-package by Wolfgang Viechtbauer (Version: 0.5-5) to
calculate random-effects meta-analyses using Correlations and Sample Sizes
as the raw data.
(By the way: Really a nice piece of work, Wolfgang! Thanks heaps.)
I specified the rma.uni' function
This is probably far more discussion than the question warranted, but...
On Thu, Dec 3, 2009 at 11:14 PM, David Winsemius dwinsem...@comcast.net wrote:
On Dec 3, 2009, at 10:52 PM, Gray Calhoun wrote:
The data import/export manual can elaborate on a lot of these; this is
all straightforward,
On 12/04/2009 02:24 PM, Romain Francois wrote:
On 12/04/2009 02:18 PM, Lee William wrote:
Dear All,
I have a correlation matrix say 'M' (4000x4000) for 4000 genes and I
want to
subset it to 'N' (190x190) for 190 genes.
The list of those 190 genes are in variable 't'. So the idea is to
read
Hello everybody,
I'm new in the R world and I'm struggling to set the working directory.
Up to now, I just set it up every time I start R ( 'setwd()' ) but I'd
like it to be set automatically. I've read the FAQ as well as the help
on Startup ('?Startup') about the environment variables and
Hi,
Yet another one of my very naive ideas on the subject: maybe you can
first evaluate the circumscribed and inscribed spheres of the base set
of points (maximum and minimum of their distances to the center of
gravity). Any points within a distance smaller than the infimum is
good, any point
hello R-masters.
i have an R-issue here that i don't know if you'd wish to help me about it:
briefly i'd like to generate many (say hundred) realizations of a random walk,
execute a few operations on each of them (mean time of return), and graph each
realization on the same plot.
IN OTHER
Hi
I want to generate from invers gamma distribution truncated but when I use
the rinvegamma() function, the system can not find this function.
Is ther someone to help me please?
thanks
soleiman
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Dear R-helpers,
I am very new to R and trying to run the conditional logit model using
clogit command.
I have more than 4000 observations in my dataset and try to predict the
dependent variable from 14 independent variables. My command is as follows
clmtest1 -
Dear all,
is it possible to perform logstic type of geographical weighted
regression in R software?
thanks in advance.
robert.
[[alternative HTML version deleted]]
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Hallo,
I have a dataset with one or two columns with character data
and the rest with numeric data.
Using latex.table from the quantreg package produced a table,
but I cannot set the decimals.
For instance:
---
x-data.frame(Name=c(Jan,Piet,Jan), V=c(1,2.991,3))
Hi to all
This is the first time I am quoting a question and I hope, my
question is not too basic...
For the following data, I wish to draw a fitted curve.
x - c(123,129,141,144,144,145,149,150,158,159,163,174,183,187,242,248)
y -
Thanks for your answer,
@Dennis Murphy: no, I don't know the functionnal form, this is purely
empirical data
@ Ted Harding: Thank you for your lines of code, they are actually a
pretty smart way...
SW
2009/12/4 Ted Harding ted.hard...@manchester.ac.uk:
True enough -- ?density does not address
Hello,
I'm trying out flexmix and mclust for the first time on some univariate data
which is typically best described as lognormal, but can sometimes be gamma
distributed as well. I first tried using EM on mclust assuming the data was
lognormally distributed and could only get it to work in E
Hi All,
I am trying to run the following script but have problem,
coxm- coxph(Surv(sdat$time, sdat$cens)~hd+nawtg+nwwg+ntpg+cy+nseas,data=sdat)
coxm-stepAIC(coxm,~.^2)
The error message is
Error: could not find function stepAIC
I tried to install the package but I could not find it. Where
On Fri, 2009-12-04 at 05:54 -0800, Federico Bonofiglio wrote:
hello R-masters.
i have an R-issue here that i don't know if you'd wish to help me
about it:
briefly i'd like to generate many (say hundred) realizations of a
random walk, execute a few operations on each of them (mean time of
A simple y vs log(x) fit seems to work pretty well here:
fit - lm(y ~ log(x))
summary(fit)
plot(y ~ log(x))
abline(fit)
On Fri, Dec 4, 2009 at 9:06 AM, Pascale Weber pascale.we...@wsl.ch wrote:
Hi to all
This is the first time I am quoting a question and I hope, my question is
not too
First, note that all attachments are removed from messages sent to
R-help, please use plain text only. I took the time to bring up the
attachment in a web browser (there is a link to it), but you are
unlikely to get a lot of readers when the question is captured as a pdf.
1. Tobit regression on
Alexandre,
You are mining for association rules with an absolute support count of
1001*0.01 = 10.1. From your 40 minutes processing time I guess that your
survey data set is very dense and that results in an enormous number of
frequent itemsets (potentially up to 2^k - k - 1 which is in your
Hello all,
Quick question: I want to do posthoc contrasts for a linear mixed
effects model. However, when trying to use the csimtest function in
multcomp package I receive an error message saying it cannot find the
function, even after installing and loading package multcomp.
Any
Hi all,
Imagine I have a matrix G
with N rows
and M columns
So L=NxM is the number of different cells in my matrix.
I want to create a column vector F whose size will be F(L,1)
So the fisrt row in F is G(1,1)
Second row in F is G(1,2)
When we arrive to a point M
the element M+1 will be G(2,
On Dec 4, 2009, at 9:29 AM, Ashta wrote:
Hi All,
I am trying to run the following script but have problem,
coxm- coxph(Surv(sdat$time, sdat$cens)~hd+nawtg+nwwg+ntpg+cy
+nseas,data=sdat)
coxm-stepAIC(coxm,~.^2)
The error message is
Error: could not find function stepAIC
Perhaps you have
Dear R-users,
I was wondering if anybody would have the source code used to create the
last figure in the frame.pdf documentation distributed with the grid
package.
Thanks in advance.
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On Fri, 4 Dec 2009, d.m.perk...@qmul.ac.uk wrote:
Hello all,
Quick question: I want to do posthoc contrasts for a linear mixed effects
model. However, when trying to use the csimtest function in multcomp package
I receive an error message saying it cannot find the function, even after
Daniel,
quick guess: There has been a major change in the package some time ago,
with quite a few functions vanishing and others added. So I guess your
recycled code was based on an older version of multcomp. My current
version (1.1-0) does not have csimtest anymore either. I guess you want
to
Hello,
I have a friday problem.
I'm trying to plot the number of measures by day with this command between
the 2008-07-31 and the 2009-11-13 (it works) :
plot(unique(as.Date(strptime(data$date, format=%Y-%m-%d %H:%M:%S))),
measuresbyday)
then I would like to plot vertical lines for each month.
matrix(t(G), nc=1)
b
On Dec 4, 2009, at 1:19 PM, Jose Narillos de Santos wrote:
Hi all,
Imagine I have a matrix G
with N rows
and M columns
So L=NxM is the number of different cells in my matrix.
I want to create a column vector F whose size will be F(L,1)
So the fisrt row
On 12/04/2009 04:28 PM, Sebastien Bihorel wrote:
Dear R-users,
I was wondering if anybody would have the source code used to create the
last figure in the frame.pdf documentation distributed with the grid
package.
file.show( vignette( frame, package = grid )$file )
Thanks in advance.
You set this on the properties of the shortcut you use to start R,
just like any other Windows application.
R's working directory is always initially the directory it is started
from.
This *is* in the FAQ:
http://cran.r-project.org/bin/windows/base/rw-FAQ.html#How-do-I-run-it_003f
even
Dear Sebastian,
Glad to hear you find the package useful.
Before I get to your questions, just as an aside - you can leave default
arguments out of the call. So:
MAergebnis-rma.uni(ri=PosOutc, ni=N, data=dm,
slab=c(dm$Article, dm$StudyNo), measure=ZCOR, method=DL)
would do exactly the same as
Pazur, Robert wrote:
Dear all,
is it possible to perform logstic type of geographical weighted
regression in R software?
thanks in advance.
robert.
[[alternative HTML version deleted]]
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On Dec 4, 2009, at 9:22 AM, Hien Nguyen wrote:
Dear R-helpers,
I am very new to R and trying to run the conditional logit model using
clogit command.
I have more than 4000 observations in my dataset and try to predict
the
dependent variable from 14 independent variables. My command is as
Thank you Romain,
I appreciate the help.
Romain Francois wrote:
On 12/04/2009 04:28 PM, Sebastien Bihorel wrote:
Dear R-users,
I was wondering if anybody would have the source code used to create the
last figure in the frame.pdf documentation distributed with the grid
package.
file.show(
?arima
?write.table
groet,
Paul
Jose Narillos de Santos wrote:
Hi all,,I´m using function arima()
I.e
series is my data
model-arima(series,c(1,0,0))
forecast-predict(model,80)
I want to create a variable:
b1-forecast$pred - 1.96*forecast$se
and save in a txt file
but using this:
save(b1,
On Dec 4, 2009, at 9:02 AM, khaz...@ceremade.dauphine.fr wrote:
Hi
I want to generate from invers gamma distribution truncated but when
I use
the rinvegamma() function, the system can not find this function.
Is ther someone to help me please?
Check your spledding.
thanks
soleiman
Lauren,
I think (?) you mean to say that you wish to create a factor and control the
range of values assigned to each level.
The breaks argument can specify either the number of intervals you desire
OR the values you wish to use to define levels of your factor. See '?cut'
and the following
Dear R-users,
For the past few days, I have been trying to find the reason why some of
my plots were showing symbols of different sizes, while I thought I was
using the same .cex arguments everywhere. The problem is exemplified by
the following example code where the xyplot and grid.points
On Dec 4, 2009, at 6:55 AM, Pazur, Robert wrote:
Dear all,
is it possible to perform logstic type of geographical weighted
regression in R software?
We even have a fortune for such questions:
library(fortunes)
fortune(Yoda)
Evelyn Hall: I would like to know how (if) I can extract some of
Sorry, but i was out for two days!
I just want to call R scripts from java code. So i think i need to review
the jri and the REngine API.
I will tell you whatever i find.
Thank you so much, because i was really lost!
2009/12/4 Romain Francois romain.franc...@dbmail.com
On 12/03/2009 08:43 PM,
In developing a machine learner to classify sentences in plain text
sources of scientific documents I have been using the caret
package and
following the procedures described in the vignettes. What I miss
in the
package -- but quite possibly I am overlooking it! -- is functions
A question that has come up a few times on r-help is how to rename columns
of a data.frame. There are several ways to do this by hand (see the list
archives). There is also a 'rename' function in the reshape package.
I often use the 'transform' function shortly after reading in a data file
and
On Dec 4, 2009, at 7:07 AM, StRose, Suzanne wrote:
Hi again,
Apologies for the last email I forwarded. Apparently, my data was
not legible. So, I have a question regarding the construction of 3D
graphs in ‘R’, BUT these graphs also need to illustrate movement
(with time) of the prostate
Stephanie Cooke wrote:
Is there a place to find the code for R functions like lsoda? Thanks
Yes, all code is in the source version of the package that contains that
function.
Best,
Uwe Ligges
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Hi,
I think the size mismatch occurs because of a different default for
the fontsize (and grid.points has a size of 1 character by default).
Compare the following two examples,
# default
grid.newpage()
pushViewport(viewport(x=unit(0.5, npc), y=unit(0.5, npc)))
Dear R forum,
I want to replace all the elements in a data frame (dd) which match the
character x with 0.
What's the most elegant way of doing this (there must be an easy way which
I've missed)? I settled on the following loop:
for(i in 5:12){# These are the column of dd I am
On Tue, Dec 1, 2009 at 4:04 PM, Charles C. Berry cbe...@tajo.ucsd.edu wrote:
On Tue, 1 Dec 2009, Peng Yu wrote:
Could somebody recommend some textbook how to compute contrast when
there are interactions terms? Applied Linear Regression Models
(book) mentioned contrast, but I cannot extend it
Here a way of doing it:
for (i in 5:12){
# convert to character so you can substitute 'x'
a - as.character(dd[,i])
a[a == 'x'] - '0' replace with zero
dd[,i] - as.numeric(a)
}
On Fri, Dec 4, 2009 at 11:55 AM, Allen L allen.laroc...@gmail.com wrote:
Dear R forum,
I want to
On Dec 4, 2009, at 11:55 AM, Allen L wrote:
Dear R forum,
I want to replace all the elements in a data frame (dd) which match
the
character x with 0.
What's the most elegant way of doing this (there must be an easy way
which
I've missed)? I settled on the following loop:
for(i in
The external grep program has an option -v to select non-matching
lines. I'm wondering if how to exclude certain patterns in grep() in
R?
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On 04/12/2009 12:52 PM, Peng Yu wrote:
The external grep program has an option -v to select non-matching
lines. I'm wondering if how to exclude certain patterns in grep() in
R?
?grep
Duncan Murdoch
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Hello R-users,
I would like to know how to find the standard deviation for each element
in a set of matrices.
Given the following files,
File1File2File3
1 1 1 4 4 4 7 7 7
2 2 2 5 5 5 8 8 8
3 3 3 6 6 6 9 9 9
I want to calculate the standard deviation for every
Hello, All,
I want to write a function to do some works based on the arguments. For
example, bind some variables (arguments) as this:
myfunction - function(arg1, arg2, arg3, …)
{
x - cbind(arg1, arg2, arg3, …)
}
myfunction(arg1, arg2, arg3, …)
The function can automatically determine
This reminds me of a quote I saw once (I think it may have been in one of those
Murphy's Laws calendars), my parahpase:
If you make someone think that they are thinking,
They will love you for it.
If you make them actually think,
They will hate you for it.
This explains why
Hi,
try ?do.call
do.call(cbind, replicate(3, 1:10, simplify=FALSE))
HTH,
baptiste
2009/12/4 Lisa lisa...@gmail.com:
Hello, All,
I want to write a function to do some works based on the arguments. For
example, bind some variables (arguments) as this:
myfunction - function(arg1, arg2,
An alternative to str is the TkListView function in the TeachingDemos package.
You still get the long listing, but it is in a separate window that you can
control the scrolling on by hand. For more complicated lists/objects it
provides a tree structure so that you can look at only the
On Fri, 4 Dec 2009, Peng Yu wrote:
On Tue, Dec 1, 2009 at 4:04 PM, Charles C. Berry cbe...@tajo.ucsd.edu wrote:
On Tue, 1 Dec 2009, Peng Yu wrote:
Could somebody recommend some textbook how to compute contrast when
there are interactions terms? Applied Linear Regression Models
(book)
Muhammad -
Here's one way:
files = c('File1','File2','File3')
themats = lapply(files,read.table)
ans = matrix(0,3,3)
for(i in 1:3)for(j in 1:3)ans[i,j] = sd(sapply(themats,function(x)x[i,j]))
Here's another
files = c('File1','File2','File3')
themats = lapply(files,read.table)
ans =
Hi Everyone,
I am new to R and just trying my hand at plotting a network from my dataset. I
am trying to teach myself network analysis, so this is probably an easy
question.
Using the package network, I have successfully plotted my network. I simply
want to add labels to my vertices, with
Pascale,
If you do want an nls fit with the associated error structure
assumptions, check ?SSlogis.
fm - nls(y ~ SSlogis(x, Asy, xmid, scal))
summary(fm)
xx - seq(123, 248, length = 101)
yy - predict(fm, list(x = xx))
plot(x, y)
lines(xx, yy)
-Peter Ehlers
Gabor Grothendieck wrote:
A
Hi Muhammad,
Load the data from all of the files into an array (probably using a
for loop), then call apply on the resulting array: ie
## replace the first line with code to load your data
rr - array(c(rep(1:3,3), rep(4:6,3), rep(7:9,3)), c(3,3,3))
apply(rr, c(1,2), sd)
[,1] [,2] [,3]
On Dec 4, 2009, at 1:27 PM, Gray Calhoun wrote:
Hi Muhammad,
Load the data from all of the files into an array (probably using a
for loop), then call apply on the resulting array: ie
I like that idea a lot and it does not need an explicit loop:
apply( array(c(File1, File2, File3),
Thank you for your reply. But this is not what I want.
For example, I have several variables, like
arg1 - c(1, 2, 3, 5, 6, 6)
arg2 - c(3, 1, 5, 5, 7, 8)
arg3 - c(8, 10, 4, 0, 9, 1)
arg4 - c(11, 22, 30, 5, 61, 22)
…
I just want to bind some of these variables based on the arguments assigned
in
Dear all
Is it normal that R ignores options(width=100) at start-up? Although
li...@debian-liv:~$ cat /usr/lib/R/etc/Rprofile.site | grep width
options(width = 100)
, R will start with
[Previously saved workspace restored]
options()$width
[1] 80
Am I doing something wrong?
Liviu
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