On 12/11/2009 08:41 AM, Achim Zeileis wrote:
On Fri, 11 Dec 2009, Rainer M Krug wrote:
Hi
is there an easy and fast way, to generate a BibTeX file of all
installed /
loaded packages and R?
I know about toBibtex(citation()) to extract the BibTeX for a single
package, but how can I generate a
On Thu, 10-Dec-2009 at 10:14PM -0800, z_axis wrote:
|
| The following is sampling data:
| No V1 V2 V3
| 1 0.23 0.12 0.89
| 2 0.11 0;56 0.12
| ...
|
| I just want to draw three lines on same picture according to value of V1, V2
| and V3.
?lines
--
Hi,
I am using the windows version of R. I wanted to copy a directory (containing
several files) to another directory. Is there any command in R that will let me
do this (something like the 'cp' command in UNIX)? I have looked at
'file.copy', but as the name implies I think it only copies one
On Fri, Dec 11, 2009 at 9:41 AM, Achim Zeileis
achim.zeil...@wu-wien.ac.atwrote:
On Fri, 11 Dec 2009, Rainer M Krug wrote:
Hi
is there an easy and fast way, to generate a BibTeX file of all installed
/
loaded packages and R?
I know about toBibtex(citation()) to extract the BibTeX for a
On Thu, 10 Dec 2009 13:56:12 -0600 Peng Yu pengyu...@gmail.com wrote:
type data.frame, split.data.frame will be called? Is it the case that
if the argument is not of type data.frame, Date or POSIXct,
split.default will be called?
Yes. See ?UseMethod
I tried it. But I'm not sure how to
Dear all,
does anybody know if it is possible, and how, to compute the Gamma correlation
in R?
Thank you very much in advance!
Manuel
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R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
thanks for your answer ! Would you mind giving me an example using my data ?
Sincerely!
Patrick Connolly-4 wrote:
On Thu, 10-Dec-2009 at 10:14PM -0800, z_axis wrote:
|
| The following is sampling data:
| No V1 V2 V3
| 1 0.23 0.12 0.89
| 2 0.11 0;56 0.12
| ...
|
|
2009/12/10 Charles C. Berry cbe...@tajo.ucsd.edu:
[snipped]
Many?
set.seed(1234)
ps - matrix(rnorm(4000),ncol=4)
phull - convhulln(ps)
xs - matrix(rnorm(1200),ncol=4)
phull2 - convhulln(rbind(ps,xs))
nrp - nrow(ps)
nrx - nrow(xs)
outside - unique(phull2[phull2nrp])-nrp
done - FALSE
Peng Yu wrote:
On Thu, Dec 10, 2009 at 7:03 PM, Dirk Eddelbuettel e...@debian.org wrote:
On 10 December 2009 at 18:12, Peng Yu wrote:
| If I use system.time() to measure the runtime of an expression, I will
| not get the result. Is there a way to measure the runtime and get the
| result as
On Wed, 2009-12-09 at 18:46 +0100, baptiste auguie wrote:
barchart(1:2, ylab=expression(Concentration (*mu*g/m^3*)))
or
barchart(1:2, ylab=expression(Concentration ~ (mu*g/m^3)))
That way you don't have to worry about quoting parts of the expression.
G
2009/12/9 Peng Cai
This is the intended startup message for that package (and not a
warning), nothing to fix.
Uwe Ligges
Peng Yu wrote:
I have following the message dim(refdata) and dimnames(refdata) no
longer allow parameter ref=TRUE, use dim(derefdata(refdata)),
dimnames(derefdata(refdata)) instead when I
try this:
x - read.table(textConnection(No V1 V2 V3
1 0.23 0.12 0.89
2 0.11 0.56 0.12), header=TRUE)
matplot(x[,1], x[,-1], type='l')
On Fri, Dec 11, 2009 at 3:39 AM, z_axis z_a...@163.com wrote:
thanks for your answer ! Would you mind giving me an example using my data
?
I'd use a shell() command to call xcopy or robocopy, or cp given you
have some unix tools installed.
Uwe Ligges
Paul Evans wrote:
Hi,
I am using the windows version of R. I wanted to copy a directory (containing
several files) to another directory. Is there any command in R that will let
try this:
x - data.frame(a=c('cat', 'cat,dog', 'dog', 'dog,cat'))
x
a
1 cat
2 cat,dog
3 dog
4 dog,cat
levels(x$a)
[1] cat cat,dog dog dog,cat
# change the factors
x$a - factor(sapply(strsplit(as.character(x$a), ','), '[[', 1))
x
a
1 cat
2 cat
3 dog
4 dog
Easiest way is probably to make grouprep a factor and insert a level
without observations such as in:
mydata$grouprep - factor(mydata$grouprep, levels =
paste(rep(LETTERS[1:5], each=2), paste(grp, 1:2, sep=)))
beanplot(val~grouprep, data = mydata, ll = 0.04,
main = example, ylab = Size,
What about this as a start :
dir.copy - function( source = getwd(), target ){
files - list.files( source, recursive = TRUE )
dirs - unique( gsub( /[^/]+$, , files[grepl(/, files)] ) )
if( !file.exists( target ) ){
dir.create( target )
Bogaso wrote:
Please consider following code :
set.seed(1)
res - vector(list)
for (i in 1:5) {
res1 - vector(list)
res1[[1]] - letters[1:5]
res1[[2]] - rnorm(5)
res1[[3]] - rnorm(5); res[[i]] - res1 }
res[[1]]
# Now I want to reduce the dimension of res through creating a data
Or this which removing the comma and everything thereafter in each
level that has a comma:
levels(x$a) - sub(,.*, , levels(x$a))
On Fri, Dec 11, 2009 at 5:21 AM, jim holtman jholt...@gmail.com wrote:
try this:
x - data.frame(a=c('cat', 'cat,dog', 'dog', 'dog,cat'))
x
a
1 cat
2
Dear all,
i am new in R. I am writing a review paper about batteries. However, i
am interested in analyzing all the papers by keywords, author,
references and year.
This could be done by refviz a software, which is only running on
windows machines and which is not free.
So my question to you
Thanks Romain, Uwe!
From: Romain Francois romain.franc...@dbmail.com
To: Uwe Ligges lig...@statistik.tu-dortmund.de
Sent: Fri, December 11, 2009 5:35:57 AM
Subject: Re: [R] copyING directories and files
What about this as a start :
dir.copy - function(
Schwan wrote:
Dear all,
i am new in R. I am writing a review paper about batteries. However, i
am interested in analyzing all the papers by keywords, author,
references and year.
This could be done by refviz a software, which is only running on
windows machines and which is not free.
I am running the lmer() command in a for loop and occasionally a particular
iteration is producing the false convergence warning. I would like to be
able to mark these iterations with a dummy variable, but I can't find any
other notification besides the warning message, which, in a for loop, only
baptiste auguie baptiste.aug...@googlemail.com wrote in message
news:de4e29f50912110200g7e43551kef5e8053fbf6e...@mail.gmail.com...
2009/12/10 Charles C. Berry cbe...@tajo.ucsd.edu:
[snipped]
Many?
snip Charles' elegant coding of the algorithm he summarises as:
Any point that is in the convex
Hi,
from what I understand, you may be interested in text mining, so perhaps
you want to look at the tm package.
Then again, depending on what you are really trying to do, you may be
better served with perl, awk and similar tools than with R...
HTH,
Stephan
Schwan schrieb:
Dear all,
i
Hi, all
How can generate a sample from truncated inverse gamma distribution in R?
thanks
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R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
Thanks for all the comments,
and sorry about the unstructured question! I am trying to:
1: analyze keywords, names from Authors and year of publication from
citations (with abstracts) i downloaded fron various sites(these
downloads can be converted into .txt files as well)
2: to cluster these
Schwan wrote:
Thanks for all the comments,
and sorry about the unstructured question! I am trying to:
1: analyze keywords, names from Authors and year of publication from
citations (with abstracts) i downloaded fron various sites(these
downloads can be converted into .txt files as
Hello,
I would like to get a lattice plot of 8 panels (unique(df$fact)=8) with 2
graphs (df$y1 and df$y2 as a function of df$x) and 1 red point at (500,
ymax) per panel.
The script below is quite ok but I'm not able to define two different colors
for the two graphs.
If you have an idea how to
Ok good question I havent explain!
Well,lets keep it simple for the begining. By analyzing the
keywords(which can also include the authors name) I mean,
1) investigate in which paper the keyword occur and how often
2) investigate if keywords occur together
X axis can show the paper title (or
Hi everybody,
It might be a stupid question, but please excuse it!
I would just like to export my ANOVA table from that kind of code:
stats - lm(Asfc~TO_POS, ssfa)
anova(stats)
into a *.csv or *.txt file.
Can anyone help please?
Thanks in advance
Ivan
The lack of a reproducible example is a bigger problem than any lack
of clarity of the explanation.
-Ista
On Fri, Dec 11, 2009 at 2:08 AM, bawa...@googlemail.com wrote:
Apologies,
I didn't explain this clearly. The Rscript is called by a perl script, which
creates input_file.txt by
It sounds pretty simple so far. Just put the citation info in a data
frame, and plot it. I would use ggplot2 for plotting, but it could be
done in base or lattice too.
On Fri, Dec 11, 2009 at 8:04 AM, Schwan s.s.hosse...@utwente.nl wrote:
Ok good question I havent explain!
Well,lets keep it
Hi,
Is there a way to get the enclosing function name within a function?
For example, I would like to have a function getEnclosingFunctionName().
It works like below
f = function(){
print(getEnclosingFunctionName())
}
f() # will print f
Thanks
Jeff
Try placing this in your function:
Name - match.call()[[1]]
On Fri, Dec 11, 2009 at 8:50 AM, Hao Cen h...@andrew.cmu.edu wrote:
Hi,
Is there a way to get the enclosing function name within a function?
For example, I would like to have a function getEnclosingFunctionName().
It works like
On Dec 11, 2009, at 8:17 AM, Ivan Calandra wrote:
Hi everybody,
It might be a stupid question, but please excuse it!
I would just like to export my ANOVA table from that kind of code:
stats - lm(Asfc~TO_POS, ssfa)
anova(stats)
into a *.csv or *.txt file.
capture.output(anova(model),
copyDirectory() in the R.utils package.
/Henrik
On Fri, Dec 11, 2009 at 1:01 AM, Paul Evans p.evan...@yahoo.com wrote:
Hi,
I am using the windows version of R. I wanted to copy a directory (containing
several files) to another directory. Is there any command in R that will let
me do this
Try this;
f - function()as.character(sys.call())
On Fri, Dec 11, 2009 at 11:50 AM, Hao Cen h...@andrew.cmu.edu wrote:
Hi,
Is there a way to get the enclosing function name within a function?
For example, I would like to have a function getEnclosingFunctionName().
It works like below
f =
Hans, you're my personal hero today !
The function seems to work fine for the tests I did already.
Thank you very much !
Geert
On Thursday 10 December 2009, Hans W Borchers wrote:
Geert Janssens janssens-geert at telenet.be writes:
On Wednesday 9 December 2009, Hans W Borchers wrote:
Hello,
I am learning how to use functions, but I'm running into a roadblock.
I would like my function to do two things: 1) convert an object to a
dataframe, 2) and then subset the dataframe. Both of these commands work
fine outside the function, but I would like to wrap them in a function so I
Greetings,
I am making 3D plots using persp3d, and would like to set z-axis
limits and make axis labels (the automatic numbers at tick marks) bold.
I have tried zlim, but this does not seem to force the plot to
restrain itself within certain bounds (e.g., 0-1). The surface I am
plotting (z
Hi,
.NotYetImplemented gives an example,
function ()
stop(gettextf('%s' is not implemented yet,
as.character(sys.call(sys.parent())[[1L]])),
call. = FALSE)
environment: namespace:base
HTH,
baptiste
2009/12/11 Hao Cen h...@andrew.cmu.edu:
Hi,
Is there a way to get the enclosing function
Thanks, but how should I put the citation inside a data frame?
data.frame(first txt file, second txt file...)
plot (what should I insert here) type=p
And how should I load the txt files anyway inside the frame?
On Fri, 2009-12-11 at 08:37 -0500, Ista Zahn wrote:
It sounds pretty
They are in Bibtex
For example:
@ARTICLE{adsdifvanadiumcationexchange,
author = {Jin-qing Chen and Bao-guo Wang and Ji-chu Yang},
title = {Adsorption and Diffusion of VOsup2+/sup and
VOsub2/sub sup+/sup
across Cation Membrane for All-Vanadium Redox Flow Battery},
journal = {Solvent
I think I located the problem. the data frame associated with my spatial object
(Insitu_sp) contains some NAs. And in this case, the function plot does not
like NAs. It simply behaved strangely. The code below did the trick :
idx = is.na(Insitu[,SPM])
ptsize = 0.35*(sqrt(Insitu[!idx,SPM])+1)
On Fri, Dec 11, 2009 at 3:04 PM, Schwan s.s.hosse...@utwente.nl wrote:
Thanks, but how should I put the citation inside a data frame?
data.frame(first txt file, second txt file...)
plot (what should I insert here) type=p
And how should I load the txt files anyway inside the frame?
Hi,
I would like to get the actual object name passed as a parameter of a
function and am using deparse(substitute(x)) to do that. It doesn't work
when it is used along with the foreach package. Appreciate if any one can
give some suggestions on how to make it work with foreach.
FUN.aaa -
On Fri, Dec 11, 2009 at 2:04 PM, Schwan s.s.hosse...@utwente.nl wrote:
Thanks, but how should I put the citation inside a data frame?
data.frame(first txt file, second txt file...)
plot (what should I insert here) type=p
And how should I load the txt files anyway inside the frame?
Katharine,
The problem of estimation of parameters in R is that you have to know the
value of the initial estimates very accurately, otherwise it does not
converge.
The example below could be resolved in Excel, however in does not converge.
How to solve the problem?
I made the chart on a
It works ! thank you very much.
Moreover, How about reading data from file ? The file is formatted as:
No V1 V2 V3
1 0.23 0.12 0.89
2 0.11 0.56 0.12
..
jholtman wrote:
try this:
x - read.table(textConnection(No V1 V2 V3
1 0.23 0.12 0.89
2 0.11 0.56 0.12),
Hans, you're my personal hero today !
The function seems to work fine for the tests I did already.
Thank you very much !
Geert
On Thursday 10 December 2009, Hans W Borchers wrote:
Geert Janssens janssens-geert at telenet.be writes:
On Wednesday 9 December 2009, Hans W Borchers wrote:
hi r-help,
i am doing kmeans clustering in stats. i tried for five clusters clustering
using:
kcl1 - kmeans(as1[,c(contlife,somlife,agglife,sexlife,
rellife,hordlife,doutlife,symtlife,washlife,
chcklife,rptlife,countlife,coltlife,ordlife)],
5,
I think I my original response was bad. And I also realize that I
don't really understand what you want to do.
Here is what I was thinking:
Format your bibliography as CSV (you can convert common bibliography
formats to .csv using Tellico or similar software). Then read the
references into a
Dear all, I am meeting some problems with memory allocation. I know it is an
old issue, I'm sorry.
I looked for a solution in the FAQs and manuals, mails, but without finding the
working answer.
I really hope you can help me.
For instance, if I try to read micorarray data I get:
Hello,
I am trying to include legend text with math symbols from a predefined
character variable that is read in from a file.
If there is only one line of text in the legend, the following, although
cumbersome, works for me:
LegendText = 'U' [infinity], '=10 m/s' # (read in from a file)
%cat test.csv
No,HS,ZangF,ZenF
1,0.25,0.5,0.57
2,0.10,0.23,0.12
3,0.20,0.25,0.1
..
d - read.csv(000301.txt)
matplot(d[,1], d[,-1], type='l')
It works. However, i hope the legend is displayed.
Sincerely!
z_axis wrote:
It works ! thank you very much.
Moreover, How about reading data
Hi,
I´m trying to use the calibrate function from rms package (made by prof.
Harrell) after fitting a model using cph. But it returns the following error
message:
calibrate(modelo1,B=200,bw=F,u=13)
Using Cox survival estimates at 13 Days
Convergence problems stopping addition
Error in
Dear R community,
just in case some haven't noticed my previous email.
I realize hclust relies on a Fortran routine, but I hoped
some of you might exactly know how that Y.hc_c$height
is computed. And, thus, explain the anomaly I found.
Thank you.
J
Dr James Foadi PhD
Membrane Protein Laboratory
Hello
I've created a function to make a plot with multiple pannels from columns
of data that are created in a previous function. In the example below the
number of columns is 8, giving 4 pannels, but in general it takes data
with any number of columns and figures out a nice layout.
The panels
Ista,
Here is the full code:
file-read.table(file=input_file.txt,sep=\t)[,c(1,3:5)]
file.rows- c(nrow(file)/288)
full.array - array(0,dim=c(8,file.rows,12))
cellnames - rep(A,file.rows)
barcodes - rep(A,file.rows)
t - rep(A,file.rows)
t11 - rep(A,file.rows)
cv - rep(A,file.rows)
for (k in
Hi Mark,
You're on the right track. You just need your function to return dataframe. Try
convert-function(d) {
d-data.frame(d); #convert object to dataframe
d-subset(d,select=c(time,coords.x1,coords.x2)) #select some columns
return(d)
}
-Ista
On Fri, Dec 11, 2009 at 9:19 AM, Mark Na
Sorry, the nasty for (min... loop is probably easier to read like this:
for (m in 1:8){
for (n in 1:12){
p- 3*q; x.array[m,n] - mean(as.matrix(x[(p-2):p,2:4])); q - q+1;
if (n == 1){
z-3*m; x.blank2[(z-2):z,]-as.matrix(x[(p-2):p,2:4])
}; if (n==11){
Dear R-users,
I am preparing graphs for an upcoming article using the different functions
of the ggplot2 package and I've been having problems with the legend
background. It doesn't seem to scale when the text size is increased. Here's
the mandatory reproducible example:
library(ggplot2)
The problem of estimation of parameters in R is that you have to know the
value of the initial estimates very accurately, otherwise it does not
converge.
This was discussed on R-help in the last 2 weeks; see the thread on
'Starting estimates for nls Exponential Fit'.
The example below
OK Thanks again for the help.
I have tried
example - read.csv(/PATH/test.cvs)
If i call for the results R is plotting all the data separated by title,
Keyword, author...)
However, I dont know how to tell R that it just should look for e.g.
author,keywords and year and how to plot these for
Dear Ms Karunambigai,
the kmeans algorithm depends on random initialisation.
There are two basic strategies that can be applied in order to make your
results reproducible:
1) Fix the random number generator by means of set.seed (see ?set.seed)
before you run kmeans. The problem with this is
Dear R family
I am attempting to create a matrix. e.g.,
0 0 0 0 1
1 0 0 0 0
0 1 0 0 0
0 0 1 0 0
0 0 0 1 0
How could I write a R program?
Later I want to extend it to a N by N case.
Thanks in advance
best
Moohwan
__
Hi Mark,
This question would probably be better suited for the r-sig-geo mailing
list. In addition, please read the posting guide and provide a piece of
code that reproduces the problem.
library(sp)
convert-function(d) {
d-data.frame(d); #convert object to dataframe
On Dec 11, 2009, at 6:24 AM, Ambrosi Alessandro wrote:
Dear all, I am meeting some problems with memory allocation. I know
it is an old issue, I'm sorry.
I looked for a solution in the FAQs and manuals, mails, but without
finding the working answer.
I really hope you can help me.
For
Try this:
N - 5
diag(1, N)[c(N, 1:(N - 1)),]
On Fri, Dec 11, 2009 at 1:47 PM, Moohwan Kim kmhl...@gmail.com wrote:
Dear R family
I am attempting to create a matrix. e.g.,
0 0 0 0 1
1 0 0 0 0
0 1 0 0 0
0 0 1 0 0
0 0 0 1 0
How could I write a R program?
Later I want to extend it
Hi,
i am new to the R-project but until now i have found solutions for every
problem in toturials, R Wikis and this mailing list, but now i have some
problems which I can't solve with this knowledge.
I have some data like this:
# sample data
head1 = a;b;c;d;e;f;g;h;i;k;l;m;n;o
data1 =
Hi,
i am new to the R-project but until now i have found solutions for every
problem in toturials, R Wikis and this mailing list, but now i have some
problems which I can't solve with this knowledge.
I have some data like this:
# sample data
head1 = a;b;c;d;e;f;g;h;i;k;l;m;n;o
data1 =
Hi
try
R library(magic)
R ashift(diag(5),1)
HTH
rksh
enrique Dallazuanna wrote:
Try this:
N - 5
diag(1, N)[c(N, 1:(N - 1)),]
On Fri, Dec 11, 2009 at 1:47 PM, Moohwan Kim kmhl...@gmail.com wrote:
Dear R family
I am attempting to create a matrix. e.g.,
0 0 0 0 1
1 0 0 0 0
0 1 0 0
Hi Him.
Did you read the Help/Manual in PDF/A Instroduction to R.PDF?
MyVect-scan()
0 0 0 0 1
1 0 0 0 0
0 1 0 0 0
0 0 1 0 0
0 0 0 1 0
MyVect
MyMat-matrix(MyVect, ncol=5, byrow=T)
MyMat
bests
milton
On Fri, Dec 11, 2009 at 10:47 AM, Moohwan Kim kmhl...@gmail.com wrote:
Dear R family
I
Doing a hessian estimate at each Nelder-Mead iteration is rather like going
from den Haag
to Delft as a pedestrian walking and swimming via San Francisco. The structure of the
algorithm means the Hessian estimate is done in addition to the NM work.
While my NM code was used for optim(), I
Rodrigo wrote:
Hi,
I´m trying to use the calibrate function from rms package (made by prof.
Harrell) after fitting a model using cph. But it returns the following error
message:
calibrate(modelo1,B=200,bw=F,u=13)
Using Cox survival estimates at 13 Days
Convergence problems stopping
Dear R family
I have a following question.
Suppose I have a matrix as follows, for instance:
tau=
0 0 0 0 1
1 0 0 0 0
0 1 0 0 0
0 0 1 0 0
0 0 0 1 0
I want to have the inverse of the above matrix and then add some
exponent to it. That is, I want to calculate tau to the (-m). For
example, m=893.
Ask on the bioconductpr mailing list, where you will be diirected to
several solutions for analyzing what I guess are 100's is cel files
http://bioconductor.org
--
Martin Morgan
On Dec 11, 2009, at 8:02 AM, Marc Schwartz marc_schwa...@me.com wrote:
On Dec 11, 2009, at 6:24 AM, Ambrosi
Hi Moohwan,
On Dec 11, 2009, at 11:26 AM, Moohwan Kim wrote:
Dear R family
I have a following question.
Suppose I have a matrix as follows, for instance:
tau=
0 0 0 0 1
1 0 0 0 0
0 1 0 0 0
0 0 1 0 0
0 0 0 1 0
I want to have the inverse of the above matrix and then add some
The following examples are confusing to me. It is OK, to assigned NULL
to one element in a list. The result is still a list. However, a list
of NULL's are reduced to NULL. I don't understand how this conversion
occurs. Could somebody let me know what is going on?
X=matrix(1:8, nr=4)
apply(X,1,
Hi,
I am teaching a one month class in applied statistics and want to
bring my students up to speed in R without devoting much/any lecture
time to R instruction. I think that the best way to do this is to
provide them with a lot of R questions for homework. These questions
would be numerous
-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of Peng Yu
Sent: Friday, December 11, 2009 8:44 AM
To: r-h...@stat.math.ethz.ch
Subject: [R] Why a list of NULL's are reduced to NULL?
The following examples are confusing to me.
All,
I'm relatively new to using R, having used it thus far for some simple
statistics and plotting. However, I'm not new to programming by any
measure.
I've been looking at the various modules available for clustering,
factor analysis, etc. and find that I need advice on which modules I
should
Dear R users,
I am trying to apply SVM regression for a set of microarray data. I am using
the function svm() under the package {e1071}. Can anyone tell me what
the *residuals
*value represents? I have some observed values *y_obs* for the parameter
that I want to estimate and I would expect that
http://cran.r-project.org/doc/FAQ/R-FAQ.html#How-can-I-set-components-of-a-list-to-NULL_003f
The explanation on this FAQ entry is not clear. It says '... similarly
for named components...'. What I understood was x[i]-list(NULL) is
the same as x$a_name-list(NULL). But, they are not. As the example
-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of Karl Ove Hufthammer
Sent: Thursday, December 10, 2009 1:46 AM
To: r-h...@stat.math.ethz.ch
Subject: Re: [R] How to figure out which the version of split is used?
On Wed, 9 Dec
Hi Eleni,
On Dec 11, 2009, at 12:04 PM, Eleni Christodoulou wrote:
Dear R users,
I am trying to apply SVM regression for a set of microarray data. I am using
the function svm() under the package {e1071}. Can anyone tell me what
the *residuals
*value represents? I have some observed values
On Fri, Dec 11, 2009 at 11:01 AM, William Dunlap wdun...@tibco.com wrote:
-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of Peng Yu
Sent: Friday, December 11, 2009 8:44 AM
To: r-h...@stat.math.ethz.ch
Subject: [R] Why a list of
Try this using xyplot.zoo in the zoo package. We define the baseline
and a panel function. The panel function just performs the default
action to display the graphs and adds the baseline. The screens
variable is 1,1,2,2,3,3,4,4. We create a zoo object from dat and use
screens to name the
Hi,
On Dec 11, 2009, at 12:07 PM, Peng Yu wrote:
http://cran.r-project.org/doc/FAQ/R-FAQ.html#How-can-I-set-components-of-a-list-to-NULL_003f
The explanation on this FAQ entry is not clear. It says '... similarly
for named components...'. What I understood was x[i]-list(NULL) is
the same
On Fri, Dec 11, 2009 at 11:27 AM, Steve Lianoglou
mailinglist.honey...@gmail.com wrote:
Hi,
On Dec 11, 2009, at 12:07 PM, Peng Yu wrote:
http://cran.r-project.org/doc/FAQ/R-FAQ.html#How-can-I-set-components-of-a-list-to-NULL_003f
The explanation on this FAQ entry is not clear. It says '...
-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of Peng Yu
Sent: Friday, December 11, 2009 9:18 AM
To: r-h...@stat.math.ethz.ch
Subject: Re: [R] Why a list of NULL's are reduced to NULL?
On Fri, Dec 11, 2009 at 11:01 AM,
On Dec 11, 2009, at 12:36 PM, Peng Yu wrote:
[snip]
What seems confusing to me is:
even 'x[i]-list(NULL)' and 'x[[i]]-list(NULL)' are different, why
x[i]-NULL and x[[i]]-NULL are the same?
Shouldn't the meaning of 'x[[i]]-NULL' be defined as the set the i'th
element NULL, rather than
On Fri, Dec 11, 2009 at 11:43 AM, William Dunlap wdun...@tibco.com wrote:
-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of Peng Yu
Sent: Friday, December 11, 2009 9:18 AM
To: r-h...@stat.math.ethz.ch
Subject: Re: [R] Why a list
Hi Dave,
I have a few drills available from http://had.co.nz/stat405 - see the
right hand column, about half way down. They seem similar in spirit
to what you're thinking of. You might want to look at the Little
Schemer for a similar approach with a different programming language.
However, I'm
A very common situation is that the users don't know all the possible
return types of 'some_third_party_function()'. If the users don't know
all the return types, he/she can not make sure the return type of
function(x) {...} be always the same. How do you deal with this case?
It's not that
I suspect that you don't know about 'profile' confidence
intervals. If that's true then I can recommend the
discussion in MASS (the book) in section 8.4.
In a nutshell, I don't think that you want to do
a profile confint calculation manually (unless typing
instructions that use the function
Hi Luc,
You want:
legend.title=theme_text(size=20, hjust = 0)
So the legend title is left aligned, not centred.
Hadley
On Fri, Dec 11, 2009 at 9:26 AM, MUHC_Research
villa...@dms.umontreal.ca wrote:
Dear R-users,
I am preparing graphs for an upcoming article using the different functions
On Fri, Dec 11, 2009 at 11:51 AM, Steve Lianoglou
mailinglist.honey...@gmail.com wrote:
On Dec 11, 2009, at 12:36 PM, Peng Yu wrote:
[snip]
What seems confusing to me is:
even 'x[i]-list(NULL)' and 'x[[i]]-list(NULL)' are different, why
x[i]-NULL and x[[i]]-NULL are the same?
Shouldn't
On Fri, Dec 11, 2009 at 12:05 PM, hadley wickham h.wick...@gmail.com wrote:
A very common situation is that the users don't know all the possible
return types of 'some_third_party_function()'. If the users don't know
all the return types, he/she can not make sure the return type of
function(x)
Many thanks for the replies to my call for help this morning. I didn't know
about return() and that helped quite a bit.
Best, Mark
On Fri, Dec 11, 2009 at 10:00 AM, Paul Hiemstra p.hiems...@geo.uu.nlwrote:
Hi Mark,
This question would probably be better suited for the r-sig-geo mailing
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