That's what he tried, but the bottom line is that just because something is
called foo.xpt there is no guarantee that it actually is a SAS XPORT file.
Firefox plugins use the same extension but it could really be anything - naming
conventions are just that: conventions.
So dig deeper and find
Does read.xport read both version 5 and version 8 xpt files? This link to
the Library of Congress can get you started on how to interpret the
header. (It states that Version 8 was introduced in 2012 but was not in
wide use as of early 2017.)
> On Apr 14, 2018, at 12:18 PM, WRAY NICHOLAS via R-help
> wrote:
>
>
> Original Message --
> From: WRAY NICHOLAS
> To: peter dalgaard
> Date: 14 April 2018 at 20:18
> Subject: Re: [R] Reading xpt files
> When I look at the SASxport::read.xport function code, it is in fact,
_not_ the
> same function. But it does have the R statement about what it thinks
> qualifies as a SAS xprot file:
>
> xport.file.header <- "HEADER RECORD***LIBRARY HEADER
> RECORD!!!00
"
>
Hei,
I just wonder the use of family=binomial in glm function.
As I learned from book (e.g. Andy Field) that logistic regression (binary
logit) can use glm funtion with family = binomial. Here the y is a factor
variable (e.g. value = 1 or 2).
But I have also seen i many other cases, same
On 14/04/2018 5:33 PM, Zhang Wilson wrote:
Hei,
I just wonder the use of family=binomial in glm function.
As I learned from book (e.g. Andy Field) that logistic regression (binary
logit) can use glm funtion with family = binomial. Here the y is a factor
variable (e.g. value = 1 or 2).
Original Message --
From: WRAY NICHOLAS
To: peter dalgaard
Date: 14 April 2018 at 20:18
Subject: Re: [R] Reading xpt files into R
Well yesterday I'd downloaded the "foreign" package and tried to open the xpt
file using that:
Greetings,
I have been having a problem installing RQDA on my Mac (OS 10.13.2). I
followed the installation process on the RQDA page (
http://rqda.r-forge.r-project.org/), but I keep getting an error message
saying that I am missing pkg-config and GTK. I reinstalled XQuartz and GTK+
2.24.17
Funciona, gracias una vez más,
Manuel
Quoting "Carlos J. Gil Bellosta" :
Probaría con
apply(data, 1, function(x) names(table(x))[which.max(table(x))])
No sé si he contado los paréntesis bien.
El sáb., 14 abr. 2018 a las 20:33, Manuel Mendoza ()
Hola de nuevo. Mi problema es parecido al anterior.
Tengo una df con n filas con un valor para cada una de las 5 variables
(v1 a v5), y necesito construir un vector con la variable para la que
cada fila tiene el valor máximo. El vector tendrá n elementos del tipo
v3,v2,v2,v5,
vec<-
Gracias Carlos J., sale bien, pero me transforma las 6 categorías en
números del 1 al 6
¿sabes cómo evitarlo?
Quoting "Carlos J. Gil Bellosta" :
apply(data, 1, function(x) which.max(table(x)))
El sáb., 14 abr. 2018 a las 19:54, Manuel Mendoza
Hola,
Solo te falta incluir ese vector de índices en el vector de nombres.
Aquí tienes un ejemplo:
> head(airquality)
Ozone Solar.R Wind Temp Month Day
141 190 7.4 67 5 1
236 118 8.0 72 5 2
312 149 12.6 74 5 3
418 313 11.5 62 5 4
Buenas tardes de sábado. LLevo más de una hora intentando una cosa que
debe ser una chorrada; a ver si alguien puede ayudarme.
Tengo una matriz (data) de 1000 muestras (filas) y 6 categorías
posibles. Hay 100 columnas, es decir, 100 votos para cada muestra, y
necesito crear un vector con
apply(data, 1, function(x) which.max(table(x)))
El sáb., 14 abr. 2018 a las 19:54, Manuel Mendoza ()
escribió:
>
> Buenas tardes de sábado. LLevo más de una hora intentando una cosa que
> debe ser una chorrada; a ver si alguien puede ayudarme.
>
> Tengo una matriz (data)
G'day Ista,
I'm having trouble getting an example small enough to show. Some work
properly and others (usually longer ones) don't. Can't imagine what
makes the difference.
I'll be at the machine where I normally work and there I'll find a
small example.
Thanks for looking at my problem.
best
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