I have to fit a model to growth data of Hevea (rubber) trees. The details
are outlined in the attached docx file. Kind help is solicited.
--
Dr. TR Chandrasekhar, M.Sc., M. Tech., Ph. D.,
Sr. Scientist
Rubber Research Institute of India
Hevea Breeding Sub Station
Kadaba - 574 221
DK Dt.,
I have to fit a model to growth data of Hevea (rubber) trees. The details
are outlined in the attached docx file. Kind help is solicited.
--
Dr. TR Chandrasekhar, M.Sc., M. Tech., Ph. D.,
Sr. Scientist
Rubber Research Institute of India
Hevea Breeding Sub Station
Kadaba - 574 221
DK Dt.,
Hi All,
I have to fit the following model to growth data of Hevea (rubber) trees.
[image: a = a - (a - b){e^{ - \,\,\frac{2}{T}(F(t) - F({t_0}))}}] where [image:
F(t) = t + \frac{A}{{2\pi }}\sin 2\pi (t - {t_1})], [image: F({t_0}) =
{t_0} + \frac{A}{{2\pi }}\sin 2\pi ({t_0} - {t_1})], and *t1*
Dear All,
I have to fit the following model to growth data of Hevea (rubber) trees:
*a=a-(a-b)exp(-(2/p)(F(t)-F(t0))).* Where *F(t)=t+(A/2pi)(sin 2pi(t-t1))*,
*F(t0)=t0+(A/2pi)(sin 2pi(t0-t1)), t1* signifies the maximum point of
*f(t)*. Thus the equation becomes: