Le 09/06/2015 06:50, Viviane Pons a écrit :
Hi everyone,
I'm doing this:
sage: FreeA.a,b,c,d,e,f = FreeAlgebra(QQ,implementation=letterplace)
sage: P = a*b*a*c*c*b + a*b*a*d*d*b + a*c*a*d*d*c + b*c*b*d*d*c
sage: X = P.lm()
sage: X
a*b*a*c*c*b
And now I would like a way to cut my element X
The thing is: we actually need this specific implementation which is much
quicker for what we're doing. So I'm going to look closer at the object and
probably open a ticket to allow for such basic operation.
Best
Viviane
2015-06-09 2:24 GMT-05:00 Nicolas Borie nicolas.bo...@univ-mlv.fr:
Le
Yes, I actually figured that out after some time.
We've opened a ticket here : http://trac.sagemath.org/ticket/18653 and I'm
on it: doing basically what you're saying.
Best
Viviane
2015-06-09 12:32 GMT-05:00 John H Palmieri jhpalmier...@gmail.com:
sage: list(X)
[((1, 0, 0, 0, 0, 0, 0, 1, 0,
sage: list(X)
[((1, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0,
0, 0, 1, 0, 0, 0, 0, 1, 0, 0, 0, 0),
1)]
It looks like the tuple is a concatenation of 6 (one for each factor of X)
tuples of length 6 (one for each generator): (1,0,0,0,0,0), (0,1,0,0,0,0),
etc.,
Hi everyone,
I'm doing this:
sage: FreeA.a,b,c,d,e,f = FreeAlgebra(QQ,implementation=letterplace)
sage: P = a*b*a*c*c*b + a*b*a*d*d*b + a*c*a*d*d*c + b*c*b*d*d*c
sage: X = P.lm()
sage: X
a*b*a*c*c*b
And now I would like a way to cut my element X into two factors of a
given size. Something like
